Physical Sciences Grade 12 Paper 2 NSC June 2013 Memo

_ Downloaded from hlayiso.com a basic education Department: Basic Education REPUBLIC OF SOUTH AFRICA SENIOR CERTIFICATE EXAMINATION SENIORSERTIFIKAAT-EKSAMEN PHYSICAL SCIENCE P2/NATUUR- EN SKEIKUNDE V2 CHEMISTRY/CHEMIE HIGHER GRADE/HOER GRAAD 2013 POSSIBLE ANSWERS / MOONTLIKE ANTWOORDE MARKSI/PUNTE: 200 This memorandum consists of 12 pages. Hierdie memorandum bestaan uit 12 bladsye. pe mare Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 2 DBE/2013 SCE/SSE —- Memorandum QUESTION 1/VRAAG 1 1.1 DvuvwYy (4) 1.2 Ave (4) 1.3 CY¥vwYY (4) 14 Buy (4) 1.5 A ¥vYY (4) 1.6 BYYYY (4) 17 Ae (4) 18 7 (4) 1.9 Curvy (4) 1.10 Dwr (4) 1.11 Dryvwr (4) 1.12 Dywyy (4) 1.13 Byyyy (4) 1.14 ® 4a (4) 1.15 — (4) (15x 4) [60] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief or

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/41G/V2 3 DBE/2013 SCE/SSE —~ Memorandum QUESTION 2/VRAAG 2 pV 2.1 PIM _P2V2 OR use/OF gebruik oak T, T, x Y QO x10 «Va (if V converted to dm? etc., it has to b ct = converte: im” etc., jas to be corre C8) NE V2 = 40,0 cm? ~ (40- 40,0335 cm? ) OR/OF ¢ vw PIV ~P2V2y, SEORTOD 478" 40,0335 om? T 7, G98) x 360 a 2.2.1. The pressure of an enclosed (fixed) mass (amount) of gas is inversely proportional to its volume at constant temperature. Die druk van 'n ingeslote (vaste) massa (hoeveelheid) gas is omgekeerd eweredig aan die volume daarvan by konstante temperatuur. Y correct variables (volume and pressure)/korrekte veranderlikes (volume en druk) “relationship correct(in words, not symbols)iverwantskap korrek (in woorde, nie simbole nie) v_enclosed (fixed) mass (amount) of gas AND constant temperature ingeslote (vaste) massa (hoeveelheid) gas EN konstante temperatuur ; : If indirectly proportional — max 2/3 accept p directly proportional a As indirek eweredig — maks 2/3 aanvaar p direk eweredig aan 1, 2.2.2 vo (Gradient =) & = maT) Es 8,31 x(288)= 168,54 J ~ a Y (Gradient =) =(0,07 x 83 (288) = 168,54 J” formula/formule calculate n/bereken n substitute both n and R/substitueer beide nen R substitute 288/substitueer 288 Answer = 168,5 J/ Antwoord = 168,5 J eeeccee If n= 0,07 mol had been used, answer = 167,5 J As n= 0,07 mol gebruik is, antwoord = 167,5 J 6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief un

