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NATIONAL
SENIOR CERTIFICATE
NASIONALE
SENIOR SERTIFIKAAT
GRADE/GRAAD 11
MATHEMATICS P2/WISKUNDE V2
NOVEMBER 2017
MARKING GUIDELINES/NASIENRIGLYNE
MARKS/PUNTE: 150
These marking guidelines consist of 19 pages.
Hierdie nasienriglyne bestaan uit 19 bladsye.
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Mathematics Grade 11 P2 National Exemplar November 2017 Memo
Grade 11 Mathematics Paper 2 memorandum from the National Exemplar November Exam 2017 (Afrikaans), 19 pages. Read online or download the free PDF.
Mathematics · Grade 11 · National Exemplar November Exam · 2017 · Afrikaans. Memorandum, 19 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 11
- Language
- Afrikaans
- Document type
- Memorandum
- Year
- 2017
- Exam period
- National Exemplar November Exam
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 19
- File size
- 777.9 KB
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This exam
National Exemplar November Exam 2017
Questions in this paper
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Mathematics P2/Wiskunde V2 2 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
NOTE:
• If a candidate answered a question TWICE, mark only the FIRST attempt.
• If a candidate crossed out an answer and did not redo it, mark the crossed-out answer.
• Consistent accuracy applies to ALL aspects of the marking guidelines.
• Assuming values/answers in order to solve a problem is unacceptable.
LET WEL:
• As 'n kandidaat 'n vraag TWEE keer beantwoord het, sien slegs die EERSTE poging na.
• As 'n kandidaat 'n antwoord deurgehaal en nie oorgedoen het nie, sien die deurgehaalde
antwoord na.
• Volgehoue akkuraatheid is op ALLE aspekte van die nasienriglyne van toepassing.
• Dit is onaanvaarbaar om waardes/antwoorde te veronderstel om 'n probleem op te los.
QUESTION/VRAAG 1
10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66
1.1.1 min = 12 min + max
Q1 = 17 median, Q1 and/en Q3
median / mediaan = 30 (2)
Q3 = 38
max = 65
1.1.2 IQR = Q3 − Q1 answer/antw
= 38 − 17 (1)
= 21
1.1.3 Skewed to the right OR positively skewed answer/antw
Skeef na regs OF positief skeef (1)
5 8 10 17 20 29 32 48 50 50 63 y 107
1.2.1 439 + y
Mean/Gemiddeld =
13
439 + y 439 + y
41 = 41 =
13 13
439 + y = 533
answer/antw
y = 94 (2)
1.2.2 σ = 30,94 answer/antw
(1)
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Mathematics P2/Wiskunde V2 3 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
1.2.3 41 × 13 = 533
6 × 18 = 108 108
533 + 108 = 641
answer/antw
533 + 108 641 (3)
= = 33,74
19 19 [10]
QUESTION/VRAAG 2
2.1 CUMULATIVE
AGE OF PERSON FREQUENCY/
SURVEYED/OUDERDOM FREQUENCY/FREKWENSIE KUMULATIEWE
VAN PERSOON IN OPNAME FREKWENSIE
20 < x ≤ 30 7 7
30 < x ≤ 40 20 27
40 < x ≤ 50 25 52
50 < x ≤ 60 12 64
60 < x ≤ 70 8 72 20, 12
70 < x ≤ 80 4 76 8, 4
