Physical Sciences Grade 12 Paper 2 Free State Mock 2018 Memo

Downloaded from hlayiso.com PREPARATORY EXAMINATION VOORBEREIDENDE EKSAMEN GRADE/GRAAD 12 PHYSICAL SCIENCES: CHEMISTRY (P2) FISIESE WETENSKAPPE: CHEMIE (V2) SEPTEMBER 2018 MARKS/PUNTE: 150 MEMORANDUM This memorandum consists of 15 pages. Hierdie memorandum bestaan uit 15 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 2 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum QUESTION 1/VRAAG 1 1.1 C (2) 1.2 A (2) 1.3 D (2) 1.4 D (2) 1.5 A (2) 1.6 C (2) 1.7 D (2) 1.8 B (2) 1.9 B (2) 1.10 D (2) [20] QUESTION 2/VRAAG 2 2.1.1 A (1) 2.1.2 ANY TWO/ENIGE TWEE B C D (1) 2.2 2.2.1 Compounds with the same molecular formula but different types of chains. Verbindings met dieselfde molekulêre formule, maar verskillende soort kettings. (2) 2.2.2 IF/INDIEN: • H atom omitted/H-atoom uitgelaat: - 1 • Condensed structure/Gekondenseerde struktuur: -1 (2) 2.3 H2 (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 3 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum 2.4 2.4.1 Butanal/Butanaal (1) 2.4.2 3-methyl but-1-yne /3-methyl-1-butyne 3-metielbut-1-yn/3-metiel-1-butyn (2) 2.5 Marking guidelines/Nasienriglyne • Ignore/Ignoreer ⇌ • Accept H2O if condensed./Aanvaar H2O as gekondenseerd. • Any additional reactants and/or products/Enige addisionele reaktanse en/of produkte: Max./Maks. 3/4 • Accept coefficients that are multiples. Aanvaar koëffisiënte wat veelvoude is. • Incorrect balancing/Verkeerde balansering: Max./Maks. 3/4 • Condensed formulae/Gekondenseerde formules: Max./Maks. 3/4 Molecular formulae/Molekulêre formules: Max./Maks. 1/4 (4) 2.6 Marking criteria/Nasienriglyne: • At least one structural formula of ethanol as shown. Ten minste een struktuurformule van etanol soos aangetoon. • Dotted line drawn from O-atom of one molecule to H-atom bonded to an O-atom in the second molecule (H-atom should be between two O- atoms). Stippellyn getrek vanaf O-atoom op een molekuul na 'n H-atoom gebind aan 'n O-atoom in die tweede molekuul (H-atoom moet tussen twee O- atome wees). (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 4 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum 2.7 2.7.1 Addition polymerisation/Addisiepolimerisasie (1) 2.7.2 n Bal. n Marking guidelines/Nasienriglyne • Ignore/Ignoreer ⇌ • Any additional reactants and/or products/Enige addisionele reaktanse en/of produkte: Max./Maks. 2/3 • Incorrect balancing/Verkeerde balansering: Max./Maks. 2/3 • Condensed formulae/Gekondenseerde formules: Max./Maks. 2/3 • Molecular formulae/Molekulêre formules: 0/3 (3) [20] QUESTION 3/VRAAG 3 3.1 Haloalkanes/Alkyl halides/Haloalkane/Alkielhaliede (1) 3.2 3.2.1 London forces/dispersion forces/induced dipole forces Londonkragte/dispersiekragte/geïnduseerde dipoolkragte (1) 3.2.2 Structure/Struktuur: Compound B has a longer chain length/larger molecular size/molecular structure/molecular mass/surface area than compound A. Verbinding B het 'n langer kettinglengte/groter molekulêre grootte/ molekulêre struktuur/molekulêre massa/oppervlak as verbinding A. Intermolecular forces/Intermolekulêre kragte: Stronger intermolecular forces/induced dipole forces/London forces/ dispersion forces/Van der Waals forces. Sterker intermolekulêre kragte/geïnduseerde dipoolkragte/Londonkragte/ dispersiekragte/Van der Waalskragte. Energy/Energie: More energy needed to overcome/break intermolecular forces. Meer energie benodig om intermolekulêre kragte te oorkom/breek. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 5 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum OR/OF Structure/Struktuur: Compound A has a shorter chain length/smaller molecular size/molecular structure/molecular mass/surface area than compound B. Verbinding A het 'n korter kettinglengte/kleiner molekulêre grootte/ molekulêre struktuur/molekulêre massa/oppervlak as verbinding B. Intermolecular forces/Intermolekulêre kragte: Weaker intermolecular forces/induced dipole forces/London forces/ dispersion forces/Van der Waals forces. Swakker intermolekulêre kragte/geïnduseerde dipoolkragte/Londonkragte/ dispersiekragte/Van der Waalskragte. Energy/Energie: Less energy needed to overcome/break intermolecular forces. Minder energie benodig om intermolekulêre kragte te oorkom/breek. (3) 3.3 Positional (isomers)/Posisie(-isomere) (1) 3.4.1 69 °C (1) - 3.4.2 • Compare compound D to compound B: Vergelyk verbinding D met verbinding B: Compound D is more branched/more compact/has a smaller surface area than compound B. Verbinding D is meer vertak/meer kompak/het 'n kleiner oppervlak as verbinding B. • Compare compound D to compound E: Vergelyk verbinding D met verbinding E: Compound D is less branched/has a longer chain length/larger surface area than compound E. Verbinding D is minder vertak/het 'n langer kettinglengte/het 'n groter oppervlak as verbinding E. • Intermolecular forces in compound D are weaker than in compound B and stronger than in compound E. Intermolekulêre kragte in verbinding D is swakker as in verbinding B en sterker as in verbinding E. • Less energy is needed to overcome/break intermolecular forces in compound D than in compound B and more energy is needed to overcome/break intermolecular forces in compound D than in compound E. Minder energie benodig om intermolekulêre kragte in verbinding D te oorkom/breek as in verbinding B en meer energie benodig om intermolekulêre kragte in verbinding D te oorkom/breek as in verbinding E. (4) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 6 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum QUESTION 4/VRAAG 4 4.1 4.1.1 Z (1) 4.1.2 X (1) 4.1.3 V (1) 4.1.4 Y (1) 4.2 4.2.1 Propan-2-ol/2-propanol (1) 4.2.2 Propane/propaan (1) 4.3 4.3.1 Both reactions take place in the presence of a strong base/NaOH/ KOH/LiOH. Beide reaksies vind plaas in teenwoordigheid van 'n sterk basis/NaOH/ KOH/LiOH. (1) 4.3.2 Y: concentrated base/ethanolic base & Z: dilute base/base in water/water Y: gekonsentreerde basis/etanoliese basis & Z: verdunde basis/basis in water/water Y: heat (strongly)/high temperature & Z: mild heat Y: verhit (sterk)/hoë temperatuur & Z: matige hitte (2) 4.3.3 H H H H H H H C C C H + H - Br H C C C H H H Br H Marking guidelines/Nasienriglyne • Ignore/Ignoreer ⇌ • Accept HBr if condensed./Aanvaar HBr as gekondenseerd. • Any additional reactants and/or products/Enige addisionele reaktanse en/of produkte: Max./Maks. 2/3 • Accept coefficients that are multiples. Aanvaar koëffisiënte wat veelvoude is. • Incorrect balancing/Verkeerde balansering: Max./Maks. 2/3 • Condensed formulae/Gekondenseerde formules: Max./Maks. 2/3 • Molecular formulae/Molekulêre formules: Max./Maks. 1/3 (3) [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 7 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum QUESTION 5/VRAAG 5 5.1 5.1.1 (a) Concentration (of Na2S2O3)/Konsentrasie (van Na2S2O3) (1) (b) To dilute (the Na2S2O3)/Om Na2S2O3 te verdun. OR/OF Decrease concentration (of Na2S2O3.) Verminder