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NATIONAL
SENIOR CERTIFICATE
GRADE 11
NOVEMBER 2016
MATHEMATICAL LITERACY P1
MEMORANDUM
MARKS: 100
This memorandum consists of 4 pages.
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Mathematical Literacy Grade 11 P1 2016 Memo (Eng)
Grade 11 Mathematical Literacy Paper 1 memorandum from the Eastern Cape November 2016 (English), 4 pages. Read online or download the free PDF.
Mathematical Literacy · Grade 11 · Eastern Cape November · 2016. Memorandum, 4 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 11
- Document type
- Memorandum
- Year
- 2016
- Exam period
- Eastern Cape November
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 4
- File size
- 985.0 KB
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Eastern Cape November 2016
Questions in this paper
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2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2016)
KEY
Symbol Explanation
M Method
A Accuracy
CA Consistent accuracy
RT/G/M/ Reading from the table/graph/map/plan
SF Substitution in a formula
S Simplification
P Penalty (no units, incorrect rounding etc.)
QUESTION 1 [23]
Q Solution Explanation Mark
1.1.1 Bennie’s Service Station Motors Buffalo City 2M L1(2)
1.1.2 A= R3 390,96 –R2 093,46 1RT
= R1 297,50 1A L1(2)
1.1.3 𝑅 1 234,96 1M numerator and
× 100 denominator
𝑅2 469,92
1M multiply by 100
= 50% L2(2)
1.1.4 R212,82 + R4,99 + R75,87 + R697,13 + 1M
R2 469,92 + R726,16 = R4 186,89 1CA if one value is
omitted or R159,50 is
added L1(2)
1.1.5 B = VAT = R3 390,96 × 14% 1M
= R474,73 1A
OR
B = R3 865,96+R0,09 – R3 390,96
= R 474,73 L1(2)
1.1.6 R2 469,92 – R4,99 1 Correct values
= R2 464,93 1M
1CA L1(3)
1.2.1 Opening balance is the balance that is 2A
reflected or displayed on the first day listed in Explanation
the statement before any other transactions. L1(2)
1.2.2 9,50 1M dividing by 500
× 100 = 0,019 × 100 = 1,9% 1M
500
1CA when the different
value from the
statement is used L1(3)
1.2.3 R110,00 + R55,00+R1,10 × 2 1M
R165,00 + R2,20 1S
= R167,20 1CA L2 (3)
1.2.4 Eighteen Thousand, Five Hundred 2A expanding
and Eighty Two Rand, and Seven Cents L1(2)
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(EC/NOVEMBER 2016) MATHEMATICAL LITERACY P1 3
QUESTION 2 [19]
Q Solution Explanation Mark
2.1.1 Length= 30 ft 2 RD
Width = 25 ft L1(2)
2.1.2 30 ft × 25 ft 30 ft = 9,1435 1M
= 750 ft 2 OR 25 ft = 7,6196 1S
750ft2
= 10,764 A = 9,1435 × 7,6196 1 M Dividing by 10,764
= 69,6698 m2 1CA
= 69,68 m2 = 69,67 m2
(Accept 69,677 𝑚2 ) L2 (4)
2.1.3 20 × 15 1M numerator
Amount of fertiliser = 1M denominator
100
300 ft2 1S
= 100ft2
1M Multiply by 2
= 3 × 2 pounds 1CA
= 6 pounds
OR
2 pounds × 3 = 100 ft 2 × 3
6 pounds = 300 ft 2 L2 (5)
2.1.4 0,15 × 2 1M Multiply by 2
= 0,3 1A
1 1A
Approximately = 3 cup
OR
1
= 6,66666667
0,15
2
Therefore 0,666666667
= 0,3 cups = ⅓ cup L1(3)
2.2.1 Morning + Evening
(10𝑚ℓ + 15𝑚ℓ + 10𝑚ℓ ) × 2 2M
= 35𝑚ℓ × 2
= 70 𝑚ℓ 1CA L1(3)
2.2.2 10 𝑚ℓ + 10 𝑚ℓ = 20 𝑚ℓ 1M
1A L1(2)
QUESTION 3 [19]
Q Solution Explanation Mark
3.1.1 4 2 RT L1(2)
3.1.2 Water monitoring station 2 RT L1 (2)
3.1.3 MA-1 2 RT L1(2)
3.1.4 103 mm (10,3 cm) 2 RT L1(2)
3.1.5 10,3 × 250 000 1C
100 000 1 Division
= 25,75 km 1CA L3(3)
3.2.1 Table B (Accept H/I) 2A RP L1(2)
3.2.2 South East 2A RP L1(2)
3.2.3 Impossible/Zero/0% 2A L1(2)
3.2.4 Table C 2RP L1(2)
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4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2016)
QUESTION 4 [27]
Q Solution Explanation Mark
4.1 32,49; 29,63; 23,62; 17,89 ; 14,59; 12,03; 10,31;
9,89; 9,57 2M L1(2)
4.2 Median=R14,59 2M L2(2)
4.3 Range=R 33,73 – R9,68 =R24,05 2RT L2(3)
4.4 R-3,32 2M L1(3)
4.5 Margarine 500g 2 RT L1(2)
4.6 No Mode 2RT L2 (2)
4.7 Area Margarine Rice Sunflower Ceylon Tea White Sugar
Urban 21,68 23,45 17,25 9,68 26,31
Urban food prices
Prices in Rands
Selected food items
1mark per food item correctly plotted × 5 = 5 marks + 1 = 6 marks
1mark for correct graph L2(6)
4.8 Rural area people pay more or less on certain 2A Explanation
items L3(2)
4.9 0,56 + 0,72 + 1,11 + 1,24 + 3,79 + (-0,17) + 2,66 + 1M
(-0,21) + (-3,32) 1Dividing
R6,38 1CA
= 𝑅0,71 L2(3)
9
4.10 2 1numerator
× 100 = 22,2% = 22% 1denominator
9 1CA L2(3)
QUESTION 5 [12]
Q Solution Explanation Mark
5.1 R36,99 2RT L1(2)
5.2 R200,00 2 RT L1(2)
5.3 𝑅278,78 1M dividing by 13
= R21,44 = R20,00
13 1S
1A L1(3)
5.4 6 × R17,99 OR 17,99 1A for 6 1M ÷ 1,14
= 15,78 × 6
𝑅107,94 1,14
= = R94,68 1CA
1,14 = R94,68 L2(3)
5.5 R99,98 1M
= R49,99
2 1A L1(2)
5.6 Total = 22,49 + 29,26 + 25,59 + 99,98 + 22,00 + 1M
17,99 + 9,99 + 13,49 + 1,00 = R241,79 1CA
OR Total = 478,78 – 200 – 278,78 = R241,79 L2(2)
TOTAL: 100
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