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Physical Sciences Grade 12 P1 KwaZulu Natal Mock 2022 Memo

MemorandumPhysical SciencesGrade 12202233 pages

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KwaZulu Natal Mock Exam 2022

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LI 4 ? ss Baas Sangh KYVAQUILUSRIATAL PROVENCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 12 m PHYSICAL SCIENCES P1 (PHYSICS) * a PREPARATORY EXAMINATION : i SEPTEMBER 2022 : VOCS CPO Ce errr reer rer rrrr rr? tt ri MARKS: 150 TIME: 3 hours This question paper consists of 15 pages and 3 data sheets. L___Copyright Reserved _ Please Turn Over
Physical Sciences P1 Downloaded. from hlayiso,com ber 2022 Preparatory Examination Downloaded from Stanmefephysics. com INSTRUCTIONS AND INFORMATION TO CANDIDATES 1, 10. 1:43 12: Write your name on the ANSWER BOOK. This question paper consists of TEN questions. Answer ALL the questions in the ANSWER BOOK. Start EACH question on a NEW page in the ANSWER BOOK. Number the answers correctly according to the numbering system used in this question paper. x Leave ONE line between two sub questions, for example between G QUESTION 2.1 and QUESTION 2.2. . y oY ‘ou may use a non-programmable calculator. ss You may use appropriate mathematical instruments. Ro You are advised to use the attached DATA woe Show ALL formulae and substitutions in AL bleulatons Round off your final numerical soos minimum of TWO decimal places. Give brief motivations, aoc et cetera where required. Write neatly and ACP o w ay Copyright Reserved Please Turn Over
Physical Sciences P1 Downloaded from hlayiso.com Downloaded from Stanmorepitysics.com QUESTION 1: MULTIPLE CHOICE Various options are provided as possible answers to the following questions. Choose the answer and write only the letter (A-D) next to the question number (1.1 — 1.10) in the ANSWER BOOK, for example 1.11 D. At 12 Copyright Reserved Which ONE of the following physical quantities is a measure of the inertia of a body? A Mass. B Velocity. Cc Energy. D Acceleration. RS The distance between the centres of two planets, P and Q is rTae mass of P is TWICE that of Q. S xs ie Consider the following tat ents regarding the gravitational force exerted by the planets. KS) (i) The fore Wild always be attractive. (ii) The fo OO ered by P on Q is twice that exerted by Q on P. (ii) TI ete that the bodies exert on each other is independent of their mat Ss h (iv) TI force exerted by P on Q is equal in magnitude but apposite in direction to the force exerted by Q on P. Which statement(s) is/are TRUE? (i) only (i) and (ii) (i) and (iv) (ii) and (iii) CoOU> tember 2022 Preparatory Examination (2) Please Turn Over RTA A
Physical Sciences P14 1.3 1.4 1.5 1.6 Downloaded from hlayiso.com _ Septémber 2022 Preparatory Examination Downloaded from Stanmorephysics.com A ball is thrown vertically upwards and it returns to the starting point. Which ONE of the following statements regarding the rate of change of velocity of the ball is TRUE? A Its direction for the upward and downward motionsiare different. B It is always directed downwards during the motion: Cc It is zero at the maximum height reached. D It is in the same direction as the velocity of the ball. (2) A vehicle is moving horizontally at a constant velocity on a frictionless path. The kinetic energy of the vehicle is K and the magnitude of the momentum is p. The speed of the vehicle can be given as: K A ‘et Pp Pp . K ec 2p 2K D par p (2) The engine.of &,Car does work, W, to increase its velocity from 0 to v. The work done by the engine to increase the velocity from v to 2y, is A W. B 2w Cc 3w D 4w (2) A taxi sounds it hooter whilst it is moving at a constant velocity away from a stationary listener. Compared to the sound waves detected by the taxi driver, the sound waves detected by the observer has a greater ... A wavelength. B frequency. c energy. D speed. (2) Copyright Reserved Please Turn Over