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 4 DBE/2013 SCE/SSE — Memorandum 2.2.3 ” straight line /reguitlyn (Ignore origin/ignoreer oorsprong) Y greater gradient / groter gradient (2) 2.3 The hydrogen bonding ~“between the molecules of HF is stronger ~” than the Van der Waals forces “ between molecules of Cf, therefore the deviation from ideal gas behaviour (OR because it is a real gas)/smaller volume/volume decreases ~” Die waterstofbinding tussen die molekule van HF is sterker as die Van der Waalskragte tussen die molekule van Cl, daarom die afwyking van ideale gasgedrag (OF omdat dit ‘n ware gas is) /kleiner volume / (4) volume neem af. [19] we Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 5 DBE/2013 SCE/SSE — Memorandum QUESTION 3/VRAAG 3 3.1.1: FeS/CuS/ PbS (or other sulphide) / (of ander sulfied) (no marks for name / geen punt vir naam) (1) 3.1.2 colour changes from orange/yellow/brown > green ~ Kleur verander van oranje/geel/bruin > groen (yellow/sulphur) suspension or precipitate/cloudy/milky / (2) (geel/swawel) suspensie of neerslag/troebel/melkerig ~“ 3.1.3 Fe?* (FeCt,/Iron(Il) ion / tron(II)chloride) “~~ and S (sulphur) “~~ Fe?* (FeCt,/ Yster{il)ion / yster(Ii)chloried) ““ and S (swawel) “” = (4) 3.1.4 eon v (1) 3.1.5 VHS >S+2H*+2e ~“ ANDIEN Fe*+e°'>Fe* OR/OF H2S is oxidised / loses e"/ H2S word geoksideer / verloore’ ~“ ANDI/EN Fe™ is reduced / gains e" / Fe** word gereduseer wen e “ OR/OF Electrons are transferred ~’ from H2S to Fe** ~/ elektrone is oorgedra ~ van H2S na Fe* ~ (2) ORIOF H2S acts as RAY, Fe* acts as OAY 3.2.1 Cu is nota strong enough reducing agent “to reduce the dilute sulphuric acid vto SO. “ /Cu is nie ‘n sterk genoeg reduseermiddel “ om die verdunde swawelsuur te reduseer” tot SO nie “ OR/ OF: Dilute sulphuric acid is not a strong enough oxidising agent “to oxidise the Cu”toCu= ~ Verdunde swawelsuurs nie ‘n sterk genoeg oksideermiddel “om Cu tot Cu” te oksideer nie. (3) : Cu = Cu* + 2e (1/2) ag y ww 3.2.2 (a) Cu + Cu* + 2e Cu +26 = cu (012) Cu* + 2e +Cu (0/2) Cu** + 2e - Cu (1/2) | (@y 3.2.2 (b) SO,7 + 4H* + 2e°-—> SO, + 2H,0 vw SO, + 4H* + 2e° = SOQ. + 2H,O (1/2) SO, + 2H,0 ~ SO, + 4H* + 26 (1/2) SOQ, + 2H20 — SO, + 4H* + 2e (0/2) SO, + 2H.0 = SO,2+ 4H* + 26 (0/2) (2) Copyright reserved/Kopiereg voorbehou Please turn over/Biaai om asseblief Soe = ae

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 6 DBE/2013 SCE/SSE — Memorandum 3.3.1 Catalyst / increase rate of reaction / provides medium for reaction to take place / makes protons available ~“ katalisator | verhoog reaksietempo / verskaf medium waarin reaksie kan plaasvind / maak protone beskikbaar. ~ (1) 3.3.2 Density (heavier) of SO2 higher ~~ (than H2S) / (2) Digtheid van SOz2 groter (swaarder) (as H2S) 3.3.3. Yellow ~ (sulphur) precipitate “forms Geel ~“(swawel) neerslag ~vorm (2) 3.3.4 sulphur dioxide / swaweldioksied “~~ (SO2”%) (2) 3.3.5 HS ~ : OR: Hydrogen sulphide / OF: waterstofsulfied (1) [25] QUESTION 4/VRAAG 4 4.1.1 Yellow” precipitate/solid ~ forms / (2) gee! “ presipitaat/neerslag/vaste stof “ vorm 4.1.2 Nal (aq) + AgNO3(aq) > Agl(s) + NaNOs(aq ~reactants/reaktante ~ products/produkte ~balancing/balansering (3) OR/ OF: Ag*(aq) + I'(aq) — Agl(s) 4.1.3 (a) lodine (lz) / jodium (lz) (1) (b) Sodium chloride (NaCé) “ = / natriumchloried (NaCé) (1) 41.4 purple “/pers “ (1) 4.2.1 Platinum (Pt) / Rhodium (Rh) (1) 4.2.2 Water (H2O) (1) 4.2.3 NO »“~ OR/ OF: Nitrogen oxide / stikstofoksied (2) 4.2.4 NO2 ~“ (nitrogen dioxide/stikstofdioksied) ~“ (2) {14] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief (~~

