PHY-P1-Sep-QP & Memo-2016-Gr10_hlayiso.com_.pdf

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Downloaded from hlayiso.com Physical Science (P1) NSC 2 INSTRUCTIONS AND INFORMATION 1, 2. Copyright reserved _ Answer ALL the questions. Non-programmable calculators may be used. Appropriate mathematical instruments may be used. September Common Test 2016 Number the answers correctly according to the numbering system used in this question paper You are advised to use the attached data sheets. Give brief motivations, discussions, ete where required. Round off your final numerical answer to a minimum of TWO DECIMALS. Please turn over

{ Downloaded from hlayiso.com Physical Science (P1) NSC QUESTION 1: MULTIPLE- CHOICE QUESTIONS September Common Test 2016 Four possible options are provided as answers to the following questions. Each question has only ONE correct answer. Write ONLY letters (A — D) next to the question number (1.1 — 1.3) in the ANSWER BOOK, for example 1.5 E. 1.1. Which of the following combinations is correct? VECTOR SCALAR A Force distance B Force velocity Cc distance Speed D distance acceleration (2) 1.2 Abody accelerates uniformly from rest for x seconds after which it continues ; A v(m.s"') | x t(s) A ) c v (ms) t(s Ox Copyright reserved v(m.s") v(m.s) B x ts x D t(s) with a constant velocity, Which one of the following graphs is the correct representation of the body's motion? (2) Please turnover |

Downloaded from hlayiso.com Physical Science (P1) NSC September Common Test 2016 4 1.3. Inthe equation Ax = yates ad the part sane represents... A time B velocity Cc displacement D acceleration (2) [6] Copyright reserved Please turn over

Physical Science (P1) NSC Downloaded from hlayiso.com 5 QUESTION 2 The velocity time graph below illustrates the motion of a man riding on a motorcycle, initially in an easterly direction, for a period of 70s. wl ANSWERING THE FOLLOWING QUESTIONS, NO EQUATIONS OF MOTION MUST BE vores) 12 10. a 8 USED. 2.1 2.2 2.3 24 2.5 Describe the motion of the motorcycle from 20s to 60s. What happened to the motorcycle at 60s? Use the graph to calculate the acceleration during the following time intervals: 2.3.1 0-20 seconds 2.3.2 60s - 70s Use the graph to calculate the: 2.4.1 Displacement of the motorcycle during the time interval 40 — 70 seconds. 2.4.2 Distance covered by the motorcycle during the time interval 40 — 70 seconds THE FOLLOWING QUESTION MUST BE ANSWERED WITHOUT DOING A CALCULATION: Which time interval was the acceleration greater? 0 — 20 seconds or 30 ~ 40 seconds Give a reason. Copyright reserved - Please turn over September Gommon Test 2016 (4) (1) (2) (2) (6) (2) (2) [19]

Downloaded from hlayiso.com Physical Science (P1) NSC September Common Test 2016 6 QUESTION 3 A car C and a truck T are both travelling at a constant velocity of 30 m.s"! east. The driver of the car C follows the truck T, keeping a distance of 35 m between them. Seeing a herd of cattle ahead on the road, the driver of the truck T brakes to reduce the speed uniformly to stop in 12 s. Direction of motion > > TRUCK T CAR CG 4 | \ 35m ( ome CO 3.1 Convert 108 km.h"! to metres per second (m.s"). (2) 3.2 Define acceleration. (2) 3.3 Calculate the acceleration of the truck while slowing down. (4) 3.4 Calculate the distance travelled by the truck during the 12 s braking period. (4) 3.5 If the car continued at its original motion, how far ahead of the truck will the car be when the truck stops? (5) (17) QUESTION 4 4.1 Aboy walks at 2 m.s east in a train that is moving at 15 m.s" east. What will his velocity be relative to: 4.1.1 a person sitting in the train. (2) 4.1.2 a person sitting on the road observing the train go past. (2) 4.2 Willa change in velocity always produce a change in speed? (YES or NO). Explain the answer. (4) [8] GRAND TOTAL= [50] Convriaht reserved a : - Please turn over

Downloaded from hlayiso.com Physical Science (P1) NSC September Common Test 2016 7 DATA FOR PHYSICAL SCIENCES GRADE 10 PAPER 1 (PHYSICS) GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 10 VRAESTEL 1 (FISIKA) TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES MOTION/BEWEGING Ve =Vjt+adt Ax=v,At+tadt? orlof Ay = v,At+4adt? vi" = ve +2aAx orlof v,? =v? +2aay AX = (4) At orfof Ay = Me) At Copyright reserved

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Downloaded from hlayiso.com Physical Sciences/P1 3 September-Cor, Test 2016 Memorandum oe QUESTION 3 31 108 kmh = 108 x 1000 | 3600 | =20ms'¥ @ 3.2 acceleration is the rate of change of velocity. v ” (2) 3.3 Ve=Vyjtadty 0 =30+a(12)¥ =-2,5m.s? a=2,5 ms* Vwest¥ (4) 3.4 {Positive marking from 3.3) OPTION 1 OPTION 2 OPTION S v Ax=vAt+taat? = ¥ vp sw) +2adx¥ axa nat _ 1 2 0 = 302% 2(-2,5)axv 040. ¥ = 90(12) + 32,5) (12% ax= 180m =a ” =180m v =180m % = 4) 3.5 The truck stops in 12 s and the distance covered by the car in 12s is: ax=viAt+daat? =30 (12)v +0 = 360 mY The truck travels 180 m in 12s as calculated above «the car distance away from where the stopped truck = 360 — 180 mv - 35 m “= 145 mv(5) {17] QUESTION 4 41.1 2ms'¥ east ¥ (2) 4.1.2 2+15=17ms1v east ¥ (2) 42 No, ¥ Velocity has magnitude and v’ direction. When direction changes, velocity ” changes. This has no effect on magnitude. “ Hence speed remains the same. (4) [8] GRAND TOTAL: [50] Copyright Reserved