Downloaded from hlayiso.com Physical Sciences P1 ptember 2022 Preparatory Examination Downloaded from Stanmorepffysics.com 1.7 Sketches I, II and Ill, not drawn to scale, are different ways in which three point charges are arranged. The charges are identical in MAGNITUDE and the distance ‘d’ between the charges is the same. ® i iy! . +q d -q d “q il ¢ oe 8 -q d +q d -q q Ui d a +q d -q In which of these sketches will the magnitude of the NET electrostatic force experienced by the + q charge be LARGEST and SMALLEST respectively? LARGEST NET FORCE on +q_ | SMALLEST NET FORCE on +q | ll Ul Ut Hi | Ul Ul DO a> 1.8 Three identical resistors X, Y and Z are connected as shown in the circuit below. LZ If the power in X is P, then the power in Y is ... A 2P BOY cP dp % (2) Copyright Reserved Please Turn Over
Downloaded from hlayiso, com Physical Sciences P1 September 2022 Preparatory Examination Downloaded from Stanmotephysics. com 1.9 The graph below shows the relationship between maximum kinetic energy (Kmax) of the photoelectrons and frequency of incident photons during an experiment on the photoelectric effect. A = S 5 * > G - Frequency (Hz) ZG v The point labelled G on the graph represents the ... threshold wavelength. maximum frequency. threshold frequency. work function. (2) lekens De 2 1.10 Which ONE of the following graphs best represents the relationship between the maximum kinetic energy of the emitted photoelectrons and the intensity of the incident light when light is shown on a metal surface? A B 4 > a o 2 oO © c 5 io) 3 2 3 3 2 — Ui. = a4 i ‘ me intensity intensity B D c £ 3 f 2 o g 2 = intensity = intensity (2) [20] Copyright Reserved Please Turn Over
Downloaded from hlayiso.com Physical Sciences P1 eptember 2022 Preparatory Examination Downloaded from Stanmorepffysics.com QUESTION 2 A 10 kg block is connected to another block of unknown mass ‘m' by a light inextensible string. The blocks are placed on a rough horizontal surface. When a force of 45 N is applied to the 10 kg at an angle of 30° to the horizontal, as shown in the sketch below, the blocks accelerate at 2,5 m's? to the LEFT. 10 kg string m The block of mass m kg experiences a constant frictional force of magnitude 1.N whilst moving. 2.1 Draw a labelled free body diagram indicating ALL the forces acting on the 10 kg block while it is accelerating. (5) 2.2 Define the term normal force. (2) 2.3 Calculate the magnitude of the normal force acting on the 10 kg block. (4) The co-efficient of kinetic friction (yx), between the 10 kg block and the surface is 0,125. 2.4 Calculate the unknown mass ‘m’. (6) [17] Copyright Reserved Please Turn Over
Downloaded from hlayiso.com Physical Sciences P1 eptémber 2022 Preparatory Examination Downloaded from Stanmofephysics.com QUESTION 3 A small stone is projected vertically upwards from the ground with a speed of 20 ms“. It passes the roof of an 8 m tall building on its way up and reaches its maximum height at A. On its way down, the stone passes the roof at point B as shown in the diagram below. Ignore the effects of air friction. caer: " 1 i} } SA el = eee TRE 1 I O a 8m ' 1 3.1. Write down the acceleration of the stone at point A. (2) 3.2 Using equations of motion, calculate