Technical Mathematics P2 May June 2022 MG Afr Eng_hlayiso.com_.pdf

Downloaded from hlayiso.com SENIOR CERTIFICATE EXAMINATIONS/ NATIONAL SENIOR CERTIFICATE EXAMINATIONS SENIORSERTIFIKAAT-EKSAMEN/ NASIONALE SENIORSERTIFIKAAT-EKSAMEN GRADE/GRAAD: 12 TECHNICAL MATHEMATICS P2/TEGNIESE WISKUNDE V2 2022 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 CODE/ EXPLANATION/VERDUIDELIKING KODE A Accuracy/Akkuraatheid AO Answer only/Slegs antwoord CA Consistent accuracy/Volgehoue akkuraatheid I Identity/Identiteit M Method/Metode NPR No penalty for rounding/Geen penalisering vir afronding nie NPU No penalty for omitting units/Geen penalisering vir eenhede weggelaat nie R Rounding/Afronding RE Reason/Rede S Simplification/Vereenvoudiging SF Substitution in correct formula/Vervanging in korrekte formule ST/RE Statement with reason/Bewering met rede F Correct formula/Korrekte formule PR Penalty for rounding/Penalisering vir afronding These marking guidelines consist of 22 pages. Hierdie nasienriglyne bestaan uit 22 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 2 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne NOTE:  If a candidate answers a question TWICE, only mark the FIRST attempt.  The method of consistent accuracy marking must be applied in all aspects of the marking guidelines where applicable as indicated with the marking code CA  If a candidate strikes off a response to a question and does not attempt the question again, then the struck off question should be marked LET WEL:  Indien 'n kandidaat 'n vraag TWEE keer beantwoord, sien slegs die EERSTE poging na.  Die metode van volgehoue akkuraatheid-nasien moet, waar moontlik, tot alle aspekte van die nasienriglyne toegepas word soos aangedui deur the nasienkode CA.  Indien ʼn kandidaat ʼn antwoord deurhaal en nie poog om die vraag weer te beantwoord dan moet die deurgehaalde antwoord gemerk word. QUESTION/VRAAG 1 yP  yR 1.1.1 mPR  xP  xR 2  (2)  2  6  SF A 1  gradient/gradiënt CA 2 AO Full marks/ (2) 1 CA from/ vanaf Q/V1.1.1 1.1.2 tan  m   2  SF CA ref.   26,57  ref angle/verw. hoek CA    180  26,57   153, 43 value of angle/waarde van hoek CA AO Full marks/Volpunte NPR (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 3 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 1.1.3 QR  ( xQ  xR ) 2  ( yQ  yR ) 2  SF A  CA  ( 0  6 ) 2  (  4  (2) ) 2  Length of QR in surd form/ Lengte in wortelvorm CA  40 OR 2 10 AO Full marks/Volpunte (2)  x P  xQ y P  y Q  1.1.4 E  ;   2 2    2  0 2  (4)  E ;   2 2   x-value/waarde E  1;  1 A  y-value /waarde A OR/OF x x y  y2 xE  1 2 , yE  1 2 2  2 0 2  (4) xE  , yE   x-value/waarde A 2 2 E  1;  1  y-value /waarde A [Penalty of one mark if not simplified/ Penaliseer met een punt indien nie vereenvoudig nie] (2) 2  ( 4)  mPQ A 1.1.5 mPQ   3  2 0 mSR.   3  mSR CA y   3x  c  2   3 (6)  c substitution/vervanging CA c  16  y   3x 16 equation/vergelyking CA OR/OF OR/OF 2  ( 4) mPQ   3  mPQ A  2 0 y  y1  m ( x  x1 ) y  (2)   3 ( x  6 )  mSR CA y   3 x 18  2 substitution/vervanging CA  y   3 x  16 equation/vergelyking CA (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 4 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 1.1.6 y   3x 16   34 16  SF CA  y coordinate/-koördinaat CA 4 OR/OF OR/OF mRS   3 m2 3  subst./verv. (4; m) CA 46 m26  value of m/waarde van m CA m  4 AO Full marks/Volpunte (2)  2  ( 4) 1.2 mQR  60 gradient of/gradiënt van QR 1  A 3 1 product/produk A mPQ  mQR   3    1 3 OR/OF OR/OF PQ  (2  0)  (2  ( 4)) 2  40 2 2 PR 2  (2  6) 2  (2  ( 2)) 2  80  length of/lengte van PQ and PR 2  PQ 2  QR 2 PR A  Pyth. theorem PR A (2) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 5 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 2 2.1.1 G  1;  5 x A y A (2) 2.1.2(a) mOF  5 gradient/gradiënt A (1) 1 gradient/gradiënt 2.1.2(b) mtang  CA 5 y  mx  c OR/OF y  y1  mx  x1  1 1 5   1  c OR/OF y  5   x  (  1)  substitution/vervanging A 5 5 26 c 5 1 26  y  x or/of y = 0,2 x + 5,2 equation/vergelyking CA 5 5 OR/OF OR/OF Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 6 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne r 2  (1) 2  (5) 2  r 2  26 x1  x  y1  y  r 2  x  5 y  26 5 y  x  26  value of r 2 /waarde van r 2 A 1 26 y x or / of y  0, 2 x  5, 2 5 5 substitution/vervanging CA equation/vergelyking CA (3) 2.2 both x-intercepts/ beide x-afsnitte A both y-intercepts beide y-afsnitte A elliptical shape/eliptiese vorm CA (3) [9] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 7 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 3 3.1.1 cot P  Q = cot 71  42 substitution/vervanging A 1 I A = tan 29  1,80 A  1,80 AO Full marks/Volpunte (3) cos Q 3.1.2 sec P substitution/vervanging A cos 42 = sec 71 1 I A = cos 42  cos 71  0,24  0, 24 CA (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 8 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 3.2 3sec   5  0 5 sec β  OR/OF  sec/cos ratio/-verhouding 3 A 5 2  3 2  y 2 y 2  16 substitution/vervanging A y  4 y  4  correct y-value/korrekte y-waarde CA  diagram CA sin 2   cos 2  2 2  4  3        5 5  sin ratio/-verhouding CA 7  cos/-verhouding CA  25  simplification/vereenv. CA (7) 3.3 cos 2 x  tan 29  0 cos 2 x  tan 29  cos 2 x  tan 29 A cos 2 x  0 , 554309051 ref.  56,34  ref. angle/verwys. hoek 2 x  56,34 or 2 x  360  56,34 CA  correct quadrants/korrekte  x 28,17 or x 151,83 kwadrante A  28,17 CA  151,83 CA (5) [18] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 9 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 4 4.1 cot 2 A  sin 2 A  cos 2 A  tan 2 A cos 2 A cos 2 A sin 2 A  I for/ vir A =  sin 2 A + cos 2 A  sin 2 A sin 2 A cos 2 A sin 2 A  cos 2 A + sin 2 A  I for/vir A cos 2 A =1 S CA  I for/vir 1 CA (4) sin 2 (   )  cos(180   )  sec(360   ) 4.2  cos 2  tan(2   )  cot(180   ) sin 2   ( cos  )  sec  sin 2  LHS  A  tan   cot    cos  A 1  sec A sin 2   cos   cos    tan  A  1  cot  A  tan   tan  1  I for/ vir A sin   1 2 cos   1  I for/ vir 1 A tan   (1  sin 2  )  cos 2     simplification/vereenv. CA 1 1  I for/ vir  cos2  A  cos 2   LHS = RHS (9) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 10 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 5 5.1 180  period/periode A (1) 5.2 f: shape/vorm A intercepts/afsnitte  turning point/ draaipunt A g:  shape/vorm A intercepts/afsnitte A end-points/ eindpunte A (6) [7] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 11 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 6 6.1  P R Q  33 , 9  33 , 9  180 M A   P R Q  112 , 2  size of/grootte van  PRQ CA AO Full marks/Volpunte (2) 6.2 RQ 481,1   SF sin 33 , 9 sin 112 , 2 CA  RQ subject/ 481, 1  sin 33 , 9 RQ  -onderwerp A sin 112 , 2  value of/waarde van  RQ 289,81 m RQ CA OR/OF OR/OF PR 2   481,1  2(481,1)PRcos33, 9  SF CA 2 RQ 2 962, 2PRcos33,9 231 457 , 21 231 457 , 21  PR subject/ PR 962, 2cos33,9 -onderwerp A  value of/waarde van RQ 289,81 m PR  RQ RQ CA (3) 6.3 h tan 23 ,5   tan ratio/-verhouding A 289 , 81  h subject/-onderwerp CA h  289 , 81 tan 23 ,5  value of/waarde van h CA  h  126 m PR (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 12 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 6.4 Area of QPR  1 481,1289, 81sin 33 , 9  SF CA 2  area value/ 38 882,53 m 2 oppervlaktewaarde CA from/vannuit 6.1 and 6.2 OR/OF OR/OF 1 Area of QPR   289,81 289,81 sin112  SF CA 2  area value/ 38 881,86 m 2 oppervlaktewaarde CA from/vannuit 6.1 and 6.2 (2) [10] QUESTION/VRAAG 7 7.1 Perpendicular to the chord/ Loodreg op die koord answer/antw. A (1) 7.2 7.2.1 Diameter// middellyn: 16m + 4m = 20m ST A OM = 10 m (1) 7.2.2   line from centre to midpoint of chord/  M A O P M  90   6 A  lyn van middelpunt na mdpt van koord  SF CA OM2  OP2  MP2 (pythagoras) S CA 10 2  6 2  MP2 Value of/Waarde van MP2  100  36 MP CA MP  8 m OR/OF OR/OF Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 13 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 4h 2  4hd  x 2  0 F A  SF A 4(4) 2  4(4)(20)  MN 2  0 MN 2  256  simplification/vereenv. A MN  16 Value of/Waarde van MN A MP  8 m Value of/Waarde van MP A (5) [7] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 14 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 8   ST A 8.1 D1  37 (tangents from the same point/raaklyne van dieselfde  RE A punt) ST A  H1  74 (exterior/buite  in  )  RE A OR/OF OR/OF   C 4  B 2  37 ( tan-chord th./rklyn-koord st )  ST A    RE A D1  B2  37 ( tan-chord th./rklyn-koord st )   C 4  D1  37  ST A  H1  74 (exterior/buite  in  )  RE A (4)   8.2 C 4  F1  37 (tan-chord th./rklyn-koord st)  ST A   C 2  F1  37 (alt/ verw.  , BC||FD) s  RE A  ST CA  RE A (4)   8.3 C 2  D 3  37 (  s in the same segment/in dieselfde segment)  ST CA  F1  37 (proven/bewys in 8.2)  RE A RE A  MD = MF (sides opp./sye teenoor =  ) OR/OF OR/OF   F1  B2 ( s in the same segment/in dieselfde segment)  ST CA    RE A D 3 = B2 (alt/ verw.s , BC||FD)   ST A F1  D3  MD  MF (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 15 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne   ST CA 8.4 M1  74 (exterior/buite  of  )  RE A   H1  M1 (exterior/buite  of  )  ST CA  CHDM is a cyclic quad. (exterior  = op pint  ) CHDM is ‘n koordevierhoek./ (buite  = teenst  ) RE A OR/OF OR/OF  H2  180  74  106 sum of/som van s of   ST CA   RE A M1  74 ext./buite  of   ST CA   H 2  M1  180  CHDM is