Physical Sciences Grade 10 KZN March Test 2026 Paper & Memo

Downloaded from Stanmorephysics.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 10 | MARKS: 100 DURATION: 2 hours This question paper consists of 11 pages and a data sheet.

Phyiewsteaded from Stanmorepleysics.com March 2026 2 INSTRUCTIONS AND INFORMATION 1. 10. 11. This question paper consists of SEVEN questions. Answer ALL the questions in the ANSWER BOOK. Start EACH question on a NEW page in the ANSWER BOOK. Number the answers correctly according to the numbering system used in this question paper. Leave ONE line between two sub-questions, for example between QUESTION 2.1 and QUESTION 2.2. You may use a non-programmable calculator. You may use appropriate mathematical instruments. You are advised to use the attached;DATA SHEET. Show ALL formulae and : bstitu BN Round off your final numet in ALL calculations. Ss to a minimum of TWO decimal places. Give brief motivations, di sions et cetera where required. Write neatly and legibly. Copyright reserved

Phyiewsteaded from Stanmorepleysics.com March 2026 3 QUESTION 1: MULTIPLE-CHOICE QUESTIONS Various options are provided as possible answers to the following questions. Choose the correct answer and write only the letter (A to D) next to the question number(1.1 to 1.7) in your ANSWER BOOK, for example 1.8 D 1 1.2 1.3 14 13 1.6 The term given to distance between two successive points in phase A amplitude B_ period C_ wavelength D_ frequency Sound waves cannot travel through a vacuum because sound waves : A have low frequencies Bare transverse waves C require a medium to transfemenergy D have small amplitudes | Ultrasound can be described bysfrequencies that are A Higher than 100kHz a) ‘ B_ Higher than 20kHz but lower than 100kHz C Lower than 20kHz- D_ Higher than 100kHz but lower than 1000kHz When the frequency of vibration of a wave with a period T is doubled, then its period is A T B 2T C 4T D O.5T Which ONE of the following statements is CORRECT A Loudness of sound depends on the frequency of the sound B Pitch of sound depends on the amplitude of the sound C Speed. of sound waves is always constant D All electromagnetic waves travel faster than sound waves A radio station transmits radio signals with a frequency range from 3MHz to 6MHz.The maximum wavelength of the radio signal transmitted is : 100m 200m 0,02m 0,01m 0NW>D Copyright reserved (2) (2) (2) (2) (2) (2)

Phpiewslamded from Stanmorepleysics.com March 2026 4 1.7 & Two identical spheres, P and Q, placed on insulated stands consist of charges of +3nC and +9nC respectively as shown below +9nC In which di e when the spheres are brought into contact? A FromQtoP B FromPtoQ C No movement, ele a D No movement as positively charged (2) [14] Copyright reserved

Phyiewstended from Stanmorepleysics.com March 2026 5 QUESTION 2 (Start on a new page.) Two pulses, A and B travel along a string in opposite directions and approach each other at the same speed as shown in the diagram below. Pulse A has an amplitude of 5cm when itis at-position P. Pulse B has an UNKNOWN amplitude when it is at position Q. Pulses A and B meet at position R resulting in a pulse that has an amplitude of +3cm from the rest position. Points P and Q are the same distance from point R. NOTE: Diagrams are NOT drawn to scale A > +-_—_ B 2.1 Define the term amplitude (2) 22 What type of interference occurs at point R? Explain your answer. (3) 23 Calculate the amplitude of pulse B at point Q (2) 2.4 After the two pulses pass each other: 2.4.1 In which direction will pulse B move ?Write to the RIGHT or to the LEFT (1) 2.4.2 How will the amplitude of pulse A change after the pulses meet compared to before they met? Write INCREASES,DECREASES OR REMAINS THE SAME (1) [9] Copyright reserved

Phyiewsteaded from Stanmorepleyisics.com 6 QUESTION 3 (Start on a new page.) The diagram below represents a transverse wave. The speed of the transverse wave i 3.1 3.2 3.3 3.4 12cm March 2026 Define the term freq Write down the : 312.1 letters of two frre ‘ 3.2.2 name given to point D Determine the following : 3:3:1 amplitude 3.3.2 wavelength Calculate the: 3.4.1 frequency of the wave 3.4.2 time taken for one wave to pass a fixed point Copyright reserved (2) (1) (1) (2) (2) (3) (2) [13]

Phyiewsteaded from Stanmorepleysics.com March 2026 7 QUESTION 4 (Start on a new page.) Consider the wave below. The distance between points X and Y is 1m. It takes 0.5s for a particle of the medium to complete one full vibration from the rest position and back again. 41 4.2 4.3 44 45 4.6 4.7 noe Wa MAMA ANETTA TT Define the term /ongitudinal wave What term is given to the underlined statement above? Write down the name of the label 4.3.1 P 4.3.2 Q Determine the wavelength of the wave above. Calculate the speed of the wave The wave is propagated through a slinky spring .If length of the spring is 20m, calculate the time it takes for the wave to move through the spring The medium is changed so that the wave now travels faster, but the source of the wave remains the same 4.7.1 State whether the frequency CHANGES or REMAINS THE SAME 4.7.2 Give a reason to the answer in 4.7.1 4.7.3 What happens to wavelength? Choose INCREASES, DECREASES or REMAINS THE SAME. Explain the answer. Copyright reserved (2) (1) (1) (1) (2) (4) (3) (1) (2) (3) [20]

Phyiewsleaded from Stanmorepleysics.com March 2026 8 QUESTION 5 (Start on a new page.) Mary stands at point P, between two high buildings A and B, and hits a drum once. Two sound waves travel from the drum in opposite directions toward the buildings. The distance between Mary and building B is X metres, and the buildings are 265 m apart. ro, A sound detector at building B records the sound 0,22 s after it is detected at building A. Mary and both buildings are onthe same plane and in a straight line.. oad a P _ a Ik 265m 2 5.1 Define the termecho i, (1) 5.2 How would the time taken to detect the sound at each building change if the same activity was repeated on a hotter day? Choose from INCREASES,DEGREASES or REMAINS THE SAME (1) 53 Give a reason for the answer in 5.2 (2) 5.4 Calculate the distance X, between Mary and building B. (5) The speed of sound in air is 340m.s*. Ultrasound is used to detect depths of seas. In one occasion, a boat emitted a sound and a return signal was received in the boat 10 seconds later. Take the speed of sound waves in water to be 1500m.s*. 5:5 Calculate the distance of the midway point between the boat and the sea floor. (3) 5.6 Ultrasound is also often used in the medical field to examine the insides of the human body. Explain why this method is often preferred to other types of body scanning (2) [14] Copyright reserved

Phyiewsteaded from Stanmorepleysics.com March 2026 9 QUESTION 6 (Start on a new page.) The diagram below shows the electromagnetic spectrum in order of increasing wavelength. Visible light nan gamma_ | X-rays P Q microwaves | Radio rays waves ‘10:4 10° 108 = 108 | 104-4 nae sele 4 10? Wavelength (m) 6.1 Define the term photon 6.2 Name the electromagnetic radiation represented by the letter: 6.2.1 P 6.2.2 Q 6.3. Which radiation has the | { penetrating ability? Write GAMMA RAYS or RADIO WAVES. - Explain your answer. Electromagnetic radiation has many applications in everyday life. 6.4 Wireless headphones receive electromagnetic waves with a frequency of 2.42 GHz from an audio device. 6.4.1 Show, by a calculation that the wavelength of these waves is 0.12 m. 6.4.2 Identify the part of the electromagnetic spectrum that these waves belong to. Copyright reserved (2) (1) (1) (2) (2) (1)

Phyiewsteaded from Stanmorepleysics.com March 2026 10 X-rays are used in dental procedures to examine the condition of a patient's teeth. During this procedure the patient's head is exposed to X-rays. 6.5 Calculate the energy of a photon of the radiation absorbed by the patient's head if X-rays radiation of wavelength 0.3nm is used 6.6 How will the energy you calculated in 6.5 change if the wavelength of the radiation was decreased. Choose from INCREASES,DECREASES OR REMAINS THE SAME QUESTION 7 (Start on a new page.) (4) (2) [15] Two identical metal spheres, A and B, are on insulated surfaces. Sphere A, carries a charge of +3 x10°° C while sphere B has an’excess of 1.25x10" electrons. +3 x10°°C \ (s) 1.25x10'excess electrons Tell State the principle of conservation of charge . 72 Give a reason why we place charged spheres on insulated stands 7.3 Calculate the charge of sphere B The two spheres are brought into contact and then separated again. When the spheres get into contact, sphere A gains electrons. 74 Give a reason why sphere A gains electrons and not sphere B. 7.5 Sketch a graph of net charge on sphere A (Y-axis) versus number of electrons transferred to charge A(X-axis) Copyright reserved (2) (1) (3) (1) (2)

Phpiewslanded from Stanmoreplaysics.com March 2026 11 7.6 Calculate the : 7.6.1 new charge on each sphere after the spheres have separated again (3) 7.6.2 number of electrons transferred during contact (3) [15] TOTAL: 100 Copyright reserved

PhAewseaded from Stanmoce~bysics.com March 2026 12 DATA FOR PHYSICAL SCIENCES GRADE 10 PAPER 1 (PHYSICS) TABLE 1: PHYSICAL CONSTANTS NAME SYMBOL VALUE Acceleration due to gravity g 9,8 m.s2 Speed of light in a vacuum c 3,0 x 108 m-s* Planck's-constant h 6,63 x 10°%4 J-s Charge on electron de - 1,6 x 107°C Electron mass Me 9,11 x 10° kg TABLE 2: FORMULAE WAVES, SOUND AND LIGHT v=faA or c=fa E =hf distance time speed = ELECTROSTATICS Q=n Xe Q Copyright reserved

KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE MARKS: 100 DURATION: 2 hours Copyright reserved

Downloaded from Stanmorephysics.com QUESTION 1 4A Cvv¥ 12 Cvv 1:3 Byv 1.4 Dvv 15 Dvv 1.6 AvvY 10 Byv QUESTION 2 2.1 Maximum displacement of particles from the rest/equilibrium position v ¥ (2 or 0) 22 Destructive Interference. v (Theyphenomenon that occurs) when the crest of one pulse overlaps with the trough of another resulting in a pulse of reduced amplitude. ¥ —_ x+5=3V iy 2.3 x=-2cm a Amplitude of B = (-)2cm ¥ 24.1 Lefty eae Remains the same ¥ QUESTION 3 3.1 The number of (full)waves/cycles (passing a fixed point) per second.v ¥ 3.2.1 BandDv 3.2.2 Trough ¥ 3.3.1 0,4 i =— Vv Arial 2 NOTE: Award full marks for correct =0.2mv answer 3.3.2 0,12 Wavelength = ——Y NOTE: Award full marks for correct a answer = 0.06 mv Accept: 6em vv Copyright reserved (2) (2) (2) (2) (2) (2) (2) [14] (2) (3) (2) (1) (1) [9] (2) (1) (1) (2) (2)

Downloaded from Stanmorephysics.com 3.4.1 POSITIVE MARKING FROM 3.3.2 A wave in which the particles of the medium vibrate parallel to the direction POSITIVE MARKING FROM 3.4.1 OPTION 2 50 waves in 1 v 1 wave in T s. T = 0.02 s¥ NOTE: Award full marks for correct answer POSITIVE MARKING FROM 4.4 OPTION 1 1 Tq yi 1 =v 50 = 0.02 s¥ OPTION 3 distance Speed =——_——_ time _ 0,06 7 time time = 0,02sv QUESTION 4 4.1 of motion of the wave. vv 4.2 Period ¥ 4.3.1 Rarefaction V 4.3.2 Compression ¥ 4.4 Wavelength = 1x2 v =2mv 45 wf "95 [2 Hz v =fixA Vv =2x 2V =4ms'v Copyright reserved (3) [13] (2) (1) (1) (1) (2) (4)

Dowpregrleds Gnome Stanmorephysics. com 2v 0,5” = 4mstv POSITIVE MARKING FROM 4.5 4.7.3 Increases ¥ Because v =f xA anc QUESTION 5 5.1 Reflection of/reflected sound wav 5:2 Decreases ¥ 5.3 Sounds travels faster when temperature of the medium increases/the higher the temperature of the medium, the faster sound travelsv ¥ Copyright reserved (3) (1) (2) (3) [20] (1) (1) (2)

5.4Downloaded from Stanmorephysics.com MARKING CRITERIA Use of correct equation ¥ Correct substitution (for building A) v Correct substitution (for building B) v Subtraction of times/calculation of total v time for B or time for A Answer within the correct range(1,69m- v 1,70m) OPTION 1 OPTION 2 Time for sound to reach building B : Distance to building B: Speed distance J Sneed distance 7 peed = - Accept peed =——_ Accept time _ Ax time ye bt ~ At ~ At 340 =_* 340 =~ v ~ time B t+0,22 X = 340t +74,8...... (i) time B = —— 340 Time for sound to reach building A : Distance to building A: _ 265—-X 340 = time A 265—-X 265-X we = time A = a0 340 = t v F ‘ _ X = 265 -340t ...... (ii) tie BE ene 6 082 340t +74,8=265 -340tv ae Oe v = 340 340 0,22 t =0,28s X = 169,9 mv X =169,8mv OPTION 3 Let the distance from A to P be Y: distance Speed =—————_v time Copyright reserved

5.5 OPTION 1 OPTION 2 dist dist = = vo Speed line v Speed time dist — dist 1500 = - Distance = 7500 mY Distance = 15000m/2v =7500mv Accept: Speed = ast, i pees time Accept: Speed = er time 7500 Half-way dist. = —s ¥ 7500 Half- dist. = ———_ v = 3750mv aa = 3750mv 5.6 It does not damage the soft tissues of human organs (which could be a danger in X-rays) VW OR : Ultrasound has less energy than Gamma Rays or X Raysv¥ ¥ QUESTION 6 me 4 340 == v Y= 340t Let the distance from P to B be X: _ xX 340 =aoa2 Y X= 340(t+0,22) X+Y= 265mv 340(t+0,22) + 340t= 265m t= 0,28s X= 340(0,28+0,22) = 170mv Downloaded from Stanmorephysics.com Copyright reserved (3) (2) [14]

6.1 Dowalgacedof casio Stanmaragtiy Sica. Palitle of light that contains energy.” Y (2 or 0) (2) 6.2.1 -Ultraviolet/UV (radiation) “” (1) 6.2.2 Infrared/IR (light) ¥ (1) 6.3 Gamma rays ¥ (2) It has the highest frequency/energy ¥ 6.4.1 c =ixa ¥ Accept v=fxA 3x10® =2,42x109x AVY Final £0.12 tb _ inal answer of 0.12 m must be a een shown, otherwise MAX (1) (2) 6.4.2 Microwaves ¥ (1) 6.5 ay A _ 6,63 x 10-34 x 3x 108” 0.3x109 % (4) E=6,63x 106 Jv OR: v=fav :3x10®=f x 0,3x 109% f =1x 10'8Hzv E=hf v E= 6,63 x 10734 x 1x 1018 E=6,63 x 107 Jv 6.6 Increases V¥ (2) [15] QUESTION 7 Te The net charge of an isolated system remains constant during any physical process. YY (2 or 0) (2) 72 To prevent the loss of electrons or charges. ¥ OR To prevent leakage of charges. ¥ (1) OR To prevent transfer of chargesY 73 Q=nxq, ¥ Q=1,25x10" x -1,6x10°° v Q=- 2x10 CY (3) Copyright reserved

Ts 4. Downtas dacticfenag or Sisarunairs fakes positigayreharged (than sphere B) ¥ OR Charges are transferred from a negatively charged sphere to a positively charged sphereY (1) MARKING CRITERIA Straight line Vv eGraph slopes downwards/has negative gradientY > (2) Stafimorephysies.com Copyright reserved

Downloaded from Stanmorephysics.com POSITIVE MARKING FROM QUESTION 7.3 a+, 2 7.6.1 Q= AB 3x10°% +(- 210%) y 2 =+5x107CV (3) POSITIVE MARKING FROM QUESTION 7.3 7.6.2 fiz AQ qe OR _ 5x10" — (-2x10%)v _ 5 x107— 3x 10%v + 1,6 x 10°?v -1,6 x 10°?v = 1,56 x 10’? electrons ¥ = 1,56 x 10" electrons ¥ (3) [15] Copyright reserved