Mathematical Literacy P2 Nov 2018 FINAL Memo Afr Eng hlayiso.com . hlayiso.com

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SETIFIKAAT GRADE/GRAAD 12 MATHEMATICAL LITERACY P2/ WISKUNDIGE GELETTERDHEID V2 NOVEMBER 2018 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 Symbol/Kode Explanation/Verduideliking M Method/Metode MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid C Conversion/Herleiding S Simplification/Vereenvoudiging RT Reading from a table/graph/document/diagram/Lees vanaf tabel/grafiek/dokument/diagram SF Correct substitution in a formula/Korrekte vervanging in 'n formule O Opinion/Explanation/Opinie/Verduideliking P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede, verkeerde afronding, ens. R/RCA Rounding off/Afronding /Rounding with CA/Afronding met CA NPR No penalty for rounding/Geen penalisasie vir afronding nie AO Answer only/Slegs antwoord MCA Method with constant accuracy/Metode met volgehoue akkuraatheid This marking guideline consists of 17 pages. Hierdie nasien riglyne bestaan uit 17 bladsye. Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 2 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops at the second calculation error. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra incorrect item presented. LET WEL: • As 'n kandidaat 'n vraag TWEE KEER beantwoord, merk slegs die EERSTE poging. • As 'n kandidaat 'n antwoord van 'n vraagdoodtrek(kanselleer) en nie oordoen nie, merk die doodgetrekte (gekanselleerde) poging. • Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglynetoegepas, dit hou op by die tweede berekeningsfout. • Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra verkeerde item. QUESTION/VRAAG 1 [38 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L F 1.1.1 Discount percentage/Persentasie afslag L2  RT 1RT numerator and R6 140 = × 100%  MA denominator R160 087,72 1MA multiply correct values with 100 % = 3,835397... ≈ 3,8%  A 1A simplification rounded to one decimal place AO (3) F 1.1.2 Sub Total/Subtotaal 1M subtracting discount L2 M  RT  MA 1RT all values = R160 087,72 – R6 140 + (2 × R3 500 + R4 298,25 + R1 315,79) 1MA adding accessories, on roads & transaction fee = R166 561,76 (3)  O F 1.1.3 Safety reason/as a safety feature - protect against thieves / L4 hijackers /sunlight / door against damages Veiligheidsrede/as 'n veiligheidskenmerk - beskerm teen diewe / kapers / sonlig / deur teen beskadiging OR/OF  O Beautification of the car / reduce sunlight Verfraaiing van die motor/ sonlig te verminder 2O reason OR/OF  O Longer lasting /Langdurend OR/OF Convenience / Gemak  O OR/OF  O For insurance purposes / Vir versekeringsdoeleindes (2) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 3 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 1.1.4 Interest Year 1/ Jaar1 rente 1MA calculating interest L3 = 6% × R 1 250 000 = R 75 000  MA 1CA 1st year value Interest Year 2/ Jaar2 rente 1CA 2nd year interest  CA = 6% × (R 1250 000 + R 75 000) = R 79 500  CA 1C conversion to years (allocated since there are 3 Interest rate 3 Months /Rentekoers vir 3 maande C periods) = 6% ÷ 4 = 1,5% or 6% × 3 = 1,5% 1M dividing % value by 4 12 M (or the interest by 4) Interest 3 Months/3 Maande rente 1CA last 3 months interest = 1,5% × (R 1 325 000 + R 79 500) = R 21 067,50  CA Interest earned/ Rente verdien 1M adding the interest values M 1CA available amount = R 75 000+ R 79 500 + R 21 067,50 = R 175 567,50 CA Interest earned is not enough / not sufficient to cover the price 1O conclusion of the bakkie. O Die rente verdien is nie genoeg om die aankoopprys te dek nie OR /OF OR/OF 27 months = 2 years and 3 months or 2 1 years 1C conversion to years 4 C 27 maande = 2 jaar en 3 maande of 2 1 jaar 4 1st year value/1ste jaar waarde 1MA calculating interest  MA  CA 1CA 1st year value = R1 250 000 × 6% + R1 250 000 = R1 325 000 2nd year value/2de jaar waarde 1CA 2nd year value  CA = R1 325 000 × 6% + R1 325 000 = R1 404 500 Last 3 months/Laaste 3 maande 1M dividing % value by 4 1CA last 3 months value 6%  M  CA = R1 404 500 × + R1 404 500 = R1 425 567,50 4 1MA subtracting Difference/Verskil 1CA available amount  MA  CA = R1 425 567,50 – R1 250 000 = R175 567,50 O 1O conclusion It is not enough / not sufficient /Dit is nie genoeg nie. OR/OF OR/OF 2M multiply the principal Value the interest after 27 months/ Rentewaarde na 27 maande M  M CA C with 106 % = R1 250 000 × 1,06 × 1,06 × 1,015 – R1 250 000 1M 2nd year value 2CA 3months rate and value = R1 425 567,50 – R1 250 000 MA CA 1C conversion to years = R175 567,50 1MA subtracting 1CA available amount Not enough / not sufficient /Nie genoeg nie. O 1O conclusion (9) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 4 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L O F 1.1.5 Mistake: calc. 14% on original price AND an extra 1% on 1O reason L4 accumulated price Fout: bereken 14% op die oorspronklike EN tel 'n ekstra 1% by die totaal. Correct calculation should be 15% on original price Korrekte berekening sou wees om 15% by oorspronklike prys te tel New selling price / Nuwe verkoopsprys = R160 087,72 + 15% of R160 087,72  MA 1MA calculating 15% = R160 087,72 + R24 013,16  MA 1MA adding = R184 100,88  CA 1CA simplification OR/OF OR/OF The dealer added 1% on the VAT inclusive price of  O 1O stating the error or R182 500 / Calculating VAT on VAT the solution Die handelaar het 1% by die BTW insluitende prys van R182 500 getel/ Bereken BTW op BTW He should have calculated the 15% directly on the original selling price excluding VAT. Hy moet die 15% direk op die oorspronklike verkoopsprys sonder BTW tel New selling price inl. VAT/ Verkoopsprys BTW ingesluit A 1A 115% = 115% × R160 087,72  MA 1MA multiplying  CA 1CA simplification = R184 100,88 OR/OF OR/OF Mistake is calculating the increased 1% on the VAT inculsive amount. O 1O describing the error The 1% must be added to the original price Die fout wat hy gemaak het is om die 1% op die prys wat reeds BTW bevat uit te werk Increased price incl. VAT / Verhoogde prys met BTW 1MA calculating 1% on  MA original amount  MA 1MA adding to VAT incl. = R182 500 + R160 087,72 × 1% amount = R184 100,88  CA 1CA simplification (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 5 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L M 1.2.1 Surface area of an open box/Buite opp. van oopboks  SF L3 (a) = Width × length + 2(length × height + width × height) A 1SF Substitution = 1,374 m × 1,807 m + 2(1,807 m × 0,535 m +1,374 m × 1A correct values used 0,535 m) = 2,482818 m2 + 2 (1,701835 m2) S 1S simplification = 5,886488m2 CA 1CA total area Surface area of bin (bakkie)/Opp. van bak MCA = 5,886488 m2 + 2% × 5,886488 m2 1MCA increasing by 2% = 5,886488 m2 + 0,11772976 m2 = 6, 