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Physical Sciences Grade 10 P2 National November 2016 Memo

MemorandumPhysical SciencesGrade 10201614 pages

Grade 10 Physical Sciences Paper 2 memorandum from the National November 2016, 14 pages. Read online or download the free PDF.

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ale basic education REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 10 i PHYSICAL SCIENCES: CHEMISTRY (P2) + 7 FISIESE WETENSKAPPE: CHEMIE (V2) ty a 7 NOVEMBER 2016 : i un i il N MEMORANDUM n MARKS/PUNTE: 147 This memorandum consists of 12 pages. Hierdie memorandum bestaan uit 12 bladsye. DEPARTMENT OF BASIC BDUC ATION PRIVATE BAG X58, PRETORIA boot 2016 -11- 11 APPROVED MARKING GUIDELINE ao . PUBLIC EXAMINATION \w\ @ Copyright reserved/Kopiereg voorbehou
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Wetenskappe/V2 DBE/November 2016 CAPS/KABV — GradelGread 10- Memorandum QUESTION 1/VRAAG 1 1.4 CvY (2) 1.2 AvvY (2) 1.3 Cvv (2) 14 Dvv (2) 1.5 Cvv (2) 1.6 Avv (2) 1.7 ByYY (2) 1.8 Byv (2) 1.9 Cv¥v (2) 1.10 Dvv (2) [20] QUESTION 2/VRAAG 2 2.1 A pure substance is a substance that cannot be separated into simpler components by physical methods. “ OR A pure substance is made up of one (same) type of element or molecule. “ ‘n Suiwer stof is 'n stof wat nie deur fisiese metodes in eenvoudiger komponente opgebreek kan word nie. OF ‘n Suiwer stof bestaan siegs uit een (dieselfde) tipe element of molekule. (1) 2.2 2.2.1 Element ¥ (1) 2.2.2 Consist of only one type of atom.” Besiaan uit net een tipe atoom (1) 2.2.3 Mixtures ¥/Mengsel (1) o¢ 2.2.4 It is a combination of many gases. “ Dit is 'n kombinasie van baie gasse (1) 2.3 Pots and pans are made of metal, because metal is a good conductor “that allows heat to be transferred so that the food can cook. The handles are insulators (poor conductor of heat) VW so that you do not burn your hands when you pick up a hot pot. Potte en panne word van metaal gemaak, omdat metaal 'n goeie geleier van hitte is wat toelaat dat hitte oorgedra word, sodat die kos kan gaar word. Die handvaisels is isolators (swak geleiers van hitte) sodat jou hande nie brand as jy 'n warm pot optel nie. (2) 2.4 2.4.1 NaCt DEPARTMENT OF BASIC (2) 2.42 alas 7 2) SSS q00t Me 2016 -11- 14 APPROVED MARKING GUIDELINE PUBLIC EXAMINATION Copyright reserved/Kopiereg voorbehou Please turn over/Biaai om asseblief
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Wetenskappe/V2 3 DBE/November 2016 CAPS/KABV — Grade/Graad 10 - Memorandum QUESTION 3/VRAAG 3 3.1 3.2 3.3 3.4 3.5 3.6 3.7 3.8 3.9 3.1.1 Temperature V/Temperatuur 3.1.2 Time ¥ Also accept phase change Tyd. Aanvaar ook faseverandering What is the relationship between an increase in temperature over a period of time and/or phase change? Vv” Wat is die verwantskap tussen 'n toename in temperatuuir vir 'n tydperk en/of faseverandering? NOTE: -YThe dependent and independent variable must be mentioned. ¥The relationship between the variables must be identified. The question should not be answered with a YES or NO. LET WEL: Die onafhanklike en afhanklike veranderlike moet genoem word. Die verwantskap tussen die veranderlikes moet ook genoem word. Die vraag moet nie kan beantwoord word deur 'n JA of NEE antwoord nie. Solid “/Vaste stof -24°Cv Boiling point is the temperature of a liquid at_which its vapour pressure is equal to the external (atmospheric) pressure. es Kookpunt is die temperatuur van 'n vioeistof waar sy dampdruk gelyk is aan die eksterne (atmosferiese) druk. Liquid changes to gas. v/Vioeistof na gas The kinetic energy of the particles remains the same’, the energy is used to overcome/break/weaken the intermolecular forces (forces of attraction) between the particles’, particles move further away from each other (increase in potential energy)“ resulting in a phase changew’. Die kinetiese energie bly dieselfdew, die energie word gebruik om die intermolekulére kragte (aantrekkingskragte) tussen die deeitjies te oorkom /oreek/verswak v{die deeltjies beweeg verder uit mekaar uit, dus neem die potensiéle energie toe.“ en sodoende vind 'n faseverandering piaas. “” Substance 2.V Substance 2 has a lower meiting and/or boiling point than substance 1. “ Stof 2. Stof 2 het 'n laer smelt- en/of kookpunt as stof. Thermometer “/Termometer DEPARTMENT OF BASIC EDUCATION PRIVATE BAG X895, PRETORIA 0001 2016 -11- 11 APPROVED MARKING GUIDELINE % PUBLIC EXAMINATION Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief (1) (1) (2) (1) (1) (2) (1) (4) (2) (1)
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Wetenskappe/V2 4 DBE/November 2016 CAPS/KABV - Grade/Graad 10 - Memorandum 3.10 Gi TO.” O\ substance 1 and 2 are at the same temperature. Therefore they will have the same average kinetic energy.” GELYK AAN. Stof 1 en 2 is by dieselfde temperatuur. Dus sal hulle oor dieselfde gemiddelde kinetiese energie beskik. QUESTION 4/VRAAG 4 41 4.2 4.3 lonisation energy is the energy needed to remove an electron from (one mole) of an atomv v in a gaseous phase. lonisasie-energie is die energie benodig om 'n elektron uit (een mol) van ‘n atoom in 'n gasfase te verwyder. 4.2.1 Metals_have_lower_first_ionisation energy than _non-metalsvv, therefore metals would rather lose electrons to form a positive ion (cation). Metale het laer eerste ionisasie-energie as nie-metale, daarom sal metale eerder elekirone verloor om 'n positiewe ioon (katioon) fe vorm. 4.2.2 Non-metals have higher first ionisation energy than _metalsv v, therefore non-metals would rather gain electrons to form the negative ions (anions). Nie-metale het hoér eerste ionisasie-energie as metale, daarom sal nie-metale eerder elektrone opneem om die negatiewe ione (anione) te vorm. The second electron is removed from the energy level very close to the nucleus (atomic radius decreases), therefore the force of attraction between the electron and the nucleus is stronger” hence more energy is needed to remove the second electron”. OR When lithium loses its first electron, it attains a stable electron configuration’, hence more energy is needed to remove the second electron’. Die tweede elektron word verwyder van die energieviak wat naby aan die kem is (atoomradius verminder), dus is die aantrekkingskrag tussen die elektron en die kern sterker. Daarom word meer energie benodig om die tweede elektron te verwyder. OF Wanneer fitium die eerste elektron verloor, verkry dit ‘n meer stabiele elektronkonfigurasie. Daarom word meer energie benodig om die tweede elektron te verwyder. DEPARTMENT OF BASIC EDUGATION PRIVATE SAG X80, PRETORIA 0007 2016 -11- 11 APPROVED MARKING GUIDELINE 4, PUBLIC EXAMINATION Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief (2) [18] (2) (2) (2) (2) 18]
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Wetenskappe/V2 DBE/November 2016 CAPS/KABV — Grede/Groed 10 - Memorandum QUESTION 5/VRAAG 5 5.1 Isotopes are atoms of the same element having the same number of protons but different numbers of neutrons. a) OR different atomic mass (mass number). Isotope is afome van dieselfde element Wat dieselfde getal protone het, maar verskillende getalle neutrone. Isotopes are atoms of the same ber having the same atomic number but OF isotope is atome van dieselfde element wat dieselfde atoomgetal het, maar verskillende atoommassas (massagetal) het. (2) 5.2 5.24 18x and/en 29x v OR/OF A and/en CY (1) 5.2.2 Fluorine” /Fluoor (1) 5.3 69 % Wn” Ar(Cu — x63 — x65 (Cu)= (a Js (io =63.62¥v (4) 5.4 5.4.1 19 Vv 5.4.2 10v 5.4.3 Mg (isotope) OR magnesium (isotope) “ Mg (isotoop) OF magnesium (isotoop)” 5.4.4 12Vv 5.4.5 138Vv (5) 55 (NHz)2S0, “ (1) 5.6 Covalent bond’. lectrons are shared” between the atoms of hydrogen and nitrogen. Kovalente binding. Elektrone word gedee! tussen die atome van waterstof en stikstof. (2) 5.7 DEPARTMENT OF BASIC v EDUCATION 2s? It 4 PRIVATE BAG K395, PRETORIA 0001 2016 -11- 11 ‘s' t s v APPROVED MARKING GUIDELINE (2) PUBLIC EXAMINATION 5.8 5v (4) 9 Copyright reserved/Kopiereg voorbehou Please turn over/Biaai om asseblief
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Wetenskappe/V2 6 DBE/November 2016 CAPS/KABV — Grade/Graad 10- Memorandum 5.9 ee H Ww 2 QUESTION 6/VRAAG 6 6.1 6.1.1 Reaction (ii) v/Reaksie (ii) (1) 6.1.2 Reaction (i) ~/Reaksie (i) (1) 6.2 Gas phase Vv Gasfase (1) 6.3 6.3.1 aluminium carbonate: Atz(COs)3 7) aluminiumkarbonaat. Ato(COs)3 (2) 6.3.2 aluminium oxide: Af,O3 ”) aluminiumoksied: AtO3 (2) 6.4 Cle «+ He > 2HC&g) “Reactants/ Reagense ~ Products/ Produkte (2) 6.5 Reactants/Reaktante: M (Cf2) + M (H2) = (2)(35,5) + (2)(1) = 73 g.moltv Products/Produkte: M (2 HC2) = (2)(1 + 35,5) = 73 g.molt ” Thus the mass of the reactants = mass of the products ¥ Dus die massa van die reaktante = massa van die produkte. (3) 6.6 M(HCE) = 1 + 35,5 = 36,5 (g.mol") v *H= 100 or 36.5 =2,74% ¥ ic 35 5 DEPARTMENT ON *Ct= 365 x 1 00 PRIVATE BAG 8956, PRETORIA cant = 97.26% v 206 -t1- 14 8) APPROVED MARKING GUIDELINE [15] PUBLIC EXAMINATION $ Copyright reserved/Kopiereg voorbehou Please tum over/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Wetenskappe/V2 DBE/November 2016 CAPS/KABV — Grade/Gred 10 - Memorandum QUESTION 7/VRAAG 7 7.1 An electrolyte is a solution that conducts electricity Vv’ through the movement 7.2 7.3 7.4 7.5 70 of ions. ‘n Elektroliet is 'n oplossing wat elektrisiteit gelei deur die beweging van ione. KCLY —K*v +CErv KCe: K* 1:1 Thus 2 mol of KC£ dissolves. vv Dus 2 mol KC£ los op. 39 %K = 745 x100 v =52,35% ¥ Increase V/Toeneem NEGATIVE MARKING FROM QUESTION 7.5. NEGATIEWE NASIEN VAN VRAAG 7.5. With an increase in concentration of the metal salt, potassium chloride, more ions are released v into the solution. Thus, more free ions are available to conduct electricity. “ Met 'n toename in die konsentrasie van die metaalsout, kaliumchloried, word meer jone in die oplossing vrygelaat. Dus is meer ione beskikbaar om elektrisiteit te gelei. Ic TMENT CF BAS DEPADUGATION TAG XBOG, PRETORIA 6004 PRIVATE B: amie -it- 11 APPROVED MARKING GUIDELINE PUBLIC EXAMINATION Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief (2) (3) (2) (2) (1) (2) [12]
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Weftenskappe/V2 8 DBE/November 2016 CAPS/KABV ~ Grade/Graad 10 - Memorandum QUESTION 8/VRAAG 8 8.1 8.1.1 The empirical formula is the simplest whole number ratio of atoms in a compound. Die empiriese formule is die eenvoudigste heelgetalverhouding van atome in 'n verbinding. (2) 8.1.2 If 100 g of the compound is available then: Indien 100 g van die verbinding beskikbaar is, dan is daar: 53,3g 0 40gC 6,6 gH M(©) = 16 g:‘mol"* = M(C) = 12 g:mol™? M(H) = 4 g-mol"* n=m/M n=m/M n=m/M n= §3,3/16 n= 40/12 n=6,6/1 n=3,33125 mol“ n=3,3mol” n=6,6 mol” Thus/Dus: O:C :H 3.33125: 3.3 :6.6 33 33 33” 1:1 :2 Emiprical formula/Empiriese formule = C Hz OV ACCEPT TABLE METHOD AANVAAR TABEL METODE (5) 8.1.3 M(CH20) = 12 + 2(1)+ 16 = 30 g-mor' v Formule mass/Formulemassa 60 =2v Empirical mass/Empiriese massa 30 Thus the molecular formula Dus is die molekulére formule = (CH20) x 2 al C2H.02 v (3) 8.2 M (Na2COs) = 106 g-‘mol! ¥ M (x H2O) = 268 — 106 ~ ssimer OF BASIC 162 OPA DUGATION __ FOR GOOT n(H.Q) = — PRIVATE BAG XS98, PRET v = 9 mol” 2016 -t1- 11 4 APPROVED MARKING GUIDELINE ii vy PUBLIC EXAMINATION % Copyright reserved/Kopiereg voorbehou Please tum over/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Wetenskappe/V2 9 CAPS/KABV — Grade/Graad 10 - Memorandum QUESTION 9/VRAAG 9 9.1 9.2 9.2.1 DBE/November 2016 Temperature/Temperatuur. 273 K or/of 0 °C ¥ Pressure/Druk: 1,013 x 10° Pa (101,3 kPa) or/of 1 atm ” MARK OPTION 1 AND 2 IF 10g | MARK OPTION 3 IF 2dm* Na IS USED. WATER IS USED MERK OPSIE 1 EN 2 INDIEN MERK OPSIE 3 INDIEN 2dm’ 10g Na GEBRUIK IS. WATER GEBRUIK IS. OPTION 4/OPSIE 7: OPTION 3/OPSIE 3: m n(Na)=Y 2 mol H2O : 1 mol He ” 40 (2)(18) Vv :2v “33 v 2000 g : xv = v = 0,43 mol Na x= 111,11g Na: He. 2:1v% Thus 0,22 mol H2 produced ¥ Dus 0,22 mol H2 word geproduseer. m n(H2) = — (He) M m 0,22 =— 2 m=0,43gv Hz produced/gevorm OPTION 2/OPSIE 2: 2 mol Na produces 1 mol H2 “” (2)(23g) V produces (1)(2g) “ 10g produces x¥ x =0,43g” —SSNENT GF BASIC | Copyright reserved/Kopiereg voorbehou DEPATEDUGATION 30, PRETORIA 0001 PRIVATE BAG X35 ante -t1- 41 APPROVED MARKING GUIDELINE PUBLIC EXARN ATION ty Please turn over/Biaai om asseblief (2) (5)
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Wetenskappe/V2 DBE/November 2016 CAPS/KABV — Grade/Greed 10- Memorandum 9.2.2 POSITIVE MARKING FROM 8.2.1 POSITIEWE NASIEN VAN 9.2.1 MARK OPTION 1 AND 2 IF 10 g Na IS USED. MERK OPSIE 1 EN 2 INDIEN 10g Na GEBRUIK IS. OPTION 1/OPSIET: n(H:) =< ¥ m 0,22 = v 22,4 V=4,93 dm? v Accept 4,82 dm® OPTION 2/OPSIE 2: 4 mol: 22,4dm? v 2g : 22,4 dmv 0,439 : x x= 4, 82 dm°v MARK OPTION 3 IF 2dm® WATER IS USED MERK OPSIE 3 INDIEN 2dm’ WATER GEBRUIK IS. OPTION 3/OPSIE 3: 1 mol: 22,4dm> v 2g : 22,4 dmv 111,119 : x X = 1244,43 dm? (3) DEPARTMENT OF BASIC EDUCATION PRIVATE BAG X696, PRETORIA 0001 2016 ~{1- 11 APPROVED MARKING GUIDELINE PUBLIG EXAMINATION 9 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Wetenskappe/V2 11 DBE/November 2016 CAPS/KABV — Grade/Graad 10 - Memorandum 9.2.3 POSITIVE MARKING FROM 9.2.1 POSITIEWE NASIEN VAN 9.2.1 MARK OPTION 1 AND 2 IF 10 g Na IS USED. MERK OPSIE 1 EN 2 INDIEN 10g Na GEBRUIK IS. OPTION 1/OPSIE 1: n(Na) : n(NaOH) 2:2V Thus mol NaOH = 0,43 mol Dus mol NaQH = 0,43 mol n(NaOH) = M v m —___—___-v (23+16+1) m=17,2 g VY of NaOH produced/gevorm 0,43 = OPTION 2/OPSIE 2: 1 mol Na produces/produseer 1 mol NaOH ¥ 23g produces/produseer 40g v 10g produces/produseer xv x= 17,399” MARK OPTION 3 IF 2dm* WATER IS USED MERK OPSIE 3 INDIEN 2dm* WATER GEBRUIK IS. OPTION 3/OPSIE 3: 1 mol H2O : 1 mol NaOH ~ 18g : 40g ¥ 2000g : x” x = 4444 44gv (4) POSITIVE MARKING FROM 9.2.3 OSITIEWE NASIEN VAN 9.2.3 DEPARTMENT OF BASIC EDUGATION _ -3 c= 0,22 mol.dm~ v PRIVATE BAG X695, PRETORIA 0007 2016 -11- 11 APPROVED MARKING GUIDELINE PUBLIC EXAMINATION [14] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences/P2/Fisiese Wetenskappe/V2 12 DBE/November 2016 CAPS/KABV — Grade/Graad 10 - Memorandum QUESTION 10/VRAAG 10 10.1. Precipitate v/Presipitaat/Neersiag (1) 10.2 10.2.1 Step |: BaCl, ¥ 10.3 10.4 10.5 Step Il: no reaction ¥ Stap I: BaCl, Stap Il: geen reaksie V (2) 10.2.2 Step I: AgNO; ~ Step Il: HNO3 Stap I: AgNO3 Stap Il: HNO3 (2) 10.2.3. White “/Wit (1) 10.3.1 Cv (1) 1032 Dv (1) 103.3 Av (1) Precipitation v/Presipitasie (neerslag) Evaporation v/Verdamping Condensation V/Kondensasie (3) Building dams that store drinking water and water for household needs or agriculture. Boreholes are used to tap ground water for use. Any applicable answer. “” Bou damme vir drinkwaier en huishoudelike gebruik of landbou. Boorgate word gebruik om grondwater te gebruik. Enige aanvaarbare antwoord. VV (2) [14] TOTALITOTAAL: 147 PARTMENT OF BASIC DEPAPLDUGATION PRIVATE BAG X09S, PRETORIA 0001 2016 -1i- 41 APPROVED MARKING GUIDELINE PUBLIC EXAMINATION ‘fy Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om assebfief
TO: Downloaded from hlayiso.com basic education Department: Basic Education REPUBLIC OF SOUTH AFRICA Private Bag X895, Pretoria, 0001, Sol Plaatie House, 222 Struben Street, Pretoria, 0002, South Africa Tel.: (012)357 3000, Fax: (012) 323 0601, www.education.gov.za HEADS OF EXAMINATION SECTIONS HEADS OF CURRICULUM SECTIONS | EXAMINATION INSTRUCTION NO 35 OF 2016 AMENDMENTS TO THE MARKING GUIDELINE OF THE 2016 COMMON EXAMINATION FOR GRADE 10: PHYSICAL SCIENCES P2 Error on both English and Afrikaans versions: Question 9. An etror was identified in sub question 9.2.4. Information required to calculate the concentration of NaOH was omitted. This sub question which carried 3 marks must not be marked, and, these 3 marks must be excluded. Consequently the total marks for the question paper must be reduced to 147 marks, then scaled up to 150 marks. Refer to Annexure A that provides the conversion table that must be used to calculate the learner's total marks. her information please contact ihe Director: Examinations and Assessment, se pgaaneno at 012 357 3909 or email: Oqunbanjo.o@dbe.gov.za Ow = DR RR POLIAH CHIEF DIRECTOR: NATIONAL ASSESSMENT AND PUBLIC EXAMINATIOS DATE: = IS- Nth, DEPARTMENT OF BASIC EDUCATION PRIVATE BAG X95, PRETORIA 0001 2016 -11- 11 APPROVED MARKING GUIDELINE PUBLIC EXAMINATION Basic Education» Basiese Onderwys » Imfundve Lesisekelo « Ifundosisekelo » IMfundo Eyisieckelo= IMfundo esiSissko « Dyondze yale Hansi Pfunzo ya Mutheo® Thuto ya Matheo* Thuto ya Mctheos Thutoe Pottana
Downloaded from hlayiso.co Annexure A: GRADE 10 PHYSICAL SCIENCES P2:; ENGLISH AND AFRIKAANS VERSIONS- M JARKS CONVERTED FROM 147 TO 150 pis Converted Wald Converted Mars Converted (REE Converted out of | to 150 out of | to 450 out of | to 150 out of | to 150 147 147 147 147 1 1 45 46 89 91 133 136 2 2 46 47 90 92 134 137 3 3 47 48 91 93 135 138 4 4 48 49 92 94 136 139 5 5 49 50 93 95 137 140 6 6 50 51 94 96 138 141 7 7 51 52 95 97 139 142 8 8 52 53 96 98 140 143 9 9 53 54 97 99 141 144 10 10 54 55 98 100 142 145 11 41 55 56 99 101 143 146 12 12 56 57 100 102 144 147 13 13 S7 58 101 103 145 148 14 14 58 59 102 104 146 149 15 15 59 60 103 105 147 150 16 16 60 61 104 106 17 17 61 62 105 107 18 18 62 63 106 108 19 19 63 64 107 109 20 20 64 65 108 110 21 21 65 66 109 111 22 22 66 67 110 112 23 23 67 68 111 113 24 24 68 69 112 114 25 26 69 70 113 115 26 27 70 71 114 116 27 28 71 72 115 117 28 29 72 73 116 118 29 30 73 74 117 119 30 31 74 76 118 120 31 32 75 77 119 121 32 33 76 78 120 122 33 34 7 79 121 123 34 35 78 80 122 124 35 36 79 81 123 126 36 37 80 82 124 127 37 38 81 83 125 128 38 39 82 84 126 129 39 40 83 85 127 130 40 41 84 86 128 131 41 42 8&5 87 129 132 42 43 86 8&3 130 133 43 44 87 89 131 134 ry 44 4S 88 90 132 135 = DURATION Easle PRIVATE B&G X595, PRETORIA CQUT 2016 -11- 41 APPROVED MARKING GUIDELINE PLIFRI tes rw a neine mri

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