konsentrasie (van Na2S2O3.) (1) 5.1.2 Graph of volume of Na2S2O3(aq) versus reaction rate Grafiek van volume Na2S2O3(aq) teenoor reaksietempo 30 25 Volume Na2S2O3(aq) (cm3) 20 15 10 5 0 0 0,02 0,04 0,06 0,08 0,10 0,12 0,14 -1 Reaction rate/Reaksietempo (s ) Marking criteria/Nasienriglyne Any three points plotted correctly./Enige drie punte korrek gestip. All the points plotted correctly./ Alle punte korrek gestip. Best-fit line drawn./Beste paslyn getrek. (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 8 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum 1 1 1 5.1.3 / = = 0,09 (s-1 ) reaction time reaksietyd 11 On graph: Dotted line starting from 0,09 s on x axis drawn to y axis as shown on graph. Op grafiek: Stippellyn geteken vanaf 0,09 s op x-as na y-as soos getoon op grafiek. Reading on y axis/Lesing op y-as: 17,5 cm3 (Accept/Aanvaar: 17 – 18 cm3) Note/Let wel: Award mark for answer only if 0,09 s used and dotted lines shown on graph./Ken punt vir antwoord slegs toe indien 0,09 s gebruik is en stippellyn op grafiek aangetoon is. (3) 5.1.4 Higher than/Hoër as - OPTION 1/OPSIE 1 In experiment 1/In eksperiment 1: • More (Na2S2O3) particles per unit volume. Meer (Na2S2O3)-deeltjies per eenheidsvolume. • More effective collisions per unit time. Meer effektiewe botsings per eenheidstyd. OPTION 2/OPSIE 2 In experiment 5/In eksperiment 5: • Less (Na2S2O3) particles per unit volume. Minder (Na2S2O3)-deeltjies per eenheidsvolume. • Less effective collisions per unit time . Minder effektiewe botsings per eenheidstyd. (3) 5.2 5.2.1 The minimum energy needed for a reaction to take place. Die minimum energie benodig vir 'n reaksie om plaas te vind. (2) 5.2.2 (a) - 20 kJ•mol-1 (1) (b) 185 kJ•mol-1 (1) 5.2.3 Reverse (reaction)/Terugwaartse (reaksie) (1) [16] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 9 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum QUESTION 6/VRAAG 6 6.1 Reversible reaction/Omkeerbare reaksie (1) 6.2 Marking criteria/Nasienriglyne: • Use M(NH4Cℓ) = 53,5 g·mol-1 to calculate n(NH4Cℓ) Gebruik M(NH4Cℓ) = 53,5 g·mol-1 om n(NH4Cℓ) te bereken. • m(NH4Cℓ)used/gebruik = m(NH4Cℓ)initial/begin - m(NH4Cℓ)equil/ewe OR/OF n(NH4Cℓ)used/gebruik = n(NH4Cℓ) initial/begin - n(NH4Cℓ) equil/ewe • USING ratio/GEBRUIK verhouding: NH4Cℓ : NH3 : HCℓ = 1 : 1 : 1 • n(NH3)equil/ewe = n(NH3)form/gevorm & n(HCℓ)equil/ewe = n(HCℓ)form/gevorm • Divide/Deel n(NH3)equil/ewe & n(HCℓ)equil/ewe by/deur 0,5 dm3 • Correct KC expression/Korrekte Kc-uitdrukking • Substitution of concentrations into KC expression. Vervang konsentrasies in Kc-uitdrukking. • Final answer/Finale antwoord: to/tot 0,01 Range/Gebied: 0,009,447 x 10-3 to/tot 0,01 OPTION 1/OPSIE 1 NH4Cℓ(s) NH3(g) HCℓ(g) Initial quantity (mol) 10,7 = 0,2 0 0 Aanvanklike hoeveelheid (mol) 53,5 Change (mol) Ratio/ 0,05 0,05 0,05 Verandering (mol) verhouding Quantity at equilibrium (mol) 8,1 = 0,15 0,05 0,05 Hoeveelheid by ewewig (mol) 53,5 Equilibrium concentration Ewewigskonsentrasie - 0,1 0,1 Divide by/Deel (mol·dm-3) deur 0,5 Kc = [NH3][HCℓ] No KC expression, correct substitution/Geen Kc- = (0,1)(0,1) uitdrukking, korrekte vervanging: Max./Maks. 7/8 = 0,01 Wrong KC expression/Verkeerde Kc-uitdrukking: Max./Maks. 5/8 IF/INDIEN: [NH4Cℓ] = 1 in Kc = [NH3][HCℓ] [NH4Cℓ] No mark for Kc expression, but continue marking substitution and answer. Geen punt vir Kc-uitdrukking, maar sien substitusie en antwoord na. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 10 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum OPTION 2/OPSIE 2: ∆m(NH4Cℓ) = 10,7 – 8,1 = 2,6 g ∆n(NH4Cℓ) = 2,6 = 0,05 mol 53,5 ∆n(NH3) = ∆n(NH4Cℓ) = 0,05 mol ∆n(HCℓ) = ∆n(NH4Cℓ) = 0,05 mol n(NH3)equi/ewe = n(NH3)initial/begin + ∆n(NH3) = 0,05 mol n(HCℓ) equi/ewe = ∆n(HCℓ)initial/begin + ∆n(HCℓ) = 0,05 mol [NH3]equi/ewe = 0,05 = 0,1 mol 0,5 Divide by/Deel deur 0,5 [HCℓ]equi/ewe = 0,05 = 0,1 mol 0,5 No KC expression, correct substitution/Geen Kc- Kc = [NH3][HCℓ] uitdrukking, korrekte vervanging: Max./Maks. 7/8 = (0,1)(0,1) Wrong KC expression/Verkeerde Kc-uitdrukking: = 0,01 Max./Maks. 5/8 IF/INDIEN: [NH4Cℓ] = 1 in Kc = [NH3][HCℓ] [NH4Cℓ] No mark for Kc expression, but continue marking substitution and answer. Geen punt vir Kc-uitdrukking, maar sien substitusie en antwoord na. (8) 6.3 Endothermic/Endotermies - • Increase in temperature increases concentration of products/favours forward reaction. Toename in temperatuur verhoog die konsentrasie van die produkte/bevoordeel die voorwaartse reaksie. • Increase in temperature favours the endothermic reaction. Toename in temperatuur bevoordeel die endotermiese reaksie. (3) 6.4 6.4.1 Remains the same/Bly dieselfde (1) 6.4.2 Increases/Verhoog (1) 6.4.3 Remains the same/Bly dieselfde (1) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 11 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum QUESTION 7/VRAAG 7 7.1 7.1.1 A dilute base contains a small amount/number of moles of base in proportion to the volume of water and a concentrated base contains a large amount/number of moles of base in proportion to the volume of water. 'n Verdunde basis bevat 'n klein hoeveelheid/aantal mol basis in verhouding tot die volume water en 'n gekonsentreerde basis bevat 'n groot hoeveelheid/aantal mol basis in verhouding tot die volume water. (2) 7.1.2 Phosphoric acid (solution)/Fosforsuur(oplossing) (1) 7.1.3 (a) Increases/Toeneem (1) (b) Increases/Toeneem (1) 7.2 7.2.1 Marking criteria/Nasienriglyne: n • Formula/Formule: pH = -log [H3O+] OR/OF c = v • Substitute/Vervang pH = 2. • Use mol ratio/Gebruik molverhouding: n(H3PO4) : n(H3O+) = 1:3 • Substitute/Vervang [H3PO4] & 0,5 dm3 in n= cV. • Final answer/Finale antwoord: 1,67 x 10-3 mol / 1,665 x 10-3 mol pH = -log [H3O+] 2 = -log [H3O+] [H3O+] = 0,01 mol·dm-3 [H3PO4] = [H3O+] Any one/Enige een = x 0,01 = 3,33 x 10-3 mol·dm-3 n(H3PO4)ini/aanv = cV = (3,33 x 10-3)(500 x 10-3) = 1,67 x 10-3 mol (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 12 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum 7.2.2 POSITIVE MARKING FROM QUESTION 7.2.1. POSITIEWE NASIEN VANAF VRAAG 7.2.1. Marking criteria/Nasienriglyne: • Use M = 58 g·mol-1 to calculate n(Mg(OH)2)reacted Gebruik M = 58 g·mol-1 om n(Mg(OH)2)gereageer te bereken. • Use mol ratio/Gebruik molverhouding: n(H3PO4) : n(Mg(OH)2) = 2:3 • Subtraction/Aftrekking: n(H3PO4)excess/oormaat = n(H3PO4)initial/aanvanklik - n(H3PO4)react/reageer • Use Va = 14 x 10-3 dm3/14 cm3. Gebruik Va = 14 x 10-3 dm3/14 cm3. • Use mol ratio/Gebruik molverhouding: n(H3PO4) : n(NaOH) = 1:3 • Use Vb = 25 x 10-3 dm3/25 cm3 to calculate [NaOH]. Gebruik Vb = 25 x 10-3 dm3/25 cm3 om [NaOH] te bereken. • Final answer/Finale antwoord: 9,58 x 10-5 mol·dm-3 Range/Gebied: 9,66 x 10-4 to/tot 9,76 x 10-4 mol·dm-3 m n(Mg(OH)2) = M 0,12 = 58 = 2,07 x 10-3 mol n(H3PO4)reacted/reageer = ⅔n(Mg(OH)2) = ⅔(2,07 x 10-3) = 1,38 x 10-3 mol n(H3PO4)excess/oormaat = 1,67 x 10-3 - 1,38 x 10-3 = 2,9 x 10-4 mol 14 n(H3PO4)excess/oormaat in 14 cm3 = 