Physical Sciences Grade 12 P2 Eastern Cape Mock 2014 Memo

Downloaded from hlayiso.com Province of the EASTERN CAPE EDUCATION NATIONAL SENIOR CERTIFICATE GRADE/GRAAD 12 SEPTEMBER 2014 PHYSICAL SCIENCES P2 FISIESE WETENSKAPPE V2 MEMORANDUM MARKS: 150 This memorandum consists of 20 pages. Hierdie memorandum bestaan uit 20 bladsye.

Downloaded from hlayiso.com 2 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (SEPTEMBER 2014) GUIDELINES FOR MARKING/RIGLYNE VIR NASIEN This section provides guidelines for the way in which marks will be allocated. The broad principles must be adhered to in the marking of Physical Sciences tests and examinations. Hierdie afdeling verskaf riglyne vir die manier waarop punte toegeken sal word. Die breë beginsels moet tydens die nasien van Fisiese Wetenskappe toetse en eksamens gevolg word. 1.1 MARK ALLOCATION/PUNTETOEKENNING 1.1.1 Definitions/Definisies: Two marks will be awarded for a correct definition. No marks will be awarded for an incorrect or partially correct definition. Twee punte sal vir ʼn korrekte definisie toegeken word. Geen punte sal vir ʼn verkeerde of gedeeltelik korrekte definisie toegeken word nie. 1.1.2 Calculations/Berekeninge: o Marks will awarded for: correct formula, correct substitution, correct answer with unit. Punte sal toegeken word vir: korrekte formule, korrekte substitusie, korrekte antwoord met eenheid. o No marks will be awarded if an incorrect or inappropriate formula is used, even though there may be relevant symbols and applicable substitutions. Geen punte sal toegeken word waar ʼn verkeerde of ontoepaslike formule gebruik word nie, selfs al is daar relevante simbole en relevante substitusies. 1.1.3 Explanations and interpretations/Verduidelikings en interpretasie: Allocation of marks to questions requiring interpretation or explanation e.g. AS 1.4, 2.2, 2.3, 3.1, 3.2 and 3.3, will differ and may include the use of rubrics, checklists, memoranda, etc. In all such answers emphasis must be placed on scientific concepts relating to the question. Toekenning van punte by vrae wat interpretasie of verduideliking vereis bv. AS 1.4, 2.2, 2.3, 3.1, 3.2 en 3.3, sal verskil en mag die gebruik van rubrieke, kontrolelyste, memoranda, ens. insluit. By al hierdie antwoorde moet die beklemtoning op die wetenskaplike konsepte, met betrekking tot die vraag, val. 1.2 FORMULAE AND SUBSTITUTIONS/FORMULES EN SUBSTITUSIE 1.2.1 Mathematical manipulations and change of subjects of appropriate formulae carry no marks, but if a candidate starts with the correct formula and then changes the subject of the formula incorrectly, marks will be awarded for the formula and the correct substitutions. The mark for the incorrect numerical answer is forfeited. Wiskundige manipulering en verandering van die voorwerp van toepaslike formules dra geen punte nie, maar as ‘n kandidaat begin met die korrekte formule en dan die voorwerp van die formule verkeerd uitwerk, sal punte vir die formule en korrekte substitusie toegeken word. Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 3 1.2.2 When an error is made during substitution into a correct formula, a mark will be awarded for the correct formula and for the correct substitutions, but no further marks will be given. Wanneer ʼn fout gedurende substitusie in ʼn korrekte formule begaan word, sal ʼn punt vir die korrekte formule en vir korrekte substitusie toegeken word, maar geen verdere punte sal toegeken word nie. 1.2.3 Marks are only awarded for a formula if a calculation had been attempted, i.e. substitutions have been made or a numerical answer given. Punte sal slegs toegeken word vir ʼn formule as ʼn poging aangewend was om ʼn berekening te doen d.w.s. substitusie was gedoen of ʼn numerieke antwoord word verskaf. 1.2.4 Marks can only be allocated for substitutions when values are substituted into formulae and not when listed before a calculation starts. Punte kan slegs toegeken word vir substitusies wanneer waardes in formules ingestel is en nie vir waardes wat voor ʼn berekening gelys is nie. 1.2.5 All calculations, when not specified in the question, must be done to two decimal places. Alle berekenings, wanneer nie in die vraag gespesifiseer word nie, moet tot twee desimale plekke gedoen word. 1.3 UNITS/EENHEDE 1.3.1 Candidates will only be penalised once for the repeated use of an incorrect unit within a question or sub-question. ʼn Kandidaat sal slegs een keer gepenaliseer word vir die herhaaldelike gebruik van ʼn verkeerde eenheid in ʼn vraag of subvraag. 1.3.2 Units are only required in the final answer to a calculation. Eenhede word slegs in die finale antwoord tot ʼn vraag verlang. 1.3.3 Marks are only awarded for an answer, and not for a unit per se. Candidates will therefore forfeit the mark allocated for the answer in each of the following situations:  correct answer + wrong unit  wrong answer + correct unit  correct answer + no unit. Punte word slegs vir ʼn antwoord en vir ʼn eenheid per se toegeken nie. Kandidate sal derhalwe die punt vir die antwoord in die volgende gevalle verbeur:  korrekte antwoord + verkeerde eenheid  verkeerde antwoord + korrekte eenheid  korrekte antwoord + geen eenheid 1.3.4 SI units must be used except in certain cases, e.g. V.m-1 instead of N.C-1, and cm.s-1 or km.h-1 instead of m.s-1 where the question warrants this. (This instruction only applies to Paper 1). SI-eenhede moet gebruik word behalwe in sekere gevalle, bv. V.m-1 inplaas van of N.C-1, en cm.s-1 of km.h-1 inplaas van m.s-1 waar die vraag dit verlang. (Hierdie instruksie geld slegs by Vraestel 1). Copyright reserved Please turn over

Downloaded from hlayiso.com 4 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (SEPTEMBER 2014) 1.4 POSTIVE MARKING/POSITIEWE NASIEN Positive marking regarding calculations will be followed in the following cases: Positiewe nasien met betrekking tot berekeninge sal in die volgende gevalle geld: 1.4.1 Sub-question to sub-question: When a certain variable is calculated in one sub-question (e.g. 3.1) and needs to be substituted in another (3.2 or 3.3), e.g. if the answer for 3.1 is incorrect and is substituted correctly in 3.2 or 3.3, full marks are to be awarded for the subsequent sub-questions. Subvraag na subvraag: Wanneer ʼn sekere veranderlike in een subvraag (bv. 3.1) bereken word en dan in ʼn ander vervang moet word (3.2 of 3.3), bv. Indien die antwoord vir 3.1 verkeerd is en word korrek in 3.2 of 3.3 vervang, word volpunte aan die daaropvolgende subvraag toegeken. 1.4.2 A multi-step question in a sub-question: If the candidate has to calculate, for example, current in the first step and gets it wrong due to a substitution error, the mark for the substitution and the final answer will be forfeited. ʼn Vraag met veelvuldige stappe in ʼn subvraag: Indien ʼn kandidaat byvoorbeeld, die aantal mol verkeerd bereken in ʼn eerste stap as gevolg van ʼn substitusiefout, verloor die kandidaat die punt vir die substitusie sowel as die finale antwoord. 1.4.3 If a final answer to a calculation is correct, full marks will not automatically be awarded. Markers will always ensure that the correct/ appropriate formula is used and that workings, including substitutions, are correct. Indien ʼn finale antwoord tot ʼn berekening korrek is, sal volpunte nie outomaties toegeken word nie. Nasieners sal altyd verseker dat die korrekte toepaslike formule gebruik word en dat bewerkings, insluitende substitusies korrek is. 1.4.4 Questions where a series of calculations have to be made (e.g. a circuit diagram question) do not necessarily always have to follow the same order. FULL MARKS will be awarded provided it is a valid solution to the problem. However, any calculation that will not bring the candidate closer to the answer than the original data, will not count any marks. Vrae waar ʼn reeks berekeninge gedoen moet word (bv. ʼn stroombaan diagram vraag) hoef nie noodwendig altyd dieselfde orde te volg nie. VOLPUNTE sal toegeken word mits dit ʼn geldige oplossing tot die probleem is. Maar, enige berekening wat nie die kandidaat nader aan die antwoord bring as die oorspronklike data, sal geen punte tel nie. 1.4.5 If one answer or calculation is required, but two given by the candidate, only the first one will be marked, irrespective of which one is correct. If two answers are required, only the first two will be marked, etc. Indien een antwoord of berekening verlang word, maar twee word deur die kandidaat gegee, sal slegs die eerste een nagesien word, ongeag watter een korrek is. Indien twee antwoorde verlang word, sal slegs die eerste twee nagesien word, ens. Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 5 1.4.6 Normally, if based on a conceptual mistake, an incorrect answer cannot be correctly motivated. If the candidate is therefore required to motivate in question 3.2 the answer given to question 3.1, and 3.1 is incorrect, no marks can be awarded for question 3.2. However, if the answer for e.g. 3.1 is based on a calculation, the motivation for the incorrect answer for 3.2 could be considered. Normaalweg, as dit gebaseer is op ʼn voorstellingsfout, kan ʼn verkeerde antwoord nie korrek gemotiveer word nie. As die kandidaat derhalwe gevra word met ʼn vraag in 3.2 om die antwoord in vraag 3.1 te motiveer, en 3.1 is verkeerd, sal geen punte vir vraag 3.2 toegeken word nie. Maar, as die antwoord in bv. 3.1 gebaseer is op ʼn berekening, kan die motivering vir die verkeerde antwoord oorweeg word. 1.4.7 If instructions regarding method of answering are not followed, e.g. the candidate does a calculation when the instruction was to solve by construction and measurement, a candidate may forfeit all the marks for the specific question. Indien instruksies aangaande metode van beantwoording nie gevolg word nie, bv. die kandidaat doen ʼn berekening wanneer die instruksie los op deur konstruksie en meting was, mag die kandidaat al die punte vir die spesifieke vraag verbeur. 1.4.8 For an error of principle, no marks are awarded (Rule 1) e.g. If the potential difference is 200 V and resistance is 25 Ω, calculate the current. Vir ʼn foutdraendebeginsel, sal geen punte toegeken word nie (Reël 1) bv. As die potensiaalverskil 200 V en die weerstand 25 Ω is, bereken die stroom. CORRECT ANSWER (1) POSSIBLE ANSWER (2) POSSIBLE KORREK ANTW. (1) MOONTLIK ANTW. (2) MOONTLIK 1.5 GENERAL PRINCIPLES OF MARKING IN CHEMISTRY/ ALGEMENE BEGINSELS VAN NASIEN BY CHEMIE The following are a number of guidelines that specifically apply to Paper 2. Die volgende is ʼn aantal riglyne wat spesifiek op Vraestel 2 van toepassing is. 1.5.1 When a chemical FORMULA is asked, and the NAME is given as answer, only one of the two marks will be awarded. The same rule applies when the NAME is asked and the FORMULA is given. Wanneer ʼn chemiese FORMULE gevra word en die NAAM word as antwoord gegee, sal slegs een van die twee punte toegeken word. Dieselfde reël geld wanneer die NAAM gevra word en die FORMULE gegee word. Copyright reserved Please turn over

Downloaded from hlayiso.com 6 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (SEPTEMBER 2014) 1.5.2 When redox half-reactions are to be written, the correct arrow should be used. If the equation H2S → S + 2H+ + 2e- (2/2) is the correct answer, the following marks will be given: Wanneer redokshalfreaksies geskryf moet word, moet die korrekte pyltjie gebruik word. Indien die bostaande vergelyking die korrekte antwoord is, sal die volgende punte toegeken word: H2S ⇋ S + 2H+ + 2e- (1/2) H2S ← S + 2H+ + 2e- (0/2) S + 2H+ + 2e- ← H2S (2/2) S + 2H+ + 2e- ⇋ H2S (0/2) 1.5.3 When candidates are required to give an explanation involving the relative strength of oxidising and reducing agents, the following is unacceptable:  Stating the position of a substance on Table 4 only (e.g. Cu is above Mg).  Using relative reactivity only (e.g. Mg is more reactive than Cu).  The correct answer would for instance be: Mg is a stronger reducing agent than Cu, and therefore Mg will be able to reduce Cu2+ ions to Cu. The answer can also be given in terms of the relative strength as electron acceptors and donors. Wanneer kandidate ʼn verduideliking moet gee oor die relatiewe sterkte van oksideer- en reduseermiddels, is die volgende onaanvaarbaar.  Meld slegs die posisie van ʼn stof op tabel 4 (bv. Cu is bo Mg).  Gebruik slegs relatiewe reaktiwiteit (bv. Mg is meer reaktief as Cu).  Die korrekte antwoord sal byvoorbeeld wees: Mg is ʼn sterker reduseermiddel as Cu en derhalwe sal Mg in staat wees om Cu2+-ione na Cu te reduseer. Die antwoord kan ook in terme van die relatiewe sterkte van elektronakseptors of donors gegee word. 1.5.4 One mark will be forfeited when the charge of an ion is omitted per equation. Een punt sal verbeur word wanneer die lading van ʼn ioon per vergelyking weggelaat is. 1.5.5 The error carrying principle does not apply to chemical equations or half- reactions. For example, if a learner writes the wrong oxidation/reduction half-reaction in the sub-question and carries the answer to another sub- question (balancing of equations or calculations of Eθcell) then the learner is not credited for this substitution. Die foutdraendebeginsel geld nie vir chemiese vergelykings of halfreaksies nie. Byvoorbeeld, indien ʼn leerder die verkeerde oksidasie/reduksie- halfreaksie vir die subvraag skryf en die antwoord na ʼn ander subvraag dra (balansering van vergelyking of E𝜃sel) dan word die leerder nie vir die substitusie gekrediteer nie. Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 7 1.5.6 When a calculation of the cell potential of a galvanic cell is expected, marks will only be awarded for the formula if one of the formulae indicated on the data sheet (Table 2) is used. The use of any other formula using abbreviations etc. will carry no marks. Wanneer ʼn berekening van die selpotensiaal van ʼn galvaniesesel verlang word, sal punte slegs vir die formule toegeken word as een van die formules op die gegewensblad (Tabel 2) gebruik word. Die gebruik van enige ander formule, die gebruik van afkortings, ens. Sal geen punte dra nie. 1.5.7 In the structural formula of an organic molecule all hydrogen atoms must be shown. Marks will be deducted if hydrogen atoms are omitted. In die struktuurformules van ʼn organiese molekuul moet alle waterstofatome getoon word. Punte sal afgetrek word vir die weglating van waterstofatome. 1.5.8 When a structural formula is asked, marks will be deducted if the candidate writes the condensed formula. Wanneer ʼn struktuurformule gevra word, sal punte afgetrek word indien die leerder die gekondenseerde formule skryf. 1.5.9 When an IUPAC name is asked, and the candidate omits the hyphen (e.g. instead of 1-pentene the candidate writes 1 pentene), marks will be forfeited. Wanneer die IUPAC naam gevra word en die koppelteken(s) in die naam word uitgelaat (bv. In plaas van pent-1-een of 1-penteen skryf ʼn kandidaat pent 1 een of 1 penteen), sal punte verbeur word. Copyright reserved Please turn over