the: 3.2.1 Time it takes for the stone to reach point A (3) 3.2.2 Magnitude of the velocity of the stone at the instant it reaches pointB = (3) 3.2.3. Total time it takes for the stone to move from the ground until it reaches point B on its way down (4) 3.3. Sketch a velocity — time graph for the motion of the stone from the instant it is projected-until it reaches point B on its way down. Indicate the following in your graph: e Initial velocity e Time taken to reach maximum height e The final velocity at point B (4) [16] Copyright Reserved Please Turn Over
Downloaded from hlayiso.com Physical Sciences P1 eptember 2022 Preparatory Examination Downloaded from Stanmorepffysics.com QUESTION 4 Two friends on wheel chairs are playing on a surface that has NEGLIGIBLE friction. The combined mass of girl A and her wheelchair is 60 kg whilst that of girl B and her wheelchair is 85 kg. Girl A moves to the right at a velocity of 0,60 m-s"! and collides with girl B, who is stationary. After the collision, girl A and her wheelchair move with a velocity of 0,20 ms" to the left in the same straight line. BEFORE AFTER 0,20 mst 0,60 ms" py 4.1 State the principle of conservation of momentum in words (2) 4.2 Calculate the velocity of the friend on wheelchair B immediately after the collision? (5) 4.3 Determine by means of a relevant calculation whether the collision was ELASTIC or INELASTIC. (5) AE Copyright Reserved Please Turn Over
Downloaded from hlayiso.com Physical Sciences P1 Nays 2022 Preparatory Examination Downloaded from Stanmorephysics. com QUESTION 5 A block of mass 2 kg was dropped from point X and reaches point Y. Neglect friction. 2kg | xX 5m ie 5.1. State the principle of conservation of mechanical energy in words. (2) 5.2 Use the principle of conservation of mechanical energy to calculate the speed of the block when it reaches point Y. (4) The same block was then released from X again, but travelled along a path XZ which is frictionless, aS shown below 2 kg _X if 5m 5.3 State the work — energy theorem in words (2) 5.4 Use the work — energy theorem to calculate the speed of block when it reaches point Z. (4) 5.5 How should the answers of QUESTIONS 5.2 and 5.4 compare according to physics principles? Choose from: EQUAL or UNEQUAL Explain the answer. (3) [15] Copyright Reserved Please Turn Over
Downloaded from hlayiso.com Physical Sciences P1 September 2022 Preparatory Examination Downloaded from Stanmoreptffsics.com QUESTION 6 A policeman with a speed detector is standing on a straight section of a road where the speed limit is 80 km-h’. The hooter of a car moving on this section of the road with a constant UNKNOWN speed emits sound waves of frequency 400 Hz. The wavelength of the sound waves detected by the police man is 0,80 m. The speed of sound in air is 340 ms. 6.1. State the Doppler Effect in words. (2) 6.2 Calculate the frequency of the sound wave detected by the policeman. (3) 6.3. Determine, with the aid of a suitable calculation, whether the car is EXCEEDING the speed limit or not. (5) 6.4 How would your answer to QUESTION 6.2 be affected if the car travels at a LOWER constant speed? Choose from GREATER THAN, LESS THAN or THE SAME AS. (1) 6.5 State two uses of the Doppler effect in medicine (2) [13] Copyright Reserved Please Turn Over
