Physical Sciences Grade 12 KZN March Test 2026 Paper & Memo

Downloaded from Stanmorephysics.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 12 MARKS : 100 TIME : 2 Hours This question paper consists of 10 pages and 4 data sheets Copyright reserved Please turn over

PmscaS8Wiloaded from Stanmorephysics.com March 2026 INSTRUCTIONS AND INFORMATION 1. 10. 11. This question paper consists of SEVEN questions. Answer ALL the questions in your ANSWER BOOK. Start EACH question on a NEW page in the ANSWER BOOK. Number the answers correctly according to the numbering system used in this question paper. Leave ONE line between two sub questions, for example between QUESTION 2.1 and QUESTION 2.2. You may use a non-programmable calculator. You may use appropriate mathematical instruments. You are advised to use the atta ed)D SHEETS. Show ALL formulae an NS L calculations. Round off your final numeri ers to. a minimum of TWO decimal places. Give brief motivations, discu et cetera where required. Write neatly and legibly. Please turn over

Physicaf¥owvdoaded from Stanmorephysics.com March 2026 QUESTION 4 Four possible options are provided as answers to the following questions. Each question has only ONE correct answer. Choose the correct answer and write the letter (A — D) next to the relevant question number (1.1 — 1.6) on the answer sheet. 4.1 1.2 1.3 Which ONE of the following physical quantities is the rate of change of momentum? A Impulse B_ Acceleration C Power D Force (2) An object is dropped from thé top of a’tall/building. After time t, the object's momentum is p. What will enema the object be after time 2t? Ignore the effect of air friction. ; A ‘’p Bp C 2p D 3p (2) A boy pushes a heavy box across a rough floor with a constant force of 250 N. The box experiences a constant frictional force of 50 N while it is moving. 250N ol aq The magnitude of the force exerted by the box on the boy is ... A 50N B 200N C 250N D 300N (2) Copyright reserved Please turn over

Physica ooo fo] 1.4 1.5 1.6 Ce} 4 R March 2026 Wnloaded from Stanmorephysics.com Consider the organic compounds (I to IV) shown below. I: CH= C -CH2-CHs I; [CH3— C = C — CH2—- CHs3 Ile | CH3 — C = C — CHs IV: | CH3 - C = CH Which of the compounds above are positional isomers? A landll Bland Ill Cc landlv D_Iland Ill (2) In which one of the followi fernatives are the three compounds listed in order of their increasing {a ssure? A Pentanoic acid; Pentan = 1° B_ Pentane; Pentan — 1 — C C Pentan — 1 - ol; Pentane; Pentanoic ac D Pentan — 1 — ol; Pentanoic acid; Pentane (2) An organic compound X has the molecular formula CaHsOz. When X is heated with an excess of ethanol in the presence of concentrated sulfuric acid, a sweet-smelling compound forms. When Compound X reacts with sodium carbonate solution, carbon dioxide is produced. Stanmorephysics Which ONE of the following is the IUPAC name of compound X? A Ethyl Ethanoate. B_ Butanoic acid C Butyl Ethanoate D Ethyl Butanoate (2) 112]

PhysicallSeisavehoaded from Stanmorephysics.com March 2026 QUESTION 2 In the diagram below, two blocks, A and B, of mass 8 kg and 5 kg, respectively, are connected by a light, inextensible string. The string is passed over a light, frictionless pulley so that the blocks hang down as shown. Initially, the blocks are held stationary at the same position above the floor. Each block is 0, 3 m high. ea (0,3 m 1 4 A B 8 ka 5kg Floor f c aaa ] ps as The blocks start moving when they are released. Ignore air friction when answering the questions below. 2.1. Draw a Free-body diagram of ALL the forces acting on block B. (2) 2.2 State Newton’s second law of motion in words. (2) 2.3 Calculate the blocks' acceleration after they are released. (4) Block A touches the floor a second later after the release. The blocks come to rest as shown below. downloaded Stanmorephysics 8kg Floor tr 2.4 Calculate the vertical distance d measured from the top of block A to the bottom of block B at the instant block A touches the floor. (5) [13]

