Physical Sciences Grade 12 Question Paper

POST TEST TESTMEMO MEMO Question 1  1.1 y ( x  x 2 )2 5 x 2x  x 4  2 (a) correct simplification 3 (ca) each term dy 1  5x  4x 3  2 dx (4) 1.2. (a) correct values (1) 1.2.1 (0;1) 1.2.1 y  log3 x (a) correct equation (1) 1.2.3 0 < x ≤ 1  (a) correct interval (2) 1.2.4 x = 1 (a) correct value (1) Question 2 2. 2.1 cos 2x  7 cos x  3 0 2cos2 x  1  7cox  3 0  2cos2x – 1 2cos2 x  7 cos x  4  0  standard form  correct factors (2cos x  1)(cos x  4)  0 2cos x 1or  cos x 4  1 cos x   or n / a 2 x  cos 1 ( 1 ) 2 x  60 0 ref angle  ref angle  120o and 2400 1200  k.3600 ,k  x or  k є 𝛧𝛧 0 0 x 240  k.360 ,k  (6)

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https://ultradeep.co.za POST TEST MEMO TEST MEMO Question 3 3.1 If the two triangles are equiangular, then the corresponding sides are in the same proportion  (1) in MTK and ONK  angle K with reason K̂ is common  angle M with reason 3.2.1 M̂1  Oˆ ext  of cyclic quad  angle T with reason T ˆ ˆ ext  of cyclic quad N (3) 2  MTK / / / ONK (AAA) KM KT (a) prop reason  (from / / /) (a) conclusion 3.2.2 KO KN (2) KM. KN  KT. KO 3.2.3 KT = ?, OT = 6units, MN = 3 units & MK = 5 units KT KM  KN KO KM . NK KT (KO  KT  OT) KO 5. (3  5) KT (NK NM  MK)  (a)(a) correct substitution KT  6  KT 2  6KT  40  (a) correct factors  KT 2  6 KT  40 0   (ca)KT (KT  10)(KT  4)  0 (4) KT  10  or KT 4   KT 4units  GRAND TOTAL 25 https://tvetpapers.co.za