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y th) Basic Education
We REPUBLIC OF SOUTH AFRICA
NATIONAL
SENIOR CERTIFICATE/
NASIONALE
SENIOR SERTIFIKAAT
GRADE/GRAAD 10
eS SS SRS Ras SS Ts Sa EE RREE
« PHYSICAL SCIENCES: PHYSICS (P1) "
" FISIESE WETENSKAPPE: FISIKA (V1) ;
" NOVEMBER 2017 *
i MARKING GUIDELINES/NASIENRIGLYNE "
Se eee eee eee eee eee eee eee eee!
MARKS/PUNTE: 150
| PRIVATE BAG X895, PRETORIA 0001
2b -1- 12
ARKIN!
WIDELINE |
These marking guidelines consist of 13 pages.
Hierdie nasienriglyne bestaan uit 13 bladsye.
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Physical Sciences Grade 10 P1 National November 2017 Memo
Grade 10 Physical Sciences Paper 1 memorandum from the National November 2017, 13 pages. Read online or download the free PDF.
Physical Sciences · Grade 10 · National November · 2017. Memorandum. Read online or download the PDF.
- Subject
- Physical Sciences
- Grade
- Grade 10
- Document type
- Memorandum
- Year
- 2017
- Exam period
- National November
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 13
- File size
- 607.3 KB
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National November 2017
Questions in this paper
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Physical Sciences P1/Fisiese Wetenskappe V1 2DBE/November 2017
CAPS/KABV ~ Grade/Graad 10 — Marking Guidelines/Nasienriglyne
QUESTION/IVRAAG 1
1.1 BYvY (2)
1.2 Cvv (2)
13. Avv (2)
1.4 Dvv (2)
1.5 Cv¥v (2)
16 cvy (2)
1.7 AVY (2)
1.8 Cv¥v (2)
1.9 Dvv (2)
1.10 Dvv (2)
[20]
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Physical Sciences P1/Fisiese Wetenskappe V1 3 DBE/November 2017
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 2
2.1 The total distance travelled per total timev”
Die totale afstand beweeg per totale tyd. Vv
OR/IOF
The distance travelled divided by the total timev ”
Die afstand beweeg gedeel deur die totale tyd. VV (2)
2.2 A /Gemiddele d= distance travelled/afstand
erage speed/Gemiddelde spoed = time taken/tyd
_ (500 + 800)”
~ (30 x 60)¥
=0,72 msi v (4)
2.3. | MARK ALLOCATION: PUNTETOEKENNING:
¥1x correct scale length for 800 m ¥1 x korrekte skaal vir 800 m
v1 x arrow and ¥1 x pylpunt
“1x 800m (3) | ¥ 1.x 800m
~--- 500m Le « 800 m
1 300
@®--------------- meee -- +e ee > (3)
24 POSITIVE MARKING FROM QUESTION 2.2
POSITIEWE NASIEN VANAF VRAAG 2.2
distance travelled/afstand
Average speed/Gemiddelde spoed = time taken/tyd
O72v = (00 + 500 + 1 300) v
time taken/tyd
t=3 194,445 v (4)
[13]
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Physical Sciences P1/Fisiese Wetenskappe V1 4 DBE/November 2017
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 3
3.1 (Average) velocity v/(Gemiddelde) snetheid ¥ (1)
3.2.1 Time v/Tyd v (1)
3.2.2 Position v/Posisie v (Accept: Change in position/Aanvaar verandering in
posisie)) (1)
3.3 4
=
o t a
< el
2 4
3 3
a | -
|
|
Time (s)/Tyd (s)
¥ 1xcorrect y-axis label and unit ¥ 1x y-as benoem en eenheid
| MARK ALLOCATION: PUNTETOEKENNING:
¥ 1xcorrect x-axis label and unit || “ 1x x-as benoem en eenheid
vv 2x points plotted and joined vv 2x punte geplot en verbind
v¥ 1xshape of graph | ¥ 1x vorm van grafiek 6)
- A
34 GradientiHelling = “Y v
Ax
20-5”
= rar Accept: other sets of values/Aanvaar:
7 enige ste! korrekte waardes
=5(ms') ¥ (4)
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Physical Sciences P1/Fisiese Wetenskappe V1 5 DBE/November 2017
CAPS/KABV ~ Grade/Graad 10 — Marking Guidelines/Nasienriglyne
3.5 A
Velocity/ |
snetheid H
(m-s*) i
! 3 Y Correct shape/korrekte vorm
Time (s)/Tyd (s) Vv Axes/Asse
(2)
3.6 The car has zero (acceleration)/ 0 m-s? v “as its velocity is constant.
Die motor het geen versnelling /O_m:s? Vv “nie as gevolg van 'n konstante
snelheid. (2)
[16]
QUESTION/VRAAG 4
4.1 Rate of change of velocity ¥v/Tempo van verandering in snetheid VY (2)
42.1 axe vate Laaty
1
Ax= O(2)¥+ 5 (19)2°¥
Ax = 30 mv (4)
4.2.2 POSITIVE MARKING FROM QUESTION 4.2.1
POSITIEWE NASIEN VANAF VRAAG 4.2.1
| OPTION 1/OPSIE 1 ___| OPTION 2/OPSIE 2 _
vP= vi2+2aAxY V;= Vv (taAt
v= 02v+2(15)(30)” =0V + 15x2v
| |v; = 30 m:s" to the right” regs Vv; = 30 m-s" to the right” /regs
| OPTION 3/OPSIE 3
Vit VF
= v
ax=(S ) at
Ov+ vy
= v
30 ( 7) )2
Vv; = 30 m:s" to the right” /regs
Accept: To the right/East/In the direction of motion
Aanvaar: Regs/Oos/in die bewegingsrigting (4)
4.3 When following a car, a motorist should keep a safe distance such that it takes
more than 2sv to reach the same position “as the car in front.
Motoriste moet ‘n veilige afstand tussen ander voertuie handhaaf, sodat dit
meer as 2 sekondes v sal neem om dieselfde posisiev as die voertuig voor jou
te bereik.
(2)
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Physical Sciences P1/Fisiese Wetenskappe V1 6 DBE/November 2017
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
OR/OF
The car will need 2 s to stop in an emergency and not hit the car in front. vv
Die motor het 2 sekondes nodig om in 'n noodsituasie tot stilstand te kom,
sonder om die voertuig voor jou te stamp.v Vv
4.4 Convert 90 km-h" into m-s“/Skakel 90 km-ht om na m-st
90km_ 90x 10°_
Saee agg = 2emsvY
OPTION 4/OPSIE 1: OPTION 2/OPSIE 2:
AX= vAtt Faaty Ax= ) At’
AX= (25)(2)¥+ Fo) AX= e = ) Y(2)¥
Ax = 50 mv Ax = 50 m¥ 6)
45 POSITIVE MARKING FROM QUESTION 4.4
POSITIEWE NASIEN VANAF VRAAG 4.4
108 km_ 108 x 10°
Th —-3600
Difference in speed/Verskil in spoed: 30 — 25
=5ms'v
Car has to travel 30 m (80 — 50) at 5 ms"'to be at a 2 second distance behind
the truck. Therefore: distance = (v) (t) ¥
30v = (5) (t)
t=6sv
Motor moet 30 m (80 - 50) teen 5 m-s'ry om 2 sekonde-afstand agter trok te
wees. Daarom: afstand = (v) (t) ¥
=30ms'tv
30 v= (5) (t)
t=6sv (5)
[21]
QUESTION/VRAAG 5
5.1 The energy an object has as a result of its motion. “¥”
Die energie wat 'n voorwerp het as gevolg van sy beweging. vv (2)
6.2 Ep = mghv
=72x9,8 x 100”
= 70 560 Jv (3)
5.3 The sum of the gravitational potential energy and kinetic energy” in an isolated (2)
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Physical Sciences P1/Fisiese Wetenskappe V1 7 DBE/November 2017
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
system is constant. v
Die som van die gravitasie-potensiéle_energie en kinetiese_ energie Y in 'n
geisoleerde/gesiote stelsel bly behoue/konstant. ¥
ORIOF
The total mechanical energy of an isolated system remains constant. VW
Die totale meganiese energie in ‘n geisoleerde/gesiote stelsel bly
behoue/konstant. ¥V
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Physical Sciences P1/Fisiese Wetenskappe V1 8 DBE/November 2017
CAPS/KABV — Grade/Graad 10 - Marking Guidelines/Nasienriglyne
5.4 POSITIVE MARKING FROM QUESTION 5.2
POSITIEWE NASIEN VANAF VRAAG 5.2
(Ep + Ex)topioa = (Ep + Ek)bottom/onder ia
mgh + 0 =mgh + %mv2 v
70 560 v¥ =(72)(9,8)(50) v¥+%x72xv? v
v=31,3mst v (8)
5.5
S
[-3
Ww
Ex (J)
Marking criteria for graph
Nasienkriteria vir grafiek
Axes with correct/appropriate labels v
Asse met korrekte/toepaslike byskrifte
| Straight line with decreasing slope vv
Reguitlyn met afnemende helling
Lines not touching (deduct a mark)
Indien lyne nie die asse raak (trek een punt af)
(3)
[15]
QUESTION/VRAAG 6
6.1 Superposition of pulses.“ Algebraic sum of the amplitudes of two pulses that
occupy the same space at the same time. VW”
Accept: Interference of waves” Phenomenon where the crest of one pulse
overlaps with the trough of another, resulting in a pulse of reduced amplitude.
vv
Superposisie van pulse.v Die algabraiese som van die amplitudes van twee
pulse wat in dieselfde ruimte op dieselfde tyd is. vv
Aanvaar: Interferensie van pulsev Die verskynse!l waar die kruin van een puls
kruis met die trog van ‘n ander. Die gevolg is ‘n pulse met ‘n verminderde
amplitude. vv (3)
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Physical Sciences P1/Fisiese Wetenskappe V1 9 DBE/November 2017
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
6.2
Pan (2)
ar (Shape/Vorm) ¥
6.3 Destructive (interference) “/Destruktiewe (interferensie) “ (1)
6.4 Amplitude = (+4) + (-6)
= 2cmv¥v — (Accept/Aanvaar. - 2 cm)
(Marks/Punte: 2 or/of 0) (2)
6.5 REMAINS THE SAMEW/BLY DIESELFDE ¥ (1)
[9]
QUESTION/VRAAG 7
7.1 Sound with frequencies that are higher than what is audible to the human
ear. vv
Klank met frekwensies wat hoér is as wat vir die menslike oor hoorbaar is. VV (2)
7.2 v=fav
1480 v = 130 000A v
“R= 0,011 mv 4)
7.3 distance/afstand
—_—_ v
Speed/Spoed time/tyd
4 480v = distance/afstand
2v
«. distance/afstand = 2 960 mv (4)
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Physical Sciences P1/Fisiese Wetenskappe V1 10 DBE/November 2017
74
7.5
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
e The speed of sound in air is slowerv, as air is less dense “and the particles
are further apart.
Die spoed van klank in lug is stadiger” as in water, omdat lug minder dig “
is/deeltjies is verder van mekaar af.
OR/ OF
e The speed of sound in sea water is faster”, as sea water is denser wand the
particles are closer together.
Die spoed van klank in water is vinniger’_as lug, omdat water meer dig isv/
die deeltjies nader aan mekaar is. (2)
Doiphins send out a sound frequency”/Dolfyne stuur klankgolwe uit V
The sound reflects off the prey and returns to the dolphiny
Die klank weerkaats vanaf die prooi terug na die dolfyn toe.”
¢ The dolphin estimates distance from prey by using time for echo to return
Die dolfyn skat dan die afstand tussen sy prooi en homself deur die tyd te
gebruik wat die eqgo geneem het om te weerkaats. V (3)
[15]
QUESTION/VRAAG 8
8.1.1
8.1.2
8.2.1
8.2.2
8.2.3
Infrared waves” /Infrarooi golwe Vv (1)
Radio waves OR microwaves~/Radiogolwe OF mikrogolwe (1)
Packet of energy found in lightvv
Pakkie energie wat in lig aangetref word. Vv (2)
OPTION 1/OPSIE 1: , OPTION 2/OPSIE 2:
c=hxiy E= he
3 x 108 = Fx 620 x 10°Y A
f= 4,84 x 1014 Hz
E =hfv
= 6,63 x 10°34v x 4,84 x 1014 E=321x10% J) v
= 3,21 x 10°19 Jv
34 8
= ©:63x 10 3x10 y
620 x 10°”
(6)
e Laser light has high frequency and can penetrate soft tissues of humans”
Laserlig het 'n hoér frekwensie“ en kan sagte weefsel indring
e This can lead to damage of eye tissue”
Dit kan_skade aan oogweefsel veroorsaak ” (2)
[12]
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Physical Sciences P1/Fisiese Wetenskappe V1 11 DBE/November 2017
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CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 9
9.1
9.2
9.3.1
9.3.2
9.3.3
Magnetic field: A region in space where another magnet or ferromagnetic
substance can experience a magnetic force. vv
Magneetveld: 'n Gebied in die ruimte waar 'n magneet of ferromagnetiese
materiaal 'n magnetise krag sal ondervind.v ¥
W-
Xe
MARK ALLOCATION: | PUNTETOEKENNING:
¥ 1x lines not touching ¥ 1x lyne raak nie
v 1x curved magnetic lines v 71x vorm van magneetveldlyne
Y 1x field direction away from ¥ 1x veldrigting weg van die N-
north pool |
Magnetic force is inversely proportional “ to the distance (or square of the
distance) between two magnets. OR If the distance between the magnets
increases, the force decreases.
Magnetiese krag is omgekeerd_eweredig Vv aan die afstand tussen twee
magnete. OF Indien die afstand tussen die magnete toeneem, sal die krag
afneem.
O1NY
10 cmv
QUESTION/VRAAG 10
10.1
10.2
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Neutral object: Has equal amount of both protons and electrons”
Charged object: Has either gained or lost electrons. ¥
Neutrale voorwerp: Gelyke hoeveelhede protone en elektrone. ¥
Gelaaide voorwerpe het elektrone gewen of verloor.“
Gain v/Bygevoeg ¥
Please turn over/Blaai om asseblief
(2)
(3)
(1)
(1)
(1)
[8]
(2)
(1)
iM
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Physical Sciences P1/Fisiese Wetenskappe V1 12 DBE/November 2017
CAPS/KABV — Grade/Graad 10 ~ Marking Guidelines/Nasienriglyne
10.3 n= Qy,
e
15
n= 3,5 x 10 ev
1,6x 10°
=21875 ~v (electrons/elektrone ) (3)
10.4.1. When the charged plastic ruler is brought closer to the uncharged pieces of
Paper, the paper is polarised.“ The negative charges on the paper are
repelled by the negative charges on the ruler. “ This leaves the side of the
paper closest to the ruler positive. VW
Die stukkies papier word gepolariseer “ sodra die gelaaide liniaal nader
gebring word. Die negatiewe ladings van die papiertjies word afgestoot ~ deur
die negatief gelaaide |finiaal. Dit laat die kant van die papier wat na die liniaal
toe wys positief V en die papier word aangetrek. (3)
10.4.2 Photocopier” /Fotostaatmasjien ¥
Finger printing/Vingerafdrukke
Spray painting/Spuitverf (Any one/Enige een) (1)
[10]
QUESTION/VRAAG 11
11.1 Work done per unit charge by the source (battery) vv
Die arbeid verrig per eenheidslading deur die bron (battery) Vv (2)
11.2 1 1 1 —
—=—+ —
Rp Ri Ro lee Rix Re
PR, +R,
1 1
“T5' Ts” _1,5x 1,5 v |
, , 1,5+ 1,5
o24 2 “Re = 0,750 v
3.3
= 4 _
~3
3
“Rp = 7" 0,750 v
(2)
11.3.1 15AVv (1)
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Physical Sciences P1/Fisiese Wetenskappe V1 13 DBE/November 2017
11.3.2
11.4
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
Vy= Vy + V2 |
9=V, + 2V, ¥
9=3v, v
Vi =3
Accept:/Aanvaar
V=IRVY
V = 1,5(2) v
V= 3V¥ (3)
e INCREASEY/TOENEEM ¥
If 1,5 Q resistor is added, the resistance of the whole circuit decreases “
Indien 1,5 Q resistor bygevoeg word, neem die totale weerstand van die
stroombaan af. v
e SinceRa t if R decreases, .. Vis constant and | of the circuit increases”
Aangesien R a 5 indien R afneem en V konstant bly, sal | _van_ die
stroombaan toeneem. ¥ (3)
111]
TOTALITOTAAL: 150
NOTE: Some provinces felt that 11.4 was an unfair question because it is not within
the curriculum of grade 10 physical sciences. Therefore, these provinces
can opt to exclude question 11.4 and mark the paper of the total of 147 and
scale the total to 150.
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