Downloaded from Stanmorephysics.com March 2026 Physical Sciences 6 NSC QUESTION 3 A soft ball with a mass of 0,3 kg is projected vertically upwards from the roof of a 45m tall building with velocity v. It hits the balcony below with a velocity of 29,36 m.s", and bounces off with a velocity of 13,77 m.s“!. The balcony is 12 m above the ground, as shown below. Ignore the effects of friction. 45m Balcony 12m } ’ +} Ground 3.1 Define the term Projectile. (2) 3.2 Calculate: 3.2.1 The magnitude of the velocity v, with which the ball was thrown from the roof of the building. (4) 3.2.2 The velocity with which the ball strikes the ground. (3) It takes 8,2 s from the time the ball is released from the roof until it strikes the ground. 3.3 Calculate the NET FORCE that the balcony surface exerted on the ball. (7) [16]

Physical Sci . “Downloaded from Stanmorephysics.com March 2026 QUESTION 4 Car A of mass 900 kg is stationary at a traffic light when it is hit from behind by Car B, of mass 1100 kg, travelling at 19 m-s” to the right. Immediately after the collision, Car A moves to the right at 10 m:s“!. Stanmorephysics Stationary be’ Unknown velocity 10 ms? a a 4.1 State the law of conservation of linear momentum in words. (2) 4.2 Calculate the velocity of car B immediately after the collision. (4) 4.3. “Modern cars are designed to partially crumple on impact. A crumple zone is a specially designed part of a motor vehicle that is designed to deform or collapse during a collision.” Explain how crumple zones are used as a safety measure in motor vehicles. (2) 4.4 Determine, by means of a calculation, whether the collision between car A and car B is ELASTIC or INELASTIC. 4.5 A traffic officer arrives at the accident scene and makes the following observation: “In a head-on collision involving two cars of different masses, the risk of passenger injury in the heavier car is lower than in the lighter car”. Use Physics principles to explain the observations made by the traffic officer. (2) [15] Copyright reserved Please turn over

Physical Sciences 8 ‘ March 2026 jownloaded from Stanmorephysics.com QUESTION 5 (Start on a new page) The letters A to F in the table below represent six organic compounds. H eo wo A fy i | i Ethy! propanoate ae H H | H H | H H H Cc Cc Cc foo | | H H e— H E} Butane 5.1 Define homologous series. Stanmorephysics (2) 5.2. Towhich homologous series does compound B belong? (1) 5.3 Draw the structural formula of compound B. (3) 5.4 Write down the LETTER that represents the following: 5.4.1. Anunsaturated hydrocarbon. (1) 5.4.2 Acompound with the general formula CnH2n0. (1) 5.5 Write down: 5.5.1. The IUPAC name of compound A. (2) 5.5.2 The IUPAC name of compound D. (2) 5.5.3 The balanced equation, using MOLECULAR FORMULA, of the complete combustion of compound E. (3) [15] Copyright reserved Please turn over

Physical Sciences March 2026 9 ‘ ownloaded from Stanmonegshysics.com QUESTION 6 (Start on a new page) The boiling points of various primary straight-chain alcohols are provided in the table below. Alcohol Boiling point (°C) Methanol 65 Ethanol 78 Propan — 1 —ol 97 Butan — 1 -ol 118 Pentan — 1 6.1 Write down the NAME of the fu 6.2 Define the term boiling point. (2) 6.3. Which ONE of the alcohols mentioned above is the LEAST flammable at room temperature? Explain your answer by referring to vapour pressure and risk of ignition. (3) 6.4 Use the information in the table above to answer the following questions. 6.4.1. On the graph paper provided, draw a graph of Boiling point versus the number of carbons in each alcohol. Stanmorephysics (4) 6.4.2 State the trend shown on the graph. (2) 6.4.3. Explain your answer in 6.4.2 by referring to the TYPE and STRENGTH of the intermolecular forces involved. (3) [15] Copyright reserved Please turn over

Physical eweloaded from Stanmorefhysics.com Mare'2026 QUESTION 7 (Start on a new page) 7.1. The following equation represents the cracking of a hydrocarbon at high temperature and pressure: C11H24 > 2C2Ha + ¥ + CaHio Draw the structural formula of compound Y. (2) 7.2. The flow diagram below shows the preparation of different organic compounds using compound P, which has the general formula CnHansz. Reaction 1 Inorganic Compound P cn 2-Chlorobutane | compound X Compound Q y (Major product) oreph| Compound R 7.2.1 Write down ONE reaction condition for Reaction 1. (1) 7.2.2 |s2-chlorobutane a PRIMARY, SECONDARY, or TERTIARY haloalkane? Explain your answer. (2) 7.2.3. Write down the balanced equation, using STRUCTURAL FORMULAE for Reaction 3. (4) 7.3. Reaction 2, in the flow diagram above, is an elimination reaction during which the organic compound Q and TWO inorganic compounds are formed. Write down: 7.3.1 The NAME of this type of elimination reaction. (1) 7.3.2 The IUPAC name of Compound Q. (2) 7.3.3 The FORMULA of EACH inorganic product formed during Reaction 2. (2) [14] TOTAL MARKS: [100] Copyright reserved Please turn over

Physical Science: Downloaded from Stanmorephysics.com 11 March 2026 DATA FOR PHYSICAL SCIENCES GRADE 12 PAPER 1 (PHYSICS) GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12 VRAESTEL 1 (FISIKA) TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES NAME/NAAM SYMBOL/S/MBOOL VALUE/WAARDE Acceleration due to gravity “g2 Swaartekragversnelling a sald Speed of light in a vacuum 8 m-s-1 Spoed van lig in 'n vakuum ¢ 3,0 x 10" ms Planck's constant -34 J. Planck se konstante n scitadihiallida Coulomb's constant 9 N-m2-C-2 Coulomb se konstante 3 a eRe Charge on electron Lading “1,6 x 10°9-C op elektron ~<o 4 Electron mass Elektronmassa * | 9,11 x 10°31 kg TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING Vp = Vi + aAt Ax = v,At~ at‘ orfof Ay =v At - :aAt® Ap =mv, -mv, 5 - 7 {Vv +Ve ; iVosMe v2 =v? +2aax orlof v.27 =v72+2ary | Ax=| 5 [At or/of Ay =! aa a At \ FORCE/KRAG Free =Ma p=mv F.At =Ap w=mg WORK, ENERGY AND POWERI/ARBEID, ENERGIE EN DRYWING W =FAxcos 0 U=mgh orfof Ep =mgh K my! oof E, =p" Wra = AK oof W,.. = AE, AK=K,-K, offof AE, = Ey, - Ey, “ P= Fy Copyright reserved Please turn over

Physical $geprivaded from Stanmorephysics.com March 2026 DATA FOR PHYSICAL SCIENCES GRADE 12 PAPER 2 (CHEMISTRY) GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12 VRAESTEL 2 (CHEMIE) TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES NAME/NAAM SYMBOL/S/MBOOL VALUE/WAARDE Standard pressure 5 Standaarddruk pe Latee 19° Fe Molar gas volume at STP - Molére gasvolume by STD Vm 22,4 dm?-mot" Standard temperature 273K Standaardtemperatuur Charge on electron Lading 1,6x109C op elektron Avogadro's constant Avogadro-konstante 6,02 x 1023 mol n=m n=N M Na c= oof c= ™@ n=V Vv MV Vin CaVa= Na “ oe he pH = -log[Hs0*] Kw = [H3O*][OH‘] = 1 x 10°4 at/by 298 K or/of or/of Ecetie = Ecathodeo —Eanodeo /Eese! =Exatoseo —Eanodes Ecetio = Ereductione— Eoxidatione/Eese! = Ereduksieo— Eoksidasies Eceiie = Eoxidisinge agent — Ereducinge agent /Eose! =Eoksideermio dde! — Ereduseermié ddet Copyright reserved Please turn over

Physifaoawistaaded from Stanmorephysics.com 14 March 2026 : NSC _ TABLE 3: THE PERIODIC TABLE OF ELEMENTS i iL 3: DIE PERIODIEKE TABEL VAN ELEMENTE 1 2 3 4 E) 6 7 8 9 10 11 12 13 14 15 16 17 18 (I) (Il) ; (my (ivy) (Vy) (ts Atomic number a KEY/SLEUTEL Atoomgetal A av e N 1 7 29 4 3 4 Electronegativity J Gy [Symbol 5 6 7 8 9 10 2 Li |Z Be Elektronegatiwiteit “| - ana Simbool s BIS = Nle0]$¢ Ne 7 9 ! 11 12 14 16 19 20 11 12 tT 13 14 15 16 17 18 3 Na/= Mg Approximate relative atomic mass 2AQI2 SiS P| S |3Ce! Ar 23 24 Benaderde relatiewe atoommassa 27 28 31 32 35,5 40 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 @ K |2 Ca/2 Sc /2 Ti |& 2 Cr |2Mn|2 Fe |2 Co|2 Ni |2 Cu|2 Zn |2 Ga|2 Ge |& As |S Se |S Br| Kr 39 40 45 48 51 52 55 56 59 59 63,5 65 70 73 75 79 80 84 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 oe Rbi2 Sri Y |= Zr} Nb|2 Mol? Te |S Ru/a Rh|& Pd |2 Ag |= Cd |= In 2 Sn/2 Sb|& Te /a | Xe 86 88 89 91 92 96 101 103 106 108 112 115 119 122 128 127 131 55 56 57 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 S$ Cs/2 Ba| La|2 Hf} Ta] W| Re| Os} Ir| Pt] Au] Hg|2 T2/2Pb/2 Bi |S Pols At| Rn 133 137 139 179 181 184 186 190 192 195 197 201 204 207 209 87 88 89 nw oa o Fr |e se Ac 58 59 60 61 62 63 64 65 66 67 68 69 70 71 Ce | Pr | Nd | Pm | Sm | Eu | Gd | Tb | Dy | Ho| Er | Tm| Yb | Lu 140 141 144 150 152 157 159 163 165 167 169 173 175 90 91 92 93 94 95 96 97 98 99 100 101 102 103 Th | Pa | U | Np} Pu | Am | Cm | Bk | Cf | Es | Fm | Md | No | Lr 232 238 Copyright reserved Please turn over

Prysictheipifoaded from Stanmorefhysics.com REN EBS NOTE: Tear this page off and submit it with your answer booklet. Learner's name: 6.4.1 | i | | | ] i 1 T T ze ee 4 2 aes ee Oe om BB Fe Oa Fe: a vk: om a ia Torry [ } i i — a ee ee pes Bt Es +14 + FA 4 t i ] i | ; - 4 4 4 | { i ! Era i | i | | t T I T | i | | | |] { eal \ fd a i | ide i | | } | i if if | i i st i | } | ' | ; t+ | Ail idl Beane i = i } 1 | i : { | T 4 IT. SRR Eee sees tI t - . i + | L tech is bee SRaRRESEREREEBEE i i i i ap Ste) Sores On Ce ee ee ee ee ee ann ie can Oe SS Oe ee ee ee oe oo oe t f , } { ’ 1 H { i i aa 4 funfop— ' itt Copyright reserved

Downloaded from Stanmprenysics.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 12 MARKS : 100 These marking guidelines consist of 7 pages. Copyright reserved Please turn over

PhysicdDeuetebsaded from Stanmorephysics.com QUESTION 1 1.1 bce 12 Cv 1.3 ¢6uae 14 Bvv 15 Avv 16 Bvv QUESTION 2 24 Tv Fg v 2.2 When a net force acts on an object, 2.3 2.4 Block A Fnet=ma v Fg-T=ma 8x9,8-T=8av....eqn 1. a=2,26ms?v POSITIVE MARKING FROM 2.3 Ay = viAt + % at? Vv =0+%x2,26x 12 Vv =1,13m d=1,13+1,13 v-0,3v =1,96mv Copyright reserved T-Fg=ma T-5x 9,8 = 5a v... eqn 2. March 2026 e object will accelerate in the direction of the net force with an acceleration that is directly proportional to the net force vY and inversely proportional to the mass of the object. v Please turn over (2) (2) (2) (2) (2) (2) [12] (2) (2) (4) (5) [13]

