Mathematical Literacy Grade 11 P2 2015 Memo (Eng)

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2015 MATHEMATICAL LITERACY P2 MEMORANDUM MARKS: 100 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table/Reading from a graph/Read from map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off, etc. R Rounding Off/Reason This memorandum consists of 6 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2015) QUESTION 1 1.1 1.1.1 5 Entrances  2A Identifying the number of entrances (2) 1.1.2  Walk straight towards Shop No. 6 and turn 3A left.  Explanation  Edgars will be on your left continue until you get to Shop No. 60 and turn right.   Keep walking until Shop No. 52-53 and turn left where Entrance 2 is  Accept any reasonable explanation (3) 1.2 1.2.1 1h 57 minutes  1A Hours 1A Minutes (2) 1.2.2 11:20 + 45 min + 15 min  = 12:20  1M Adding It will be too late to watch the 12:15 screening  45 min and 15 min 14:45 + 1:57 = 16:42 + 40 min = 17:22 min  1A 1O Opinion The only time slot will be the 14:45 screening and 1A Adding still be at home on time.  1h57 and 40 min 1A Time to arrive at home 1O Conclusion (6) 1.2.3  Cleaning of the cinema  1A First  To prepare for the next showing  reason OR 1A Second  Allow the cinema crew to take a break  reason Accept any other relevant reasons (2) 1.3 1.3.1 Regular pricing = 75 + 55  = R130  1A Identifying the correct values 1M Adding 1A (3) 1.3.2  It is too expensive on a Sunday or 2O weekends  Explanation OR  On other days its much cheaper  Accept any other explanation (2) [20] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2015) MATHEMATICAL LITERACY P2 3 QUESTION 2 2.1 2.1.1 (a) Total cost (in rand) = R200  + number of 1A Rental minutes more than 150  x R0,60  1A Minutes more than 150 1A Multiply by 60 cents OR Total cost (in rand) = R 200  + (number 1A Rental of minutes more than 150)  x R0,60  1A Minutes more than 150 1A Multiply by 60 cents OR Total cost (in rand) = R200 + (number of 1A Rental minutes – 150) x R0,60  1A Minutes more than 150 1A Multiply by 60 cents (3) (b) Total cost (in rand) = R200 + (number of CA from minutes – 150) x R0,60 2.1.1 (a) = 200 + (625 – 150) x 0,60  1SF = 200 + (475 x 0,60) 1S = 200 + 285  1S = R485,00  1A (4) 2.1.2 1 Mark for line 0–100 minutes 1 Mark for the correct break- Call package A even point 2 Marks for any other 3 Call package B points plotted correctly 1M Labelling Call Package A (5) 2.1.3 For the same number of minutes used the same 1A refer to amount will be paid for both Call packages  minutes 1A refer to cost (2) 2.1.4 Break-even point (450 ;380 ) CA from 2.1.2 1CA 450 minutes 1CA 380 rand If order incorrect 0 (2) Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2015) 2.1.5 Call package A Total cost = 100 + (451 – 100) x 0,80  1SF = 100 + (351 x 0,80) = 100 + 280,8 = R 380,80  1CA Call package B Total cost = 200 + (451 – 150) x 0,60 = 200 + (301 x 0,60) = 200 + 180,60 = R 380,60  1CA Difference = R 380,80 – R 380,60 = R 0,20  1CA Difference OR Call package A - Call package B = 100 + (451 – 100) x 0,80  – 200 + (451 – 150) x 1SF 0,60 = 100 + (351 x 0,80) – 200 + (301 x 0,60) 1CA = 100 + 280,80 - 200 + 180,60 1CA = R 380,80  – R 380,60  1CA = R 0,20  Difference (4) 2.1.6 Would recommend that Mr. Gardner use Call Package A  1CA Choosing With R 300 on Call Package A he will get 350 correct minutes  package With R 300 on Call Package B he will get 316 2 CA minutes to 317 minutes  2A (5) 2.2 Number of households = 10 x 10 x 10 x 10  1A Identifying = 10 000  10 1M Multiplying 10 four times 1CA (3) [28] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2015) MATHEMATICAL LITERACY P2 5 QUESTION 3 3.1 3.1.1 A = 17,20 x 1,14  OR A=17,20 + (17,20 x 0,14)  1M = R 19,61  = 17,20 + 2,41 1A = R 19,61 B = 31,95  1M 1,14 = R28,03  1A (4) 3.1.2 No, she will not pay for the first 6 kl 1A 1O (2) 3.1.3 Payment for 19,5 kl 1M = (6 x 0) + (4,5 x 7,60) + (9 x11,61)  1S = R 0 + R 34,20 + R 104,49  1A = R 138,69 x 1,14 1A Including = R 158,11  VAT (4) 3.2 3.2.1 Diameter = 750 mm, therefore radius = 375 mm = 0,375 m 1A Finding Height = 2230 mm = 2,230 m  radius Volume = 3,142 x 0,375 m2 x 2,230 m  = 3,142 x 0,140625 m2 x 2,230 m 1A Convert = 0,985311562 m3  x 1000 mm to m = 985,311562 / (both) Accept 985,312  1SF 1S radius2 Therefore; 1CA in litres 1000 l ≠ 985,311562 l OR 985,312  1A (6) 3.2.2 The given volume was rounded to the nearest 1000  1O Consumers are under the impression that you buy a tank with a capacity of 1 000 l, while it only has a tank capacity of 985 l.  2O (3) 3.2.3 Tank can overflow if it is filled above the recommended filled height  2R (2) 3.2.4 Any of the vertical round water tanks  2A (2) 3.3 Bar graph and 1A Bar graph Pie chart  1A Pie chart (2) [25] Copyright reserved Please turn over

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2015) QUESTION 4 4.1 4.1.1 Mean = 26 + 29 + 22 + 23 + 22 + 21 + 24  1M adding all 7 day temp = 167 1M/7 7 = 23,85714286  1CA = 24 ºC  1CA (4) 4.1.2 Range = 29 ºC – 15 ºC  1M concept of = 14ºC  range 1A (2) 4.1.3 Median = 15; 16; 17; 17; 17; 20; 21 1M Arrange = 17 ºC  values 1A (2) 4.1.4 Night temperatures decreases from Wednesday to Friday and then increases on Saturday and then from Sunday remains constant until Tuesday  2O (2) 4.1.5 Monday with 1RT Day 4 ºC  1A Difference (2) 4.1.6 Friday  2RT (2) 4.1.7 Day and night temperatures for George from 14 Jan - 20 Jan 2015 40 Temperature in °C 30 Any 4 pairs 20 correctly Day temp plotted 10 0 Night temp 1Mark for Wo Do Vr Sa So Ma Di legend Days 1 Mark correct graph (6) 4.2 It is highly unlikely that it will rain on Friday because it is only 30% which is small chance for rain to fall  2O (2) 4.3 4.3.1 Time = Distance Speed = 64,7 km  1M 90 km/h = 0,7188….hours x 60  1S = 43,133… = 43 minutes  1A (3) 4.3.2 Your speed will decrease therefore it will take you 1A refer to longer to complete the trip speed 1A refer to time (2) [27] TOTAL: 100 Copyright reserved Please turn over