Downloaded from hlayiso.com 8 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (SEPTEMBER 2014) SECTION/AFDELING A QUESTION/VRAAG 1 1.1 A (2) 1.2 B (2) 1.3 D (2) 1.4 A (2) 1.5 A (2) 1.6 C (2) 1.7 B (2) 1.8 C (2) 1.9 A (2) 1.10 D (2) TOTAL SECTION/TOTAAL AFDELING A: 20 Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 9 SECTION/AFDELING B QUESTION/VRAAG 2 2.1 √ 2,3-dibromobutane √ CORRECT IUPAC NAME, BUT ONE OR MORE OF THE FOLLOWING ERRORS: OMITTING 2,3-dibroombutaan HYPHENS AND/OR COMMAS; INCLUDING (2) EXTRA HYPHENS AND /OR SPACES 2.2 CnH2n + 1-OH √ MAX/MAKS ½ KORREKTE IUPAC-NAAM MAAR EEN OF (1) MEER VD VOLGENDE FOUTE GEMAAK: WEGLATING VAN KOPPELTEKENS EN/OF 2.3 KOMMAS; INSLUITING VAN EKSTRA SPASIES EN/OF KOPPELTEKENS OR/OF OR/OF (1) 2.4 √ – functional group/funksionele groep √ – rest of structure correct/res van struktuur korrek (2) 2.5 √ – functional group/funksionele groep √ – rest of structure correct/ res van struktuur korrek OR/OF (2) [8] Copyright reserved Please turn over

Downloaded from hlayiso.com 10 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (SEPTEMBER 2014) QUESTION 3 3.1 3.1.1 addition √ addisie 3.2.1/3.2.2/3.4.1 NAMES ONLY/ (1) ALLEENLIK NAME AND/EN 3.1.2 elimination √ V3.3/3.4.3 FORMULAE ONLY/ eliminasie ALLEENLIK FORMULES (1) 3.1.3 substitution √ substitusie (1) 3.2 3.2.1 water √ (1) 3.2.2 (dilute)sulphuric acid / (dilute)phosphoric acid √ (1) (verdunde)swawelsuur / (verdunde)fosforsuur 3.3 -1 FOR CONDENSED/ MOLECULAR FORMULAE -1 VIR GEKONDENSEERD/ MOLEKULÊRE FORMULES IGNORE RULE 3.10/IGNOREER REËL 3.10 -1 FOR ADDITIONAL REACTANTS/ PRODUCTS / VIR ADDISIONELE REAGENSE /PRODUKTE -1 IF ARROW OMITTED/ GEEN PYLTJIE (4) 3.4 3.4.1 propanoic acid √√ propanoësuur (2) 3.4.2 esterification √ or (acid catalysed) condensation esterifikasie of (suur gekataliseerde) kondensasie (1) Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 11 3.4.3 H H O H H √ – functional H C C O C C C H group/funksionele groep √ – rest of structure correct/ H H H H res van struktuur korrek OR/OF H H O H H H C C C O C C H H H H H (2) 3.5 3.5.1 a molecule containing a large number of atoms √ ʼn molekule wat uit ʼn groot aantal atome bestaan (1) 3.5.2 addition √ (polimerisation)/addisie (polimerisasie) (1) 3.5.3 (Any TWO of)/(enige TWEE van) used to make plastic bags/squeeze bottles/clingwrap √√ word gebruik om plastieksakke/spuitbottels/kleefplastiek te maak (2) [18] QUESTION 4 4.1 Relative molecular mass/molar mass √ Relatiewe molekulêre massa/molêre massa (1) 4.2 4.2.1 Boiling point √ Kookpunt (1) 4.2.2 Type of organic compound/homologous series/functional group √ Tipe organiese verbinding/homoloë reeks/funksionele groep (1) 4.3 4.3.1 Saturated√ – single bonds only between C-atoms √ Versadig – alleenlik enkelbindings tussen C-atome (2) 4.3.2 LOWER THAN/LAER AS √ - negative marking (1) 4.3.3  2-methylpropane is a spherical molecule, therefore smaller surface area √ is presented to other molecules(sphere is 3D shape with lowest surface-to-volume ratio)  Less surface area at which van der Waals interactions with other molecules can occur √ /fewer van der Waals interactions/fewer cohesive interactions  Less energy required √ to overcome cohesive forces as liquid hydrocarbon is vaporised Copyright reserved Please turn over

Downloaded from hlayiso.com 12 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (SEPTEMBER 2014)  2-metielpropaan is ʼn sferiese molekule wat ʼn kleiner oppervlaksarea aan ander molekule bied(sfeer is 3D vorm met die laagste oppervlak-tot-volume verhouding)  Minder oppervlakarea waarby van der Waals-interaksies met ander molekule kan plaasvind/minder van der Waals interaksies/minder kohesie interaksies  Minder energie benodig om kohesie kragte te oorkom soos die vloeibare koolwaterstof verdamp (3) 4.4 ethanoic acid – it is possible for 2 √ H-bonds (at C=O and O-H) to form C between adjacent carboxylic acid molecules Therefore H-bonds stronger in carboxylic acid √ Therefore more energy required to √ overcome the stronger Forces of attraction/to break the bonds BETWEEN molecules OR propan-1-ol ─ H-bonds weaker in alcohol √ as it is only possible for 1 H√ B bond at O-H to form between adjacent molecules of alcohol therefore less energy required √ to overcome the strong forces of attraction/to break the bonds BETWEEN molecules etanoësuur – H-bindings sterker in karbosielsuur omdat C dit moontlik is vir 2 H-bindings om te vorm tussen aangrensende molekule van die karboksielsure (by C=O and O-H) en dus word meer energie benodig om Die sterker aantrekkingskragte te oorkom/bindings TUSSEN Molecule te breek OF propan-1-ol – H-bindings swakker in alkohole omdat dit net B moontlik is vir 1 H-binding om te vorm tussen aangrensende molekule van alkohole en dus minder energie benodig om die sterker aantrekkingskragte te oorkom/bindings TUSSEN molekule te breek (3) [12] Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 13 QUESTION 5 5.1 activation energy √ aktiveringsenergie (1) 5.2 5.2.1 _ negative marking C √  total area under graphs A and C more or less the same , but more molecules with greater average Ek therefore area X of graph C greater –more molecules with greater average Ek√ negatiewe merk C  totale area onder grafieke A en C min of meer dieselfde, maar meer molekule met hoër gemiddelde Ek, dus is area X van grafiek C groter meer molecule met hoer gemiddelde Ek (2) 5.2.2  Increased temperature therefore increased average kinetic energy of molecules √  More of these molecules will have sufficient kinetic energy √ to react  More effective collisions per second/unit time √  Increased rate of reaction √  Verhoogde temperatuur daarom verhoogde gemiddelde kinetiese energie van molekules  Meer molekules het genoegsame kinetiese energie om te reageer  Meer effektiewe botsings per sekonde/eenheidstyd  Verhoogde reaksietempo (4) 5.3 5.3.1 A catalyst will speed up a chemical reaction √ (2) without itself undergoing permanent change √ ʼn Katalisator versnel ʼn chemiese reaksie sonder dat dit self ʼn permanente verandering ondergaan 5.3.2 INCREASES/NEEM TOE√ negative marking (1) - 5.3.3 A catalyst will create an alternative path of lower activation energy √ “line Y” moves to the left √ – therefore area X increases in size. ʼn Katalisator skep ʼn alternatiewe roete van laer aktiveringsenergie “lyn Y” beweeg na links – daarom neem area X toe in grootte (2) [12] Copyright reserved Please turn over

Downloaded from hlayiso.com 14 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (SEPTEMBER 2014) QUESTION 6/VRAAG 6 6.1 4NH3 + 5O2 ⇌ 4NO + 6H2O (8) ni 2 1√ 0 0 nu/p 0,4 0,5 √ 0,4 0,6√ratio ne 1,6 0,5 0,4 0,6√ Refer to rule 1.4/ n C = /V√ 0,8 0,25 0,2 0,3 Verwys na reël 1.4 H O 6 NO  ni (NH3) =2 and ni (O2)=1  ne (H2O)=0.6  USE correct ratio (4:5:4:6) GEBRUIK die regte verhouding (4:5:4:6)  Add and subtract correctly. Tel op en trek korrek af  Calculate concentration (ne in every column) Bereken die konsentrasie (ne in elke kolom)  Correct Kc expression/ korrekte uitdrukking  Substitution correct/Korrekte substitusie  Answer correct/Korrekte antwoord Option 2/Opsie 2 4NH3 + 5O2 ⇌ 4NO + 6H2O ci 1 0,5 0 0 cu/p 0,2 0,25 0,2 0,3 ratio ce 0,8 0,25 0,2 0,3 H O 6 NO =  Calculate concentration( ne / 2 in every column)  Bereken die konsentrasie (ne / 2 in elke kolom)  [NH3] = 1 AND [O2] = 0,5  [H2O] = 0,3 (+ marking)  USE correct ratio (4:5:4:6) Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 15 GEBRUIK die regte verhouding (4:5:4:6)  Add and subtract correctly (+marking) Tel op en trek korrek af  Correct Kc-expression/korrekte uitdrukking  Substituion correct/Korrekte substitusie (+marking)  Answer correct/Korrekte antwoord 6.2 [products] < [reactants] √ OR/OF (1) Incomplete forward rxn/onvolledige voorwaartse