PhysicdDeneeboaded from Stanmorephysics.com QUESTION 3 3.1 3.2.1 3.2.2 3.3 An object that has been given an initial velocity and then moves under the influence of the gravitational force only. vv” Upward as positive ve = vi? + 2ady ¥ (- 29,36)? v= vi? + 2 (- 9,8) (- 33)” vi = 14, 67 m.s! ¥ Downward as positive ve = vi? + 2aAy ¥ (29,36)? v= vi? + 2 (9,8) (33) vi= 14,67 mst v Upward as positive vie = vit + 2aAy ¥ = (13, 77)? + 2(- 9.8 uth an vi = 20, 61 m.s" downward POSITIVE MARKING FRO! Time | Downward as positive vi = vi? + Zady ¥ (- 13, 77)? + 2(9,8) (12)” vi = 20, 61 m.s“', downward v and 3.2.2 n the rou to the balcony Upward as positive Vr = vi + adt ¥ (-29, 36) = 14, 67 + (- 9,8) At ¥ Downward as positive vr = vi + aAt ¥ (29, 36) = - 14, 67 + (9,8) At v At=4,49s At=4, 49s Time from the balcony to the ground Upward as positive Downward as positive Vr = vi t+ adt vi = vi + adt (-20, 61) = 13, 77 + (- 9,8) At Vv (20, 61) = - 13, 77 + (9,8) At v At=3,51s At=3, 51s Contact time: 8,2 — (4, 49 + 3,51) V=0,2s Fnet = ™@r-w At Fnet = smart a88e) y Fnet = 64, 70 N, upward ¥ Copyright reserved Please turn over March 2026 (2) (4) (3) (7) [16]

PhysicdDeuieteboaded from Stanmorephysics.com March 2026 QUESTION 4 4.1. The total linear momentum of an isolated system is conserved. v Vv (2) 4.2 > Pbefore = > Patter Mavai+ MeVei = Mavar + MBVer 0 + (1100 x 19) v= (900 x 10) + 1100ver ¥ Vi = 10, 82 m.s"", to the right v (4) 4.3 Crumple zones increase the collision time” , which reduces the net force V experienced by the cars. (2) 4.4 POSITIVE MARKING FROM 4.2 > Ek before = % mavait + a maver? v =0+%x = 198550 J > Ek after = % mavar?+ % =%x 900 x 1 «(10 82)? v = 109389, 82 J > Ekbefore # > Ekafter v Collision is INELASTIC (5) 4.5 Newton’s third law: Both cars experience equal force. ¥ Newton's second law: Acceleration is inversely proportional to the mass. v Therefore, a heavier car experiences smaller acceleration than a lighter car. (2) [15] Copyright reserved Please turn over

PhysicdDeneteboaded from Stanmorephysics.com March 2026 QUESTION 5 5.1. A series of organic compounds that can be described by the same general formula. Vv (2) 5.2 Esters. v (1) v v v 5:3 A XK ( \ Oo \ (3) 5.4.1 Fv (1) 54.2 Av (1) v v 5.5.1 2-methylpentan-3-one (2) v v 5.5.2 2-methylbutan-2-ol (2) 5.5.3 2CaH10 + 1302 ¥> 8CO2+10H20Y Bal. ¥ (3) [15] Copyright reserved Please turn over

PhysicdDeneteboaded from Stanmorephysics.com March 2026 QUESTION 6 6.1. Hydroxyl (group) ~ (1) 6.2 The temperature at which the vapour pressure of a substance equals the atmospheric pressure. vv (2) 6.3 e Pentan-1-ol. ¥ e It has the lowest vapour pressure. ¥ e It produces fewer flammable vapours at room temperature, which reduces the risk of ignition. v (3) 6.4.1 Boiling Point vs Number of Carbon Atoms (First Five Primary Alcohols) 140 = 130 7 120 110 Boiling point (*C) ” § 8 8 x 3 Number of carbon atoms Marking criteria: e Both axes correctly labelled with appropriate scale: ¥ e All five points plotted accurately: vv e Graph with a positive gradient: v (4) 6.4.2 The boiling point increases as the number of carbon atoms/chain length/surface area/molecular mass increases. vv (2 or 0) (2) 6.4.3. As the number of carbon atoms increases, the London/Dispersion forces ¥ get stronger. Vv More energy is required to overcome the intermolecular forces. V (3) [15] Copyright reserved Please turn over

PhysicdDoneweboaded from Stanmorephysics.com March 2026 QUESTION 7 iv Oh | <1 H H (2) 7.2.1. Heat or Light ¥ (1) 7.2.2 Secondary. v The carbon atom bonded to the halogen/Cl is attached to two other carbon atoms (in the compound). ~ 7.2.3 (2) v vi v tT, oo H—C—C— C— C —H+ C—C— C—H+ K-Cl | | | | || H H H H H H H (4) 7.3.1 Dehydrohalogenation. v (1) 7.3.2 But-2-ene vv (2 or 0) (2) 7.3.3 KClY and H20 v (2) [14] TOTAL MARKS: [100] Copyright reserved