Physical Sciences Grade 12 Paper 1 North West Mock 2019 Memo

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 PHYSICAL SCIENCES: PHYSICS (P1) FISIESE WETENSKAPPE: FISIKA (V1) SEPTEMBER 2019 MEMORANDUM MARKS/PUNTE: 150 This memorandum consists of 7 pages./ Hierdie memorandum bestaan uit 7 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 2 NW/September 2019 NSC/NSS – Memorandum QUESTION 1/VRAAG 1 1.1 A 1.2 C 1.3 C 1.4 B 1.5 D 1.6 A 1.7 B 1.8 C 1.9 A 1.10 D [20] QUESTION 2 2.1 A body will remain in its state of motion (at rest or moving at constant velocity) until a net force acts on it. /'n Liggaam sal in sy toestand van beweging (in rus of beweging teen konstante snelheid) volhard, totdat 'n netto krag daarop inwerk. (2) 2.2 The two surfaces gliding across each other are the same (rubber and gras) /Die twee oppervalktes wat oor mekaar gly is dieselfde (rubber en gras) (2) 2.3.1 FN/N – Normal/Normaal Fg /f – friction/wrywing T – Tention w/Fg – weight/gewig (4) 2.3.2 fk = µk · N fk = 0,6(15)(9,8) fk = 88,2 N (3) 2.3.3 + marking from/nasien van 2.3.2 FNet = ma = 0 For B: T = fk ∴T = 88,2 N For A: Fx = T + fk F·cos 14o = 88,2 + 0,6·10·9,8 F = 151,5 N (6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 3 NW/September 2019 NSC/NSS – Memorandum 2.4 2.4.1 + marking from/nasien van 2.3.2 FNet = ma 88,2 = 15·a a = 5,88 m·s-2 (2) 2.4.2 The work done on an object by a net force is equal to the change in the object's kinetic energy /Die arbeid verrig op 'n voorwerp deur 'n netto krag is gelyk aan die verandering in kinetiese energie van die voorwerp. Or/of The net work done on an object by a force is equal to the change in the object's kinetic energy /Die netto arbeid verrig op 'n voorwerp deur 'n krag is gelyk aan die verandering in kinetiese energie van die voorwerp. (2) 2.4.3 + marking from/nasien van 2.3.2 W net = ΔK = Kf - Ki -88,2·Δx = ½·15·0 – ½·15·82 Δx = 5,44 m (4) [25] QUESTION 3 3.1 Only force acting on the object is gravitational force(gravity) /Die enigste krag wat op die voorwerp inwerk is gravitasie krag. (2) 3.2 v = v + 2·a·Δy Take downwards as + 312 = 0 + 2·9,8·Δy Δy = 49,03 m (3) 3.3 Wnet = m·a·Δx·cos Ө = ΔK = Kf - Ki = = ½·m·v – ½·m·v 80·a·10·cos 180o = ½·80·252 – ½·80·0 a = - 31,25 m·s -2 (4) 3.4 + marking from/nasien van 3.2 Δy = 75 – 49,03 – 10 = 15,97 m Δy = v ·Δt + ½ ·a·Δt2 15,97 = 0 + ½ ·9,8·Δt2 Δt = 1,81 s (5) 3.5 v = v + a·Δt 25 = 0 + 31,25·Δt Time in free fall = 1,81 – 0,8 Δt = 0,8 s (Time for 10 m) = 1,01 s Δy = v ·Δt + ½ ·a·Δt2 Δy = 25·1,01 + ½ ·-9,8·1,012 Δy = 20,25 m Δy of John from the ground = 15,97 + 20,25 + 10 = 46,22 m (6) 3.6 P = F·v = 80·9,8·2 = 1568 W (3) [23] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 4 NW/September 2019 NSC/NSS – Memorandum QUESTION 4 4.1 The product of the net force (acting on an object) and the time the (net) force acts (on the object) /Die produk van die netto krag wat op 'n voorwerp inwerk en die tyd wat die netto krag op die voorwerp inwerk. (2) 4.2 p before p after m ∙v m ∙v m m ∙v 100·5 + 65 ∙0 = (100 + 65) vf vf = 3,03 m ∙s-1 In same direction as the original direction of boat (5) 4.3 FNET ∙Δt = Δp FNET ∙0,2 = 165 (0 – 3,03) FNET = - 2499,75 FNET = 2499,75 N in opposite direction as boat (4) [11] QUESTION 5 5.1. v = λ ∙f 340 = λ ∙384 λ = 0,89 m (3) 5.2. Longer /Langer (1) 5.3. Remains the same /Bly dieselfde. (1) 5.4 Towards /Na (1) 5.5 fL = ∙fs fL = ∙384 (fL become/word fs) 391 = ∙ ∙384 (vL = v s) 391 = ∙ ∙384 -1 v = 13,55 m∙s (Range: 13,50 – 13,70) (6) [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 5 NW/September 2019 NSC/NSS – Memorandum QUESTION 6 6.1 The magnitude of the electrostatic force exerted by one point charge (Q1) on another point charge (Q2) is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance (r) between them /Die grootte van die elektrostatiese krag wat een puntlading (Q1) op 'n ander puntlading (Q2) uitoefen, is direk eweredig aan die produk van die groottes van die ladings en omgekeerd eweredig aan die kwadraat