Gauteng-Physical-Sciences-Grade-12-March-2023-QP-and-Memo.pdf

i widoaded from Stanmorephysics.com GRADE 12 CONTROLLED TEST education Department: Education GAUTENG PROVINCE NATIONAL SENIOR CERNE AT! MARKS: 100 TIME: 2 hours This question paper consists of 13 pages and 3 data sheets. Copyright reserved Please turn over

Downloaded from Stanmor ephysics.rognal sciences Grade 12 controlled test INSTRUCTIONS AND INFORMATION 1. Write your NAME in the appropriate space on the ANSWER BOOK. 2. This question-paper consists of ELEVEN questions. Answer ALL the questions in the ANSWER BOOK. 3. Start EACH) question on a NEW page in the ANSWER BOOK. 4. Number the answers correctly according to the numbering system used in the question paper. 5. Leave ONE line between two sub questions, for example between QUESTION 2.1 and QUESTION 2.2. 6. You may use a non-programmable calculator. 7. You may use appropriate mathematical instruments. 8. You are advised to use the attached DATA SHEETS. 9. Show ALL formulae and substitutions in ALL calculations. 10. Round off your FINAL numerical answers to a minimum of TWO decimal places. 11. — Give brief motivations, discussions, et cetera where required. 12. Write neatly and legibly.

Downloaded from Stanmorephysics.ragaital sciences Grade 12 controlled test QUESTION 1: MULTIPLE-CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Write only the letter (A-D) of the answer next to the question number (1.1 — 1.10) in the ANSWER BOOK. 1.1. A trolley moves on a flat, horizontal surface when a constant force, F, is applied to it. F oxomma Which ONE of the following physical quantities will ALWAYS remain constant while the trolley is moving? momentum acceleration kinetic energy gravitational potential energy lwhekei 2 (2) 1.2. An object, moving vertically upwards, reaches a maximum height and falls back to the ground. Ignore air resistance. Which ONE of the following statements is TRUE? The object experiences an acceleration which .... is always downwards is first upwards and then downwards is first downwards and then upwards decreases first and then increases whem 2 (2) 1.3. A satellite experiences a gravitational force of magnitude F on the surface of the earth. The radius of the earth is R. The satellite now circles the earth at an unknown height above the surface of the earth and experiences a gravitational force of magnitude % F. This unknown height is .... A R B 2R Cc 3R D 4R (2)

Downloaded from Stanmor ephysics.rognal sciences Grade 12 controlled test 1.4 A spacecraft, made up of two modules R and J of masses 3m and m respectively, is travelling horizontally at a velocity v due east. An explosion causes the two modules to separate. N R J E 3m m Module J continues in its original direction immediately after the explosion with a velocity of 3v. What will be the magnitude and direction of module R’s velocity immediately after the explosion? Magnitude of velocity of R | Direction of R after explosion A iv East B 1v West Cc AN East D AV West (2) 1.5 Consider the structural formula of an organic compound below. H oH | | H—E—C=0 H Which ONE of the following is the correct IUPAC name of this compound? A Ethanone B Ethene. C Ethanol D_ Ethanal. (2) 1.6 Which ONE of the following reaction types can be used to prepare ETHENE from bromoethane? A Hydrogenation B Substitution C Dehydrohalogrnation D Addition (2)

Downloaded from Stanmor ephysics.rognal sciences Grade 12 controlled test 1.7. Consider the structural formula of an organic compound below. H H HOH n—ton H | H | H Hc —C==¢—e —¢-n | 4 H—C—H | H Which ONE of the following is the correct IUPAC name of this compound? 2,2,4-trimethylpent-2-ene 2,2,4-trimethylpent-3-ene 2,4,4-trimethylpent-2-ene 2,4,4-trimethylpent-3-ene (2) VUNDN>Y 1.8The following equation represents the cracking of a hydrocarbon at high temperature and pressure: Cy, Hyg — 2C,H, + ¥4+C Hy Which ONE of the following is the IUPAC name of product Y? A Prop-1-ene. B Propane. Cc Ethene. D Ethane. (2) 1.9Consider the structural formula of a compound below. LOT G4 I} i rn nn an H H H H Which ONE of the following pairs of reactants can be used to prepare this compound in the laboratory? Propanoic acid and ethanol Propanoic acid and methanol Ethanoic acid and propan-1-ol Methanoic acid and propan-1-ol (2) wen

Downloaded from Stanmor ephysics.rognal sciences Grade 12 controlled test 1.10 Which ONE of the following combinations correctly indicates the STRONGEST intermolecular forces found in ethanol, ethanoic acid and ethyl ethanoate respectively? ETHANOL ETHANOIC ACID ETHYL ETHANOATE A_| Hydrogen-bonds Dipole-dipole forces _| Hydrogen bonds B_| Hydrogen‘bonds Hydrogen bonds Dipole-dipole forces C_| Hydrogen bonds Hydrogen bonds Hydrogen bonds D_| Dipole-dipole forces _| Hydrogen bonds Dipole-dipole forces (2) [20] QUESTION 2 (Begin on a new page.) Two blocks of masses 5 kg and 3 kg respectively are connected by a light inextensible string that runs over a light frictionless pulley as shown in the diagram below. The 5 kg block experience a frictional force of 8 N and the coefficient of kinetic friction between the 3 kg block and the surface of the inclined plane is 0,15. 5k aN SN, 30° 2.1 Define the term frictional force. (2) 2.2 Draw a labelled free-body diagram to indicate all the forces acting on the 3 kg block. (3) 2.3 Calculate the: 2.3.1 Magnitude of the frictional force acting between the 3 kg block and the surface of the inclined plane (3) 2.3.2 Magnitude of the tension T in the string (6) [14]

Downloaded from Stanmorephysics.ragaital sciences Grade 12 controlled test QUESTION 3 (Begin on a new page.) Ball A is thrown vertically downwards from the top of a building, 80 m high, at a velocity of 12 m-s‘t. At the same instant a second identical ball B is thrown upwards at a velocity of 30 m-s:!. Ball A and ball B pass each other after 2,135 s. Ignore all effects of air friction; A Taz mst 80m 30 m.st B 3.1 Give the direction of the acceleration of ball B while moving upwards. (1) 3.2 Calculate the velocity of ball B the moment it passes ball A. (3) 3.3 Calculate the distance between ball A and B 2,5 s after it was projected. (6) 3.4 Sketch a position-time graph for the motion of ball A till it reaches the ground as well as for the motion of ball B until it passes ball A. Use the ground as zero position. Clearly indicate the time at which the balls pass each other. (3) [13] QUESTION 4 (Begin on a new page.) A trolley, mass 5 kg, moves at 4 m-s? east across a frictionless horizontal surface. A brick of mass 1,5 kg is dropped onto the trolley. 1,5 kg| | 4m-st 5 kg —_——> © C 4.1 Define in words the Law of Conservation of Momentum. (2) 4.2 State the condition for an elastic collision. (1) 4.3 Calculate the change in momentum of the 5 kg trolley. (5) [8]

5.1 5.2 Downloaded from Stanmorephysics.ragaital sciences Grade 12 controlled test QUESTION 5 The structural formula of an unsaturated compound is given below. 5.1.1 5.1.2 Define the term unsaturated compound. Write down the IUPAC name of the compound. Butanoic acid is a FUNCTIONAL isomer of methyl propanoate. 5.2.1 5.2.2 5.2.3 5.2.4 5.2.5 5.2.6 Write down the NAME of the functional group of butanoic acid. Draw the STRUCTURAL formula of butanoic acid. Draw the STRUCTURAL formula of methyl propanoate. Explain why butanoic acid and methyl propanoate are described as FUNCTIONAL isomers. Write down the IUPAC name of the alcohol used to prepare methyl propanoate. Write down the IUPAC name of a POSITIONAL isomer of methyl propanoate. (2) (2) (2) (2) (2) (2) (2) (2) [18]

Downloaded from Stanmor ephysics.rognal sciences Grade 12 controlled test QUESTION 6 [START ON A NEW PAGE] A learner conducts an investigation to determine the boiling points of different organic compounds. The data_is recorded in the table below. FORMULA MOLECUAR MASS (g-mor) BOILING POINT (CC) A | CH3(GH3)40H 88 138 B | CHs(CH2)sCHO 86 103 C | CHs(CH2)2CO2H 88 164 D | CHs(CH2)4CH3 86 69 6.1 Write down the IUPAC name for compound B. (2) 6.2 Is compound A considered as a PRIMARY, SECONDARY or TERTIARY alcohol? Give a reason for the answer. (2) 6.3 The boiling point of compound B is now compared with the boiling point of compound D. 6.3.1 Is this a fair comparison? Write down YES or NO. Refer to the data in the table and give a reason for the answer. (2) 6.3.2 Refer to INTERMOLECULAR forces and explain why compound B has a higher boiling point than compound D. (3) 6.4. Another learner investigates the vapour pressure of the compounds in the table. 6.4.1 Define the term vapour pressure. (2) 6.4.2. Which compound, A or C has the HIGHEST vapour pressure? (2) [13]

Downloaded from Stanmorephysics.ragaital sciences Grade 12 controlled test QUESTION 7 [START ON A NEW PAGE] The flow diagram below represents the interconversion between the following three organic compounds: butan-2-ol, compound X and compound Y. Butan-2-ol Reaction B Reaction C Reaction A Compound X (major product) H i; H H H Cc Cc c c H Reaction D H H H H Compound Y 7.1 Reaction B represents the ELIMINATION of water from butan-2-ol to form compound X. 7.1.1 Write down the NAME of a catalyst required in reaction B. (1) 7.1.2. Name the TYPE of elimination reaction represented by reaction B. (1) 7.1.3. Using STRUCTURAL FORMULAE, write down a balanced equation for reaction B. (4) 7.2 State the TWO reaction conditions for reaction A? (2) 7.3 Which GENERAL type of reaction takes place in reaction C? (2) 7.4 Write down the: 7.4.1 IUPAC name of compound Y. (2) 7.4.2 Reaction condition for reaction D. (2) [14] Grand Total: 100

Downloaded from Stanmor éphysics.rognal sciences Grade 12 controlled test DATA FOR PHYSICAL SCIENCES GRADE 12 PAPER 1 (PHYSICS) GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12 pat VRAESTEL 1 (FISIKA) TABLE ‘pivateat CONSTANTS/TABEL 1: FISIESE KONSTANTES SRAME/NAAM SYMBOL/S/MBOOL VALUE/WAARDE Acceleration due to gravity Jd Swaartekragversnelling g 378 0S Universal gravitational constant Sh ae Universele gravitasiekonstant & Ge cetgs~ Nimakg Speed of light ina vacuum é 3,0 x 10° ms Spoed van lig in 'n vakuum Planck's constant h 6,63 x 10°4 J-s Planck se konstante Coulomb's constant 9K) 2.02 Coulomb se konstante : sf aro B ad cia Charge on electron 419 Lading op elektron : “1,6 10°C Electron mass Me 9,11 x 10°" kg Elektronmassa [EBB

Phydvawaneeaed from Stanmorephysics.com Limpopo DoE September2014 NSC TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING ——" VE = Vj +a fet Ax=v,At+tadt? or/of Ay =v,At+taat? Vi =v, ae orlof v,° =v, +2ady_ | Ax -(* - Jat orlof Ay -(% ~ Ja FORCE/KRAG Fret = ma p=mv fx = ukN Fat =AB — fs = UsN Ap= mv; —mvy; WORK, ENERGY AND POWER/ARBEID, ENERGIE EN DRYWING W =FAxcos@ U=mgh orlof Ep,=mgh 1 F Wret = AK orlof = Whe = AE, K=5 mv? orlof Ex ane AK=K,-K, orof AE, =E,,-E, W,, =AK +AU orfof W,, = AE, +AE, Paw P=Fv WAVES, SOUND AND LIGHT/GOLWE, KLANK EN LIG v=fa TS f + + foe gp oe E=hf orfof E=h© viv, viv, a E=W,+E, where/waar E=hf and/en W, =hf, and/en E, =pmv" Copyright reserved Please turn over

19 Downloaded from Stanmorephysics. cewiical sciences Grade 12 controlled test ELECTROSTATICS/ELEKTROSTATIKA r i + 2 z d fF q ie q ELECTRIC CIRCUITS/ELEKTRIESE STROOMBANE emf (€)=(R+r) Ra I emk (€) = I(R +r) R,=R,+ Rp + CE iC ANS q=I At Ry Ry Re W=Vq _W ~ At W=VIAt W=PRaAt Pau an P=FR w= VAt Rs bs = ALTERNATING CURRENT/WISSELSTROOM r I Eee =Vinslims / Pyemiddela = Vwvok Lok lL. =m / Tasie= a5 rms 2 we 2 v2 Pe iaade a eR / Premaaaaia = Trae V, V, Vo. = I Vig, = mas v2 v2 rms J2 gk J2 P — ims: / Reade = ak average R R Copyright reserved

Downloaded from Stanmorephysics.com a education Department: Education GAUTENG PROVINCE NATIONAL SENIOR CERTIFICATE This memorandum consists of 6 pages. / Hierdie memorandum be: uit 6 bladsye Copyright reserved Please turn over

Downloaded from Stanmorephysics.com QUESTION! Vraag 1 11 BYY (2) 1.2 Avv (2) 1.3 AVY (2) 14. Cvv (2) 15 D¥v (2) 1.6 Cvv (2) 1.7 C¥v (2) 18 AvY (2) 1.9 Cvv (2) 1.10 BYY (2) [20] QUESTION 2/VRAAG 2 2.1 The force that opposes the motion” of an object and which act parallel to the surfacev Die krag wat die beweging van 'n voorwerp teenstaan en parallel aan die opperviak inwerk. (2) 2.2 f/F / Frriction/friction ¥/Fivrywing, wrywing v Fy/w/weight/force of gravityY /gewig, gravitasiekrag (3) 2.3.1 fk(maxy = UkFNY = 0,15(3)(9,8)(cos 30°)” = 3,82 NV (3) 2.3.2 Positive marking from 2.3.1! Positiewe merk van 2.3.1 Right/downwards as positive:/ Regs/afwaarts as positief 5kg block: Fnet = ma v T + f = ma T_- (8) = 5av 3kg block: T+ f +Fgv= ma -T - 3,82 + (3)(9,8)sin30° v= 3av -T + 10,88 =3a Substitute 2 into 1: a = 0,36 m-s? Substitute a into 1: T - 8 = (5)(0,36) v T = 9,8 NY (6) [14]

quesRewsionded 3from Stanmorephysics.com 3.1 3.2 3.3 3.4 Downwards/AfwaartsY Upwards positive/Opwaarts positief: Vp = Vi + ADEY = 30-4040/(-9,8)(2,135) = 9,084m's7, upwards” Downwards positivel/Afwaarts positief: Ve = Vj + AAT Y - 30” + (9,8)(2,135) - 9,078 m-s? 9,08 m-s+, upwards “ Upwards positive/Opwaarts positief: Ball A: Ay =v At+ saat? v = -12(2,5) + ¥2(-9,8)(2,5)2¥ = - 60,625 m (Height /Hoogte= 19,375 m) Ball B: Ay =v; At+ dat? = 30(2,5) ¥ + Y%(-9,8)(2,5)2v = 44,375m Distance = 44,375 - 19,375” = 25mv Downwards positive/Afwaarts positief: Ay =v,At+ taht? v = 12(2,5) + 2(9,8)(2,52” = 60,625m (Height /Hoogte= 19,375 m) Ball B: Ay =v,At+ tat? = -30(2,5) ¥ + 14(9,8)(2,5)°Y = - 44,375 m Distance = 44,375 - 19,375” 25 mv OPTION 1/OPSIE 1 Upwards positive/Opwaarts positief: Ay (m) t (2,135s) . Time/tyd(s) Criteria for graphi/Kriteria vir grafiek: Marks/ Punte Shape for ball A up till zero position. Vorm vir bal A tot zero posisie. v Shape for ball B up till intersection of lines time. v Vorm vir bal B tot grafieklyne kruis. 2,135 s. Indication of time 2,135 s. Aanduiding van tyd 2,135 s. v Ground not zero position (provided everything else is correct): 2/3 Grond nie zero posisie nie (op voorwaarde die res is korrek) : 2/3 (3) OPTION 2/OPSIE 2 (1) (3) (6)

DayiieasleshalivenoprbatsnegaterySics.com (2,135s) Ay (m) Timeitya(s) ' A ae wn aye Marks/ Criteria for graph/Kriteria vir grafiek: Punte Shape for ball A up till zero position. Vv Vorm vir bal A tot zero posisie. Shape for ball B up till intersection of lines time. V Vorm vir bal B tot grafieklyne kruis. 2,135 s. Indication of time 2,135 s. v Aanduiding van tyd 2,135 s. Ground not zero position (provided everything else is correct): 2/3 Grond nie zero posisie nie (op voorwaarde die res is korrek): 2/3 (3) QUESTION 4/VRAAG 4 4.1 The total linear momentum of a closed system” remains constant ” Die totale linieére momentum in 'n geslote sisteem bly konstant 4.2 The kinetic energy remains constant. Vv OR The kinetic energy before the collision equals kinetic energy after the collision. Die kinetiese energie bly konstant. OF Die kinetiese energie voor botsing is gelyk aan die kinetiese energie na botsing. 4.3 2 Pbefore = 2 Patter v 5)(4) = (6,5)vi v Vi = 3,077 m-st Ap = m(vr - vi) = 5(3,077-4) v = - 4,62 kg-m-st Links/wes/teenoorgesteld aan bewegingsrigting 4,62 kg-m-s"V,, left/west/ opposite to direction of motion Vv [13] (2) (1) (5) [8]

quesAowslvadessfrom Stanmorephysics.com 5.1.1 5.1.2 5.2.1 5.2.2 5.2.3 5.2.4 5.2.5 5.2.6 Compounds with one or more multiple bonds between carbon atoms in their hydrocarbon chains. vv 2-methylbut-2-ene vv Carboxyl group vv A H H | | H — C—cC——C | | | H HH H o\ HoH | “i) row, H—C —-+ 0 —= C= G—_C awe | H HH They have the same molecular formula, v but different functional groups. ¥ Methanol vv Propyl methanoate vv QUESTION 3/VRAAG 6 6.1. 6.2 6.3.1 6.3.2 6.4.1 3.4.2 (2) (2) (2) MARKING GUIDELINES: Y Functional group Y Correct structure Correct condensed structure ¥% (2) MARKING GUIDELINES: ¥ Functional group Y Correct structure Correct condensed structure % (2) (2) (2) (2) [18] B — Pentanal vv (2) Primary V_ The hydroxyl group is bonded to one carbon only. “ (2) Yes. v The molar mass of the two compounds is the same/equal. (2) Compound D is an alkane and has weaker London forces. “ Compound B has stronger dipole-dipole forces (and London forces}7” More energy is needed to overcome the intermolecular forées in compound B than compound D. “ (3) The pressure exerted by a vapour Yat equilibrium with its liquid in a closed system. ¥ (2) Compound A vv (2) [13]

Downloaded from Stanmorephysics.com QUESTION 7/VRAAG7 7.1.1 Concentrated Sulphuric acid/Hydrogen sulphate “ OR Phosphoric acid/Hydrogen phosphate “ ( 7.1.2 Dehydration< v () 7.1.3 = | Bet fox Poy H = 4 ra —h ————>_ WC = gy H H H H | | | | | (4) MARKING GUIDELINES: ¥ OH on 2™ C for alcohol v 4C’s ¥ Double bond between 2" and 3m v structure for HzO 7,2 A low concentration (dilute solution) of a strong base/NaOH/KOH or waterY Heat (under reflux) (2) 7.3. Addition Vv (2) 7.4.1 2-bromobutane Vv (2) 7.4.2. No water may be present vv (2) [14] GRAND TOTAL:100