Physical Sciences Grade 10 National November 2018 Memo

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 10 PHYSICAL SCIENCES: PHYSICS (P1) FISIESE WETENSKAPPE: FISIKA (V1) NOVEMBER 2018 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 These marking guidelines consist of 12 pages. Hierdie nasienriglyne bestaan uit 12 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 2 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 1.1 C 1.2 C 1.3 A 1.4 A 1.5 C 1.6 A 1.7 B 1.8 B 1.9 C 1.10 C/B [20] QUESTION 2/VRAAG 2 2.1 The difference in position (in space). /Die verskil in posisie in ruimte. OR/OF The change in position (of an object.)/Die verandering in posisie van 'n voorwerp. (2) 2.2 12 m west/wes or/of -12 m  IF/INDIEN – 12 m West/Wes (Award 1 mark only/Ken 1 punt toe) Accept/Aanvaar 12 m left/links  (2) 2.3 ∆x v= ∆t 5  = 30  = 0,17 m·s-1 west/wes  Accept/Aanvaar  0,17 m·s-1 left/links  (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 3 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne 2.4 POSITIVE MARKING FROM 2.2 and 2.3/POSITIEWE NASIEN VANAF 2.2.en2.3 dis tan ce afs tan d Speed = / Spoed = time tyd -1 (0,17)(2)  = 0,34 m·s 12 0,34  =  ∆t Δt = 35,29 s  (4) [12] QUESTION 3/VRAAG 3 3.1 Motion with uniform velocity: Motion at constant velocity. / Motion with zero or no acceleration. Beweging met uniforme snelheid: Beweging teen konstante snelheid./ Beweging met nul of geen vernselling. Uniform accelerated motion: Motion with constant acceleration./Velocity changes with the same amount during each time interval. /Motion during which the velocity changes with a constant amount per unit time. / Uniforme versnelde beweging: Beweging met konstante versnelling/Snelheid verander met dieselfde hoeveelheid gedurende elke tydinterval/Beweging waartydens die snelheid met 'n konstante hoeveelheid per eenheid tyd verander. (4) 3.2.1 Motion with uniform velocity/Beweging met uniforme snelheid (1) 3.2.2 Uniform accelerated motion /Uniforme versnelde beweging (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 4 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne 3.3 ● 30 3.5  25 ● Position/Posisie (m) 20 15 ● 10 ● 5 ● 0 0 1,5 3 4,5 6 7,5 9 time/tyd (s) MARKING GUIDELINES/NASIENRIGLYNE  x-axis and units correctly labelled/x-as en eenhede korrek gemerk  y-axis and units correctly labelled/y-as en eenhede korrek gemerk  2 points correctly plotted and joined/2 punte korrek gestip en verbind  shape of the graph (0 – 3 s/vorm van die grafiek(0 – 3s) / straight line/reguitlyn  shape of graph 3 – 7,5 s curved / vorm van grafiek 3 – 7,5 s kurwe / tangent /raaklyn (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 5 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne 3.4 Instantaneous velocity: rate of change in position. /Oombliklike snelheid: tempo van verandering in posisie. OR/OF Displacement divided by a very small time interval. /Verplasing gedeel deur 'n baie klein tydinterval. OR/OF Velocity at a particular time. /Snelheid op 'n spesifieke tyd. (2) 3.5 Refer to the graph./Verwys na die grafiek. (Tangent to the curve/ Raaklyn aan kurwe) (2) 3.6 ∆x v= ∆t 6−0  = 3−0  = 2 m·s-1 right/regs  (4) [19] QUESTION 4/VRAAG 4 4.1 The rate of change of velocity. /Die tempo van verandering van snelheid. (2) 4.2.1 v f =v i + aΔt  0 = 15 + (-4,5)Δt  Δt = 3,33 s  OR/OF v f =v i + aΔt  0 = -15 + (4,5)Δt  Δt = 3,33 s  (4) 4.2.2 OPTION 1/OPSIE 1 v f 2 = v i 2 + 2aΔx  02 = 152 + 2(-4,5)Δx  Δx = 25 m  OPTION 2/OPSIE 2 POSITIVE MARKING FROM 4.2.1/POSITIEWE NASIEN VANAF 4.2.1  v + vi  Δx =  f  Δt   2   0 + 15  =  (3,33)  2  = 24,98 m  OPTION 3/OPSIE 3 POSITIVE MARKING FROM 4.2.1/POSITIEWE NASIEN VANAF 4.2.1 Δx = v i Δt + ½ aΔt2  = (15)(3,33) + ½ (-4,5)(3.33)2 Δx = 25 m  (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 6 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne 4.3 OPTION 1/OPSIE 1 v f 2 = v i 2 + 2aΔx  02 = 302 + 2(-4,5)Δx  Δx = 100 m  Car B has a larger stopping distance (100 m > 25 m) /Kar B het 'n groter stopafstand (100 