education
Department:
Education
PROVINCE OF KWAZULU-NATAL
NATIONAL
SENIOR CERTIFICATE
GRADE 12
MARKS: 300
MARKING PRINCIPLES:
Penalties for foreign items are applied only if the candidate is not losing marks elsewhere in the question for
that item. No double penalty applied.
Penalties for placement or poor presentation (e.g. details) are applied only if the candidate is earning marks on
the figures for that item.
Full marks for correct answer. If answer incorrect, mark the workings provided.
If a pre-adjustment figure is shown as the final figure, award one mark. Not the method mark for the answer.
Unless otherwise indicated, the positive or negative effect of any figure must be considered to award the mark.
If no + or — sign or bracket is provided, assume that the figure is positive.
Where indicated, part-marks may be awarded to differentiate between differing qualities of answers from
candidates.
This memorandum is not for public distribution, as certain items might imply incorrect treatment. The
adjustments made are due to nuances in a certain question.
Where penalties are applied, the marks for that section of the question cannot be a final negative.
Where method marks are awarded for operation, the marker must inspect the reasonableness of the answer
before awarding the mark.
Operation’ means ‘Check operation’. ‘One part correct’ means ‘Operation & one part correct’.
In awarding method marks, ensure that candidates do not get full marks for any item that is incorrect.
Be aware of candidates who provide valid alternatives beyond the marking guideline.
Codes: f=foreign item; p=placement.
This memorandum consists of 14 pages
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Accounting Grade 12 KZN June 2019 Memo
Grade 12 Accounting memorandum from the KZN June 2019, 14 pages. Read online or get the free PDF download, question paper linked when available.
Accounting · Grade 12 · KZN June · 2019. Memorandum, 14 pages. Read online or download the PDF.
- Subject
- Accounting
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2019
- Exam period
- KZN June
- Curriculum
- CAPS
- Pages
- 14
- File size
- 1.9 MB
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KZN June 2019
- Other filesQuestion paperAnswer bookMemo
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Accounting 2 June 2019 Common Test
QUESTION 1
1.1 Indicate whether the following statements are TRUE or FASLE. Write only ‘true’ or
‘false’ next to the question number (i) — (iv) in the answer book.
1.2.1 Calculate the correct totals for the Cash Receipts Journal and Cash
Payment Journal for May 2019.
Cash Receipts Journal
146 970
1 800v
12 340v
Cash Payment Journal
68 900
2 100v
920”
600”
50 000v v
161 110M 122 520M
1.2.2. Prepare the Bank Reconciliation Statement on 31 May 2019.
Credit
Credit balance as per bank statement 42 440v
Credit outstanding deposit 18 000”
Debit outstanding cheques
No. 897 8 700V
No. 905 1 200v
No. 908 3 100v
Credit amount wrongly debited
Debit balance as per bank account “Operation 48 240M
Operation one part correct 61240M| 61 240M 10
10
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Accounting 3 June 2019 Common Test
1.2.3 Explain how cheque No. 908 should be treated when preparing the financial
statements as at 31 July 2015 the end of the financial year.
Explanation: vv
Increase bank and increase creditors in the Balance Sheet notes.
Increase cash and cash equivalents as well as trade and other payables in the
notes.
The amount is not recognised as paid and the debt is not reduced.
: debit Bank and credit Creditors control
1.2.4 Refer to information G. The bookkeeper has decided to write off the amount of
R50 000.
e Which GAAP principle will the bookkeeper be applying?
e The bookkeeper wants to prevent a similar problem in future. Give TWO
suggestions to improve internal control in this regard.
Principle of prudence v
Solutions: vv
Division of duties/separation of duties
Encourage EFT payments by customers / debtors
All cash received must be deposited daily/deposit slip must agree to receipts/ bank
notifications by SMS or email
Regular and timely check / monitor all large transaction
1.3. | Calculate the amount receivable from or payable to SARS for VAT on
31 March 2019.
v vv v vv v v w
21 375 — 44 550 + 4 725 — 2 130 + 72 000 — 1 800 = 49 620
on Te
— 21375 + 44 550 — 4 725 + 2 130 — 72 000 + 1 800 = 49 620
or Pe
Balance at beginning = 21 375
Output 72 000 - 1 800 — 2 130 = 68 070
Input 44 550-4 725 = (39 825)
49 620
OR
VAT CONTROL VAT CONTROL
21 375 44 550 44 550 21 375
4725 2130 2130 4725
72 000 1800 1800 72 000
49 620 49 620
98 100 98 100 98 100 98 100
Receivable/Payable: Payable — Donotaccept Receivable especive of workings) |
TOTAL MARKS
40
40
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Accounting 4
QUESTION 2
2.1
10
11
17
June 2019 Common Test
INCOME STATEMENT FOR THE YEAR ENDED 28 FEBRUARY 2019.
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Sales (6 200 000v — 20 000Y + 80 000 v — 70 000v ) 6190000 M
Cost of sales (3 000 000v + 62 500v — 43 750v ) (3 187 750) @M
Gross profit Operation one part correct 3171250 YW
Other operating income Operation one part correct 122989
Rent income ( 128 740v — 27 060v) 101680 v
Bad debts recovered (2 760v + 2 400v) 5160 v
Provision for bad debts adjustment 3149 vv
Profit on sale of an asset 13 001 vv
Gross income Operation one part correct 3 294 240
Operating expenses (Operation one part correct (2 676 240) M
Audit fees 33 800
Insurance 21 222
Bad debts 74 000
Bank charges 3 200
Directors fees (260 000” + 260 000 ) 520000 v
Salaries (1 220 000v + 15 368v) 1235368 v
Pension fund contribution (36 200v + 3 900v) 40100 v
Packing material (22 000v — 4 000v ) 18000 v
| Sundry expenses Accept (137322) Balancing figure Operation 77100
Trading stock deficit 81 250 vv
Depreciation (525 200M+ 47 000M) See 224 572200 WM
Operating profit 618000 v
Interest income Operation 32000 4
Operating profit before interest expense Operation 650 000 MJ
Interest expense (30 000) v
Net profit before taxation Operation 620000 4
Income tax (186 000) v
Net profit after tax Operation 434000 MJ
47
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Accounting 5 June 2019 Common Test
2.2.1 CALCULATIONS ANSWER
A. [5700 000 — 3800000 Operation one patconet | 1900 000
1
1
B. | 294 000 — 294 000 Operation one part corect Ov
2
2
C. | 24 000% +501 200v Operation one panconet | 626 2001
3
3
D. | 36 000 x 10/100 X 2/12 = 600 ~~ Operalion one part conect
914 000 — 450 000 = 464 000 5
464 000 X 10/100 = 46 400 vv 47 000 5
2.2.2 | Trade and other payables
Creditors 660 000
Creditors for salaries 10 538v
SARS PAYE (64 100¥ + 2880”) 66 980
Pension Fund (45 400” +3 900Y + 19507) 51 250V
Shareholders for dividends 244 800
Income received in advance 27 060v
Accrued expenses 260 000v 12
Operation one part correct 1 320 628M 12
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TOTAL MARKS
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Accounting
QUESTION 3: INVENTORY SYSTEMS
3.1.1
3.1.2
3.1.3
3.1.4
3.1.5
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Value of closing stock using the FIFO method of stock valuation. The
value of closing stock according to the Weighted Average method is
R756 750.
6 June 2019 Common Test
(40 marks; 18 minutes)
taking.
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First in First Out (FIFO) Weighted Average
120 units
80 X R6500 = R520 000vv
40 X R5500 = R220 000v v
120X 1375 = R165 000vv 7
= R905 000 1 Operation one part correct R756 750 7
Calculate Cost of Sales using the FIFO method.
O/S + purchases + Import duties - closing stock 5
= 70000V + R1930000Y + 522500 v —905 000 M1 See314
= _R1617 500% Operation one part corect 5
Calculate the number of units missing.
20 VY + 380 Y —258 VY —120 Y = 22 M missing Operation one part correct
What solutions would you offer to the CEO to help solve the problem
of the missing units. Provide TWO good solutions.
Two solutions: vv vv
e Convert to perpetual / regular stock counts and better internal control
over stock.
Safe secure environment/ improved security
Improve documentation by ensuring proper authorisation, receiving of
goods, recording and packaging. 4
e Division of duties / separation of duties 4
Cool Traders uses the Periodic Stock system. Briefly explain to the
CEO how the Perpetual Stock System works. In your explanation
state TWO main sea of the sate Stock System.
Explanation: vv
Cost of sale is recorded with each sale/ cost of goods sold recorded at the
point of sale/ continuously updating the stock on hand when sales are
made.
Two Advantages: v v
Trading Stock balance is adjusted immediately.
Deficits can be identified timeously through physical stock taking. 4
Gross profit can be calculated at any point in time without physical stock 4
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Accounting 7 June 2019 Common Test
3.1.6 | The CEO has asked you to prepare the financial report based on the
FIFO method. Would you agree to comply with the request? Provide
a detailed explanation to support your answer.
Opinion: NOv
Explanationsv v
= FIFO method would yield a higher gross profit.
« Manipulating figures is fraudulent and unethical.
= Contrary to SARS requirements.
= Professional accountant is bound by a code of ethics. 3
3
3.1.7. | What other method of stock validation can Cool Traders use?
Specific identification method v 1
1
3.2 Identify ONE problem relating to each branch. Quote figures to support
your answer. In each case, offer Bennie advice.
i vvv
BRANCH Problem wiTH A FIGURE Advice
Stock piling 75% (330/440) on Decrease mark-up % /
hand / Reduce selling price /
=| 9 i
MALAHLENI Mark- up percentage of 80% too | Sales promotions / order
high% / stock as required
Sales are only 25% (110/440) of
the stock
Missing cash of R120 000 Check the money before
MBIZENI (1 800 000 — 1 680 000) banking / ;
Division of duties /
Use EFT
Poor stock control — 400 orders | Purchase more stock/
and only 280 in stock (120 more | Take stock from
could have been sold) / Malahleni branch
Not enough stock to meet
SIVUKILE demand (400 orders and only
280 in stock) /
No (zero) stock on hand (poor 6
planning) 6
TOTAL MARKS
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Accounting 8 June 2019 Common Test
QUESTION 4
4.1. Indicate whether the following statements are TRUE or FALSE. Write only ‘true’
or ‘false’ next to the question numbers (4.1.1 to 4.1.5) in the ANSWER BOOK
4.1.1 | Truev
4.1.2 | Falsev
4.1.3 | Falsev
4
4.1.4 | Falsev 4
4.2 BALANCE SHEET ON 28 FEBRUARY 2019.
ASSETS
NON CURRENT ASSETS TA-caA 4962750 H
Fixed assets Operation one part comect |_ 4.507 750 M1
6 Fixed deposit (195 000 v X 70/30 Vv) 455000 4
CURRENT ASSETS 637 250 4
Inventory 1.690 500v / 2 450v = 690M X 325v Operation one partconect |__ 224 250 M1
Trade and other receivables
(210 000v— 11 000” + 9000v + 4000”) 212000 v
Cash and cash equivalent (5 000v +1 000v + 195 000v ) 201000 v
16 TOTAL ASSETS 5 600 000 4
EQUITY AND LIABILITIES
SHAREHOLDERS EQUITY 1i75x41600000)/100 2800 000 v
Ordinary share capital Operation one part conect | 1850000 Mi
Retained income 950000 v
NON CURRENT LIABILITIES Beoooox0s 1680000
4 Loan 1 680 000
CURRENT LIABILITIES 1120000 4
Trade and other payables ( 208 250v + 150 000v +6 000v
+ 15 000” +7 400v ~22 650” +8000) _Operationonepartcomect | 372 000 M1
Current portion of loan 570 000
Bank overdraft 178 000
36
10 TOTAL EQUITY AND LIABILITIES Operation one partcorrect_ 5 600 000 M1 36
TOTAL MARKS
40
40
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Accounting 9 June 2019 Common Test
QUESTION 5
5.1.1 | ORDINARY SHARE CAPITAL
Authorised shares
1 200 000
Issued shares
900 000 _| Shares Operation onepanconed] 4726000 M1
150 000 v | shares @ R6.30 945 000 v
(70 000) v | shares bought back @ R5.40 __ One part comect (378 000) 41
980 000 4 | Shares @ R5.40 5 292 000 v 7
5.1.2 _RETAINED INCOME
Balance at the beginning of the year 147 370
Net profit after tax 438 130 v
Buy back of shares (437 500 — 378 000) (59 500) 4
Dividends a (276 000) 4
Paid (900 000 X 0.12) 108 000 v
Final _(1 050 000 X 0.16) 168 000 v 6
Balance at the end of the year One part correct 250 000 M1 6
5.2 CASH FLOW STATEMENT FOR THE YEAR ENDED 28 FEBRUARY 2019.
Cash flow from operating activities 485 500 4
Cash generated by operations
Interest paid (86 100)
Dividends paid (120 000 V+ 108 000M See5.1.2) One part correct (228 000) 4
(120 000 + 276 000 — 168 000)
8 Tax paid (187 770v — 11 800” —2 400v) (173 570) v
-187 770 + 11 800 + 2 400
Cash flow from investing activities Operation one pari correct (1 442 000)
Purchases of fixed assets (6 177 000 v + 320 000 v (1 846 000)
+ 324 000 v — 4 975 000 v) One part correct
Proceeds on sale of asset 324 000 v
7 Changes in investment (300 000 — 220 000) 80 000
Cash flow from financing activities "One part correct 1 042 500
Proceeds on shares issued See 5.1.1 945 000 4
Buy-back of shares (437 500) v
3 Changes in non-current liabilities( 450 000 -985 000) 535 000
Net change in cash and cash equivalent ‘Operation one part correct 86 000 4
Cash and cash equivalent at the beginning (62 600) v
(65 100 — 2 500)
21
3 Cash and cash equivalent at the end 23 400 v 21
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Accounting 10 June 2019 Common Test
5.3 Current ratio
637 000 v : 490 000 v
1.3: 1 © Operation one part comect 3
3
5.4 Significant decisions above Consequence of the decision
500 000
Purchases of fixed asset by To improve the productivity of the business
1 846 000
Proceeds on shares issued by To finance the purchases of fixed asset
945 000
6
Loan increased by R535 000 To finance the purchases of fixed asset 6
5.5 ALWANDE LTD
5.5.1 | Comment on the price of R10.20 charged by Alwande Ltd for the new
shares issued.
Compare issue price to market price or NAV Vv ¥
Figures R'14,00 or R11,70 “Cou quote iteeneos Bg RSS 3
Expected responses:
e The shares were issued at the average share issue price.
The existing shareholders are being rewarded as the price is lower than the R14,00
charged on the JSE and the NAV of R11,70.
The shares could have been issued at the market price of R14,00 or the NAV of
R11,70 (they have diluted the value of the shares).
5.5.2 | Explain how the issue of new shares has affected the financial gearing and
risk of Alwande Ltd. Quote TWO financial indicators.
Explanationv v Financial indicators vv Figures v v
Expected responses:
one mark
e Gearing has improved — less risk (as there was an issue of new shares)
one mark
debt-equity ratio decreased from 0,8: 1 to 0,5: 1 (by 0,3 : 1)
one mark
e ROTCE improved (due to increased efficiency / profits on new branch)
from 19 % to 21 bas Fi 6
o
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Accounting 11 June 2019 Common Test
5.5.3 | If Sizwe wanted to retain his 55% shareholding in the company, how many
shares would he have had to buy?
v v ica}
(1 150 000 x 55%) — (1000 000 x 55%) = 82 500
632 500 550 000
OR two marks ‘one method mark (if x 60%)
150 000 x 55% = 82500
How much would he have had to pay?