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 a DBE/2013 SCE/SSE — Memorandum QUESTION 5/IVRAAG 5 5.1.1 -“ 21kI ~ (2) 51.2 165k) ~ (1) 5.1.3 186kJ ~ (1) 5.1.4 Catalyst added / Katalisator bygevoeg ~“ (1) 5.1.5 exothermic ~/eksotermies “ (1) 5.2.1. Rise in temperature// exothermic / Styging in temperatuur/ eksotermies “ sutsce area becomes more exposed because of the corrosive action of the acid / reaksieopperviak word meer blootgestel a.g.v vretende suur. (1) 5.2.2 Concentration of the acid decreases/Konsentrasie van die suur verminder~” oe a becomes smaller (surface area) / Zn monster word kleiner (reaksieopperviak) (1) Reactants being used up / Reaktanse word opgebruik 5.2.3 ANY TWO/ENIGE TWEE: ~~ Zn powdered /Verpoeierde Zn higher acid concentration / hoér konsentrasie suur increase temperature of the acid / verhoog die temperatuur van die suur. ae catalyst /katalisator QUESTION 6/VRAAG 6 6.1 The pressure gauge will give a constant reading / Drukmeter gee konstante lesing “ (1) 6.2 \% “Ko e shape of first part / vorm van eerste deel e horizontal line / horisontale lyn” (2) t Ignore labels on axes/ignoreer asse Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Pr.

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 8 DBE/2013 SCE/SSE — Memorandum 6.3 (NHa)2CO3 2NH3 H,0 COz ny 2 2 . 12,2 -0,52 = 11,68 ~ n=11,68/96 ~ a = 0,12 (0,122) Ratio An OF/OR 0,24 | o42 | 0,12 12,2-0,52 ~ (0,243) or —s a =0.12 2 subtraction ne 0,24 0,12 0,12 v n ee c=— Divide by Vv L649 | 02 (0,487) | °24 hoa 0.5 V=0,5 dm* Ke = [NHs]*[H2O] [CO] ~ = (0,48)? (0,24) (0,24) ~ = 0,01327..(OR/OF: 0,014) ~“ e Subtraction (mass or mole) [12,2 — 0,52 = 11.68 or e Divide by / dee! deur M = 96 e Mol ratio / molverhouding e Subtraction / aftrek (4n) e Divide by 0,5 / dee/ deur 0,5 e K, expression / uitdrukking e Substitution /substitusie © 0,01327.. (OR/OF: 0,014) (8) 6.4.1 Decreases /Neem af ~” (1) 6.4.2 Increases /neem toe ~ (1) 6.4.3 Decreases/Neem af ~ (1) 6.5 decrease in temperature favours the exothermic reaction “ reverse reaction is exothermic forward reaction is endothermic” concentration of products decreases “ afname in temperatuur bevoordeel die eksotermiese reaksie ~ terugwaartse reaksie is eksotermies “ konsentrasie van produkte neem af ~ (3) [17] Please turn over/Blaai om asseblief OO000 0 Copyright reserved/Kopiereg voorbehou

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 9 DBE/2013 SCE/SSE — Memorandum QUESTION 7/VRAAG 7 7.41.4 : _a m= eMV ~OR/OF c = Vv © Formuta/formule e 56g.mof? v ° 0,4dm? e Substitution / substitusie =3, 36g” e 336g ORI/OF: n=cV ~ formula/formule » substitution/substitusie = 0,06 x66) ~ (8) = 336g” 7.1.2 c, V, _n, =— e formula/formule Cy Vp My © 0,15x25 e C,x30 Ceax30K_ 1) * using ratio:na 7m = 1:2 G,15x25) 2 * 0,063 mol.dm® Ca = 0,063 mol.dm® ~ — (0,0625 mol.dm’’) ORIOF: Mp = eV 0,00375 mol ” ng = 0,5 x 0,00375 = 0,001875 mol » ratio (multiply by 0,5/ divide by 2) n c.=— ” av _ 0,001875 = 0,0625 mol.dm=> ~ (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief > Cm

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 10 DBE/2013 SCE/SSE — Memorandum 7.1.3 [OH)[H*] = 10% OR [OH}.[H']=Kw ~ 1,23 x 10% x[H*] = 104 % 8,13 x10 mol.dm? ~ pH =-log[H*] ~ [OH] = 1,23 x 10% = 10° IH] = 10-"4 40714+3,91 _ 49-10,09 4973:91 2. pH # Jog[H*] = -l0g(10"°%) = 10,09 =~ log(8,13 x 10") ~ =10,09 ~ ORI/OF: pOH log [OH] ~ - log (1,23 x 104) ” 3,917 pH = 14 3,91~ (6) = 10,09” u 7.2.4 Greater than 7 / groteras 7 “ (1) 7.2.2 \ (NH3/ NH,OH) is a base / OH ions in solution OR an alkaline solution” (1) (NH / NH4OH) is ‘n basis/OH-ione in oplossing OF ‘n alkaliese oplossing 7.2.3 NH3+H* —»NHZ (OF/OR NH3+H2O -> NH3 +. OH) ” reactants/reaktante “products/produkte “balancing/balansering (3) 7.2.4 ( Decrease / afneem (1) 7.25 NH; is a (weak) acid / proton donor ~~” NH3 is ‘n (swak) suur/ protonskenker ““ OR/OF: According to Le Chateliers principle an increase in INH4] will favour the reverse reaction in 7.2.3, which will increase the [H*] and therefore decrease the pH. Volgens Le Chatelier se beginsel sal ‘n verhoging in [| NH3] die terugwaartse reaksie in 5.2.2(b) bevoordeel, wat die [H*] vehoog en dus die pH verlaag. OR/OF: NH; is a common ion, and according to the common ion effect, the [H"] will increase, and therefore decrease the pH. NH; is ‘n gemeenskaplike ioon, en volgens die gemeenskaplike ioon-effek sal die [H*] vehoog word, en dus die pH verlaag. a Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ae a

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 11 DBE/2013 SCE/SSE — Memorandum QUESTION 8/VRAAG 8 8.1 Silver (Ag) / silwer (Ag) (1) 8.2.1 Cr—+Cr* +3e “~~ : Cr = Cr* + 3e (1/2) Cr* + 3e Cr (0/2) Cu* + 2e * Cu (1/2) crt + 3e = Cr (0/2) (2) 8.22 Ag te > Ag ~~ Agi +e Ag (1/2) Ag ~Ag + e& (0/2) Ag~ Ag’ +e& (1/2) Ag = Ag’ +e (0/2) (2) 823 Cr+ 3Ag’ - Cr* + 3Ag ~~ (ignore/ignoreer =) (2) 8.3 Increases /toeneem ~“ (1) 8.4 AgNO; “O (1) 8.5 Se = E% oxidising agent ~ E% reducing agent ~~ E%sq) = E° oxsideermidde! ~ E*recuseermiddet = 0,80”— (-0,74) ~ = 154V ~ ORIOF: = E%en = Evcathoae - Eanode /E%sor = E%katode ~ E*anode (4) 86 Cr+ 3Ag’ — Cr* + 3Aq , if LAg'lis increased ~ the forward reaction is favoured. “/ as [ Ag"] toeneem word die voorwaartse reaksie bevoordeel. OR/OF: Rate of the forward reaction increases ~ with increase in concentration ~ Tempo van reaksie neem toe met toename in konsentrasie. ORIOF: (2) [Ag’Lis increased ~ equilibrium (position) shifts to the right ~“/ Ewewig(posisie) skuif na regs. “ Copyright reserved/Kopiereg voorbehou [15] Please turn over/Biaai om asseblief

Downloaded from hlayiso.com Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 12 SCE/SSE — Memorandum QUESTION 9/VRAAG 9 oo fe 9.1.2 addition / bromination / addisie/ brominering ~~“ 9.1.3 9.2.1 9.2.2 9.2.3 9.3.1 9.3.2 9.3.3 propane / propaan “~~” (They have the same molecular formula but) different structural formulae. “~~ (Hulle het dieselfde molekulére formule maar) veskilfende Struktuurformules. “~~ a H .H H H wy OR/OF: tt mann HG tH H H OR/OF: H H H—¢—F CH hd —C— CaHan ~ methanol / methanol “~~ ethanoic acid / etanoésuur “~~ concentrated sulphuric acid“ / gekonsentreerde swawelsuur sulphuric acid” / swawelsuur concentrated H2SO,~” / gekonsentreerde H2SO, HySO,4 (0/2) Copyright reserved/Kopiereg voorbehou DBE/2013 (1) (2) (2) (2) (2) (1) (2) (2)