m > 25 m). OPTION 2/OPSIE 2 v f = v i + aΔt  0 = 30 + (-4,5)Δt Δt = 6,67 s Car B it takes longer to stop hence larger stopping distance / Kar B dit neem langer om tot stilstand te kom dus 'n groter stopafstand IF/INDIEN Car B  it has a higher velocity than car A and therefore have a larger stopping distance at the same acceleration  Max: (2/6) Kar B dit het 'n hoër snelheid as kar A en het dus 'n groter stopafstand met dieselfde versnelling Maks: (2/6) (6) 4.4 The greater/larger the speed, the larger the stopping distance  if acceleration is constant. /Hoe groter die spoed, hoe groter die stopafstand (2) indien versnelling konstant is. [18] QUESTION 5/VRAAG 5 5.1 The energy an object has because of its position in the gravitational field  relative to some reference point.  /Die energie wat 'n voorwerp het as gevolg van die posisie daarvan in die gravitasieveld relatief tot 'n sekere verwysingspunt. (2) 5.2 E p = mgh = (65)(9,8)(4,5) = 2 866,5 J (3) 5.3 The net/total mechanical energy (sum of kinetic and gravitational potential energy) in an isolated/closed system remains constant/ is conserved./Die netto/totale meganiese energie in 'n geïsoleerde/geslote sisteem bly konstant/bly konstant. (2) 5.4 (E p + E k ) top/bo = (E p + E k ) bottom/onder mgh + 0 = mgh + ½mv2  2 (65)(9,8)(4,5)= 0 + ½(65)v  v = 9,39 m∙s-1  OR/OF (E p + E k ) top/bo = (E p + E k ) bottom/onder mgh + 0 = mgh + ½mv2  2 2 866,5  = 0 + ½(65)v  v = 9,39 m∙s-1  (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 7 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne 5.5 OPTION 1/OPSIE 1 (E p + E k ) top/bo = (E p + E k ) bottom/onder mgh + 0 = mgh + ½mv2  2 (65)(9,8)h  + 0 = 0 + ½ x 65 x (9,39)  637 h = 2 865,6 h = 4,49 m No/Nee. h = 4,49 m < 6 m OPTION 2/OPSIE 2 E p at Y = mgh  = (65)(9,8)(6) = 3 822 J E mech < E p at Y therefore he will not reach point Y / E meg <E p by Y daarom sal hy nie punt Y bereik nie (5) [16] QUESTION 6/VRAAG 6 6.1 Difference/Verskil Similarity/Ooreenkoms Amplitudes Wavelength/Golflengte Period/Tydperk Frequency/Frekwensie Transverse/Transversaal (Any one)/(Enige een) (2) 6.2.1 A and/en B OR/OF C and/en D OR/OF B and/en C OR/OF A and/en D (1) 6.2.2 15 (mm)  (1) 6.3 The number of waves/wave pulses passing a point per second. /Die getal golwe/golfpulse wat per sekonde by 'n punt verby beweeg. (2) 6.4.1 1 f=  T 1 =  1,5 = 0,67 Hz  (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 8 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne 6.4.2 POSITIVE MARKING FROM 6.4.1 OPTION 2/OPSIE 2 POSITIEWE NASIEN VANAF 6.1 ∆x dis tan ce OPTION 1/OPSIE 1 v= or/of speed =  ∆t time v = fλ 0,1 = (0,67)(0,1) =  1,5 = 0,067 m·s-1  = 0,067 m·s-1 (3) [12] QUESTION 7/VRAAG 7 7.1.1 What is the relationship between the speed of sound and temperature? / Wat is die verband tussen die spoed van klank en temperatuur? OR/OF How will the temperature affect the speed of sound? /Hoe sal die temperatuur die spoed van klank beïnvloed? OR/OF What is the relationship between the time taken for the sound to travel and temperature? / Wat is die verband tussen die spoed van klank en temperatuur? (2) Marking criteria/Nasienriglyne: Dependent and independent variables correctly identified.  Afhanklike en onafhanklike veranderlikes korrek geïdentifiseer. - Ask a question about the relationship between the independent and dependent variables./Vra 'n vraag oor die verwantskap tussen die  afhanklike en onafhanklike veranderlikes. 