Downloaded from hlayiso.com Physical Sciences P1 September 2022 Preparatory Examination Downloaded from Stanmexephysics.com QUESTION 7 In FIGURE 1 below, two IDENTICAL, negative point charges are placed a distance X metres apart. The charges exert an electrostatic force of magnitude 1984 N on each other. xX + : > @ oes tebete hese veecceus -e -Q -Q Figure 1 In FIGURE 2, the charges are separated a further 0,8 m. The electrostatic force the charges now exert on each other is of magnitude 124 N. . (X + 0,8) m +¢ > Sih soe 8 tie: peca tno eit Rn pose aNd wee ees as ee aS ae e -Q -Q Figure 2 7.1. State Coulomb’s Law in words. (2) 7.2 Calculate the distance X. (4) 7.3. Calculate the magnitude of the charges. (3) 7.4 The charges are returned to their original positions as in FIGURE 1 (X metres apart). A proton is now placed at point P which is 0,4 m to the left of -Q as shown below. l+0,4 me aan) >| 625 ee eee seat nas -e Pp -Q -Q 7.4.1 Define electric field at a point in words. (2) Calculate the magnitude of the: 7.4.2 NET electric field at point P (5) 74.3 NET force experienced by the proton at P (3) [19] Copyright Reserved Please Turn Over
Physical Sciences P4 QUESTION 8 Downloaded from hlayiso.com : September 2022 Preparatory Examination Downloaded from Stanmorepif¥sics.com 8.1 Abattery is connected to two IDENTICAL resistors, R, in two separate experiments as shown below. EXPERIMENT 1 O R R LY EXPERIMENT 2 ©) The internal resistance and emf of the battery are UNKNOWN. The ammeter and voltmeter readings in both experiments are shown in the table below. AMMETER READING (A) VOLTMETER READING (V) EXPERIMENT 1 6,13 18,40 EXPERIMENT 2 1,78 20,58 8.1.1 Define emf in words. 8.1.2 Calculate the emf of the battery 8.1.3 Calculate the resistance of R 8.1.4 One of the resistors in EXPERIMENT 1 is now disconnected. How will this affect the power dissipated by the battery? Choose from: INCREASE, DECREASE or REMAIN THE SAME. Explain the answer by making reference to a suitable formula for power. (4) 8.2 Accurrent of 4,4 A passes through an oven of resistance 50 Q. Calculate the cost of electricity consumed by the oven for 6 hours if the price of electricity is R1,69 per kWh. Copyright Reserved (3) [17] Please Turn Over
Downloaded from hlayiso.com Physical Sciences P1 14 . September 2022 Preparatory Examination Downloaded from Stanmerephysics.com QUESTION 9 9.1 The sketch below represents a simplified version of a DC electric motor. coil 9.1.1. Name the component that ensures that the coil (armature) rotates continuously in the SAME direction. (1) 9.1.2 In which direction does the coil rotate? Choose from: CLOCKWISE or ANTICLOCKWISE. (2) 9.1.3 Write down the energy conversion that occurs in a motor. (2) 9.2 The above motor is CONVERTED to operate as an ac generator and the output of the generator is shown in the sketch graph below. na et a 7 ie t(s) 9.2.1 Write down TWO changes that need to be made for the above conversion. (2) 9.2.2 Calculate the rms voltage. (3) [10] Copyright Reserved Please Turn Over
Downloaded from hlayiso.com Physical Sciences P1 eptember 2022 Preparatory Examination Downloaded from Stanmorepfi¥sics.com QUESTION 10 The work functions of two metals are listed in the table below. Work function Metal (J) Sodium 2,46 x 10°18 Platinum 6,35 x 10°18 10.1. Define work function. (2) The sodium surface is illuminated with light having a wavelength of 400 x 10°m. 10.2 Calculate the energy of a photon of the incident light. (3) 10.3 Calculate the maximum speed of the ejected electrons. (4) 10.4 The same light is now incident on a platinum metal. Will electrons be ejected from the platinum metal? Choose from: YES or NO Write down a reason for your answer (2) [11] TOTAL: 150 Copyright Reserved
Physical Sciences P1 Downloaded from Stanmorephysics.com Downloaded from hlayiso.com September 2022 Preparatory Examination DATA FOR PHYSICAL SCIENCES GRADE 12 PAPER 1 (PHYSICS) GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12 VRAESTEL 1 (FISIKA) TABLE 1: PHYSICAL CONSTANTS / TABEL 1: FISIESE KONSTANTES NAME / NAAM SYMBOL / SIMBOOL VALUE / WAARDE Acceleration due to gravity 9,8 m-s? Swaartekragversnelling Universal gravitational constant G 6,67 x 10°11 N-m2-kg? Universele gravitasiekonstante Speed of light in a vacuum c 3,0 x 108 m-s* Spoed van lig in 'n vakuum Planck's constant h 6,63 x 10°34 J's Planck se konstante Coulomb’s constant k 9,0 x 109N-m?-C2 Coulomb se konstante Charge on electron e -1,6 x 10°79C Lading op electron Electron mass Me 9,11 x 10°31 kg Elektronmassa Mass of Earth M 5,98 x 10% kg Massa van Aarde Radius of Earth Re 6,38 x 10°m Radius van Aarde Copyright Reserved Please Turn Over
Physical Sciences P1 Downloaded from hlayiso.com eptember 2022 Preparatory Examination Downloaded from Stanmorephysics.com TABLE 2: FORMULAE / TABEL 2: FORMULES MOTION / BEWEGING Vp=vjitadt Ax =v At+ 4adt? or/of Ay = v,At+ taat? v, =v; +2aAxorlofv,” =v,’ + 2aAy ax-(% = atorotay -(“ ~ Jas FORCE / KRAG Fret =ma p=mv fs(max) = UsN fk = UkN F_,At=Ap w=mg Ap=mv, —mv, Gm,mz GM re 2 ae WORK, ENERGY AND POWER / ARBEID, ENERGIE EN DRYWING W=FAxcos 0 U=mgh or/ofE, =mgh = A i K= i mv? eiore. = pm? Whret = AK or/of Wret = AE AK = Kr—- Ki or/of AEk = Ext - Eki Whe = AK + AU or/of Whe = AEk + AEp p= Pay = F-Vav 1 Pgem = F-Vgem WAVES, SOUND AND LIGHT / GOLWE, KLANK EN LIG v=fr Te! f vty, viv, f. s f= E=hf orlof E=h= E = Wo + Eximay or/of E = Wo + Kimax) where/waar E=hf and/en Wo=hfo and/en Ekimax = i mVivex orlof Kimax) = 5 MVitax Copyright Reserved Please Turn Over
Downloaded from hlayiso.com Physical Sciences P1 September 2022 Preparatory Examination Downloaded from Stanmorephysics.com ELECTROSTATICS / ELEKTROSTATIKA kQ4Q2 kQ Fa sci2 bat r2 r2 vow pak q q n=2 OR/IOF n=2 e€ qe ELECTRIC CIRCUITS / ELEKTRIESE STROOMBANE i Vv emf (e) =I (R +15) rl emk (e) =(R +n) R, =R, +R, + 4 4 4 q=IAt eS tot... R, R, R, W=V i _w W=VIAt At P=VI = |2 W=PRAt P=PR 2 _ Vat pov We = R ALTERNATING CURRENT / WISSELSTROOM Pave =Vimslams / Premiddeta = V wok Tek I I Lao / Two = maks. rms wa V2 v2 Paglia! f° -Pactiniad= le R AVA Vv, Vins =F 1 Vg = SEE Vi Vk V2 m V2 Pies =R 1 Pyemiddeld = = Copyright Reserved
Downloaded from hlayiso.com Downloaded from Stanmorephysics.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 12 MARKS: 150 This marking guideline consists of 15 pages. Copyright Reserved Please Turn Over
a Downloaded from hlayiso.com i Physica se iloa ey” from S tanmere. phySies.£O. ryperember 2022 Preparatory Examination QUESTION 1 1. Avy (2) 12 Cvv (2) 13. BYv (2) 14. Dvv (2) (2) (2) L7 Dvv (2) 18 BYY (2) 19 Dvv (2) 110 BY (2) [20] Copyright Reserved Please Turn Over
Downloaded from hlayiso.com September 2022 Preparatory Examination Pus euniloaded from Stanmorephysiesn£oln QUESTION 2 21 Fapp.v Fapplied Formal we Frormal¥ v v F OR Fapp.h uy Feravityl~ Feravityl~ nocert the fokowing symbols If components of Fapp and Normal : $ Fapplied | 45,0N/F/Fa/Fapp Fapp oe eran T Frension/Tensional force LAU Fx f</f/friction/Fr Ww. Fg/mg/98N Notes + Mark is awarded for label and arrow. * Do not penalise for length of arrows. + Deduct 1 mark for any additional force. + If force(s) do not make contact with body/dot: Max:4/5 + If arrows missing but labels are there: Max:4/5 6) 2.2 Normal is the force or the component of a force which a surface exerts on an object with which it is in contact, and which is perpendicular to the surface. Vv (2) NOTE: If any one of the underlined key words in the correct context is omitted deduct 1 mark. 2.3 Fnet=mav Fv +N—Fyg=0 45sin30° + N — 10(9,8) v = OY N = 75,50 NY (4) Copyright Reserved Please Turn Over