van die afstand (r) tussen hulle. (2) 6.2.1 FXY = 5 x 10-3 ∙cos 58o (or sin 32o) = 2,65 x 10-3 N (2) 6.2.2 FXY = ∙ ∙ , ∙ ∙ 2,65 x 10-3 = r = 4,51 m (∴ ½r = 2,26 m) , ∙ 5 x 10-3 ∙cos 32o (or sin 58o) = , QZ = - 1,20 x 10-6 C (7) (mark polarity independent) [11] QUESTION 7 7.1 Negative/Negatief (1) 7.2 Negative Arrow direction Arrows touching - charge (3) 7.3 A region of space in which an electric charge experiences a force /'n Gebied in die ruimte waarin 'n elektriese lading 'n krag ondervind. (2) 7.4 ENet = EV + Ew , ∙ , ∙ 2 x 10-2 = , + , (QV = QW ) -16 Q = 6.15 x 10 C (5) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 6 NW/September 2019 NSC/NSS – Memorandum QUESTION 8 8.1. The total amount of energy supplied (by the source) per coulomb charge or per unit charge/Die totale hoeveelheid energie (deur die bron) per coulomb of per eenheidslading. (2) 8.2.1 = = = RE = 2,67 Ω RT= RE+ R4+ Rr = 2,67 + 3 + 1 = 6,67 Ω (4) 8.2.2 I= = = 1,8 A , V = I ∙R = 1,8 ∙2,67 = 4,80 V (4) 8.2.3 ∙∆ , ∙ W= = = 694,08 J or/of , I= = = 1,20 A W = I2R∆t = 1,22 ∙4 ∙120 = 691,20 J or/of W = VI∆t = 4,80 ∙1,2 ∙120 = 691,20 J (3) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 7 NW/September 2019 NSC/NSS – Memorandum QUESTION 9 9.1 T= = = 0,033 s 0,033 x 2,5 = 0,0825 s (2) 9.2 The value of the direct current that dissipates power in a resistor/Die waarde van die gelykstroom wat drywing in ʼn weerstand vrystel. (3) 9.3 , Vrms = √ = √ = 219,91 V R= = = 18,325Ω Pav= Vrms ∙Irms = 219,91 ∙12 = 2638,92 W , or/of Pav = = = 2639,04 W , or/of Pav = Irms 2R = 122 ∙18,325 = 2638,8 W (4) 9.4 Irms = √ 12 = √ Imax = 16,97 A (2) 9.5 16,97 A tx -16,97 A Imax shown Time interval (2,5 wave lengths) Graph line (sinus graph) (3) [14] QUESTION 10 10.1 Absorption of specific wave lengths or frequencies of light when passing through a cold gas/Absorbsie spektrum van spesifieke golflengte of frekwensie van lig wat deur ʼn koue gas beweeg. (2) 10.2 Emission (line) spectrum/emmisie spektrum (1) 10.3.1 E = , ∙ = , = 3,32 x 10-19 J (3) 10.3.2 E = W o+ Ek 3,32 x 10-19 = 2,3 x 10-19 + ½ ∙9,11 x 10-31 ∙v 2 (4) v = 4,72 x 105 m.s-1 [10] TOTAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 8 NW/September 2019 NSC/NSS – Memorandum ANALYSIS GRID 2017 PHYSICAL SCIENCE P1 Taxonomy Knowledge area SYNTHESIS, APPLICATION, Knowledge,Recall, COMPREHENSION, WAVES, SOUND & Question No. ELECTRICITY & MECHANICS TOTAL MARKS Question Totals EVALUATION,Higher MAGNETISM ANALYSIS, Problem Abilities, Hard new TOTAL Low Demand Basic Questions LIGHT MATTER & problems, Challenge Solving MATERIALS Level Content E M D E M D E M D E M D Marks 1.1 force 2 2 2 1.2 work 2 2 2 1.3 energy 2 2 2 1.4 momentum 2 2 2 1.5 work 2 2 2 1.6 sound 2 2 2 1.7 charge 2 2 2 1.8 fields 2 2 2 1.9 electricity 2 2 2 1.10 light 2 2 2 20 Newton's 2.1 2 2 Law 2 Newton's 2.2 2 1 Law 2 Newton's 2.3.1 4 4 Law 4 Newton's 2.3.2 3 3 Law 3 Newton's 2.3.3 6 6 Law 6 Newton's 2.4.1 3 3 Law 3 2.4.2 Energy 2 2 2 2.4.3 Energy 4 4 4 25 3.1 projectile 2 2 2 3.2 Projectile 3 3 3 3.3 Energy 4 4 4 3.4 Projectile 5 5 5 3.5 Projectile 6 6 6 3.6 Energy 3 3 3 23 4.1 momentum 2 2 2 4.2 momentum 5 5 5 4.5 momentum 4 4 4 11 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 9 NW/September 2019 NSC/NSS – Memorandum 5.1 Doppler 3 3 3 5.2 Doppler 1 1 1 5.3 Doppler 1 1 1 5.4 Doppler 1 1 1 5.5 Doppler 6 6 6 12 electrostati 6.1 2 2 cs 2 electrostati 6.2.1 2 2 cs 2 electrostati 6.2.2 7 7 cs 7 11 electrostati 7.1 1 1 cs 1 electrostati 7.2 3 3 cs 3 electrostati 7.3 2 2 cs 2 electrostati 7.4 5 5 cs 5 11 8.1 circuit 2 2 2 8.2.1 circuit 4 4 4 8.2.2 circuit 4 4 4 8.2.3 circuit 3 3 3 13 9.1 dynamics 3 3 3 9.2 dynamics 2 2 2 9.3 dynamics 4 4 4 9.4 dynamics 2 2 2 9.4 dynamics 3 3 3 14 photoelectr 10.1 2 ic 2 2 photoelectr 10.2 1 ic 1 1 10.3. photoelectr 3 1 ic 3 3 10.3. photoelectr 4 2 ic 4 4 10 69 14 55 12 150 150 0 69 14 55 12 9. 36. 8 46 3 7 % % % % % % % % 45 8 36 10 15 35 40 10 % % % % Overall E M D % % % 30 40 30 Copyright reserved/Kopiereg voorbehou