NATIONAL SENIOR CERTIFICATE/
NASIONALE SENIORSERTIFIKAAT
GRADE/GRAAD 12
JUNE/JUNIE 2024
TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2
MARKING GUIDELINE/NASIENRIGLYN
MARKS/PUNTE: 75
This marking guideline consists of 11 pages./
Hierdie nasienriglyn bestaan uit 11 bladsye.
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Technical Sciences Grade 12 P2 Eastern Cape June 2024 Memo
Grade 12 Technical Sciences Paper 2 memorandum from the Eastern Cape June Exam 2024 (Afrikaans), 11 pages. Read online or download the free PDF.
Technical Sciences · Grade 12 · Eastern Cape June Exam · 2024. Memorandum, 11 pages. Read online or download the PDF.
- Subject
- Technical Sciences
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2024
- Exam period
- Eastern Cape June Exam
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 11
- File size
- 540.1 KB
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Eastern Cape June Exam 2024
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2 TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
QUESTION/VRAAG 1
1.1 C ✓✓ (2)
1.2 B ✓✓ (2)
1.3 D ✓✓ (2)
1.4 A ✓✓ (2)
1.5 D ✓✓ (2)
[10]
QUESTION/VRAAG 2
2.1 An atom or a group of atoms that determine the chemistry of a molecule.
OR
An atom or a group of atoms that determine(s) the physical and chemical
properties of a group of organic compounds.
ʼn Atoom of ʼn groep atome wat die chemie van ʼn molekule bepaal.
OF
ʼn Atoom of ʼn groep atome wat die fisiese en chemiese eienskappe van ʼn
groep organiese verbindings bepaal. (2)
2.2 2.2.1 E (1)
2.2.2 A and/en D (1)
2.2.3 F (1)
2.2.4 A, D and/en H (1)
2.2.5 A and/en D (1)
2.3 2.3.1 pent-1-ene (accept 1-pentene/aanvaar 1-penteen)
pent-1-een (1)
2.3.2 Propanone / Propanoon (1)
2.3.3 Hexanoic Acid / Heksanoësuur (1)
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EC/JUNE/JUNIE 2024) TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 3
2.4 2.4.1
MARKING CRITERIA:
• Correct functional group
• Whole structure correct
NOTE: If a bond or hydrogen is missing ½
NASIENKRITERIA:
• Korrekte funksionele groep
• Hele struktuur korrek
LET WEL: Indien ʼn binding of waterstof ontbreek ½. (2)
2.4.2
(1)
2.4.3 C5H11 (1)
2.4.4 Carboxyl group / Karboksiel-groep (1)
2.4.5
MARKING CRITERIA:
• Correct functional group
• Whole structure correct
NOTE: If a bond or hydrogen is missing ½
NASIENKRITERIA:
• Korrekte funksionele groep
• Hele struktuur korrek
LET WEL: Indien ʼn binding of waterstof ontbreek ½ (2)
[17]
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4 TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
QUESTION/VRAAG 3
3.1 The pressure exerted by a vapour at equilibrium with its liquid phases of a
substances are at equilibrium. /
Die druk uitgeoefen deur ʼn damp in ewewig met sy vloeistof in ʼn geslote
sisteem. (2)
3.2
Dampdruk (kPa)
Molekulêre massa (g.mol-1)
Marking criteria
1 mark Both axes correctly labelled
1 mark All points indicated
1 mark Shape of the graph
Nasienkriteria
1 punt Beide asse korrek benoem
1 punt Alle punte aangedui
1 punt Vorm van die grafiek (3)
3.3 The greater the molecular mass of organic compounds/alkanes, the lower the
vapour pressure. /
Hoe groter die molekulêre massa van organiese verbindings/alkane, hoe laer
is die dampdruk. (1)
3.4 Used as fuels/Word as brandstof gebruik (1)
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EC/JUNE/JUNIE 2024) TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 5
3.5 • Compound Z / pentane has 5 carbon atoms which makes it to have a longer
chain / greater molecular mass than compound Y / butane which has 4
carbon atoms which makes it to have a shorter chain/less molecular mass
than compound Z.
Verbinding Z / pentaan het 5 koolstofatome wat maak dat dit ʼn langer
ketting / groter molekulêre massa as verbinding Y het / butaan wat 4
koolstofatome het, wat maak dat dit ʼn korter ketting / minder molekulêre
massa as verbinding Z het.
• The greater the molecular mass / longer the chain length the stronger the
Intermolecular forces / London forces in compound Z are stronger than
those in compound Y which are weaker.
Hoe groter die molekulêre massa / langer die kettingslengte, hoe sterker is
die intermolekulêre kragte / Londonkragte in verbinding Z is sterker as die
in verbinding Y, wat swakker is.
• More energy will be required to overcome intermolecular forces/London
forces in Compound Z than in compound Y where less energy will be
required to overcome intermolecular forces.
Meer energie sal benodig word om intermolekulêre kragte/Londenkragte in
verbinding Z te oorkom as in verbinding Y waar minder energie nodig sal
wees om intermolekulêre kragte te oorkom.
• (Compound Z / pentane will have lower vapour pressure than compound
Y/butane which will have higher vapour pressure than Compound Z.)
• (Verbinding Z / pentaan sal laer dampdruk hê as verbinding Y / butaan wat
hoër dampdruk as verbinding Z sal hê.)
OR/OF
• Compound Y / Butane has 4 carbon atoms which makes it to have a
shorter chain / lesser molecular mass than compound Z / pentane which
has 5 carbon atoms which makes it to have a longer chain / greater
molecular mass than compound Y.
Verbinding Y / Butaan het 4 koolstofatome wat maak dat dit ʼn korter
ketting / minder molekulêre massa het as verbinding Z / pentaan wat 5
koolstofatome het wat maak dat dit ʼn langer ketting / groter molekulêre
massa as verbinding Y het.
• The lesser the molecular mass / shorter the chain the weaker the
intermolecular forces/London forces in compound Y than in Compound Z
which are stronger.
• Hoe kleiner die molekulêre massa / korter die ketting hoe swakker is die
intermolekulêre kragte/Londen kragte in verbinding Y as in verbinding Z
wat sterker is.
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6 TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
• Less energy will be required to overcome intermolecular forces/London
forces in compound Y than in compound Z where more energy will be
required to overcome intermolecular forces.
Minder energie sal benodig word om intermolekulêre kragte/Londen-
kragte in verbinding Y te oorkom as in verbinding Z waar meer energie
benodig sal word om intermolekulêre kragte te oorkom.
• (Compound Y / butane will have higher vapour pressure than compound
Z / pentane which will have lower vapour pressure than Compound Y.)
(Verbinding Y / butaan sal hoër dampdruk hê as verbinding Z / pentaan
wat laer dampdruk as verbinding Y sal hê.) (3)
3.6 3.6.1 Z (1)
3.6.2 X (1)
3.6.3 X (1)
[13]
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EC/JUNE/JUNIE 2024) TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 7
QUESTION/VRAAG 4
4.1 The temperature at which the vapour pressure is equal to the atmospheric
pressure.
Die temperatuur waarby die dampdruk gelyk aan die atmosferiese druk is. (2)
4.2 Haloalkanes/alkyl halides/Haloalkane/alkielhaliede (1)
4.3 (London forces and) Dipole-dipole intermolecular forces /
(Londenkragte en) Dipool-dipool intermolekulêre kragte (1)
4.4 The boiling point increase with an increase in the number of chlorine atoms
in haloalkanes. /
Die kookpunt verhoog met ʼn toename in die aantal chlooratome in
haloalkane. (1)
4.5 4.5.1 Tetrachloromethane / Tetrachlorometaan (1)
4.5.2 One independent variable
Accept same chain length / same number of carbons
Een onafhanklike veranderlike
Aanvaar dieselfde kettinglengte / dieselfde aantal koolstofstowwe. (1)
4.5.3 The vapour pressure of compound I will be lower than the vapour
pressure of compound L.
OR
The vapour pressure of compound L will be higher than the vapour
pressure of compound I.
Die dampdruk van verbinding I sal laer as die dampdruk van
verbinding L wees.
OF
Die dampdruk van verbinding L sal hoër as die dampdruk van
verbinding I wees. (2)
[9]
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8 TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
QUESTION/VRAAG 5
5.1 Weaker/Swakker (1)
5.2 Propanol (1)
5.3 5.3.1 Addition reaction/hydration
Addisiereaksie/hidrasie (1)
5.3.2 Substitution reaction/halogenation/bromination
Substitusie reaksie/halogenering/brominering (1)
5.3.3 Combustion/Oxidation /
Verbranding/Oksidasie (1)
5.4 5.4.1
MARKING CRITERIA :
• Correct functional group
• Whole structure correct
NOTE: If a bond or hydrogen is missing ½
NASIENKRITERIA:
• Korrekte funksionele groep
• Hele struktuur korrek
LET WEL: Indien ʼn binding of waterstof ontbreek ½ (2)
5.4.2 Inorganic/Anorganies (1)
5.4.3 It does not have carbon as the main element. /
Dit het nie koolstof as die hoofelement nie. (1)
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EC/JUNE/JUNIE 2024) TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 9
5.5 5.5.1
MARKING CRITERIA
• Correct reactants
• Correct products
• Correct balancing
NOTE: Accept molecular structure of H2O
NASIENKRITERIA
• Korrekte reaktante
• Korrekte produkte
• Korrekte balansering
LET WEL: Aanvaar molekulêre struktuur van H2O (3)
5.5.2 Excess water /H2O in concentration H2SO4 / Diluted sulphuric acid /
H2SO4 /
Oortollige water / H2O in gekonsentreerde. H2SO4 / Verdunde
swaelsuur / H2SO4 (1)
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10 TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
5.6 5.6.1
MARKING CRITERIA:
• Correct functional group
• Whole structure correct
NOTE: If a bond or hydrogen is missing ½
NASIENKRITERIA:
• Korrekte funksionele groep
• Hele struktuur korrek
LET WEL: Indien ʼn binding of waterstof ontbreek ½ (2)
5.6.2 Oxygen (gas) / Suurstof (gas) (1)
5.6.3 CO2 (1)
[17]
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EC/JUNE/JUNIE 2024) TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 11
QUESTION/VRAAG 6
6.1 Boron / B (1)
6.2 Three / Drie (3) (1)
6.3 Free holes that are positively charged/positive holes. /
Vrye holtes wat positief gelaai is/positiewe holtes. (1)
6.4 Semiconductor is a material that has electrical conductivity between that of a
conductor and an insulator. /
Halfgeleier is ʼn materiaal wat elektriese geleidingsvermoë het tussen dié van
ʼn geleier en ʼn isolator. (2)
6.5 If the semiconductor is connected across the terminals of a cell, the electrons
in the valence band move from hole to hole.
The absence of an electron creates the effect of a positive charge.
As die halfgeleier oor die terminale van ʼn sel verbind is, beweeg die elektrone
in die valensieband van holte na holte.
Die afwesigheid van ʼn elektron skep die effek van ʼn positiewe lading. (2)
6.6 Improves conductivity of the semiconductor
Verbeter die geleidingsvermoë van die halfgeleier (1)
6.7 P-type / P-tipe (1)
[9]
TOTAL/TOTAAL: 75
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