Physical Sciences Grade 12 Mpumalanga March Test 2025 Memo

education MPUMALANGA PROVINCE REPUBLIC OF SOUTH AFRICA FURTHER EDUCATION AND TRAINING NKANGALA DISTRICT/ DISTRIK GRADE/ GRAAD 12 | PHYSICAL SCIENCES MARCH 2025 CONTROLLED TEST MEMO MARKS/ PUNTE:100 TIME/ TYD :2 HOURS/ URE This marking guideline paper consists 9 of pages Hierdie nasienriglyn bestaan uit 9 bladsye Page 1 of 7

QUESTION/ VRAAG 1 11. =A (2) 1.2 vDvv (2) 13 Dvv (2) 14. BYY (2) 15 Avy (2) 16 Cvv (2) (12] QUESTION/ VRAAG 2 2A When a net force acts on an object, the object will accelerate in the direction of the force and the acceleration is directly proportional to the force and inversely proportional to the mass of the object Wanneer 'n resulterende/netto krag op 'n voorwerp inwerk, versnel die voorwerp in die rigting van die krag teen 'n versnelling direk eweredig aan die krag en omgekeerd eweredig aan die massa van die voorwerp. Vv ¥ (2) 2.2 Accepted labels NY F Fa/applied force/35N/ Toegepaste krag Tv N Normal force/Fy / Normaalkrag fv F T Tension / Fr / Spanning we NS f Frictional force / Fi/f, / wrywingskrag w Fg / Fw /force of earth on block / weight / mg / gravitational force/ gewig/ gravitasiekrag (5) 2.3.1 Fre=ma Fret=0 Any one ¥ Marking criteria Fcos8 —-T-f=0 Formula/ Formule~ Fcoos@ — T — uN =0 Substitution for friction / Vervanging aH van wrywing¥ Fcos@ — T — (u,mg+35sin20°) = Whole substitution / Hele 35 cos 20 -T-(0.2)(6x9.8+35sin20°) Vv =0V vervangingY T=18.74 NY Answer with correct units / Antwoord met korrekte eenheidY (4) 2.3.2. POSITIVE MARKING FROM / POSITIWE MERK VANAF 2.3.1 Fret=ma Any one / Enige een” Fret=0 T-(mgsin®)-(u,mgcos®) = 18.74 — (mx9.8sin30")-(0.15)(mx9.8cos30")v= 0 ¥ m=3.03 kg ¥ (4) Page 2 of 7

[15] QUESTION/ VRAAG 3 3.1. Motion under the influence of the gravitational force/weight ONLY (2) Vryval is die beweging waartydens die ENIGSTE krag wat op 'n voorwerp inwerk, die gravitasiekrag is.“ ¥ 3.2. OPTION OPSIE 1 OPTION/ OPSIE 2 UPWARD AS POSITIVE/ OPWAARTS | DOWNWARD AS POSITIVE/ POSITIEF AFWAARTS AS POSITIEF vz=vi2+2ady ¥ vP=Vvi2+2ady ¥ 292=07+ 2(9,8)AyY 07=292+ 2(-9.8)AyY Ay= 42,91m ¥ Ay= 42,91m ¥ UPWARD AS POSITIVE/ OPWAARTS DOWNWARD AS POSITIVE/ | POSITIEF AFWAARTS AS POSITIEF vyr=vie+2ady v,Z=vi2+2ady ¥ (-29)?=02+ 2(-9,.8)AyY 07=(-29)2+ 2(9,8)AyY Ay= 42,91m ¥ Ay= 42,91m v (3) OPTION/ OPSIE 1 OPTION/ OPSIE 2 3.3 | UPWARD AS POSITIVE/ OPWAARTS _| UPWARD AS POSITIVE/ OPWAARTS POSITIEF POSITIEF vey taaty vevitadty 0 = 29 + (-9.8)At ¥ -29V = 29 + (-9.8)Atv At=2,96s At = 5,92 s ¥ At = 2x 2,96 V =5,92sv DOWNWARD AS POSITIVE! DOWNWARD AS POSITIVE/ AFWAARTS AS POSITIEF AFWAARTS AS POSITIEF ~ e ViSUPTAREY Vvy=VvitaAt my 29 v = -29 + (-9.8)At¥ 29 v= -29 + (9.8)At ¥ At=5.92sVv At=5,92sv i (4) 3.4 POSITIVE MARKING FROM/ POSITIEWE MERK VANAF 3.3 UPWARD AS POSITIVE/ OPWAARTS DOWNWARD AS POSITIVE! AFWAARTS AS POSITIEF POSITIEF dt _— si 1 Ay = vidt +5 abt?v Ay = vide +5 ai v= -1)+ = 12” “58 ¥= y(5.92-1)+ 4-9,8(5,92-17v | 98” = WE.O2-1 1B.8)16.92-% vi=12,32_m-s7'V¥ we12,32 ms (4) Page 3 of 7

