MATHS LIT P1 MEMO GR12 SEPT 2014 ENG FINAL hlayiso.com

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 SEPTEMBER 2014 MATHEMATICAL LITERACY P1 MEMORANDUM MARKS: 150 Symbol Explanation M Method A Accuracy CA Consistent accuracy RT/RG/RM Reading from a table/Reading from a graph/Read from map SF Substitution in a formula P Penalty, e.g. for no units, incorrect rounding off etc. This memorandum consists of 8 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (SEPTEMBER 2014) QUESTION 1 (Answer only FULL marks) Question Solution Explanation 1.1 1.1.1 2013 – 1978 √ 1M = 35 years √ 1A (2) 1.1.2 16th, 25th and 26th = R35 x 24 2M = R840 √ 1CA = +R19 x 8 x 17,50 800 √√ 1M = R2 660 + R840 √ 1S = R3 500 √ 1CA OR 17,50 x 19 x 8 + 3 x 35 x 8) √ 2 660 + 840 √ = R3 500,00 √ (3) 1.1.3 R2 660 x 5% √ 1M = R133,00 √ 1CA (If the answer used is in 1.1.2) (2) 1.2 1.2.1 R5 000 – R2 500 √ 1M = R2 500,00 √ 1A (2) 1.2.2 R5 000 x 6 + R1 000 √ 1M = R30 000 + R1 000 = R31 000,00 √ 1A (2) 1.3 1.3.1 C = 10 000 √ + 2 500 x n √ 2A 1 Mark each correct value (2) 1.3.2 A = R5 000 x 2 √ 1M = R10 000 √ 1A (2) B = R10 000 + R2 500 x 6 √ 1M = R25 000√ 1A (2) 1.3.3 (4, 20000) √√ 2A -RT (2) Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) MATHEMATICAL LITERACY P1 3 1.3.4 (0,0) – 1 mark any point – 1 mark income line graph correctly plotted (0,10000) – 1 mark any point – 1 mark Expenses line graph correctly plotted (4) 1.4 1.4.1 A = R140 x 12% 1M = R16,80 √ = R140 + R16,80 = R156,80 √ 1A OR R140 x 1,12% √ 1M = R156,80 √ 1A (2) – 1SF √ SF = x 100%√ 1S = 10,4999% = 10,5 % √ 1A C = R140 + R231,99 + R170,86 + 1M R630,50 + + R380,98 √ 1A = R1 554,33 √ (3) OR C = R1 771,94 – R217,61√ 1M = R1 554,33√ 1A (2) Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (SEPTEMBER 2014) 1.5.1 Interest 1st year Answer ONLY full = R5 000,00 x √ marks (Whole 1.5 = R375,00 √ QUESTION) OR = 5 000 x 0,075 √ 1M = R375 √ 1A (2) 1.5.2 R5 000,00 + 3 x R375 √ 1M = R6 125,00 √ 1A (2) 1.5.3 √ 1M = R170,40 √ 1A (2) [36] QUESTION 2 Question Solution Explanation Marks 2.1 2.1.1 √√ 2A (2) 2.1.2 R4 950 x 6 2A (2) = R29 700 √√ 2.1.3 Area of a tank 1Correct = 3,142 (130 cm)2 √ radius = 53 099,8 cm2 √ 1A (2) 2.1.4 V= h 1M- = 3,142 x (1,3 m)2 x 4,18 m √√ conversion = 22,19 m3 √ 1S,1CA – when cm used (3) 2.1.5 22,2 x 1 √ 1SF = 22 200 ℓ √ 1A (2) 2.1.6 per day per household √ 1D 1S = 0,3 kℓ per day per household 1A There are 18 households per tank of 22,2 kℓ = 18 household need 18 x 0,3 kℓ per day = 5,4 kℓ = 1 tank will lose 5,4 kℓ per day Then = = 4,11 days Therefore each tank will last for 4 days (3) Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) MATHEMATICAL LITERACY P1 5 2.2 2.2.1 2 kg = 2 000 grams √√ 2A (2) 2.2.2 °F = (1,8 x °C) + 32° 1SF = (1,8 x 180) + 32° √ 1A = 356° √ (2) 2.2.3 05:30:56 + : √ 1M : : √ OR 1A 5h:55min:56 sec (2) 2.2.4 √ 1M 1S = 46,5 √ 1A = 47 trays √ (3) 2.3 2.3.1 Accept weight between 2A 61 kg – 83 kg √√ Accept OR 135 lbs – 183 lbs √√ (60 kg – 83 kg) (2) 2.3.2 √ 1SF, 1S, 1CA k (Giving = √ answer = 45,4 kg/m2 √ without squaring the height) (3) 2.3.3 Obese √√ 2A (2) [55] QUESTION 3 Question Solution Explanation 3.1 3.1.1 Aquarium √√ 2A-RM (2) 3.1.2 N2 √√ 2A-RM (2) 3.1.3 50 000 x 8 √ 1M = 400 000 cm/100 000 √ 1C = 4 km √ 1A (3) 3.1.4 Summerpride √√ Cambridge/Cambridge West √√ (Any one) 2A (2) 3.2 3.2.1 5 √√ 2A-RP (2) 3.2.2 5 √√ 2A-RP (2) 3.2.3 Area = Length x breadth √ 1F = 3,55 m x 3,55 m √ 1C = 12,60 m2 √ 1A (3) Copyright reserved Please turn over

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (SEPTEMBER 2014) 3.2.4 √ = 11,46 = 12 boxes √ 1M 1A (2) 3.2.5 12 x R94,99 + R60 x 12,60 √ 1M = R1 139,88 + R756 √ 1S = R1 895,88√ 1A (3) 3.2.6 Elevation plan is a cross section plan √ from 2A correct different directions or sides of a building. √ explanation (Accept any correct explanation.) (2) [23] QUESTION 4 Question Solution Explanation Marks 4.1 4.1.1 51,54,55,56,56,56,58,63,65,71,72,73 √√ 2A 1 max mark when one number is missing (2) 4.1.2 √ 2M 1A = √ = 60,8 √ (3) 4.1.3 √ 2A = = 60,5 √ OR 46,52,52,58,59,62,63,63,64,66 121 ÷ 2 √ 1M = 60,5 √ 1A (2) 4.1.4 √ = = 57 √ 2A (2) 4.1.5 1S = √ = OR 25% √ 1A (3) 4.1.6 56 and 63 √√ 2A (2) 4.2 4.2.1 2007 √√ 2RT (2) 4.2.2 24,4% √√ 2RT (2) Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) MATHEMATICAL LITERACY P1 7 4.2.3 13,1 million √√ OR 13 100 000 √√ 2A (2) 4.2.4 13,1 million x 24,3% √ 1M = 3,1833 million 1A = 3,18 million √√ OR 3 183 300 1 Unit (3) 4.3 4.3.1 January 31 √√ 2A (2) 4.3.2 June or July √√ 2A (2) 4.4 4.4.1 R9 387,00 + R400,00 + R2 200,00 √ 1M = R11 987,00 √ 1A (2) 4.4.2 √ = 79 513,56408 $√ 1M 1A (2) 4.4.3 200 x R11,217 √ 1M = R2 243,40 √ 1A (2) 4.5 4.5.1 101 √√ 2A (2) 4.5.2 90 – 82 √ = 8 √ 2A (2) 4.5.3 Class B √ 2A (2) [39] QUESTION 5 Question Solution Explanation Marks 5.1 5.1.1 √ 2A + R82 for accommodation + R75 – food = R442,00 per child √ (2) 5.1.2 R25 x 32 √ + R23 √ 2M = R823,00 √ 1A (3) 5.2 5.2.1 13 686 – 11 246 √ 1M = 2 440 √ 1A (2) 5.2.2 The results are improving. √√ 2A (2) Copyright reserved Please turn over

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P1 (SEPTEMBER 2014) 5.2.3 Eastern Cape Results 2012–2013 25 000 20 000 Number of learners 15 000 10 000 2012 2013 5 000 0 Distinctions Bachelor Diploma Higher passes passes Certificates Matric pass categories 1 mark for correct graph 1 mark for each pair of bars correctly plotted. (4 marks) (5) 5.3 R399,00 x 5% 1M = R19,95 √ R399,00 – R19,95 = R379,05 √ 1A (2) 5.4 x √ 1M = R25,57 √ 1A (2) 5.5 5.5.1 √ %√ 2A (2) 5.5.2 √= √ Accept 73,68% 2A (2) [22] TOTAL: 150 Copyright reserved Please turn over