Mathematics Grade 10 P2 Gauteng June 2023 Memo (Afrikaans)

Downloaded from hlayiso.com PROVINCIAL EXAMINATION PROVINSIALE EKSAMEN JUNE/JUNIE 2023 GRADE/GRAAD 10 MARKING GUIDELINES NASIENRIGLYNE MATHEMATICS/WISKUNDE (PAPER/VRAESTEL 2) 6 pages/bladsye

Downloaded from hlayiso.com MARKING GUIDELINES/ MATHEMATICS/WISKUNDE NASIENRIGLYNE (PAPER/VRAESTEL 2) GRADE/GRAAD 11 QUESTION/VRAAG 1 1.1 cos 2A – sin( 12 B)   cos 2(38,6) – sin  1  141,4)  2   0,2215  0,9438 = 0,2215 ... – 0,9438 ...  Answer/Antwoord = – 0,72 (3) 1.2 1.2.1 sin 2 = 0,4  2 = 23,178 2 = 23,178 = 23,2  Answer/Antwoord (2) 1.2.2 3sin( 2 – 20) = 0,85 sin( 2 – 20) = 0,28333333  0,28333333 2 – 20 = 16,459 ...   16,459 ...   36,459 ..  2 = 36,459   Answer/Antwoord  = 72,9 (4) 1.3 1.3.1 sin245 – cos 60  Substitution/Vervang = 1 1 2 – 2  Substitution/Vervang =0  Answer/Antwoord (3) 1.3.2 (sin30)tan45 = ( 12 )1  Substitution/Vervang  Substitution/Vervang = 1 2  Answer/Antwoord (3) [15] 2

Downloaded from hlayiso.com MARKING GUIDELINES/ MATHEMATICS/WISKUNDE NASIENRIGLYNE (PAPER/VRAESTEL 2) GRADE/GRAAD 11 QUESTION/VRAAG 2 2.1 2 y  f(x) – shape/vorm y= 1 2 cos  g(x) – shape/vorm 1  (90 ; 0) 90 180 270 360  (180 ; – 12 ) –1  (0 ; 0) y = –sin  (0 ; 12 ) –2 (6) 2.2 11  Max. – Min/Maks – Min 2 =1  Answer/Antwoord (2) 2.3 360  Answer/Antwoord (1) 2.4 1  Answer/Antwoord (1) [10] QUESTION/VRAAG 3 3.1. x x y  y2  Correct sub into formula/ M( 1 2 ; 1 ) 2 2 Korrekte vervang in formule 3  1 9  (5) M( ; ) x=2 2 2 M (2 ; 2) y=2 (3) 3.2 3.2.1 y1  y2  Substitution/Vervang m AC  x2  x1 3 93  M AC   4 3  ( 5) 3 m AC  4 (2) 3.2.2 y2  y1  Substitution/Vervang mBC  x2  x1 53  1  ( 5) 4  mBC  4 3 mBC  3 (2) 3

Downloaded from hlayiso.com MARKING GUIDELINES/ MATHEMATICS/WISKUNDE NASIENRIGLYNE (PAPER/VRAESTEL 2) GRADE/GRAAD 11 3.3 3 4  product of gradients/     1 4 3 produk van gradiënte (1) 3.4 3.4.1 AC = ( 5  3) 2  (3  9) 2  Substitution/Vervang AC = 100  AC AC = 10 cm (2) 3.4.2 CB = ( x2  x1 ) 2  ( y 2  y1 ) 2  Substitution/Vervang CB = (1  ( 5)) 2  ( 5  3) 2  BC CB = 100 = 10 cm (2) 1 3.5 Area of ABC =  base/basis  height/hoogte 2  Substitution/Vervang 1 Area of ABC =  10  10 2  Answer/Antwoord Area of ABC = 50 cm2 (2) [14] 4

Downloaded from hlayiso.com MARKING GUIDELINES/ MATHEMATICS/WISKUNDE NASIENRIGLYNE (PAPER/VRAESTEL 2) GRADE/GRAAD 11 QUESTION/VRAAG 4 4.1 BÂP = 90 diagonals of a rhombus bisect at 90/ S R hoeklyne van ʼn ruit halveer op 90 (2) 4.2 BP2 = BA2 + AP2 Pythagoras S R BP2 = 82 + 62 BP = 10 cm  Answer/Antwoord (3) 1 4.3 AC = BP line drawn from midpoint parallel to 2nd side/ S R 2 lyn getrek vanaf middelpunt parallel met die 2de sy AC = 5 cm (2) 4.4 1 Area of/Oppv van BAP =  AB  AP  sub into area formula/ 2 1 vervang in oppv formule = 86 2 = 24 cm2  Area of/Oppv van BHSP = 4  Area of/Oppv van BAP  Area of a triangle/ Oppv van driehoek = 4  24  method/metode = 96 cm2  Answer/Antwoord (4) [11] TOTAL/TOTAAL: 50 5

Downloaded from hlayiso.com MARKING GUIDELINES/ MATHEMATICS/WISKUNDE NASIENRIGLYNE (PAPER/VRAESTEL 2) GRADE/GRAAD 11 TAXONOMY LEVELS GRADE 10 MATHEMATICS June 2023 ROUTINE COMPLEX PROBLEM KNOWLEDGE TOTAL QUESTION PROCEDURES PROCEDURES SOLVING DESIRED % 20% 35% 30% 15% 100% 1.1 3 1.2.1 2 1.2.2 4 1.3.1 3 1.3.2 3 2.1. 6 2.2 2 2.3 1 2.4 1 3.1 3 3.2 5 3.3 6 4.1 2 4.2 3 4.3 2 4.4 3 4 Total 3 33 14 50 Actual % 18 66 26 100 Desired % 20% 35% 30% 15% 100 6