a cyclic quad. (opp. s are supplementary RE A CHDM is ‘n koordevierhoek. ( teenst  e is supplim.) (4) [15] QUESTION/VRAAG 9 9.1 Divides the other two sides proportionally./Verdeel die  answer/antwoord A ander twee sye eweredig. (1) 9.2  ST  Prop. theorem/ewer.st.; MN QR  PM PN A 9.2.1   RE A PQ PR PM 5   substitution/verv. A 35 7 PM  25 units  length of/lengte van PM CA Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 16 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne OR/OF OR/OF PM  M Q NR PN  Prop. thereom/ewer.st.; MN QR   ST  RE A A PM 5   substitution/verv. A 35  PM 2 PM  25 units length of/lengte van PM A (4)  ST  Prop. thereom/ewer.st.; XY PR  PX RY A 9.2.2   RE A PQ RQ PX 1  35 4 35  length of/lengte van PX PX   8,75 units 4 A  XM  PM  PX M A  25  8,75  Value of/Waarde van  16, 25 units XM CA OR/OF OR/OF PX PX RY 1  Prop. thereom/        ST A XQ 35  PX QY 3  ewer.st.; XY PR   RE A 35 PX   8,75 units  length of/lengte van PX 4 A  XM  PM  PX  25  8,75 M A  16, 25 units  Value of/Waarde van XM CA OR OR QX 3  prop. theorem/   ST A     RE A 35 4  ewer.st.; XY||PR  QX  26, 25  length of/lengte van PX PX  35  26, 25  8, 75 A XM  25  8, 75  16, 25 units M A  Value of/Waarde van XM CA (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 17 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 9.3   9.3.1 D1  B1  44 (tan  chord theorem/rklyn-koord st )  ST A   D3  B1  44 (alt./verw. s; AD BC )  RE A  ST A  RE A (4)   opp. s of cyclic quad./  9.3.2 C2  180  68  112    ST A  teenoorst e van kvhk   RE A OR/OF OR/OF   s on straight line/   ST A C2  180  68  112    reguitlyn   RE A (2) 9.3.3 In Δ ABD and Δ CED   D1  D3 (proven/bewys )  ST A    ext. of cyclic quad/   ST/RE A A  C1  68    buite  van kvhk    B2  E (3rd s of/van Δs )  RE A Δ ABD ||| Δ CED (  ;  ;  ) or/of equiangular/gelykhoekig (3) [19] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 18 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 10 10.1 Radius of the circular path formed by the rotating propeller blades/ Radius van die sirkelpad gevorm deur die roterende skroefblaaie 1000  multiplying by/ 10.1.1 V  30  3600 1000 vermenigvuldig met A 25 3600  or / of 8,33 m / s 3  8, 33 m / s CA (2) 10.1.2 V   r  formula/formule A 25  converting/herlei r to 0,18 m    0,18  A 3  SF CA 1 250  rad / s or / of 46,30 rad / s  angular velocity/ 27 hoeksnelheid CA OR/OF OR/OF V   Dn  converting/herlei D to 25    0,36  n 0,36 m A 3  rotational frequency/ 625 n  rev / s or / of 7,37 rev / s rotasiesnelheid A 27   2 n  SF CA 625  2 or / of 2  7,37   angular velocity/ 27 hoeksnelheid CA 1250  rad / s or / of 46,31 rad / s NPR 27 (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 19 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 10.2  7 7 10.2.1 210   or / of 3,67 rads   rads A 180 6 6 (1) 10.2.2 sr  formula/formule A 7   5     SF CA 6  35  arc length BC/booglengte    18, 33 cm 6 CA (3) r 2 10.2.3 A  formula/formule A 2 (9) 2  54  2  SF A 2 (54 )  (9) 2 4    rad or/of  240 or/of 1,33 rad  CA 3 or/of 4,19 rad OR/OF OR/OF  formula/formule A rs A 2  SF A 9s 54  2 s  12 or / of 37 , 70 cm s  = r 12 37, 70  or / of 9 9  CA 4 (3)   rad or / of 4,19 rad 3 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 20 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 10.2.4 4h 2  4dh  x 2  0  formula/formule A 47   4187   x 2  0 2  SF A x  4(18)(7)  4(7) 2  length of chord/lengte van  x  EF  2 77 17, 55 cm koord CA OR/OF OR/OF Half-chord method/Halfkoord metode: GD  DH  GH  9  7  2 cm  length of/lengte van GD A GE  92  22  77 (Pythagoras Thm.)  length of/lengte van GE A EF  2 GE  2 77 17,55 cm  length of/lengte van EF CA OR/OF OR/OF  F D E  154,32  FE = FD 2  DE 2  2FD  DE cos F D E  cos rule/reël A = (9)  (9)  2(9)(9) cos154,32 2 2  SF A 307 ,9989914 17,55 m  length of/lengte van EF CA (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 21 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 10.2.5 Length of major arc/Lengte van grootboog EF: F A OR/ OF  SF CA  length of arc/lengte van grootboog EF CA Length of rubber belt not in contact with pulleys/ Lengte van rubberband wat nie met katrolle kontak maak nie: M A 140  (4,19  18,33  37, 70) 140  60, 21  length/lengte CA (5) 79, 78cm [21] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 22 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/ VRAAG 11 21 11.1.1 a  3m value of/waarde van a 7 A  o o  formula/formule A A T  a  1 n  o2  o3  ...  on1   2   0,9  2,4  3   1,1  2,8  3,2  2,2  1,8  1,1 m 2  2  SF CA  3 1,65  1,1  2,8  3,2  2,2  1,8  1,1 m 2  41,55 m 2 value of/ waarde van OR/OF AT CA 21 OR/OF a  3m 7 value of/waarde van a A T  a m1  m2  m3  ...  mn  A F A  0,9  1,1 1,1  2,8 2,8  3,2 3,2  2,2        3  2 2 2 2  m2  2,2 1,8 1,8 1,1 1,1  2,4  SF CA      2 2 2   3 1  1,95  3  3  2,7  2  1,45  1,75 m 2  41,55 m 2 value of/waarde van AT CA (4) 180 180 11.1.2 AT  41, 55   A 100 100  74 , 79 m 2 value of area CA OR/OF OR/OF 180 21  37,8m 100 a = 5,4m value of/waarde van a A  0,9  2, 4  AT  5, 4   1,1  2,8  3, 2  2, 2  1,8  1,1   2   74, 79m 2 value of area/waarde van oppervlakte CA (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 23 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 11.2 11.2.1 Exterior surface area  1 2  2 r 2  2 rh  F A 1   2  50   2  50  70  2 2  SF A  value of/waarde  6000 or / of 18849,56 cm 2 van TSA CA OR/OF OR/OF TSA   r   rh 2 F A   (50)   (50)(70) 2 SF A  value of/waarde 18 849,56 cm 2 van TSA CA OR/OF OR/OF A  2 r  2  rh 2  2 (50) 2  2 (50)(70) F A 37 699,12 cm 2 SF A 1  value of/waarde  TSA (37 699,12) 18849,56 van TSA CA 2 NPR (3) 11.2.2 Volume of cone  1 3   r 2h  1     200  150  3 2  SF A  2000000 cm3 or / of 6 283 185,307cm3  value of/waarde van V CA 1 Volume of half cylinder   r 2 h 2   1     50   70  2 2  SF A  87500 cm3 or / of 274889,3572 cm3 2000000 cm 3  value of/waarde number of times   22,86 van V CA 87500 cm 3 He can fully fill the half-cylindrical tank 22 times./  22 CA Hy kan die halfsilindriese tenk 22 keer heeltemal vol maak. PR (5) [14] Copyright reserved/Kopiereg voorbehou

Downloaded from hlayiso.com Technical Mathematics/P2/Tegniese Wiskunde/V2 24 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou