Mathematical Literacy P1 Nov 2018 FINAL Memo Afr Eng hlayiso.com . hlayiso.com

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 MATHEMATICAL LITERACY P1 WISKUNDIGE GELETTERDHEID V1 NOVEMBER 2018 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 Symbol/Kode Explanation/Verduideliking M Method/Metode MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid C Conversion/Herleiding S Simplification/Vereenvoudiging RT Reading from a table/graph/document/diagram/Lees vanaf tabel/grafiek/document/diagram SF Correct substitution in a formula/Korrekte vervanging in 'n formule O Opinion/Explanation/Opinie/Verduideliking P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede, verkeerde afronding, ens. R Rounding off/Afronding NPR No penalty for rounding/Geen penalisasie vir afronding nie AO Answer only/Slegs antwoord MCA Method with constant accuracy/Metode met volgehoue akkuraatheid This marking guideline consists of 20 pages. Hierdie nasienriglyne bestaan uit 20 bladsye. External Moderators (Question Paper) M.M. Tshabalala E.D. Cronje APPROVED ON 4 November 2018 L.R. de Waal Internal Moderator Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 2 DBE/November 2018 NSC – Marking Guidelines NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops at the second calculation error. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra incorrect item presented. LET WEL: • As 'n kandidaat 'n vraag TWEE KEER beantwoord, merk slegs die EERSTE poging. • As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, merk die doodgetrekte (gekanselleerde) poging. • Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, dit hou op by die tweede berekeningsfout. • Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra verkeerde item. QUESTION/VRAAG 1 [32 MARKS/PUNTE] ANSWER ONLY FULL MARKS Q/V Solution/Oplossing Explanation/Verduideliking T&L M 1.1.1 1 / one / een A L1 OR/OF A day / 'n dag A 2A for correct day OR/OF One day / Een dag A (2) F 1.1.2 Price before saving / Prys voor besparing 1M adding correct values L1 R70 + R250 M 1A simplification = R320 A (2) 1.1.3 F Ariel A 2A product L1 (2) MA M 1.1.4 750 m ℓ ÷ 1 000 1MA for dividing by 1 000 L1 = 0,75 ℓ A 1A simplification only if division OR/OF OR/OF MA 750 m ℓ × 0,001 1MA for multiplying by 0,001 = 0,75 ℓ A 1A simplification only if multiplied (2) F 1.1.5 Price / Prys 1MA multiplying correct values L1 = R11 × 3 MA 1CA simplification = R33,00 CA (only if R7,70× 3) (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 3 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L D 1.1.6 R11; R15; R18; R22; R30; R43; R44; R45; R65; 2A arranging in correct order L1 R250 A If names used max 1 mark (2) M 1.2.1 English = 35 letters OR 15 letters A 2A correct number L1 Afrikaans = 37 letters OF 17 letters A WC, FS, NC Provinces accept both (2) M 1.2.2 44 0C A 2A correct reading L1 Accept 44 - 45 0C (2) MP 1.2.3 One unit on the drawing represents twenty five units L1 in reality / Een eenheid op die tekening verteenwoordig vyf en twintig eenhede in werklikheid. A OR/OF Scale in this context means that the drawing of the 2A correct definition T-shirt is 25 times smaller than in reality / Skaal in hierdie konteks beteken dat die tekening van Accept no units die T-hemp 25 keer kleiner is as in werklikheid. A OR/OF On the picture the shirt is 25 times smaller / Op die foto is die hemp 25 keer kleiner A (2) M 1.2.4 ± 61 mm A 2A correct measurement L1 (Accept 59 mm – 64 mm) Correct answer in cm = max 1 mark (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 4 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L 1.3.1 M Two Oceans Marathon / Twee Oseane-marathon 2RT reading from table L1 RT Accept: Race on 15 April 2017 Race of 56 km Race with an entry fee of R520,00 (2) 1.3.2 M Comrades Marathon / Comrades-marathon RT 2RT reading from table L1 Accept: Race on 4 June 2017 Race