00421776 m2 CA 1CA simplification Or/of = 1,02 × 5,886488 m2 = 6, 00421776 m2 Number of litres required/Aantal liter benodig 6 ,00421776 m 2 1MA dividing with spread = MA 0 ,25 m 2 / rate = 24,01687104 ≈ 25 ℓ R 1R rounding up litres (8) CA from 1.2.1(a) F 1.2.1 Cost = Number of 5 litre × 2 coats × Price per 5 litre L2 (b) Koste = Aantal 5 liters × 2 lae × prys per 5ℓ  CA 1CA number of 5 litres 25 1MCA multiply 2 by price = × 2 × R549,00 MCA 5 = R5 490,00  CA 1CA cost for 10 litres OR/OF OR/OF MCA 1MCA multiply by 2 For two coats of paint = 25 × 2 = 50 litres 50  CA 1CA number of 5 litres Number of 5 litre tins = = 10 5 Cost = 10 × R5 49 = R5 490  CA 1CA cost AO (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 6 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L M 1.2.2 To protect the cargo bin's surface from scratching/rusting/ L4 being damaged.  O Om die vragbak te beskerm teen krappe/roes/beskadiging OR  O Extend the life span of a bakkie's loading box 2O reason Om die vragbak se leeftyd te verleng OR  O To stop goods from slipping/protection of goods/Om te keer dat goedere gly/beskadig word. (2) M 1.3 Time: Apply = 20 min × 2 coats = 40 min L2 Re-coat = 4 hours = 240 min C 1C converting Drying time = 2 hours = 120 min Tyd: Aanwend = 20 min × 2 lae = 40 min Wagtyd = 4 uur = 240 min Droogtyd = 2 uur = 120 min Total time needed/totale tyd benodig 1M adding times M  CA 1CA time needed = 40 min + 240 min + 120 min = 400 min = 6 hours 40 min Completion/Voltooiing = 8 h 15 + 6 h 40 = 14 h 55 1CA time ∴ Time/Tyd14:55  CA OR/OF OR/OF 1M adding times Apply 1st coat (20 min) 8:15 – 8:35  M Wend 1stelaag aan (20 min) 8:15 – 8:35 Waiting time (4 hours) 8:35 – 12:35 1MCA adding correct hours  MCA Wagtyd (4 uur) 8:35 – 12:35 Apply 2nd coat (20 min) 12:35 – 12:55 1MCA adding correct times Wend 2delaag aan (20 min) 12:35 – 12:55  MCA Drying time (2 hours) 12:55 – 14:55 Droogtyd (2 uur) 12:55 – 14:55  CA 1 CA time ∴ Time 14:55 or 2:55 p.m. or five to three in the afternoon ∴ Tyd 14:55 of 2:55 nm. of vyf minute voor drie die AO namiddag (4) [38] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 7 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 2 [38MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L  MA D 2.1.1 A = 216 329 − 227 665 × 100% 1MA subtracting correct L2 (a) 227 665 values A 1A denominator = – 4,979% A 1A negative simplification ≈ – 5%  RCA 1RCA value of A (4) 2.1.1  MCA CA from 2.1.1(a) D (b) –12 ;–5 ; –2 ; –1 ; 0 ; 2 ; 5 ; 10 ; 13 ; 13 ; 16 ; 18 ; 19 ; 40 1MCA arranging L3 5% + 10% M 1M median concept Median/Mediaan = 2 = 7,5%  CA 1CA median (3) 2.1.2 A D As the year increased the value of the imports of make-up 1A year increased L4 and skincare increased.  A 1A value increased Soos die jare aangaan, het die waarde van die invoere van grimering en versorg vermeerder. (2) 2.1.3 O D A Fr: import share increased from 2013 to 2014 , but 1A product L4 decreased in 2015. 1O reasoning RW:invoer vermeerder in 2014 vanaf 2013, maar verminder in 2015 A O 1A product Pf: import share decreased from 2013 to 2014, but increased 1O reasoning in 2015. Pf:invoer verminder in 2014 vanaf 2013, maar vermeerder in 2015. (4) 2.1.4  O O D No. Too many sectors and one pie chart cannot be used as L4 different years need to be shown. Nee. Teveel sektore om op een sirkeldiagram te toon omdat verskillende jare getoon moet word. OR/OF 1O No O O 1O reason No. Too many sectors/columns; some are too small /negligible. Nee. Te veel sektore/kolomme; sommige is te klein. OR/OF O O No. Negative values will be difficult to indicate. Nee. Negatiewe waardes maak dit moeilik. O OR/OF  O No. Percentages do not add up to 100%. Nee. Persentasies tel nie op tot 100% nie. (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 8 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L D 2.1.5 L3 Percentage imports and average growth of Personal Care and Cosmetics to Australia 50 % Share of 2015… 40 A 30 20 Percentage A 10 0 A A A EO Fr /RW Pf MSC/GV HC/ HP OD / MD CT / KT S A -10 -20 Products 1A first point 1A last point 3 × 1A Every other two points correctly plotted 1A Joining (6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 9 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L F 2.2.1 Total cost = Basefare+ 10 × cost per mile L2 Totalekoste = Basisfooi + 10 × koste per myl  RT  RT 2RT using correct values = $20,00 + 10× $5,00 per mile = $70,00  CA 1CA value of B if only 1 value is incorrect (3) F 2.2.2 Maximum distance (in miles)/Maksimum afstand(in myl) L3 1RT reading correct values $4,65  RT = from table $0,90 M 1M dividing = 5,166…  CA 1CA simplification ≈5 R 1R rounding (4) F 2.2.3 1 hour 9 minutes = 69 minutes  C 1 C converting to minutes L4 1 uur 9 minute = 69 minute Post trip cost/Na-ritkoste 1SF substituting correct SF = 69 min × $0,45 / min + 29,73 mi × $3,55 /mi values =$31,05+ $105,5415  S 1S simplification = $136,59  CA 1CA post trip cost Upfront cost/Vooruit koste 1SF substituting correct = $8 + 29,73mi × $3,55/mi SF values = $113,54  CA 1CA upfront trip cost Difference = $136,59 – $113,54 = $23,05  S 1S difference The statement is correct/Die stelling is korrek. O 1O conclusion OR/OF OR/OF Difference = Post trip cost – Upfront cost Verskil = Na-ritkoste – Vooruit koste 1C time to minutes C SF SF 1SF values into 1st formula = 69 min × $0,45 / min + 29,73 mi × $3,55 /mi – ($8 + 1SF values into 2nd formula 29,73mi × $3,55/mi) = 69 min × $0,45 / min – $8 S 3S simplification = $23,05  CA 1CA difference The statement is correct/Die stelling is korrek. O 1O conclusion (8) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 10 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L  O F 2.2.4 To cover cost for idle/wasted time when a vehicle could have L4 been used to assist someone when you cancel the booking. Om kostes te dek vir verlore tyd terwyl die voertuig gebruik kon word om iemand anders te help wanneer jy die bespreking kanselleer. OR/OF Penalty for booking made if one does not finally use the vehicle (time wasting).  O Boete vir'n bespreking wat gemaak is as jy aan die einde nie die voertuig gebruik nie(vermorsing van tyd) 2O reasoning OR/OF Prevent hoax calls/ Verhoed fopoproepe  O OR/OF To cover petrol costs and wear and tear of the vehicle  O Om petrol- en slytasiekoste van die voertuig te dek. OR/OF For the company to make a profit / avoid losses  O Vir die maatskappy om 'n wins te maak/ verhoed verliese (2) [38] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 11 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 3 [39MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L P  4 A 1A numerator 3.1.1 P (Coke & water) =   L2  9 A 1A denominator 1CA decimal number = 0,44 CA NPR (3) MP 3.1.2 South East OR East of South OR SE. A 2A direction L2 Suidoos OF Oos van Suid OF SO (2) MP A 3.1.3 The start is at 1 400 m running to 1 565 m at the 5 km mark 1A for height 1 400 m L4 (a) and then 1 708 m at the 10 km mark. A 1 A for height 1 708 m Die begin is by 1 400m, by die 5km merk is dit 1 565 m en dan 1 708 m by die 10km merk. [Accept increase in height above sea level/altitude] (2) MP 3.1.3 Lowest point : highest point/Laagste punt: hoogste punt L2 (b)  RT RT 2RT correct values = 1 166 m : 1 708 m = 1 : 1,464837...  CA 1CA ratio ≈ 1 : 1,46 or 1 : 1,5 NPR (3) 3.1.4 To take struggling runners out of the race because they are MP not coping.  O L4 Om hardlopers wat sukkel uit die wedren te haal omdat hulle nie die mas opkom nie. OR  O Security reasons (guards and health personnel deployed in strategic sections along the race course during specific times). Veiligheidsredes(wagte en noodhulppersoneel word ontplooi in sekere gedeeltes van die wedren vir spesifieke tye) OR/OF  O 2O understanding/reason For runners to know whether they have a realistic chance of finishing race within the time allowed for the race. Sodat deelnemers weet of hulle 'n realistiese kans het om die wedren binne die toegelate tyd te voltooi. OR/ OF  O Also helps organisers to plan appropriately for other scheduled events. Dit help ook die organiseerders om te beplan vir ander geskeduleerder items soos medalje- en perskonferensies. OR/ OF If the road was closed it needs to be opened.  O (2) Indien die pad gesluit was, moet weer oopgestel word. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 12 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L The average speed required to beat the cut-off 2: MP 3.1.5 Die gemiddelde spoed nodig om afsny 2 te haal: L4 1RT correct values (dist. & 31,5km RT time) Speed/Spoed(marathon) = 1M calculating speed / 5h15min M change the subject = 6 km/h CA 1CA simplification 16,5km Speed/Spoed(½ marathon) = MA 5h 1MA calculating speed = 3,3 km/h CA 1CA 2nd speed O The claim is correct (6 – 3,3 = 2,7 km/h). 1O conclusion Die bewering is korrek. OR/OF OR/OF M 1M calculating speed / Speed/Spoed(½ marathon) = 16,5 km ÷ 5h = 3,3 km/h CA change the subject 1CA simplification Increased speed for full marathon = (3,3 + 2,7) km/h = 6km/hMA MA 1MA calculating incr. speed Distance = 6 km/h × 5,25h = 31,5 km CA 1MA calculating distance 1CA distance Correct/Korrek O 1O conclusion OR/OF OR/OF M 1M calculating speed / Speed/Spoed(½ marathon) = 16,5 km ÷ 5h = 3,3 km/h CA change the subject MA Increased speed for full marathon = (3,3 + 2,7) km/h = 6km/h 1CA simplification MA 1MA calculating incr. speed 31,5km CA Time to cut-off = = 5,25 h 1MA calculating time 6km/h 1CA time Correct/Korrek O 1O conclusion (6) M 3.2.1 20 ℓ = 20 × 1 000 cm 3 C 1C conversion L3 Inner diameter /Binneste middellyn = 31,2 cm – 2 × 0,2 cm 1A calculating inner = 30,8 cm A diameter  MCA2 V = 3,142 × (30,8cm ÷ 2) × height/hoogte 1MCA radius  SF 3 30,8 1SF correct values 20 000 cm = 3,142 × ( cm)2 × H 2 20 000 cm 3 1M changing the subject H = M 3,142 × 237,16cm 2 20 000 1S simplification = cm  S 745,15672 = 26,84 cm  CA 1CA height (7) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 13 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L M 3.2.2 Area of base of 1 bucket/Oppervlakte van 1 emmer basis L3 (a) A 1A radius = 3,142 × (15,6 cm)2 = 764,63712 cm2  CA 1CA simplification Area of base of 11 buckets/Oppervlakte van 11 emmers = 11 × 764,63712 cm2 = 8 411,00832 cm2  CA 1CA multiply by 11 Area of base of pallet/Oppervlakte van palletbasis  SF 1SF correct values = 100 cm × 120 cm = 12 000 cm2  A 1A rectangular area Difference/Verskil = 12 000 cm2 – 8 411,00832 cm2 = 3 588,99168 cm2  CA 1CA area unused NPR (6) A M 3.2.2 120 cm = 31,2 × 3 + C 1A 120 cm L4 (b) C = 120 cm – 31,2 cm × 3  M 1M multiplying and subtracting = 26,4cm  CA 1CA finding C (3) MP 3.2.3 Length occupied by 4 buckets/Lengte van 4 emmerbasisse L3  MA 1MA multiplying A = 4 × 31,2 cm = 124,8 cm 1A correct length Length should be increased by/Lengte moet vermeerder met CA 1CA substituting 124,8 − 120 1M % change = × 100% M 120 = 4%  CA 1CA simplification OR/OF OR/OF Length occupied by 4 buckets/Lengte van 4 emmerbasisse 1MA multiplying  MA A = 4 × 31,2 cm = 124,8 cm 1A correct length 120 cm is 100% 124,8  M 1M multiply with 100% 124,8 cm is ×100% = 104% CA 1CA simplification 120 ∴ 4% increase  CA 1CA simplification (5) [39] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 14 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 4 [35 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.1.1 F Total for these capsules/totaal vir hierdie kapsules 3MA multiply tickets L4  MA  MA MA  MA by price = 23 × £27 + 5 × £27 × 90% + 8 × £22 + 7 × £25,50 2MA discount for 5 = £621 + £121,50 + £176 + £178,50 1CA total for 2 capsules = £1 097  CA Rand value/waarde = £1 097 × R16,58/ £ 1C pounds to rand = R18 188,26 C 1O conclusion O ∴ the statement is not correct/die opmerking is niekorrek nie OR/OF OR/OF Without discount for 5/sonder afslag vir 5 3MA multiply tickets by MA  MA price = 28 × £27 + 8 × £22 + 7 × £25,50  MA = £756 + £176 + £178,50 1CA simplification = £1 110,50  CA Discount for 5/Afslag vir 5 = 5 × £27 × 10% = £13,50 A 1A discount Total ticket price/Totale kaartjie prys = £1 110,50 – £13,50= £1 097  CA 1CA total Rand value/waarde = £1 097 × R16,58 /£ = R18 188,26 C 1C pounds to rand O 1O conclusion NOT correct/NIE korrek NIE OR/OF OR/OF Cost of Capsule 24 + Cost of Capsule 30 – Discount for 5 2MA multiply tickets by Adults price  MA M 1M adding costs (18 × £27 + 7 × £22 + 2 × £25,50) +  MA A 1A discount (10 × £27 + 1 × £22 + 5 × £25,50) – 5 × £27 ×10% =  CA 1CA simplification £691 + £419,5 – £13,5 = £1097  CA 1CA total Rand value/waarde 1C pounds to rand = £1 097 × R16,58 /£ = R18 188,26 C NOT correct/NIE korrek NIE  O 1O conclusion Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 15 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L OR/OF OR/OF Ticket price in rand: Adult: 27 × 16,58 = R447,66 1C conversion C Children: 22 × 16,58 = R364,76 Senior citizens: 25,5 × 16,58 = R422,79 1A discount Discount adult = R44,77  A Online ticket price = R402,89  MA  MA Total price = (23 × R447,66) + (5 × R402,89) + 4×1MA multiply tickets by  MA  MA price (8 × R364,76) + (7 × R422,79) = R18 188,24  CA 1CA total NOT correct/NIE korrek NIE O 1O conclusion (8) M 4.1.2 Circumference of the wheel/Omtrek van die wiel L2 (a) = 2× π × radius 1SF correct values = 2 × 3,142 × 197  SF = 1 237,948 feet/voet  CA 1CA circumference NPR (2) CA from 4.1.2(a) M 4.1.2 1 237,948 Distance/Afstand = feet/voet  MA 1MA dividing by 32 L2 (b) 32 = 38,685875 feet/voet 38,685875 1C conversion = m C 3,28 1R rounded distance = 11,794…m ≈ 11 m  R [also accept 12m] OR/OF OR/OF Circumference in metre/Omtrek in meter 1 237,948 = = 377,4231707m  C 1C conversion 3,28 Distance apart/afstand tussen kapsules 377,4231707 =  MA 1MA dividing by 32 32 = 11,794....m ≈11 m R 1R rounded distance (3) M  RT D 4.2.1 Difference/Verskil = 624 000 – 312 600 1RT correct values L2 1M subtraction  CA = 311 400 or/of 311,4 thousand/duisend 1CA difference in thousands (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 16 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L P 609 600 + 295 000 RT 1RT numerator & L3 4.2.2 P (Midlands West & East) = × 100% 7 146 600 denominator S 904 600 1S simplification = × 100%  M 1M multiply by 100% 7 146 600 = 12,65776….% 1CA probability NPR ≈ 12,66% CA AO (4) D 4.2.3 1 157,0  RT L4 Ratio/Verhouding = 378,3 1RT values CA = 3,0584 1CA simplification ∴ The statement is valid/Die bewering is geldig. O 1O conclusion OR/OF OR/OF Number of business visitors = 378,3 thousand And holiday visitors= 1 157 thousand  RT CA 1RT values 378,3 thousand × 3 = 1 134,9 thousand 1CA simplification 378,3 duisend × 3 = 1 134,9 duisend ∴ The statement is valid/Die bewering is geldig. O 1O conclusion OR/OF OR/OF  RT CA 1RT values 1 157 000 ÷ 3 ≈ 385 667 1CA simplification O ∴ The statement is valid/Die bewering is geldig. 1O conclusion [No penalty for omitting thousand] (3) D 4.2.4 175,1 324,8 405,7 480,5 562,7 600,8 1MA order, ascending or L3  MA descending 762,6 806,8 856,2 1594,0 3 556,0 A Q 1 /K 1 = 405,7 Q 3 /K 3 = 856,2 A 2A Q 1 and Q 3 M IQR/IKO = (856,2 – 405,7) × 1 000 1M subtracting quartiles = 450,5 × 1000 1CA IQR value [No penalty for omitting = 450 500 CA thousand] (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 17 DBE/November 2018 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L 4.2.5  O D Tourism boosts the economy (selling and buying) of the 2O reason financial L4 country. Toerismeversterk die ekonomie (koop en verkoop) van die land. OR/OF Tourism assists people to know the places they want to visit and be prepared/ exposes the goods and services of a country  O 2O environmental reason Toerisme help mense om die plekke wat hulle besoekte ken en om voor te berei/land se goedere en dienste kry blootstelling OR/OF Brings income to the country and more tourist stimulate the economy. / GDP grows. 2O economic reason  O Dit bring ekstra inkomste na die land en meer toeriste stimuleer die ekonomie./ BBP groei. OR/OF Help to promote Social and Cultural interaction.  O 2O humanitarian reason Bevorder sosiale en kulturele interaksie. (2)  M 1M multiplying with 11 D 4.2.6 Total = 162 666,5455 × 11 ≈ 1 789 332  R 1R rounding L4 Known data total = 471 928 + 170 113 + 119 639 + 107 230 + 76 496 + 120 343 + 179 450 + 226 003 + 172 282 1A known total = 1 643 484  A Wales = NE + 30 440 NE + NE + 30 440 + 1 643 484 = 1 789 332  MA 1MA two unknowns 2NE = 115 408 NE = 57 704  CA 1CA simplification OR/OF OR/OF Mean value/Gemiddelde waarde  M North East/Noordoos + Wales/Wallis + other / ander 1M concept of mean = 11  MA NE + NE + 30 440 + 1 643 484 1MA two unknowns = 162 666,5455 11  S 1S simplification 2NE + 1 673924 = 1 789 332,001 2 NE 115 408,001 = 1M dividing by 2 2 2 M NE= 57 704,00025 Direct employment of North East = 57 704 R 1R rounding Direkte werksgeleenthede van Noordooste = 57 704 (5) [35] TOTAL/TOTAAL:150 Copyright reserved/Kopieregvoorbehou