reaksie OR/OF Low yield/Lae obrengs 6.3 REMAIN THE SAME√/BLY DIESELFDE (1) 6.4 A decrease in pressure causes/ʼn afname in druk veroorsaak  equilibrium to shift towards side with greater number of gas moles√  ewewig verskuif na die kant met die groter hoeveelheid mol gas  equilibrium shifts to the right (9 : 10) √ /forward reaction is favoured  ewewig verskuif na regs (9:10)/ voorwaartse reaksie word bevoordeel  Yield of NO increases √ / increased yield/toename in opbrengs  Number of moles of NO increases/Aantal mol NO neem toe (3) 6.5 negative √/negatief _ negative marking (1) 6.6  decrease in temp favours exothermic reaction √  increase in Kc implies greater [products] √  forward reaction is favoured √ therefore forward reaction is exothermic √  afname in temperatuur bevoordeel eksotermiese reaksie  toename in Kc impliseer hoër [produkte]  voorwaartse reaksie word bevoordeel en dus is voorwaartse reaksie eksotermies (4) [18] Copyright reserved Please turn over

Downloaded from hlayiso.com 16 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (SEPTEMBER 2014) QUESTION 7 (Start on a new page.) 7.1 complete ionisation in solution √ to produces a high concentration of H3O+-ions in solution √ volledige ionisasie in oplossing en lewer ʼn hoë konsentrasie H3O+ (2) 7.2 7.2.1 pH = 3 ∴ pH = – log [H+ √ 3 = – log [H+] pH=3 ∴ [H+] = 10-3 mol·dm-3 √ OR/OF [H+] = 10-3 mol·dm-3 (2) 7.2.2 Weaker than HCℓ √ _ negative marking (1) Swakker as HCℓ 7.2.3 [H+] = 10-3 mol·dm-3 which is less than the [H+] = 10-2 mol·dm-3 of HCℓ√ ( ∴ acid not ionised completely √ therefore weaker than HCℓ OR pH = 3 is greater than pH = 2 for the same concentration of HCℓ (Higher pH implies weaker acid) [H+] = 10-3mol·dm-3 is laer as die [H+] =10-2 mol·dm-3 van HCℓ ∴suur het nie volledig geïoniseer nie en is dus swakker OF pH=3 is groter as pH=2 vir dieselfde konsentrasie van HCℓ (Hoër pH dui op swakker suur) (2) 7.3 7.3.1 Reaction of a salt √ with water √ /reaksie van ʼn sout √ met water √ (2) 7.3.2 √ √ √ NH4Cℓ + H2O  NH3 + H3O+ + Cℓ– OR/OF NH4+ + H2O  NH3 + H3O+ (3) 7.3.3 red √√ /rooi (2) Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 17 7.4 Consider reaction 2/Beskou reaksie 2 na = ca.Va √ nb = cb .Vb ∴ 1 √ = (1) .Va √ 2 = (0,5).28 Va = 7cm3 √ Va = 7cm3 used in reaction 2 ∴ Va = (50-7) = 43cm3 used in reaction 1 √ Consider reaction 1/Beskou reaksie 1 na = CaVa = (1)(0,043) = 0,043 √ mol H2SO4 nH SO = n = 0,0 3 mol √ (ratio 1:1) ∴ = nM √ = (0,0 3)( 0 + 1 + 3(16)√ = 4,3g √ OR/OF Consider reaction 2/Beskou reaksie 2 nNaOH = cV √ (0,5)(0,028) = 0,014 mol NaOH √ 2nH2SO4 :n NaOH √ => 0,007mol H2SO4 √ (ratio :1) n VH2SO4 = /c = 0,007/1 = 0,007 dm3 √ Consider reaction 1/Beskou reaksie 1 VH2SO4 reacting with CaCO3 = 0,05 – 0,007 dm3 = 0,043 dm3 √ nH2SO4 reacting with CaCO3 = cV = (1)(0,043) = 0,0 3 mol √ nH2SO4 = nCaCO3 = 0,043 mol √ (ratio 1:1) mCaCO3 = nM √= (0,0 3)(100) √ = 4,3 g OR/OF Consider reaction 2/Beskou reaksie 2 nNaOH = cV √ (0,5)(0,028) = 0,014 mol √ NaOH 2nH2SO4 excess = nNaOH √ = 0,007 mol √ (ratio :1) Consider reaction 1/ Beskou reaksie 1 nH2SO4 total = cV = 1(0,05) = 0,05 mol √ nH2SO4 reacting with CaCO3 = 0,05 - 0,007 = 0,0 3 mol √ nH2SO4 = nCaCO3 = 0,0 3 mol √ (ratio 1:1) mCaCO3 = nM √= (0,0 3)(100) √= 4,3 g √ (10) [24] Copyright reserved Please turn over

Downloaded from hlayiso.com 18 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (SEPTEMBER 2014) QUESTION 8 8.1 8.1.1  Oxalic acid half-reaction has a lower Eθvalue than the dichromate half reaction √  dichromate ions are therefore the strongest oxidising agents √  and will therefore be reduced √ while oxalic acid is oxidized OR  Oxalic acid half-reaction has a lower Eθvalue than the dichromate half reaction √  oxalic acid molecules will therefore be the strongest reducing agents √  and will therefore be oxidised while dichromate ions are reduced√ OR θ θ - θ E cell = E oxidising agent E reducing agent = (1,33) √- (-0,49)√ = + √ (positive) 1,82 V  Oksaalsuur half-reaksie het ʼn laer Eθ waarde as die dichromaat half-reaksie  dichromaat ione is dus sterkste oksideermiddels en sal dus  gereduseer word terwyl oksaalsuur geoksideer word OF  Oksaalsuur half-reaksie het ʼn laer Eθ waarde as die dichromaat half-reaksie  Oksaalsuurmolekule is dus sterkste reduseermiddels en sal  dus geoksideer word terwyl dichromaatione gereduseer word OF Eθsel = Eθoksideermiddel - Eθreduseermiddel = (1,33) – (-0,49) = + (positief) 1,82 V (3) 8.1.2 Cr2O72- + 14H+ + 6e-  2Cr3+ + 7H2O √ -1 for charges omitted/ H2C2O4  2CO2 + 2H+ + 2e- x3√ -1 as lading Cr2O72- + 8H+ + 3H2C2O4 √ 2Cr3+ + 7H2O + 6CO2 √ uitgelaat is -1 for/vir ⇋ -1 for additional reactants/products -1 vir addisionele reaktante/produkte (4) 8.2 8.2.1 B √√ (2) 8.2.2 Cu  Cu2+ + 2e- √√ Cu ⇋ Cu2+ + 2e- 1/2 Cu ← Cu2+ + 2e- 0/2 Cu2+ + 2e- ← Cu 2/2 Cu2+ + 2e- ⇋ Cu 0/2 (2) Copyright reserved Please turn over

Downloaded from hlayiso.com (SEPTEMBER 2014) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 19 8.2.3 Cu(s)/ Cu2+(aq) √ || H+(aq),H2O2(aq)/ O2(g)/Pt(s) √ √saltbridge Cu(s)/ Cu2+(aq) || H2O2(aq), H+(aq) / O2(g)/Pt(s) Accept/aanvaar: Cu(s)/ Cu2+(aq) || O2(g)/ H+(aq),H2O2(aq)/Pt(s) Cu(s)/ Cu2+(aq) || O2(g)/ H2O2(aq), H+(aq) /Pt(s) (3) 8.2.4 Eθcell = Eθcathode/katode - Eθanode √ OR any other formula from datasheet/ OF enige ander formule van inligtingsblaai af = 0,68 √ – (0,3 ) √ = 0,3 V √ -1 for using unconventional abbreviations/ onkonvensionele afkortings gebruik (4) 8.2.5 decrease in Vcell as [product ions] increase √ and [reactant ions] decrease √ rate of forward reaction decrease while rate of reverse reaction increase √ Vcell = 0 and no current flows when dynamic equilibrium is reached i.e. when rate of forward reaction = rate of reverse reaction √ afname in Vsel as [produk ione] toeneem [reaktant ione] afneem reaksietempo vir voorwaartse reaksie neem af terwyl reaksietempo vir teruwaartse reaksie toeneem Vsel = 0 en geen stroom vloei meer nie sodra dinamiese ewewig ingestel word, dus as reaksietempo van voorwaartse reaksie = reaksietempo van terugwaartse reaksie (4) [22] Copyright reserved Please turn over

Downloaded from hlayiso.com 20 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (SEPTEMBER 2014) QUESTION 9 (Start on a new page.) 9.1 fractional distillation of liquid air √ fraksionele distillasie van vloeibare lug (1) 9.2 N2 + 3H2 √ ⇋ 2NH3 √ balanced √ (3) 9.3 Ammonium sulphate √√ Ammoniumsulfaat (2) 9.4 Vanadium pentoxide √ Reactants come into contact with layers of the catalyst. √ Vanadiumpentoksied √ Reagense kom in kontak met lae van die katalisator. √ (2) 9.5 ANY TWO OF:  contain lower levels of nutrients √ therefore use more of it/cost more √  variable composition √/lead to lower yield of crop/crop failure √  may contain animal and plant pathogens √ cause diseases in animals/ humans √  organically grown produce is expensive √ poorer people cannot afford to buy √ ENIGE TWEE VAN:  bevat laer vlakke van voedingstof moet dus meer gebruik/koste verhoog  samestelling varieer en kan lei tot laer opbrengs van oes/mislukte oes  mag plant- of dierpatogene bevat wat siektes by mense en diere veroorsaak  organies geproduseerde produkte is baie duur en armer mense kan dit nie bekostig nie (4) 5 9.6 9.6.1 /9 x 6% √ =1 , %K√ (2) 9.6.2  Healthy growth /healthy development of good quality flowers and fruit √  Keep plant frost/disease resistant √  Gesonde groei/gesonde ontwikkeling van goeie kwaliteit blomme en vrugte  Hou plante bestand teen ryp/siektes (2) [16] TOTAL SECTION B/TOTAAL AFDELING B: 130 GRAND TOTAL/GROOTTOTAAL: 150 Copyright reserved Please turn over