2.4 a Downloaded from hlayiso.com ~SHGiiloaded from Stanmorephysieseco POSITIVE MARKING FROM QUESTION 2.3 OPTION 1 CONSIDER 10 kg BLOCK TAKING LEFT TO BE POSITIVE v Fret = ma Fu -T-—Fr =ma 45cos 30°Y — T— 0,125(75,50) “ = 10(2,5)” T=4,53 N CONSIDER BLOCK m Fret = ma T - Fr = m(2,5) 4,53 —1¥ = m(2,5) m= 1,41 kg¥ OPTION 2 CONSIDER 10 kg BLOCK TAKING LEFT TO BE NEGATIVE Fnet = ma a Me -Fi+ T + Fa =ma -45cos 30°V + T + 0,125(75,50) Y = -10(2,5)” T=-4,53 N CONSIDER BLOCK m Fret = ma T - Fix = m(2,5) - 4,53+1v = m(-2,5) m = 1,41 kgv¥ OPTION 3 If masses added then max 3/6 e¢ Fret =ma¥ e 45cos 30° v ° 141kgv Copyright Reserved September 2022 Preparatory Examination m (6) [17] Please Turn Over
Downloaded from hlayiso.com September 2022 Preparatory Examination Prseeuiiloaded from Stanmorephysiesn£on (2) (3) QUESTION 3 3.1 9,8 ms? ¥ downwards ¥ 3.2.1 | (downward positive) (upwards positive) v= vit alt ¥ v= vit adt ¥ O = (-20) + 9,8At v 0 = 20 + (-9,8)Atv At = 2,04s Vv At = 2,04 sv 3.2.2 OPTION1 (downward positive) (upwards positive) vit= vit+ 2aAy ¥ vee = (-20)? +2 x (9,8)(-8) Y vi = 15,60 m-s! ¥ vit= vie+ 2aAy ¥ ve? = (20)? +2 x (-9,8)(8) “ vi= 15,60 m-st ¥ OPTION 2 Considering motion from maximum height (downward positive) (upwards positive) vie= viet Zadys 0 =20* + 2(9,8) Ay Ay = 20,44) m vit= vit+ 2aAy 0 = 20? + 2(-9,8) Ay Ay = 20,41 m On its way down Ay = 20,41 — 8 = 12,41 m vit= vie+ 2ady ¥ ve= 0+ 2(9,8)( 12,41) ¥ Vi = 15,60 m-s? ¥ OPTION 3 vit= vit+ 2aAy ¥ ve= O+ 2(-9,8)(-12,41) ¥ vi = 15,60 mst ¥ Considering motion from ground to the roof (downward positive) (upwards positive) Ay = vi At + % aAt® 8 = 20 At + % (-9,8)At2 At= 0,45s v= vit alt ¥ Vi_=_(-20) + 9,8(0,45) ¥ vi = 15,60 m-st ¥ Ay = vi At + % aAt? -8 =- 20 At+ % (9,8)At2 At= 0,45s vr=vit alt ¥ v= (-20) + 9,8(0,45) W vr = 15,60 m-st ¥ (3) Copyright Reserved Please Turn Over
3.2.3 Downloaded from hlayiso.com OPTION 1 (downward positive) (upwards positive) Ay = vi At + % alt? ¥ Ay = vi At + % alt? ¥ -8 v =-20 At + % (9,8)(At)? ¥ 8 v= 20 At + % (-9,8) (At)?v At = 3,63s or At = 0,45s At = 3,63s or At = 0,45s At = 3,63s ¥ At = 3,63s ¥ OPTION 2: POSITIVE MARKING FROM QUESTION 3.2.2 (downward positive) (upwards positive) Time taken to reach maximum height from the ground. v= vit aAt ¥ 0 = (-20) + 9,8At ¥ At = 2,04 s From the maximum height to the top of the building v= vit aAt 15,60 = 0 + 9,8Atv At=1,59s The total time from the ground to the top of the building: Attota = 2,04 +1,59 = 3,63 s ¥ Time taken to reach maximum height from the ground. v= vit alt ¥ O = 20 + (-9,8)AtY At =2,04s From the maximum height to the top of the building v= vit alt -15,60 = 0 - 9,8Atv” At=1,59s The total time from the ground to the top of the building: Attotal = 2,04 +1,59 = 3,63 s ¥ OPTION 3: POSITIVE MARKING FROM QUESTION 3.2.2 (downward positive) (upwards positive) w= vit alt ¥ 15,.60V =-20+9,8At v At=3,63sv¥ v= vit alt YW -15,60Y = 20 +(-9,8)At ¥ At =3,63s v Copyright Reserved Please Turn Over September 2022 Preparatory Examination Pus euniloaded from Stanmorephysiesn£on (4)
Downloaded from hlayiso.com September 2022 Preparatory Examination Pus euiioaded from Stanmorephysiesn£oln 3.3. POSITIVE MARKING FROM QUESTION 3.2.1 AND 3.2.2 (upwards positive) (downward positive) 4 15,60 20 Nis | EEA AAR AARC AAAS é E = = : — 3 0 . 8 (e) ey 3,63 t(s) g t(s) $ -15,60 ae v v Criteria for marking the graph Marks Correct shape (straight line) having a positive and negative velocities with line | “ longer before 2,04 s than after 2,04 s Graph starts at v = 20 m:s/-20 mst andt=0s v Graph cuts t-axis at 2,04 s atv = 0 ms-1 v Graph shows the v = -15,60m-s7/15,60 m:stat t = 3,63 s v (4) [16] Copyright Reserved Please Turn Over
Downloaded from hlayiso.com September 2022 Preparatory Examination Push euiiloaded from Stanmorephysies.£oi QUESTION 4 4.1 The total linear momentum of an isolated system remains constant (is conserved). VY = (2) 4.2 OPTION1 OPTION 2 Taking right to be positive Taking left to be positive Zpi =Zpr iW Zpi =Zpr by Mavia + MBViB = Mavra + MBVsB. Mavia + MBViB = MavtA + MBVsB 60 (0,60)+85 (0) v= 60(-0,20)+85 60 (-0,60) + 85 (0) Y = 60 (0,20) + 85 vey vie vig = 0,57 ms V to the right¥ vig = - 0,57 mst Vig = 0,57 ms* v to the right¥ (5) 4.3 POSITIVE MARKING FROM QUESTION 4.2 EKIE A maAvA? + ama vee EKf = Ye ma via? + Yom vB? = ¥% (60)(0,6)2 +0V = ¥% (60)(0,2)2 + 4(85)(0,57)2” = 10,80 J = 15,01 J XKr# ZKi¥ OR Total Ek before # Total Ek after -. Collision is Inelastic “ NOTE: If learners starts with 2Kr = ZKi, then minus one mark. (6) [12] Copyright Reserved Please Turn Over
a Downloaded from hlayiso.com "~SHeiiloaded from Stanmoerephysiesecol QUESTION 5 5.1 The total mechanical energy (sum of gravitational potential energy and kinetic energy) in an isolated system remains constant. Vv“ ~ 5.2 Ema= Ene (K +U)x = (K+U)y (% mv? +mgh)x = “amv? +mgh)y 0,5)(2)(0) + (2)(9,8)(5) W = 0,5(2)v? +0” v=9,90 mstv 5.3 The net work done on an object is equal to the change in the object's kinetic energy VV OR The work done on an object by a net force is equal to the change in the object's kinetic energy. vv NOTE: If any one of the underlined key words in the correct context is omitted deduct 1 mark. 5.4 OPTION1 OPTION 3 Whet = AKY Whe = AEp + AEk ¥ mgsin30°(—>—) v= 1A(2v2_- OV OY = 2x 9,8 (0-5) + #(2)\v2 -OY v=9,90 ms!v v=9,90 mslv OPTION 2 Whet = AKY mgcos300°( = ) v= ~(2)v?_- OY sin30° v=9,90 ms!v 5.5 Equal ¥ Work done by the conservative force does not depend on the path taken. VW” OR: gravitational force is the only force doing work on the block. It is a conservative forcev Vv September 2022 Preparatory Examination (2) (4) (2) (4) (3) [15] Copyright Reserved Please Turn Over
Downloaded from hlayiso.com September 2022 Preparatory Examination Pus euiioaded from Stanmorephysigsn£oln QUESTION 6 6.1 Doppler effect as the (apparent) change in frequency (or pitch) of the sound detected by a listener, because the sound source and the listener have different velocities relative to the medium of sound propagation. vv (2) 62 v=fAv 340 = £(0,80) Vv f= 425 Hzv (3) 6.3. POSITIVE MARKING FROM QUESTION 6.2 viv i= t. fv vtv, 340 v (340 - v,) “ Vs = 20 mst 2 Vs = 72 kmh The car was not exceeding the speed limit. W NOTE: Statement must be marked in relation to answer. (5) 6.4 Less than’ (1) 6.5 Blood flow meter” Detecting foetal heartbeatv (2) [13] Copyright Reserved Please Turn Over
Pus euiioaded From Stanmorephysiesn£0. Downloaded from hlayiso.com QUESTION 7 “A 7.2 7.3 September 2022 Preparatory Examination m The magnitude of the electrostatic force exerted by one point charge (Q1) on another point charge (Qz) is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance (r) between them vv (2) NOTE: -_ = If any one of the underlined key words in the correct context is omitted deduct 1 mark. p — KQi1Q2 y r2 POSITIVE MARKING FROM QUESTION 7.2 OPTION 1 p= kQiQ2 v r2 9x 10° Q* 984 = 0277 Q = 1,27 x104 CY OPTION 2 i kQiQ2 v r2 9 2 a4 = 9x 10° Q’ : (0,27 +08 Q=1,26 x 104 Cv Copyright Reserved (4) (3) Please Turn Over
a Downloaded from hlayiso.com i Physica se aloa ery” from S tanmere. pliysies.com 2022 Preparatory Examination 7.4.1 The electric field at a point is the electrostatic force experienced per unit positive charge placed at that point. “wv (2) NOTE: If any one of the underlined key words in the correct context is omitted deduct 1 mark. POSITIVE MARKING FROM QUESTION 7.3 TAZ eo kOy r2 v X10°)(1,26x10* 2 am 7 7087500 N-C* to the right 9x10°)(1,26x10%) v Eop = a = 2526175,095 N:C* to the right 1P. Enet = E1p + Ep = 7087500 + ¥2526175,095 NOTE: The mark is for the addition = 9,61x10 N-C* to the right “ (5) 7.4.3, OPTION 1: POSITIVE MARKING FROM QUESTION 7.4.2 E-Fv q 9616375,10 = ——. v nm 1,6x1079 F = 1,54 x 10°? N to the rightY OPTION 2: POSITIVE MARKING FROM QUESTION 7.3 F — KQ1Q2 2 _ k(1,26 x10%)(1,6 x10") yf ead (0,4) = 1,134 x 107? N to the right k(1,26 x10%)(1,6 x10?) Fas appease (0,67) = 4,04 x 10 ?° N to the right Fret = Fai + Fq2 = 1,134 x 10°! + 4,04 x 10 “8 = 1,54 x 10°1? N to the rightY (3) [19] Copyright Reserved Please Turn Over
a Downloaded from hlayiso.com i Physica se iloa ey” from S tanmere. phiysies.com 2022 Preparatory Examination QUESTION 8 8.1.1 Emf is the maximum energy provided by a battery per unit charge passing through it. vv (2) NOTE: If any one of the underlined key words in the correct context is omitted deduct 1 mark. 8.1.2 | EXPERIMENT 2 EXPERIMENT 1 E=1(R+)NY E=1(R+r) € = 20,58 + 1,78r v------------ (1) € = 18,40 + 6,13rv’ --------- (2) r=0,500 € = 20,58 + 1,78(0,5) OR € = 18,40 + 6,13(0,5) ¥ € = 21,47 VW (5) 8.1.3 POSITIVE MARKING FROM QUESTION 8.1.2 OPTION 1 OPTION 2 EXPERIMENT 2 EXPERIMENT 1 car ery E=I1(R+n)nv 21,47 = 1,78(R+0,5) ¥ 21,47 = 6,13(R+0,5) ¥ R = 17;56°0 R=30 R, =R, +R; +... erg iy R, 1 R, 11,56 = Ri+R2v 1 de, — = + Vv 2,99 RR R=5,78 OY R=6QY OPTION 3 OPTION 4 V = IRext¥ V = IRext¥ 20,58 = 1,78.2RY 18,40 = 6,13 R/2vV R=5,78 OY R=6 Ov (3) 8.1.4 DecreaseY If Riis removed in circuit X, the total resistance will increase V. For a constant emfv, from P= V7/Rv,, power will decrease. (4) Copyright Reserved Please Turn Over
— Downloaded from hlayiso.com ~SHGiiloaded from Stanmorephysieseco 8.2 OPTION1 kWh = PAt 1000 _ | Rat 1000 _ (44°)(50)(6) | 1000 = 5,808 units Cost of electricity = 1,69 x 5,808 “ = R9,82v OPTION 2 V=IR =4,4x 50 =220 V 1000 1000 220° Cea? = —90_y 1000 = 5,808 units Cost of electricity = 1,69 x 5,808 v = R9,82v OPTION 3 kwh = Pat 1000 - ViAt ~ 1000 _ (220)(4,4)(6) | 1000 =5,808 units Cost of electricity = 1,69 x 5,808 “” = R9,82Y Copyright Reserved September 2022 Preparatory Examination (3) [17] Please Turn Over
a Downloaded from hlayiso.com i Physica se iloa ey” from S tanmere. phiysies.com 2022 Preparatory Examination QUESTION 9 9.1.1 Split rings (commutator) (1) 9.1.2 Anticlockwisev ¥ (2) 9.1.3. Electrical to mechanicalv ¥ (2) 9.2.1 ANY TWO The DC power supply can replaced by a load / resistor. “ The split rings (commutator) is replaced by the slip rings. ” The coil should be rotated. (2) 9.2.2 V, Vins = pe v2 31113 Vio= v rms J2 Vrms = 220 VY (3) [10] QUESTION 10 10.1 Work function issthe»minimum energy that an electron in the metal needs to be emitted from the meta! surface. vv (2) ee ‘ 10.2 he “ as ES OR c=Af E=hf - 34) 8 = es ie Le, 3x 10°=400x10°V =66x10%.7,5x 10" 400x10 E=4,97 x10 Jv f=7,5 x 10%Hz = 4,97 x 10° Jv (3) 10.3. POSITIVE MARKING FROM QUESTION 10.2 1 2 E=Wo + =Mviawx % 2 al 4,97 x 1079 v= 2,46 x 1079 v+ 5 (QAIK10 Vr Vimax) = 742322,57 ms lv (4) 10.4 Nov The work function of platinum is higher than the energy of the photon” (2) [11] TOTAL: 150 Copyright Reserved

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