82 500 shares at R10.20 each = R841 500 MM it=number of shares (above) x R9,10
Sizwe decided NOT to buy these shares. Apart from the
% shareholding, explain TWO reasons why he has made a mistake by not
taking up this option.
eres v “ater voev
Expected responses: Any two
e His dividends would have increased by R42 075 (51c x 82 500 shares). This is
more than the interest he earned on the savings account R38 709
(841 500 see above x 4.6%)
e He could buy the shares for capital growth - bought the shares for R10.20 and then
could sell them on the JSE for R14,00 / total profit could have been
R313 500 / would be a good buy as R14,00 exceeds NAV R11,70
He would have earned more dividends on bigger investment (51¢/1020c = 5,%) 7)
EE
ROSHE would be 25% on a bigger investment.
He would lose 82 500 votes at the AGM.
SUKOLUHLE LTD
5.5.4 | Comment on the liquidity of Sukoluhle Ltd. Quote TWO financial
indicators.
Explanation: vv
The liquidity situation has improved / is able to meet current debts / liquidity
ratios have decreased / liquidity ratios are more efficient
Financial indicators anytwoVv Vv Figures v v
e Current ratio has decreased (from 3,5 : 1) to 1,9: 1
e Acid-test ratio has decreased (from 1,7: 1) to 1,1: 1
e Stock-holding period appears to be efficient at 54 days (less than 2 months) 6
oa
5.5.5 Comment on the price paid by Sukoluhle Ltd for the repurchase
coer of shares.
Expected response with any figure: vv
The company is paying a premium above the average share price in order to
entice shareholders to give up their shares / they wanted to increase returns by
decreasing equity / this is a fair value same as the price on the JSE.
Compare price paid (R17,00) to
e market value R17,00 2
e net asset value R15,40 2
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Accounting 12 June 2019 Common Test
e_average issue price of shares R11.50
5.5.6 | Explain THREE ways in which Sizwe has benefited from the repurchase of
the shares by Sukoluhle Ltd.
fs eo vvv se vvv
Expected responses: Three different responses
e He has now become a majority shareholder. His 550 000 shares are 61.1%
of the total shares (40% before the share buy-back)
e Due to the reduced number of shares, his return has improved i.e. EPS
has increased by 80c / from 190c to 270c / ROSHE increased from 14% to
16%. (NOTE: EPS and ROSHE reinforce the same point).
e The reduced number of shares could have contributed to an increase in the
DPS by 57c / by 55.3% / from 103c to 160c (Directors may have
maintained the dividend pay-out policy). 6
TOTAL MARKS
75
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Accounting 13 June 2019 Common Test
QUESTION 6: RECONCILIATIONS
6.1
6.2
6.2.1
6.2.2
6.2.3
Choose the correct answer from the words provided within brackets.
Write only the answer, next to each number.
6.1.1 | Cash Payments Journal (CPJ) v
6.1.2 | Debit v
v
v
6.1.3 | Credit note
6.1.4 | Cash discount 7
DEBTORS RECONCILIATION
Calculate the correct Debtors Control balance on 31May 2018.
74 600 - 3.500 v +4500 vv” =75 600 © One part correct
(4 230 + 270) 4
4
Calculate the balances for the following debtors:
v- vv
N. Zulu 21 600 1 600 + 45004 24500
(—800 — 800)
C.Ntazi 24900 v -2500v 22400
A. Botha 11100 vv +2 700v 13800 M* 12
+ One part corect | [22
Calculate the percentage of debtors that are not complying with the
30 days credit terms.
28 000 + 8 400
36400” x100 = 52% Mone part correct
70 000 v 3
3
List TWO internal control measures that MGM Traders can use to
ensure that only reliable clients are granted credit.
e Perform credit checks (references / listing / credit bureau).
e Check employment history and salary advice.
e Contact details (residential/postal address and contact numbers). 4
4
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Accounting
14
6.3 CREDITORS RECONCILIATION
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June 2019 Common Test
CREDITOR’S LEDGER
NO. ACCOUNT BALANCE STATEMENT BALANCE
Balance 35 000 38 420
; 2970
') 7740-4770 ””
ii) (750) vv
iii) 1000 vv
(1 960)
iv) 980+980 VY
(1. mark each)
v) (3 860) vv
vi) 7120 vv
mal 13
TOTAL 38 970 38 970 13
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TOTAL MARKS
40
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