of 89 km Race with an entry fee of R460,00 (2) 1.3.3 F R520,00 – R460,00 RT 1RT correct values from the L1 = R60,00 A table 1A answer (2) M 1.4.1 12 Hours / 12 Ure A 2A correct time L1 OR/OF Accept: 12:00 OR/OF Half a day / Halwe dag A 12 o’clock Max 1 mark (2) D 1.4.2 Discrete / Diskreet A 2A discrete L1 (2) D 1.4.3 RT 1RT correct values from L1 17 031 : 13 852 A table 1A correct values in correct order Accept answer as unit ratios: 1 : 0,813 1,229 : 1 Accept answer in fraction form NPR (2) [32] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 5 DBE/November 2018 NSC – Marking Guidelines QUESTION/VRAAG 2 [41 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L 2.1.1 A F Interest refers to the amount that will be added to an L1 account that is not settled yet / A Rente verwys na die bedrag wat by die agterstallige bedrag gevoeg word. OR/OF A A Extra amount is charged on the late payments / Ekstra bedrag wat gehef word op laat betalings. OR/OF A A Extra money to be charged on overdue fees / Ekstra geld wat op agterstallige gelde gehef word. 1A amount charged OR/OF 1A reason A A Money charged for not paying fees on time / Geld gehef vir fooie nie betyds betaal nie. OR/OF A Interest in this context is the charge levied because of unpaid fees or late payment of fees / A Dit is ekstra geld wat gehef word omdat die rekening nie op tyd betaal word nie. (2) F 2.1.2 R14 819,50 RT 2RT balance L1 (2) RT F 2.1.3 148,20 100 1RT correct values L2  % M 1M multiply by 100 14 819,50 1 = 1,000033739329937 1CA answer ≈ 1% CA (3) M Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 6 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L RT 1RT code F 2.1.4 APG 2039W Design & Theory Studio II RT 1RT name L1 If APG omitted = full marks (2) F 2.1.5 RT 1RT correct values L1 R14 967,70 – R8 650,00 M 1M subtracting deposit = R6 317,70 (2) AO F 2.1.6 Total amount / Totale bedrag RT M L1 = R3 030 + R3 030 + R2 280 + R2 280 + R9 580 + 1RT reading all correct values R4 530 + R29 460 + R2 087 + R395,95 + 1M adding values R395,95 = R57 068,90 CA 1CA simplification OR/OF OR/OF Total amount / Totale bedrag 1RT reading all correct values M RT 1M subtracting values = R62 594 – R6 317,70 + 2 × R395,95 = R57 068,90 CA 1CA simplification OR/OF OR/OF Total amount / Totale bedrag RT M 1RT reading all correct values R40 386 + R23000 + R8650 – R14819,50 – 1M subtracting values 1CA simplification R148,50 = R57 068,90 CA OR/OF OR/OF Total amount / Totale bedrag RT M R3 030 + R3 030 + R2 280 + R2 280 + R9 580 + 1RT reading all correct values R4 530 + R29 460 + R395,95 + R395,95 1M adding values = R54 981,90 CA 1CA simplification OR/OF OR/OF Total amount / Totale bedrag M RT 1RT reading all correct values = R62 594 – R6 317,70 + 2 × R395,95 − R2 087 1M subtracting values = R54 981,90 CA 1CA simplification OR/OF OR/OF Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 7 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L Total amount / Totale bedrag RT M 1RT reading all correct values R40 386 + R23000 + R8650 – R14819,50 – 1M subtracting values 1CA simplification R148,50 − R2 087 = R54 981,90 CA AFRIKAANS VRAESTEL: RT M R148,20 + R3030 + R3030 + R2280 + R2280 + 1RT reading all correct values 1M adding values R9580 + R4530 + R29460 + R2087 + R395,95 + R395,95 = R57 217,10 CA 1CA simplification OR/OF OR/OF RT M 1RT reading all correct values R40 386 + R23000 + R8650 – R14819,50 1M subtracting values = R57 217,10 CA 1CA simplification OR/OF OR/OF M RT 1RT reading all correct values R62 594,70 – R6317,70 + 2 x R395,95 + 1M subtracting values R148,20 1CA simplification = R57 217,10 CA OR/OF OR/OF RT M 1RT reading all correct values R148,20 + R3030 + R3030 + R2280 + R2280 + 1M subtracting values R9580 + R4530 + R29460 + R395,95 + R395,95 = R55 130,10 CA 1CA simplification OR/OF OR/OF RT M R40 386 + R23000 + R8650 – R14819,50 – 1RT reading all correct values R2 087 1M adding values = R55 130,10 CA 1CA simplification OR/OF OR/OF M RT R62 594,70 – R6317,70 + 2 x R395,95 + 1RT reading all correct values 1M subtracting values R148,20 – R2 087 1CA simplification = R55 130,10 CA (3) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 8 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.1.7 Direct deposit / Direkte deposito RT 2RT reading correctly L1 Accept deposit only (2) F 2.1.8 Monthly instalment / Maandelikse paaiement L1 R40 386,60 ÷ 5 A 1A calculating 5 M 1M dividing by 5 = R8 077,32 OR/OF OR/OF Monthly instalment / Maandelikse paaiement R8 077,32 × 5 A 1A calculating 5 M 1M multiply by 5 = R40 386,60 OR/OF OR/OF Monthly instalment / Maandelikse paaiement R40 386,60 M 1M dividing correct values in R8 077,32 correct order 1A calculating 5 = 5 A (2) A F 2.2.1 Inflation is a measure of rate at which the cost of goods L1 is changing over a period of time and is usually expressed as a percentage / A Inflasie is die meting van die koers waarteen die prys van goedere verander oor 'n tydperk en word gewoonlik uitgedruk in persentasie. OR/OF A The percentage increase of the food prices over the period 1970 – 2015 / A Die persentasietoename van kospryse oor die tydperk 1A percentage increase 1970 – 2015. 1A time OR/OF A A Percentage increase of price over a period of time / Persentasie verhoging van prys oor 'n tydperk. OR/OF A A Inflation is the rising price of goods/items over time / Inflasie is die stygende prys van goedere/dienste oor (2) tyd. Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 9 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.2.2 R0,30 OR/OF 30c RT 2RT correct value L1 Accept 0,30 If the candidates only wrote 30 = max 1 mark (2) M AO F 2.2.3 R557,00 – R418,00 RG 1RG correct amount L1 = R139,00 CA 1M subtracting 1CA simplification (one of the 2 values must be correct) (3) F AO 2.2.4 Percentage change / Presentasieverandering L2 RT R75,00  R0,25 100  % SF 1RT all correct values R0,25 1 1SF substitute correct values 1CA correct percentage = 29 900 % CA OR/OF OR/OF Percentage change / Presentasieverandering RT 75 1RT all correct values × 100% = 30 000% 1M subtracting 0,25 M 1CA correct percentage Therefore % increase = 30 000% - 100% = 29 900% CA (3) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 10 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L AO F 2.2.5 Cost price / Kosprys L2 100 104,90 MA 1MA multiplying correct values  117,5 1 1A answer = R89,28 A OR/OF OR/OF Cost price / Kosprys 104,90 1MA dividing correct values MA 117,5% in the correct order = R89,28 A 1A answer OR/OF OR/OF Cost price / Kosprys 104,90 MA 1MA dividing correct values in the correct order 1,175 = R89,28 A 1A answer OR/OF OR/OF Cost price / Kosprys 17,5 × R104,90 = R15,62 117,5 1MA multiplying and subtracting R104,90 – R15,62 MA correct values =R89,28 A 1A answer (2) A F 2.3.1 B OR/OF R241 600 000 000 A 2A correct value L1 (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 11 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.3.2 Budget is the proposed way in which money will be L1 spent on different items / Begroting is die voorgestelde manier hoe die geld vir verskillende items gespandeer behoort te word. A OR/OF A plan on how money is going to be spent on estimated income / 'n Plan oor hoe geld op beraamde inkomste bestee gaan word. A OR/OF 2A definition A plan in how money is going to be spent / 'n Plan hoe geld uitgegee / spandeer gaan word. A OR/OF Financial plan how to spend money/finance / Finansiële plan hoe om geld / finansiering te spandeer. A OR/OF Estimated income and expenditure of money / Geskatte inkomste en uitgawes van geld. A (2) F 2.3.3 Skills development levy institutions / 2RT correct sector L1 Vaardigheidsontwikkelingheffingsinstellings RT (2) F 2.3.4 Percentage of the total education budget / L2 Persentasie van die totale onderwysbegroting RG/RT 1RG/RT correct values 15,3 1M multiply by 100 × 100% M 320,5 = 4,77% CA 1CA answer OR/OF OR/OF Percentage of the total education budget / Persentasie van die totale onderwysbegroting RG/RT R15 300 000 000 100  % M 1RG/RT correct values R320 500 000 000 1 1M multiply by 100 = 4,77% CA 1CA answer NPR (3) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 12 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L AO F 2.3.5 Education Administration plus NSFAS amount L2 to 31,1 billion rand / Onderwysadministrasie plus NSFAS bedrag tot 31,1 miljard rand 9,7% A Accept any estimation from 9,5% but less than 9,86% 2A correct estimation Aanvaar enige skatting vanaf 9,5% maar minder as 9,86% OR/OF OR/OF 15,8 + 15,3 = 31,1 billion / miljard M 1M adding values = 9,7% A 1A estimated value Accept any estimation from 9,5% but less than 9,86% Aanvaar enige skatting vanaf 9,5% maar minder as 9,86% (2) [41] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 13 DBE/November 2018 NSC – Marking Guidelines QUESTION/VRAAG 3 [18 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L M 3.1.1 15 cm + 17 cm + 19 cm + 21 cm A 1A adding of correct values L1 = 72 cm × 10 CA 1CA conversion = 720 mm CA M 1CA answer in mm (3) AO M 3.1.2a Diameter / Deursnee = 2 × radius L1 = 2 × 14 cm M 1M multiplying by 2 = 28 cm A 1A diameter (2) AO M 2 3.1.2b Volume of a cylinder = 𝜋 × 𝑟 × height L2 Volume van 'n silinder = π × r² × hoogte Volume of a cylinder = 3,142 × (14)2 × 15 cm SF 1SF substitution = 3,142 × 196 cm2 × 15 cm S 1S squaring 14 = 9 237,48 cm3 CA 1CA simplification (3) 3.1.3 M The perimeter of a shape is the total distance around L1 the edges defining the outline of that shape / A Die omtrek van 'n vorm is die totale afstand om die sye wat die uitleg van die vorm definieer. OR/OF 2A explanation Total distance around the shape / Totale afstand rondom 'n voorwerp A (2) 3.1.4 M Area of a rectangle = length × width L2 Area van 'n reghoek = lengte × breedte = 15 cm × 12 cm SF 1SF correct substitution = 180 cm2 CA 1CA simplification 35 cm × 33 cm = 1 155 cm2 Max 1 mark (2) 3.2.1 M Amount / Hoeveelheid in kg = 3,5 ÷ 2,25 C 1C conversion L2 = 1,556 A 1A simplification Accept 1,56 kg ; 1,6 kg 1,5 only = 0 marks (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 14 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L 3.2.2 M 1 mℓ flour = 0,7 g flour / 1 mℓ meel = 0,7 g meel L2 625 1C conversion × 0,7 g C 1 = 437,5 g A 1A simplification (2) 3.2.3 M °C = (°F – 32°) ÷ 1,8 L2 °C = (356° – 32°) ÷ 1,8 SF 1SF correct substitution °C = (324°) ÷ 1,8 = 180 °C A 1A simplification (2) [18] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 15 DBE/November 2018 NSC – Marking Guidelines QUESTION/VRAAG 4 [24 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L MPL 4.1.1 South West OR SW 2A direction 2 Suidwes OF SW A (2) MPL 4.1.2 Namaqua National Park / 2RM national Park 1 Namakwa Nasionale Park RM (2) RM RM MPL 4.1.3 Keimoes, Kakamas, Pofadder 2RM first correct town 1 (Any 2 of the 3/enige 2 van die 3) 1RM second correct town (3) MP 4.1.4 Ratio scale OR number scale OR numerical L1 scale 2A ratio / number / numerical Verhoudingskaal OF nommerskaal OF Accept unit ratio getalskaal A (2) A MPL 4.1.5 Measured distance /Gemete afstand = 135 mm 1A measures distance 3 1 : 3 007 874 135 mm × 3 007 874 M 1M using scale = 406 062 990 mm 406 062 990 = C 1C conversion 1 000 000 1R to the nearest km = 406 km R (Range: 130 mm to 140 mm) OR/OF OR/OF A 13,5 cm × 3 007 874 M 1A measures distance 40 606 299 cm 1M using scale C 1C conversion 100 000 = 406,06299 km 1R to the nearest km ≈ 406 km R (Range: 13 cm to 14 cm) (4) MPL 4.2.1 Voortrekker Road / Voortrekkerstraat RM 1 OR/OF 2RM correct road N14 RM (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 16 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L MP 4.2.2 Rivier Street / Rivierstraat RM 2RM correct road L2 (2) MP 4.2.3 Debs-Lodge / Debs-Lodge RM 2RM correct road L2 (2) MP 4.2.4 2,34 km 1SF calculating time L2 Time / Tyd = SF 40 km/h = 0,0585 h × 60 C 1C multiply by 60 = 3,51 minutes CA 1CA simplification NPR (3) P 4.2.5 13 A 1A numerator (independent) L2 P OR/OF 0,310 OR/OF 31% 1A denominator 42 A OR/OF OR/OF MA 1MA subtracting from 1 29 13 1A simplification 1− = 42 42 A (2) [24] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 17 DBE/November 2018 NSC – Marking Guidelines QUESTION/VRAAG 5 [35 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L 5.1.1 D R2 085 600 000 RT 2RT correct amount L1 OR/OF Table value = max 1 mark R2 085,6 million / miljoen RT OR/OF R2,0856 billion / miljard RT (2) 5.1.2 AO D RT L2 R1 323 + R2 085,6 + R3 162 + R2 158 + R1 847 + R2 732 1RT correct values 6 M 1M concept of mean million / miljoen CA = R2 217 933 333 OR/OF 1CA simplification R2 217,933333 million / miljoen NPR (3) 5.1.3 D 1A correct value L1 A A Maximum = 46,1 thousand / duisend 1A unit OR/OF OR/OF 2RT correct maximum Maximum = 46 100 RT (2) 5.1.4 AO D 1RT correct values L2 RT 1M multiply by 100 2 158 000 000 100 % 1CA simplification A= × M 3 441 000 000 000 1 1R rounding = 0,062714327% CA = 0,06% R If omitted zeros = max 3 marks (4) 5.2.1 D A person who is able and willing to work, but cannot find L1 work / 2A explanation 'n Persoon wat geskik en gewillig is om te werk, maar nie 'n werk kry nie. A OR/OF Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 18 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L People who are without work / Mens wat sonder werk is A OR/OF People who are jobless / Mense wat werkloos is A 2A explanation OR/OF Not earning a salary / wage / income Verdien nie 'n salaris / loon / inkomste nie A OR/OF (2) Retrenched / Afgedank A 5.2.2 D X = 1 748 – 506 M 1M subtracting correct values L1 =1 242 A 1A simplification OR/OF 1M subtracting correct values M 1A simplification X = 16 172 – (1 391+ 806 + 4 991+ 2 513 + 1 417 + 321 + 999 + 2 492) No penalty for = 1 242 A including zeros (2) 5.2.3 D Questionnaire / vraelys A L1 OR/OF Survey / opname A OR/OF Population census / populasie sensus A 2A correct answer OR/OF Document analysis / dokument analise A OR/OF Interview / onderhoud A (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 19 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L 5.2.4 D Percentage of people / Persentasie mense L2 RT 1RT using both correct values 1 412 000 100 1M percentage calculation  % M 1CA simplification 4 507 000 1 = 31,329 % CA If omitted zeros = full marks NPR (3) 5.2.5 D 1RT both correct values L2 RT 1A ratio in unit form 16 172 000 : 5 882 000 2,7494 : 1 A Accept: 2,749 / 2,75 / 2,7 (2) 5.2.6 AO P RT 2RT correct values L2 697 000 Probability (NEA) = 1 893 000 RT 1CA simplification = 0,368 CA OR/OF OR/OF RT 2RT correct values 697 000 Probability (NEA) = 15 475 000 RT 1CA simplification = 0,045CA OR/OF AFRIKAANS VRAESTEL RT 2RT correct values 1 196 000 Probability (NEA) = 1 893 000 RT 1CA simplification = 0,63 CA ≈ 0,6 OR/OF OR/OF RT 2RT correct values 1 196 000 Probability (NEA) = 1CA simplification 22 054 000 RT = 0,05 CA If omitted zeros = full marks ≈ 0,1 NPR (3) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 20 DBE/November 2018 NSC – Marking Guidelines Q/V Solution/Oplossing Explanation/Verduideliking T&L 5.2.7 Do not mark this question. Moenie hierdie vraag merk nie. AO P 5.2.8 3 A 2A numerator L3 9 A 1A denominator 1 1CA simplification = CA 3 (4) [35] TOTAL: 150 Upscaling of Question 5 mark Aanpassing van Vraag 5 punt QUESTION/VRAAG 5 QUESTION/VRAAG 5 Mark out of 29 Mark out of 35 Mark out of 29 Mark out of 35 29 35 10 12 28 34 9 11 27 33 8 10 26 31 7 8 25 30 6 7 24 29 5 6 23 28 4 5 22 27 3 4 21 25 2 2 20 24 1 1 19 23 18 22 17 21 16 19 15 18 14 17 13 16 12 14 11 13 Copyright reserved