MATHS LIT P1 GR12 MEMO SEPT2016 ENG hlayiso.com

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 SEPTEMBER 2016 MATHEMATICAL LITERACY P1 MEMORANDUM MARKS: 150 Symbol Explanation M Method A Accuracy CA Consistent accuracy RT/RG/RM Reading from a table/Reading from a graph/Read from map RP Reading from the plan SF Substitution in a formula S Simplifications P Penalty (no units, incorrect rounding off etc.) O Opinion J Justification R Rounding NPR No Penalty for Rounding This memorandum consists of 8 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (EC/SEPTEMBER 2016) QUESTION 1 Quest. Solution Explanation Marks 1.1.1 South African Revenue Services  2A (2) 1.1.2 15 years 9 months  1 A 15 years 9 months = 15 x 12 + 9  1M Conversion to months = 189 months  1 CA (3) 1.1.3 Five hundred and six thousand  2A In words Four hundred and seventy four rand  (2) 1.1.4 R122 138,71 – R104 227  1A Correct values 1M Subtraction: = R17 911,71  1CA (3) 1.1.5 122 138,71 : 506 474  2M Ratio of Correct 1 : 4,15  Values 1A (3) 1.1.6 R631,94  2RT (2) 1.1.7 R 6 3 1, 9 4  1M Correct Values 110% 1M dividing by 110% 1CA = R574,49 x 12  1M x12 = R6 893,89  1CA (Accept 6893,88) OR R631,94 x 𝟏𝟏𝟎  𝟏𝟎 1M Multiplying by the fraction = R57,45  1S R631,94 – R57,45  1M subtraction = R574,49 x 12  1M Multiply by 12 = R6 893,89  1CA OR 1M Multiply 100 𝑹631,94 x 100  1M Denominator 𝟏𝟏𝟎 = R574,49  x 12  1CA for R574,49 1M multiply by 12 = R6 893,89  1CA (5) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/SEPTEMBER 2016) MATHEMATICAL LITERACY P1 3 1.2.1 $225 + $200 + $175 + $50  2A Adding all the = $650 values (2) 1.2.2 $175 x 100  1M dividing by $650 $650 and multiply by 100 = 26,9%  1CA = 27%  1CA (3) 1.2.3 500 x $15,00  1M identifying 500 and $15,00 = $7 500  1A (2) 1.2.4 7500 x 15,409095  1M multiplying by R15,409095 = R115 568,2125  1S = R115 568,21  1 CA (two decimal places) (3) 1.2.5 $200  1M for 200 500 = $0,4  1CA (2) 1.2.6 1 April 2016 – 30 April 2016  2 RT (2) [34] Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (EC/SEPTEMBER 2016) QUESTION 2 Quest. Solution Explanation Marks 2.1.1 V = 𝜋𝑟 2 h  1A converting radius = 3,142 x (2,5 cm)2 x 12,5 cm  1SF = 245,47 cm3  1CA answer 1 unit NPR (4) 2.1.2 5 000 𝑐𝑚3 No. of candles = 1M for 5 000 245,47 𝑐𝑚3 = 20,4  1M = 20 candles  1CA answer (3) 2.1.3 Candle weight = density x volume = 0,93g/cm-3 x 245,47 cm3  1SF = 228,29 g  1M using 245,47 cm3 1CA answer NPR (3) 2.1.4 TSA = 2 x (2,6 x 2,8) + 2 x 6,1(2,6 + 2,8)  1SF = 2(7,28) + 12,2 x (5,4)  1S = 14,56 cm2 + 65,88 cm2  1S = 80,44 cm2  1CA answer OR 𝑇𝑆𝐴 = 2𝑥(𝑙 x 𝑤) + 2(𝑙 x ℎ) + 2(𝑤 x ℎ) 2 SF = 2(2,8 x 2,6) + 2(2,8 x 6,1) + 2(2,6 x 6,1)  1S = 2(7,28) + 2(17,08) + 2(15,86)  1CA answer = 14,56 + 34,16 + 31,72 = 80,44 cm2  (4) 2.1.5 Diameter = 2,5 × 2 = 5 cm  1M diameter 15 1M length candles No. of candles along the length = 5 = 3 15 No. of candles along the width = 5 = 3  1M width candles Total number of candles for the first layer 1CA Check 2.1.1 for =3×3 =9 radius (4) 2.1.6 (a) 312℉  2RD (2) (b) ℃ = (312° − 32°) ÷ 1,8  1SF = 280° ÷ 1,8  1S = 155,6 ℃  1A penalise if ℉ is Accept 155,56 ℃ written in the answer (3) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/SEPTEMBER 2016) MATHEMATICAL LITERACY P1 5 2.2.1 2,3 m – 0,25 m  1M Conversion to metre = 2,05 m  1M subtraction 1 CA answer (3) 2.2.2 𝐴=𝑙𝑥𝑤 12 m2 = (2,3m +1,7m) x w  1M adding 1,7 12 m2 = 4 m x w  1M dividing by 4 4m 4m 3m =w 1A (3) [29] QUESTION 3 3.1.1 North east  2A (2) 3.1.2 1 : 75  2RP (2) 3.1.3 9 𝑐𝑚 𝑥 75 1M 𝐿𝑒𝑛𝑔𝑡ℎ = 100  1A answer for length = 6,75 m 1A answer for width Width = 1,3 x 75 ÷ 100 = 0,975 m = 1 m  (3) 3.1.4 2M Drawing  (2) 3.1.5 15  2RP (2) 3.1.6 7  1M numerator 16  1M denominator (2) 3.2.1 4  2RD (2) 3.2.2 From the reception go straight along the 3RD orchard and turn right,  then go down pass the playground and turn leftand go straight you will get 11b.  (3) 3.2.3 7  2RD (2) 3.2.4 9  2RD (2) 3.2.5 Table tennis OR Pool table  2RD any facility (2) [24] Copyright reserved Please turn over

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (EC/SEPTEMBER 2016) QUESTION 4 Quest. Solution Explanation Marks 4.1.1 Av weight = 1M 92+94+96+98+102+108+110+112+115+116+117+120×2+125 1S  14 1CA 1 525 =  14 = 108,93 kg  (Accept 108,929) (3) 4.1.2 1 569  2A (2) 4.1.3 186 cm  2A (2) 4.1.4 Interval Tally Frequency 1x5=5 0− 30 //// / 6  31−60 //// //// 10  61−90 //// // 7  91−120 /// 3  121−150 // 2  1 Mark (both Tally and Frequency) x 5 = 5 (5) 4.1.5 Probability is the chance or likelihood of an event 2M Definition happening.  (2) 4.1.6 4 × 100  1 M Fraction 28 multiply by 100 = 14,3%  1CA (2) 4.1.7  1 Mark per correctly plotted bar joined to an existing one Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/SEPTEMBER 2016) MATHEMATICAL LITERACY P1 7 4.1.8 (a) 1 , 2 , 2 , 4 , 10 , 19 , 20 , 38  1M Correct values = 14  1M 2 = 7 1CA (3) (b) Range = 64 – 1  1Correct values = 63  1M Subtracting 1A (3) (c) Line graph  2A (2) 4.2.1 White  2A (2) 4.2.2 A = 41 000 938 +4 586 838 +4 615 401+1 286 930+280 454  1M Adding = 51 770 561  1A (2) 4.2.3 Whites and Coloureds  2A (2) 4.2.4 Indian / Asian  2A (2) 4.2.5 B + B+ 79,2 + 2,5 + 0,5 = 100% 1M Adding to = 100% – 82,2 make 100 2B = 17,8 1S value of B = 8,9% 2B 1A OR OR 4 586 838 4 615 5401  x 100%  x 100%  51 770 561 51 770 561 1M fraction = 8,859 = 8,915 with correct = 8,9%  = 8,9%  Values 1M multiply by 100 1A (3) [40] QUESTION 5 Quest. Solution Explanation Marks 5.1.1 Panado Medical Centre  2RT (2) 5.1.2 R24,46  2RT (2) 5.1.3 R89,80 – 24,46 1M Subtraction = R65,34  1A (2) 5.1.4 R38,91  2RT (2) Copyright reserved Please turn over

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P1 (EC/SEPTEMBER 2016) 5.1.5 R24,46 +R309,70 + R108,49 +R38,91 +R13,10 + R5,02  1M Adding = R499,68  1A (2) 5.1.6 Pain located in other parts of the lower abdomen.  2 RT (2) 5.1.7 R13,10 x 14%  1M = R1,83 + R13,10  1Adding = R14,93  1A OR R13,10 x 114%  = R14,93  (3) 5.1.8 60 days  1M = 2 months  1CA ( give a mark if answer is 30 days only) (2) 5.2.1 Morning + Evening (10 𝑚ℓ + 15 𝑚ℓ + 10 𝑚ℓ +10 𝑚ℓ + 15 𝑚ℓ + 10 𝑚ℓ)  1M = 70 𝑚ℓ 1CA OR (10 𝑚ℓ x 4) + (15 𝑚ℓ x 2)  = 40 𝑚ℓ + 30 = 70 𝑚ℓ  (2) 5.2.2 10 𝑚ℓ + 10 𝑚ℓ  1M = 20 𝑚ℓ  1A OR 10 𝑚ℓ x 2  = 20 𝑚ℓ  OR 100 𝑚ℓ – (20 𝑚ℓ x 4)  = 100 𝑚ℓ – 80 𝑚ℓ = 20 𝑚ℓ  OR 100 𝑚ℓ – (10 𝑚ℓ x 8)  = 100 𝑚ℓ – 80 𝑚ℓ = 20 𝑚ℓ  (2) 5.3. 60 3 2A  = 5 (2) 100 [23] TOTAL: 150 Copyright reserved Please turn over