2,9 x 10-4 x 500 = 8,12 x 10-6 mol n(NaOH) = 3n(H3PO4) = 3(8,12 x 10-6) = 2,44 x 10-5 mol n cb = V 2,44 × 10-5 = 25 × 10-3 = 9,76 x 10-4 mol·dm-3 (7) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 13 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum QUESTION 8/VRAAG 8 8.1 Galvanic/Galvanies (1) 8.2 Ag (1) 8.3 Zn → Zn2+ + 2e- Marking guidelines/Nasienriglyne: • Zn ⇌ Zn2+ + 2e- 12 Zn2+ + 2e- ⇌ Zn 0 2 Zn2+ + 2e- ← Zn 2 2 Zn2+ + 2e- → Zn 0 2 • Ignore if charge omitted on electron./Ignoreer indien lading op elektron weggelaat word. • If charge (+) omitted on Cu2+/Indien lading (+) weggelaat op Zn2+: 2 - Max./Maks: 1 Example/Voorbeeld: Zn → Zn + 2e 2 (2) 8.4 Increases/Verhoog (1) 8.5 n(Zn) = ½n(Ag) = ½ x 0,02 = 0,01 mol (4) 8.6 8.6.1 Pressure/Druk: 1,013 x 105 Pa/101,3 kPa/1 atm (1) 8.6.2 Zn(s) | Zn2+(aq) (1 mol·dm-3) || H+(aq) (1 mol·dm-3) | H2 (g) | Pt(s) OR/OF Zn(s) | Zn2+(aq) || H+(aq) | H2 (g) | Pt(s) OR/OF Zn | Zn2+ || H+ | H2 | Pt (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 14 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum 8.6.3 OPTION 1/OPSIE 1: Notes/Aantekeninge • Accept any other correct formula from the data sheet./Aanvaar enige ander korrekte formule vanaf = 0 - (-0,76) gegewensblad. = 0,76 V • Any other formula using unconventional abbreviations, e.g. E°cell = E°OA - E°RA followed by correct substitutions:/Enige ander formule wat onkonvensionele afkortings gebruik bv. E°sel = E°OM - E°RM gevolg deur korrekte vervangings: 3/4 Option 2: 2H+ + 2e- → H2 E° = 0,00 (V) Zn → Zn2+ + 2e- E° = 0,76 (V) (4) [17] QUESTION 9/VRAAG 9 9.1 The process in which electrical energy is converted to chemical energy. Die proses waarin elektriese energie omgeskakel word na chemiese energie. OR/OF The use of electrical energy to produce a chemical change. Die gebruik van elektriese energie om 'n chemiese verandering te weeg te bring. (2) 9.2 Oxidation/Oksidasie (1) 9.3 A substance that loses electrons/donates electrons. 'n Stof wat elektrone verloor/skenk. (2) 9.4 Cℓ–/chloride (ion)/Chloried(ioon) Accept/Aanvaar: NaCℓ/sodium chloride/natriumchloried. (1) 9.5 2H2O(ℓ) + 2e- → H2(g) + 2OH-(aq) Marking guidelines/Nasienriglyne: • 2H2O + 2e- ⇌ H2+ 2OH- 12 Zn2+ + 2e- ⇌ Zn 0 2 - - H2 + 2OH ← 2H2O + 2e 2 2 H2 + 2OH → 2H2O + 2e- 0 2 - • Ignore if charge omitted on electron./Ignoreer indien lading op elektron weggelaat word. - - • If charge (-) omitted on OH /Indien lading (-) weggelaat op OH : Max./Maks: 1 Example/Voorbeeld: 2H2O + 2e- → H2 + 2OH 2 (2) 9.6 Carbon/C/koolstof/platinum/Pt (1) [9] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 15 FS/VS/September 2018 Grade/Graad 12 Prep.Exam./Voorb.Eksam. Memorandum QUESTION 10/VRAAG 10 10.1 10.1.1 N2(g) + 3H2(g) → 2NH3(g) balancing/balansering Marking criteria/Nasienriglyne: • Reactants Products Balancing Reaktanse Produkte Balansering • Ignore phases./Ignoreer fases. • Ignore double arrows./Ignoreer dubbelpyle. • Marking rule 6.3.10/Nasienreël 6.3.10. (3) 10.1.2 Contact (process)/Kontak(proses) (1) 10.1.3 H2SO4 + 2NH3 → (NH4)2SO4 balancing/balansering Marking criteria/Nasienriglyne: • Reactants Products Balancing Reaktanse Produkte Balansering • Ignore phases./Ignoreer fases. • Ignore double arrows./Ignoreer dubbelpyle. • Marking rule 6.3.10/Nasienreël 6.3.10. (3) 10.2 10.2.1 (Fertiliser) S (1) - 10.2.2 Higher N for leaf production. Hoër N vir blaarproduksie. (2) 10.2.3 OPTION 1/OPSIE 1: OPTION 2/OPSIE 2: (3) [13] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief