Physical Sciences Grade 12 P1 2025 Memo

education MPUMALANGA PROVINCE REPUBLIC OF SOUTH AFRICA EHLANZENI DISTRICT PHYSICAL SCIENCES GRADE 12 PHYSICS & CHEMISTRY (P1 & P2) MARCH CONTROL TEST (MARKING GUIDELINES) 2025 MARKS: 100 This marking guidelines consists of 10 pages Copyright reserved Please turn over

Physical Sciences 2 March/Ehlanzeni 2025 Grade 12 QUESTION 1 11 Byv (2) 12 Avv (2) 13 Dvv (2) 14 Cvv (2) [08] QUESTION 2 2.1 A body will remain in its state of rest or motion at constant velocity unless a non-zero resultant/net force acts on it Vv ‘n Liggaam sal in sy toestand van rus of beweging teen konstante snelheid beweeg tensy 'n nie-zero resultante/netto krag op dit inwerk. vv (2) 2.2.1 Zero/0 ¥ (1) 2.2.2 EASTY (1) 2.3 Fr/N T v eS fm v v Fo/w (4) 2.4 Copyright reserved Please turn over

Physical Sciences 3 March/Ehlanzeni 2025 Grade 12 Marking criteria / Merkriglyne e Note: If Fy/w does not start from the centre deduct 1 mark. Nota: Indien_Fo/w nie vanaf die middelpunt begin nie, trek 1 punt af. 2.5.1 Upwards as positive Upwards as negative Opwaarts as positief Opwaarts as negatief =mav Foot = ma Fret = ma ¥ T+(Fo) + (F) = ma -T+F)+F=ma TASiG.8 121) 50 T +(5)(9,8) + (21) = 5(0) ¥ T=70NY T=70NY (3) 2.5.2 Fret = ma T +(-Fg) + (-F) =ma 70cos60°+ (-0.25(9.8m — 70sin60°)) Y= 0 ¥ mM = 20,472 kg ¥ (3) 2.6 INCREASESY e The net force acting on the object will increase v TOENEEM ¥ e Die netto krag wat op die voorwerp inwerk sal verhoog.¥ (2) [19] Copyright reserved Please turn over

Physical Sciences 4 March/Ehlanzeni 2025 Grade 12 QUESTION 3 3.1 Motion during which the only force acting on an object is the gravitational force VY Beweging waartydens die enigste krag wat op die voorwerp inwerk, gravitasie krag is. vv (2) 3.2.1 80mv (1) 3.2.2 9,8 m-s? ¥ downwards / afwaarts ¥ (2) 3.3.1 Option 1 Upwards as positive Upwards as negative Opwaarts as positief Opwaarts as negatief Vi = Vi + adt ¥ Vi= Vi + adt ¥ 0= vi+ (-9,8)(0,6)” O0= vi + (9,8)(0,6)¥ vi = 5,88 m-s' upwards / opwaarts ¥ vi = -5,88 m-s? ..Vi = 5,88 m-s upwards / opwaarts v Option 2 Upwards as positive Upwards as negative Opwaarts as positief Opwaarts as negatief 1 13 Ay= viat+ saat v Ay=viAt+aaty 1 2 1 2 O=vi(1,2)+5(-9.8)(1,2)'Y O=wi(1,2)+5(9.8)(1,2)'v vi = 5,88 m-s"' upwards / opwaarts V vi = -5,88 m-s™ ..Vi = 5,88 m-s' upwards/opwaarts Y (3) 3.3.2 Option 1 Option 2 h= 80-55 v h= -55+80v h=25mv h=25mv (2) 3.3.3 Upwards as positive Upwards as negative Opwaarts as positief Opwaarts as negatief V? = ve+2aAy¥ V? = v?+2adyv (0) = v? + 2(-9,8)(60)v (0)? =v? + 2(9,8)(-60)v vi= 34.293 m-s'upwards /opwaarts VY | vi = 34.293 m-supwards/opwaarts ¥ (3) Copyright reserved Please turn over

Physical Sciences 5 3.3.4 Grade 12 March/Ehlanzeni 2025 Upwards as positive Opwaarts as positief Upwards as negative Opwaarts as negatief Ve = v?+2aAy v? = (5,88)? + 2(-9,8)(-80)” vi = 40,032 m-s! downwards Vi=Vvi+ adt ¥ -40,032 = 5,88 + (-9,8)At ¥ At = 4,685 s Vi =Vi+ adt 0 = 34,293 + (-9,8)At ¥ At = 3,499 s wt = 4,685 + 3,499 = 8,184 (s) ¥ vy =v +2aay v? = (-5,88)* + 2(9,8)(80)¥ vi = 40,032 m-s! downwards Vi = Vi + aAt ¥ 40,032 = -5,88 + (9,8)At ¥ At = 4,685 s vi = vit adt = -34,293 + (9,8) At ¥ At = 3,499 s “t= 4,685 + 3,499 = 8,184 (s) ¥ Copyright reserved Please turn over (5)

Physical Sciences 6 March/Ehlanzeni 2025 Grade 12 3.4 Marking criteria / Merkriglyne e Correct shape and ends at time, t. ¥ / Korrekte vorm en eindig by tyd t Vv e Initial velocity ¥ / Aanvanklike snelheid ¥ e Velocity at which it leaves the ground after the first bounce.“ / Snelheid waarteen dit die grond verlaat na die eerst bons ¥ e Time taken to reach maximum height for the first time.~/ Tyd wat dit neem om die maksimum hoogte vir die eerste keer te bereik. ¥ Upwards as positive / Opwaarts as positief Time / Tvd (s) Velocity / Snelheid (m-s"') Upwards as negative Velocity (m-s") Time(s) -5,88 4 -34,29) Copyright reserved Please turn over

Physical Sciences 7 Grade 12 QUESTION 4 41 4.2.1 4.2.2 4.2.3 _1 2 1 2 ) Ex, =5mv* + 5mv 38,5 =" yay + 1 3)2¥ "2 2 m=5kgv¥ March/Ehlanzeni 2025 Is a system on which the net external force is zero VY (2 or 0) Is ‘n sisteem waarvan die netto eksterne kragte zero is VV 2 of 0) Note: if direction is specified in the final answer, deduct 1 mark. Nota: /ndien rigting gespesifiseer word in die finale antwoord, trek 1 punt af East as positive / Oos as positief East as negative / Oos as negatief Ap = m(v;— vi) ¥ “12,5 = 2(vi—4) ¥ vi = - 2,25 m-s! 2. Wi = 2,25 m-st ¥ Ap = m(v;— vi) ¥ 12,5 = 2(vi—(-4)) ¥ vi = 2,25 m-s'¥ Option 1 / Opsie 1 East as positive / Oos as positief East as negative / Oos as negatief (2)(4) + (5)(-3) = (2)(-2,25) + 5v2 W V2 = -0,5 m-s™ “. V2 = 0,5 m-s' west / wes ¥ (2)(-4) + (5)(3) = (2)(2,25) + 5v2 ¥ V2 = 0,5 m-s! west / wes ¥ Option 2 / Opsie 2 East as positive / Oos as positief East as negative / Oos as negatief Ap = m(v;— vi) ¥ 12,5 = 5(vi— (-3)) ¥ vi =- 0,5 m-s" . Vj = 0,5 m-s" west ¥ Ap = m(v;— vi) ¥ 12,5 = 5(v— 3) ¥ vi = 0,5 m-s" west ¥ Copyright reserved Please turn over [22]

Physical Sciences 8 March/Ehlanzeni 2025 Grade 12 4.3 EQUAL TOV The trolleys exert forces of equal magnitude on each other and the time of contact during the collision is the same v (Accept: the trolleys have equal magnitude of change in momentum). GELYK AAN ¥ Die trollies oefen kragte uit op mekaar met gelyke grootte en die kontaktyd gedurende die botsing is dieselfde. v (Aanvaar: die trollies het gelyke grootte van verandering in momentum). (2) [12] QUESTION 5 5.1. A bond or an atom or a group of atoms that determine(s) the physical and chemical properties of a group of organic compounds VY ‘n Binding of ‘n atom of ‘n groep van atome wat die fisiese en chemiese eienskappe van ‘n groep organiese verbindings bepaal Vv (2) 5.2.1 CHsCH2CH(CHs)CHO VY Marking criteria / Merk riglyne e Ending with CHO v / Eindig met CHOV e Whole structure correct and CHs in brackets v / Hele struktuur korrek en CHs in hakies ¥ (2) 5.2.2 3-methyl”butanal ¥ Marking criteria / Merk riglyne e 3-methyl/ 3-metiel ¥ e _butanal / butanaal Vv (2) 5.3.1 SECONDARY (HALO-ALKANE) ¥ The carbon atom with the halogen atom or the functional group is bonded to two other carbon atoms v SEKONDERE (HALO-ALKAAN) ¥ Die koolstofatoom met die halogen atoom of die funksionele groep is gebind aan twee ander koolstofatome v (2) Copyright reserved Please turn over

Physical Sciences 9 March/Ehlanzeni 2025 Grade 12 5.3.2 4-bromo-2,2-dimethylpentane / 4-bromo-2,2-dimetielpentaany V ¥ Marking criteria ¢ Correct stem i.e. pentane. / Correct stam, pentaan V e All substituents (bromo and dimethyl) correctly identified.“ / Alle substituente (bromo en dimetiel) is korrek geidentifiseer. ¥ e IUPAC name completely correct including numbering, sequence, hyphens and commas. ¥/ /UPAC naam volledig korrek, insluitden nommering, volgende, koppelpunte en kommas ¥ 5.4.1 (1) 5.4.2 2C4Hi0 + 1302 > 8CO2 + 10H20 Marking criteriab/ Merkriglyne e Correct reactants (CaHio and Oz) “ / Korrekte reaktante (CaHi0 and Oz) ¥ e Correct products (COz and H2O) ¥ / Korrekte produkte (COz and H2O) ¥ e Correct balancing without multiples and fractions Y / Korrekte balansering sonder veelvoude en breuke ¥ e Marking rule 6.3.10 is applied / Merkreé! 6.3.10 is toegepas 5.5.1 Carboxyl (group) ¥ / Karboksiel (groep) ¥ (1) 5.5.2 H H o wt oy Id Marking criteria / Merkriglyne e Functional group correct v / Funksionele groep is korrek ¥ e Whole structure correct Y / Hele struktuur is korrek. V (2) [18] Copyright reserved Please turn over

Physical Sciences 10 March/Ehlanzeni 2025 Grade 12 QUESTION 6 6.1 Marking criteria / Merkriglyne If any one of the underlined key words/phrases in the correct context (temperature) is omitted, deduct 1 mark. Indien enige van die onderstreepte sleutelwoorde/ frases in die korrekte konteks (temperatuur) uitgelaat word, trek 1 punt af. The temperature at which the vapour pressure of a substance equals atmospheric pressure Vv ¥ Die temperatuur waarby die dampdruk van ‘n stof gelyk is aan atmosferiese druk. VV (2) 6.2.1 London forces / induced dipole forces / dispersion forces London kragte / geinduseerde dipoolkragte / dispersie kragte ¥ (1) 6.2.2 Sv Has a higher boiling point than R v (or R has a lower boiling point then S) Sv Het ‘n hoér kookpunt as R v (of R het ‘n laer Kookpunt as S) Copyright reserved Please turn over

Physical Sciences 11 March/Ehlanzeni 2025 Grade 12 6.3 rking criteria / Merkriglyn ¢ @Q(2-bromobutane) Y / Q (2-bromobutaan) ¥ e State London forces in P ¥ / Noem Londonkragte in PV ¢ State dipole-dipole forces in Q V / Noem dipool-dipool kragte in QV ¢ Compare strengths of IMFs/compare energies required v / Vergelyk sterkte van IMK / vergelyk energie benodig ¥ ¢ Q(2-bromobutane) Y / Q (2-bromobutaan) ¥ ¢ Compound P has London forces” and compound Q has dipole-dipole forcesY ¢ Compound Q has stronger intermolecular forces than P/Compound P has weaker intermolecular forces than Q ¥ OR e More energy is required to overcome the intermolecular forces in compound Ql/Less energy is required to overcome the intermolecular forces in compound Py ¢ @Q(2-bromobutaan) ~ e Verbinding P het Londonkragte “ en verbinding Q het dipool-dipool kragte ~ ¢ Verbinding @ het sterker intermolekulére kragte as P/Verbinding P het swakker intermolekulére kragte as Q ~ OF Meer energie word benodig om die intermolekulére kragte te oorkom in verbinding Q/Minder energie word benodig om die intermolekulére kragte te oorkom in verbinding PY Copyright reserved Please turn over (4) [09]

Physical Sciences 12 March/Ehlanzeni 2025 Grade 12 QUESTION 7 7.1.1. Addition Y (accept: hydrogenation) / Addisie Y (aanvaar: hidrogenasie) (1) 7.1.2 Use Pt/Ni/Pd as a catalyst ¥ / Gebruik Pt/Ni/Pd as katalis ¥ (1) 7.1.3 Marking criteria / Merkriglyne ¢ Correct structural formula of ethene ¥ / Korrekte struktuurformule van eteen ¥ © H—-Hor/of He v/ ¢ Correct structural formula of ethane V / Korrekte struktuurformule van etaan ¥ H oH HH y - | |v” n—tat “4 + H—H/H,; —— ana H H (3) 7.2.1 Substitution’ (Accept: Halogenation) / Vervanging V ( Aanvaar: halogenering) (1) 7.2.2. Halo-alkanes/Alkyl halides Y / Halo-alkane / alkielhaliedes V (1) 7.2.3. Hydrogen chloride Y (do not accept: HC?) / Waterstofchloried Vv | Moenie HCt aanvaar nie) (1) 7.3.1 Hydrohalogenation / Hidrohalogenering ¥ (1) 7.3.2 1-chloroethane / 1-chloroetaan VY (Accept: chloroethane / aanvaar: chloroetaan) (2) 7.4 Elimination / Eliminasie ¥ (1) [12] GRAND TOTAL: 100 Copyright reserved