52
80 < x ≤ 90 4 80 76
(4)
2.2 n = 80 answ/antw
(1)
2.3 40 < x ≤ 50 answ/antw
(1)
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Mathematics P2/Wiskunde V2 4 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
2.4
Ogive/Ogief
90 Grounding (20; 0)
/Geanker by (20; 0)
80 upper limits/
boonste limiete
70
shape
(smooth curve)/
60 vorm
Cumulative Frequency/Kumulatiewe Frekwensie
(gladde kurwe)
(3)
50
40
30
20
10
0
0 10 20 30 40 50 60 70 80 90 100
Age of person surveyed/Ouderdom van persoon in opname
2.5 80 – 58 = 22 Accept/aanvaar: 56 – 59 calls/oproepe 58
22 calls/oproepe
× 100 = 27,5% 22
80 27,5%
(3)
[12]
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Mathematics P2/Wiskunde V2 5 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
QUESTION/VRAAG 3
y
C
B
T
15
x
O
A(−2 ; −5) D
3.1 1 Standard
BD y = − x+9 form/vorm
2
1
∴ m BD = −
2
answ/antw
∴ m AC = 2 (2)
3.2 y − y1 = m( x − x1 )
y − (−5) = 2( x − (−2)) subst (–2 ; –5)
answ/antw
y = 2x −1 (2)
3.3 1 1
2x − 1 = − x + 9 2x −1 = − x + 9
2 2
5
x = 10
2
x=4
x=4
y = 2(4) − 1
y=7
y=7
(3)
T (4 ; 7 )
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Mathematics P2/Wiskunde V2 6 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
3.4.1 −2+ x
4=
2
8 = −2 + x
x = 10
x = 10
−5+ y
7=
2
14 = −5 + y y = 19
y = 19 (2)
C (10 ; 19 )
3.4.2 AT = (4 − (− 2))2 + (7 − (− 5))2 subst. in
distance/afstand
= 180 form.
answer/antw
=6 5
BT 2 + AT 2 = AB 2 (Pythagoras )
subst. in pyth
BT = 15 − 180 2
( )
2
answer/antw
=3 5
(4)
3.4.3 BC is the diameter/ middellyn [subt. right / ondersp. reg ∠ ] or/of S
[conv.∠ in semi - circle/ omgk. ∠ in halfsirkel ]
s s
15 answ/antw
Radius = = 7,5 units/ eenh.
2 (2)
[15]
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Mathematics P2/Wiskunde V2 7 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
QUESTION/VRAAG 4
B (4 ; 12)
E O C
A (–5 ; –3)
4.1 12 − (−3) 5 subst. in
mAB = = gradient form.
4 − (−5) 3
answ/antw
OR/OF
(2)
− 3 − 12 5
mAB = =
−5−4 3
4.2 5 equation/verg.
y − 12 = (x − 4)
3
5
0 − 12 = ( x − 4 ) y=0
3
16
x=−
5
16 answ/antw
E − ; 0
5 (3)
OR/OF
0 − 12 5 0+3 5
= = equating/verg.
x−4 3 x+5 3 y=0
− 36 = 5 x − 20 9 = 5 x + 25
− 16 = 5 x − 16 = 5 x
− 16 − 16
x= x= answ/antw
5 5 (3)
16
E − ; 0
5
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Mathematics P2/Wiskunde V2 8 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
4.3 tan α = m AB 5
tan α =
5 3
tan α =
3
α = 59ο
α = 59 ο
(2)
4.4 76 ° + 59° =135° [ext ∠ of Δ]
135°
BĈX =135°
tan 135° = mBC tan 135ο = mBC
mBC = −1 = m// answer/antw
subst (–3 ; –5)
y − (− 3) = −1(x − (− 5)) answer/antw
y = −x − 8 (5)
[12]
QUESTION/VRAAG 5
5.1 sin(90o − x). cos(180o + x) + tan x. cosx. sin ( x −180o ) cos x
− sin x
sin x
= cos x. (−cos x) + . cos x . (− sin x) − cos x
cos x
sin x
= − cos 2 x − sin 2 x cos x
= − (cos 2 x + sin 2 x) common
= −1 factor/gemene fakt.
identity/identiteit
(6)
5.2 o
sin 315°. tan 210 .sin190°
LHS = − sin45°
cos 100°.sin 120 o
tan30°
=
(− sin45°). (tan30o ).(− sin10°) − sin10°
(− sin 10°).(sin 60o ) – sin10°
1 1 sin 60°
− . subst. of special
= 2 3 angles/inverv. van
3 sp hoeke
2
2 (6)
=−
3
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Mathematics P2/Wiskunde V2 9 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
y
R
β α
O T x
P
5.3.1 x2 + y2 = r 2 [Pythagoras]
2 2 2 subst in pyth
( x) + (3) = 5
x 2 = 16 x=4
x=4
R (4 ; 3)
3 answer/antw
tan α =
4 (3)
5.3.2 sin β
= sin (180 ο + α) β = 180° + α
− sinα
= −sinα
−3 answer/antw
=
5 (3)
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Mathematics P2/Wiskunde V2 10 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
5.3.3 y −3 y
=
10 5 10
y = −6 −3
∴ x = −8 5
y = −6
P(− 8 ; − 6 )
x = −8
(4)
5.4. 2
sin θ − tan θ . cos θ
LHS =
cos θ − (1 − sin 2θ)
sin θ
sinθ
sin θ − . cos 2θ cos θ
= cosθ
cos 2 θ
cos θ − cos 2θ
common fact/
sin θ(1 − cosθ ) gemene fakt.
=
cos θ(1 − cosθ ) common fact/
= tan θ gemene fakt.
= RHS (4)
OR/OF
sin θ − tan θ . cos 2 θ
LHS =
(
cos θ − 1 + 1 − cos 2 θ )
sin θ
cos θ
sinθ
sin θ − . cos 2 θ 1 − cos 2 θ
cos θ common fact/
=
cos θ − cos 2 θ gemene fakt.
sin θ(1 − cosθ ) common fact/
= gemene fakt.
cos θ(1 − cosθ )
= tan θ
(4)
= RHS [26]
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Mathematics P2/Wiskunde V2 11 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
QUESTION/VRAAG 6
6.1 sin( x − 30 ο ) = cos 2 x sin(90ο − 2 x)
sin( x − 30 ο ) = sin(90 ο − 2 x)
x − 30 = 90 − 2 x + 360 k
ο ο ο
x − 30 ο = 90 ο − 2 x + 360 ο k or x − 30 ο =180 ο − ( 90 ο − 2 x) + 360k
ο ο ο ο
x = 40ο + 120ο k
3 x =120 + 360 k − x =120 + 360 k
ο ο
x = 40 +120 k x = − 120 ο + 360 ο k , k ∈ Z x − 30ο =180ο − ( 90ο − 2 x) + 360k
x = − 120ο + 360ο k
(5)
OR/OF ( (
cos 90 ο − x − 30 ο ))
cos(90 ο − (x − 30 ο )) = cos 2 x
( )
cos 120 ο − x = cos 2 x
120 ο − x = 2 x + 360 ο k
ο ο ο ο
120 − x = 2 x + 360 k or 120 − x = −2 x + 360 k
x = 40ο + 120ο k
− 3 x = −120 ο + 360 ο k x = −120° + 360 ο k
x = 40 ο + 120 ο k , k ∈ Z 120 ο − x = −2 x + 360 ο k
NOTE/LET WEL: x = 240 ο + 360 ο k
x = −120° + k .360° is equivalent to/ekwivalent aan x = 240° + k .360° (5)
6.2.1 180° answer/antw (1)
6.2.2 −1 ≤ y ≤ 1 values/waardes
notation/notasie
OR/OF (2)
values/waardes
y ∈ [−1; 1] notation/notasie
(2)
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Mathematics P2/Wiskunde V2 12 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
6.2.3 y f x-
intercept
1 f at/afsnit by 30o
g shape of/
vorm van f
(180° ; 0,5)
g x-
x intercepts
−90° −60° −30° 0 30° 60° 90° 120° 150° 180° at/afsnitte by
45o and/
en 135o
(−90°;−0,7) shape
−1 of/vorm van g
TP at/DP by
(90 ο ;−1 )
(5)
6.2.4 x = − 80 ο ; x = 40 ο ; x = 160 ο one
mark per
answer/een
punt per
antw.(3)
[16]
QUESTION/VRAAG 7
Q
θ
2x
3
P
x
R
7.1 x 2 = (2 x ) + (3) − 2(2 x )(3)cos θ cos rule
2 2
subst
12 x cos θ = 3x 2 + 9
3x 2 + 9
cos θ = simplify/vereenv
12 x
(3)
3( x 2 + 3)
cos θ =
12 x
2
x +3
cos θ =
4x
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Mathematics P2/Wiskunde V2 13 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
7.2.1
cosθ =
(2,4)2 + 3 subst
cos θ = 0,9125
4(2,4)
answer/antw.
cosθ = 0,9125 (3)
ο
θ = 24,15
7.2.2 1
Area of/van ∆PQR = × PQ × QR × sin Qˆ
2
1
= × 4,8 × 3 × sin 24,15 subst
2
= 2,95 units/eenh 2 answer/antw.
(2)
7.3 For/vir x > 0 , cosθ > 0
0° < θ < 90°
x2 +3 x2 +3
0< <1 0 < <1
4x 4x
x 2 + 3x < 4 x
x2 − 4x + 3 < 0
(x −1)(x − 3) < 0
1< x< 3 1 < x < 3
(4)
[12]
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Mathematics P2/Wiskunde V2 14 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
QUESTION 8/VRAAG 8
8.1 1
V = Ah Area of square/van
3 = (16 × 16 )
1 vierk.
640 = × (16 × 16 ) × h
3 Subst in volume
h = 7,5cm form
(2)
8.2 slant height / skuinshoogte = 7 ,5 2 + 8 2 = 10 ,9658.... Subst in pyth
answer/antw
Subst in SA/
1 BO form.
Total surface / Totale buite area = (side × side ) + 4 b× ⊥ h answer/antw
2
1
= (16 × 16 ) + 4 × 16 × 10,9658.... (4)
2 [6]
= 606,91cm 2
QUESTION 9/VRAAG 9
O
1 2
R S
T
9.1 Construction/Konstr: Draw/trek radii OR and/en OS Constr/Konstr
In ΔOTR and/ en ΔOTS
OR = OS (radii ) S (OT is
common/gemeen)
OT = OT (common side/ gemene sy ) S/R
(
Tˆ = Tˆ = 90 ο ∠ s on straight line/ op 'n reguit lyn
1 2 )
(
∆OTR ≡ ∆OTS 90 ο HS ) R
S
∴ RT = TS (≡ ∆ ) s
(5)
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Mathematics P2/Wiskunde V2 15 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
A 4 F 4 B
x
O
D
9.2 line from centre ⊥ to chord/ S/R
AF = FB = 4cm 8− x
lyn van mdpt ⊥ aan koord
OD = OB = 8 − x (radii )
2 2 2
(8 − x) 2 = x 2 + 4 2
OB = OF + FB ( Pythagoras )
( 8 − x )2 = x 2 + 4 2
64 −16 x + x 2 = x 2 + 4 2 x =3
48 = 16 x
x =3
length of/ lengte van radius = 8 − x Answer/antw
(5)
= 8−5 [10]
= 3 units / eenh
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Mathematics P2/Wiskunde V2 16 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
QUESTION/VRAAG 10
V
Q
2
1
2
1
M
S
1
2
P
R
10.1 Q̂ 2 = Rˆ 2 [ tangents from common point/ rk ln e van selfde punt ] S R
S
Q̂ 2 + Rˆ 2 + 70 ο = 180 ο [sum ∠ Δ] Rˆ 2 = 55ο
2 Rˆ 2 = 110 ο
(4)
Rˆ = 55 ο
2
10.2 Qˆ 2 + Qˆ 1 = 90 ο [tan/rkl ⊥ rad] R
Qˆ1 = 35ο
Qˆ = 35 ο
1
(2)
OR/OF
R
Rˆ1 + Rˆ 2 = 90 ο [tan/rkl ⊥ rad] Qˆ1 = 35ο
Rˆ = 35 ο
1 (2)
Qˆ 1 = Rˆ1 == 35 ο [OR = OQ]
10.3 Ô1 + R̂ 1 + Q̂1 = 180 ο [sum ∠ Δ]
Ô1 = 110 ο
Ô1 = 180 ο − 70 ο = 110 ο
Ô 2 = 110ο R
equal chords subtend = ∠ at the centre/
Ô 2 = 110 ο
(3)
gelyke koorde onrsp. = ∠ by mdpt [9]
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Mathematics P2/Wiskunde V2 17 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
QUESTION/VRAAG 11
B
2
O
1
1 2
D
A
E
11.1 Bˆ1 = Bˆ 2 = x [BD bisect/halveer ∠ AB̂C ] S
ABˆ C = 2 x
Oˆ = 2 x [∠ at centre = 2 times ∠ at circumference/]
1 S R
[ midpts∠ = 2 × omtreks∠] R
∴ BC OD [corresponding ∠ are equal/ooreenk. ∠ is gelyk ] (4)
OR/OF
Bˆ1 = Bˆ 2 = x [BD bisect/halveer ∠ AB̂C ] S
Dˆ = x [angle opp = sides/∠e to gelyke sye] S R
1
R
Dˆ 1 = Bˆ 2 = x (4)
∴ BC OD [alternate angles are equal/verw ∠e gelyk]
OR/OF S
Bˆ1 = Bˆ 2 = x [BD bisect/halveer ∠ AB̂C ]
ABˆ C = 2 x S R
Oˆ = 2 x [angle at centre = 2 times angle at circumference ]
1
[ midpts∠ = 2 × omtreks∠]
ˆ
O2 = 180 − 2 x [∠ on a straight line/∠ op reguit lyn ]
ο
R
Oˆ 2 + ABˆ C = 180 ο − 2 x + 2 x = 180 ο (4)
∴ BC OD [ co-int angles are suppl/ko-binne ∠ is suppl]
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Mathematics P2/Wiskunde V2 18 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
11.2 ODˆ C = 90 ο [tan/rkl ⊥ rad ] S/R
S R
Cˆ = 90 ο [co − int / ko-binne ∠' s OD BC] (3)
OR/OF S/R
S R
Dˆ 1 = x (3)
S/R
Dˆ = 90 ο − x [tan/rkl ⊥ rad ]
2 S R
( )
Cˆ = 180 ο − 90 ο − x − x [int ∠' s of / van ∆ ] (3)
= 90 ο
[7]
OR/OF
EDˆ C = 90 ο [tan/rkl ⊥ rad ]
Cˆ = 90 ο [corresp. / ooreenk . ∠' s OD BC]
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Mathematics P2/Wiskunde V2 19 DBE/November 2017
CAPS/KABV – Grade/Graad 11 – Marking guidelines/Nasienriglyne
QUESTION/VRAAG 12
A Q
1 2
x
B
F
1
2
6 5 T
4
7 P3
8 1 2
2
2 y
1 3 1
E D R C
12.1 P̂1 = x [tan − ch th/ rkl-kdst ] SR
SR
Ĉ 2 = x [alt / verw. ∠ s AD BC ] SR
Ê = x [∠ in the same segment/dieselfde segment ]
s S/R
(7)
P̂5 = x [vert opp/ reg oorst ]
12.2 DCˆ B = x + y
S R
E Dˆ A = Dˆ = x + y [corresp / ooreenk. ∠ s = , AD
1 BC ] S R
[
∴ EP̂A = x + y ∠ s in the same segment/dieselfde segment ] (4)
12.3 Pˆ2 = y [ tan from a commom point/ rklyne v dieselfde pt ] S/R
DPˆ T = Pˆ + Pˆ + Pˆ
1 2 3
= x + y + ( x + y) Ĉ = x + y
= 2x + 2 y
Subst
Ĉ = x + y
Answ/antw
DPˆ T + Ĉ =180 ο [opp ∠ s of a cyclic quad/ teenoorst. ∠ s van kvhk]
(4)
2 x + 2 y + x + y =180 ο
[15]
3 x + 3 y =180 ο
∴ x + y = 60 ο
TOTAL/TOTAAL: 150
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