3.5 POSITIVE MARKING FROM/ POSITEWE MERK VANAF 3.3 and/ en 3.4 UPWARDS AS POSTIVE OPWAARTS AS POSITIEF 29 Marking criteria/ Merk riglyne Graph A start at the initial velocity of 29 m:s~' and Graph B start at the initial velocity 12,32 m-s-1 and at t=1s. Grafiek A begin by 29 m.s EN Grafiek B begin by 12,32 m.s” by tyd t=1s Correct shape for graph A and B/ Korrekte vorm vir | grafieke A en B The two graph a parallel and graph B below A. Grafieklyne parallel, B laer as A 12,32 Both A and B end at 5,92 s./Beide eindig by 5.92s 1 5:92 Time/ Tyd (s) cs} A oO £ oO = 2) > = 3 n fee ee ere eee ee Ss & DOWNWARD AS POSITIVE/ AFWAARTS AS POSITIEF A = dt t 5 ‘St Graph A start at the initial velocity of 29 m-s-* and Graph B start at the initial velocity 12,32 m-s-' and at t=1s. E i} = | oO \ <4 1 oO ! & { 7) ' > ' = | 2 i @® 1 > it 5.92 __Timet Td 23 Marking criteria/ Merk riglyne. Grafiek A begin by 29 m.s‘t EN Grafiek B begin by 12,32 m.s' by tyd t=1s Correct shape for graph A and B/ / Korrekte vorm vir grafieke A en B The two graph a parallel and graph B above A./ Grafieklyne_ parallel, B laer as A Both A and B end at 5,92 s./ Beide eindig by 5.92s Page 4 of 7

QUESTION/ VRAAG 4 4.1 In an isolated system the total mechanical energy is conserved/remains constant. Die totale meganiese energie (som van gravitasie- potensiéle energie en kinetiese energie) in 'n geslote sisteem bly konstant. Vv 1 2 1 2 Yong + 5 mv i= Dicng + 5mv My O+ Sx 2xvi2v = 1,2x0,65 + OY 4.2 vi= 3,57 ms" '¥ (4) 4.3 In an isolated system the total linear momentum is conserved/remains constant. Die totale lineére momentum in 'n geisoleerde sisteem bly konstant (behoue). ¥ ¥ (2) 4.4 POSITIVE MARKING FROM/ POSITIEWEE MERK VANAF 4.2 Y Pi = Y Pr Any one/ Enige een ¥ maviit Mavi2= Mivert Maver 0,4*vb¥ +0=0,4*(-0,36)+1,2% 3,57” vo=10,35 m:s-'¥ (4) [12] QUESTION/ VRAAG 5 5.1 A bond or an atom or a group of atoms that determine(s) the (physical and chemical) properties of a group of organic compounds Funksionele groep: 'n Binding of 'n atoom of 'n groep atome wat die fisiese en chemiese eienskappe van 'n groep organiese verbindings bepaal Vv” (2) 5.2.1 Av &CY¥ (2) 5.2.2 Ketone / KetoonY Marking ertterta (1) 5.2.3 4-bromo-3,3-dimethlyhexane Correct stem i.e hexane/ Korrekte stamnaam Y¥ 4-bromo-3,3-dimetielheksaan ¢ All substituents (bromo and dimethyl) correctly identified./ Alle substituente (bromo en dimetiel) korrek geidentifiseerd v + Correct IUPAC name / Korrekte IUPAC naam. ¥ (3) 5.2.4 CnHanY (1) 5.2.5 Pent-2-ene/ Pent-2-eenv ¥ (2) Page 5 of 7

5.3.1 Compound with the same molecular tormula but different functional groups Organiese molekule met dieselfde molekulére formule, maar_verskillende funksionele groepe VY (2) 5.3.2 Carbonyl/ KarbonielY (1) How 2 Marking criteria / Nasienriglyn H-G-CaG-o vv" . , H 4 4 H ¢ Correct functional group/ Korrekte funksionele groep ¥ v « Whole structure. Hele struktuur ¥ Ete + Correct IUPAC name/ Korrekte IUPAC ¥ (3) [17] QUESTION! VRAAG 6 6.1 Temperature at which the vapour pressure equals atmospheric pressure./V ¥ Die temperatuur waarby die dampdruk van die stof gelyk is aan atmosferiese druk. (2) 6.2 Whatis the relationship between chain length/ surface area/ molecular mass and boiling point of organic compound ? Wat is die verband tussen kettinglengte/ opperviakte/ molekulére massa en kookpunt van organiese verbinding? v ¥ Marking criteria/ Merk riglyne e Must be a question/ Moet ‘n vraag wees (?) e Dependent variable / Afhanklike veranderlike e Independent variable / Onafhanklike veranderlike (2) 6.3. e Chain length / surface area/ molecular mass increases from A-C. Kettinglengte /opperviakte/ molekulére massa neem toe vanaf A-C ¥ e The strength of London forces/ intermolecular forces increases from A-C. Die sterkte van Londen-kragte/ intermolekulére kragte neem toe vanaf A-C ¥ e More energy needed to overcome intermolecular forces. Meer energie word benodig om intermolekulére kragte te oorkom Vv (3) 6.5.2 Compound/ Verbinding C ¥ (1) 6.5.3 eBetween molecules of C/ alcohol has hydrogen bonds with one site of bonding Tussen molekules van C/ alkohol is daar waterstofbindings met een plek van binding ¥ e Between molecules of propanoic acid/ carboxylic acids has hydrogen bonds with two sites of bonding Vv (4) Page 6 of 7

e Intermolecular forces in propanoic acid/carboxylic acids are stronger than in compoundC /alcohol Die Intermolekulére kragte in propaansuur/karboksielsure is sterker as in verbinding C/ alkohol ~ eMore energy is needed to overcome intermolecular forces in carboxylic acids/propanoic acid than alcohol/ compound C. Meer energie is nodig om intermolekulére kragte in karboksielsure/ propaansuur te oorkom as alkohol/ verbinding C W [12] QUESTION/ VRAAG 7 7.1.1. The chemical process/reaction in which longer chain hydrocarbon/alkane molecules are broken down to shorter (more useful) molecules. Die chemiese proses waarin langer kettingkoolwaterstof-molekule afgebreek word in korter, meer bruikbare, molekules Vv“ (2) 7.1.2 CeHiav (1) 7.1.3 2C6H14¥+ 1902 — 14H20 + 12CO2” Balancing / BalanseringY (3) 7.2.1 Addition/Addisie (Hydrohalogination/ Hidrohalogenasie)” (1) 7.2.2 Marking criteria/ Merk riglyne H H H H | | | | Correct functional group/ Korrekte funksionele H—C—C—C—C—H groep ¥ | | | | e Whole structure./ Hele struktuur ¥ H Br H H (2) 7.2.3 Substitution/ Substitusie ( Hydrolysis)” (1) 7.2.4 HBrv (1) 7.2.5 Esterification/ Esterifikasie v (1) 7.2.6 Concentrated Sulphuric acid / Gekonsentreerde Swaelsuur ¥ (1) 7.2.7 Butyl ethanoate / Butieletanoaatv V (2) [15] TOTAL/ TOTAAL: 100 Page 7 of 7