7.1.2 Temperature /Temperatuur (1) 7.1.3 Speed of sound/Time taken for the sound to travel./Spoed van klank/Tyd geneem vir die klank om te beweeg. (1) 7.2 ∆x dis tan ce v= or/of speed =  ∆t time 50 =  0,146 = 342,47 m·s-1 (3) 7.3 The speed of sound increases / time taken for the sound to travel decreases / as the temperature increases. /Die spoed van klank neem toe / tyd geneem vir die klank om te beweeg neem af soos die temperatuur toeneem. (2) 7.4 Echo/Eggo (1) [10] QUESTION 8/VRAAG 8 8.1 Accelerating charges /Versnelde ladings (1) 8.2 Gamma rays /Gammastrale (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 9 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne 8.3 It has the highest frequency Energy is directly proportional to frequency / Eαf/ Dit het die hoogste frekwensie. Energie is direk eweredig aan die frekwenie/ Eαf (2) 8.4.1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 c = fλ hc E= 3 x 108 = f(600 x 10-10)  λ f = 5 x 1015 Hz  (6,63 × 10 −34 )(3 × 10 8 ) =   Any one Ultraviolet /Ultraviolet 600 × 10 −10 Enige een = 3,315 x 10-18 J E = hf 3,315 x 10-18 = (6,63 x 10-34)f f = 5x 1015 Hz  Ultraviolet /Ultraviolet (4) 8.4.2 POSITIVE MARKING FROM 8.4.1/POSITIEWE NASIEN VANAF 8.4.1 Sterilisation of medical equipment./ Sterilisasie van mediese toerusting Suntan beds /Sonbeddens Security in currency/Veiligheid in valuta Astronomy/ Astronomie (Any one/Any relevant use/Enige een/Enige relevante gebruik) (1) [9] QUESTION 9/VRAAG 9 9.1 Ferromagnetic (material) /Ferromagneties (materiaal) (1) 9.2 B (1) 9.3 South /Suid (1) 9.4 N S S N S X Y B   OR/OF Magnets X repels Y/ South pole /Magneet X stoot Y af / Suidpool Magnet Y attracts B/ South pole at B /Magneet Y trek B aan / Suidpool by B (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 10 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne 9.5 Marking criteria/Nasienkriteria Correct direction of field lines/Korrekte rigting van veldlyne  Shape of the magnetic field/Vorm van die magneetveld  No field lines crossing each other/Geen veldlyne kruis  mekaar nie. (3) 9.6.1 Less than 5 cm / Minder as 5 cm (1) 9.6.2 Magnitude of magnetic force is inversely proportional to the distance.  B, is no longer attracting Y to the right  Grootte van magnetiese krag is omgekeerd eweredig aan die afstand. B, trek nie meer Y na regs aan nie OR/OF A decrease in distance increases the magnetic force. B, is no longer attracting Y to the right  'n Afname in afstand laat die magnetiese krag toeneem, B, trek nie meer Y na regs aan nie (2) [11] QUESTION 10/VRAAG 10 10.1 Q Q n= or/of e qe Q 30 =  − 1,6 × 10 −19 Q = -4,8 x 10-18 C  Accept/Aanvaar Q Q n= or/of e qe Q 30 =  1,6 × 10 −19 Q = 4,8 x 10-18 C  (3) 10.2 Unlike/opposite charges attract/Ongelyksoortige/teenoorgestelde ladings trek mekaar aan. (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 11 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne 10.3 The net/total charge in an isolated/closed system remains constant/is conserved Die netto/totale lading in 'n geïsoleerde/geslote sisteem bly konstant. (2) NOTE/LET WEL: If any of the underlined words/phrases are omitted in the correct context: minus 1 mark.) Indien enige van die onderstreepte woorde/frases in die korrekte konteks weggelaat is: minus een punt.) 10.4 POSITIVE MARKING FROM 10.1/POSITIEWE NASIEN VANAF 10.1 Q + Q2 Q net/netto = 1  2   4 × 10 −18 + ( −4,8 × 10 −18 ) = 2 = -4 x 10-19 C  (4) [11] QUESTION 11/VRAAG 11 11.1.1 (a) V 1 = 24 (V) (1) (b) A 1 = 0 (A) (1) 11.1.2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 1 1 1 product / produk = +  Rp =  R p R1 R 2 sum / som 1 1 (8)(8) = +  =  8 8 8+8 Rp = 4 Ω =4Ω RT = Rs + Rp RT = Rs + Rp = 8 + 4 = 8 + 4 = 12 Ω = 12 Ω (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P1/Fisiese Wetenskappe V1 12 DBE/November 2018 CAPS/KABV – Grade10/Graad 10 – Marking Guidelines/Nasienriglyne 11.1.3 OPTION 1/OPSIE 1 V divides in a ratio 8 : 4  (series)/V verdeel in 'n verhouding 8 : 4 (serie) 8 2 V2 = x 24 or/of V 2 = x 24 12 3 = 16 V  OPTION2 / OPSIE 2 POSITIVE MARKING FROM 11.1.2/POSITIEWE NASIEN VANAF 11.2.1 V = IR 24 = I(12) I=2A V = IR = (2)(8) = 16 V  (3) 11.1.4 A2 = A3 .  (1) 11.2.1 Resistance is directly proportional to the length of the conducting wire. / Weerstand is direk eweredig aan die lengte van die geleidingsdraad. OR/OF As the length of the wire increases, the resistance increases./Soos die lengte van die geleidingsdraad toeneem, neem die weerstand toe (1) 11.2.2 1,35 Ω  (Range/Variasiewydte: 1,3 Ω to/tot 1,4 Ω) (1) [12] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou