Mathematical Literacy Grade 11 P2 2022 Memo (Eng)

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2022 MATHEMATICAL LITERACY P2 MARKING GUIDELINE MARKS: 100 Symbol Explanation M Method M/A Method with accuracy MCA Method with consistent accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table OR Reading from a graph OR Read from a map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding off OR Reason AO Answer only NPR No penalty for rounding This marking guideline consists of 8 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2022) QUESTION 1 [20] Ques. Solution Explanation Topic & Level 1.1 1.1.1 R40,00 ✓ ✓ RT 2RT correct value F L1 (2) 1.1.2 Hours: 8 ✓ C 1C divide by 60 M Convert 15 min = 15 ÷ 60 1A adding correct L1 = 0,25 + 8 values = 8,25 hrs. ✓ A (2) 1.2 1.2.1 Departure 14h20 1MA subtraction time M Arrive − 11h30 ✓ MA 1A simplified time L1 Lapse time = 2h50 min ✓ A (2) 1.2.2 Cost = R50,00 + (R7,00 x R3,00) ✓RT 1RT correct values F = R50,00 + R21,00 1A answer L1 R71,00 ✓ A (2) 1.3 1.3.1 It is the total length of the sides in a shape. ✓✓ 2R Explanation M OR L1 It is the distance around the outside of the shape. ✓✓ R Accept any other relevant reason. (2) 1.3.2 ✓ MA 1MA adding sides M Perimeter rectangular diagram = 210 + 210 + L1 100 + 100 1CA answer = 620 cm ✓ CA (2) 1.3.3 Numerical scale or Ratio scale ✓✓ A 2A concept scale M&P L1 (2) 1.3.4 Every 1 unit on the map represents 100 units in 2A Explanation M&P reality. ✓✓ A (2) L1 1.4 1.4.1 R44 ✓✓ A 2A correct road M&P (2) L1 1.4.2 Provincial roads serve as feeders to the national 2A Explanation M&P roads. ✓✓ A L1 OR Provincial roads also serve as trunk roads in areas where there is no national roads. ✓✓ A Accept any relevant explanation. (2) [20] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2022) MATHEMATICAL LITERACY P2 3 QUESTION 2 [30] Ques. Solution Explanation Topic & Level 2.1 2.1.1 Bar scale ✓✓ 2A 2A correct scale M&P (2) L1 2.1.2 Width of bar (measured) = 2,1 cm ✓ A 1A measured value for bar M&P Length of animal = 15,1 cm ✓ A width L2 2,1 cm 2,1 cm = 1,9 m Accept 2 – 2,3 cm ✓M 1A measured value 15,1 diagram for × 1,9 m = 13,6619 m ✓ CA 2,1 15,1 cm = 13,7 m ✓ R 1M multiply by 1,9 m 1CA correct value OR 1R one decimal number ✓A 1A measured value for bar 2,1 cm = 1,9 m width ✓ A ✓M 2,1 cm 15,1 cm ×1,9 m 15,1 cm = 1A measured value 2,1 cm diagram for 15,1 cm 1M multiply by 1,9 m = 13,6619 m ✓ CA 1CA correct value 1R one decimal number = 13,7 m ✓ R Mark according to your measured length. (5) 2.1.3 1 ton = 1 000 kilogram 1A × 1 000 M 20 ton = 20 × 1 000 ✓ A 1A correct value L1 = 20 000 kilogram ✓ A (2) 2.2 48 000 – 30 000 = 18 000 ✓ MA 1MA Subtracting correct F ✓A number of tuna L3 18 000 1A × 100 Percentage illegal fishing = × 100 1A correct percentage 30 000 = 60% ✓ A (3) Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2022) 2.3 2.3.1 M9 ✓ RT 2RT correct roads M&P M18 ✓ RT L1 (2) 2.3.2 N2 ✓ ✓ RT 2 RT M&P (2) L1 2.3.3 R75 ✓✓ RT 2 RT M&P (2) L1 2.3.4 6 provincial roads ✓✓ 2A 2A correct M&P OR number L2 R75; R102; R334; R335; R367; R368 ✓✓ 2A 2A correct list of roads (2) 2.3.5 Measured distance : 5 cm ✓ A 1A measured M&P 5 cm : 13 km ✓ M value L4 5 cm : 1300 000 cm ✓ C 1M ratio concept 5 𝑐𝑚 1 300 000 cm 1C conversion : ✓S 1S simplify 5 𝑐𝑚 5 cm values 1 : 260 000 Yes, his statement is valid. ✓ ✓ 2J 2J conclusion (6) 2.3.6 13 km 1SF correct M Time = ✓ SF substitution L2 80 km /h 1C converting hrs = 0,1625 hrs × 60 to min = 9,75 min ✓ C 1C converting = 0,75 × 60 = 45 seconds ✓ C min to seconds Total time = 9 min 45 seconds ✓ S 1S simplifying total time (4) [30] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2022) MATHEMATICAL LITERACY P2 5 QUESTION 3 [23] Ques. Solution Explanation Topic & Level 3.1 3.1.1 Perimeter = 2 (length + breadth) 1SF correct values M ✓SF 1S simplification L2 = 2 (8 500 mm + 3 500 mm) 1CA answer = 2 (12 000 mm) ✓ = 24 000 mm ✓ (3) 3.1.2 Area of floor = Length × Width ✓ C 1C convert to m M = 8,5 m × 3,5 m ✓ 1M multiply 5,8 m with V2 = 29,75 m2 ✓ 3,5 m 1CA correct value (3) 3.1.3 Volume = length × breadth × height (thickness) 2A Reason M L3 = 8,5 m × 3,5 m × 0,1 m ✓ 1SF substitute correct = 2,975 m ✓ 3 values 1CA answer for 2,975 m3 NPR (2) 3.1.4 Facing west ✓ and east. ✓ 2RT directions M&P (2) L3 Copyright reserved Please turn over

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2022) 3.2 3.2.1 ✓C 1C Convert cm to m M Area of southern wall = 8,5 m × 5 m ✓ SF 1SF correct values L3 1CA correct value for = 42,5 m2 ✓ CA 42,5 m2 Dimensions of 1 brick (with mortar) Length = 222 + 10 ✓ M 1M adding 10 mm = 232 mm Height = 73 + 10 = 83 mm Area of 1 brick = length × height 1SF correct values = 232 mm × 83 mm ✓ SF 1C divide by conversion = 19 256 mm2 ÷ 1 000 000 ✓ C factor = 0,019 256 m2 ✓ CA 1CA for 0,019256 m2 Area of the wall in m2 No. of bricks = Area of one brick in m2 1SF correct values 42,5 m2 = ✓ SF 0,019256 m2 = 2 207 ,10 1CA number of bricks = 2 208 bricks ✓ CA (9) 3.2.2 CA from 3.2.1 M 10% × 2 208 bricks = 220,8 + 2 208 ✓ M 1M adding correct no of L2 Total amount of bricks ≈ 2 428,8 bricks ≈ 2 429 bricks ✓ CA 1CA total no of bricks OR 1S simplifying correct 110% × 2 208 = 2 428,8 ✓ S number of bricks ≈ 2 429 number of bricks ✓ CA 1CA total number of bricks (2) 3.2.3 2 429 total number of bricks (answer to 1CA total number of M QUESTION 3.2.2) bricks L4 R4,75 price of one brick 1M price of one brick 1CA total amount 2 429 x R4,75 ✓ M = R11 537,75 ✓ CA (2) [23] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2022) MATHEMATICAL LITERACY P2 7 QUESTION 4 [27] Ques. Solution Explanation Topic& Level 4.1 4.1.1 Scale 1 : 30 1C conversion to cm M&P ✓C 1M divide by 30 L4 45 ×1 1CA value of 1,5 cm A= = 1,5 cm ✓ CA 30 ✓M 1M using 105 cm 1CA value of 3,5 cm ✓M 105 × 1 B= = 3,5 cm ✓ CA 30 (5) 4.1.2 Volume = l × b × h 1C conversion M ✓C 1SF substitute correct L2 = 105 cm × 45 cm × 30 cm ✓ SF values = 141 750 cm3 ✓ CA 1CA Simplification (3) 4.1.3 1 cm3 = 1 mℓ M 141 750 cm = 141 750 mℓ ✓ A 3 L2 1A ratio concept 1 litre = 1 000 mℓ ✓M 141 750 ml = 141,75 litres 1 000 ml 1M divide by 1 000 0,9 × 141,75 = 127,575 litres ✓ CA 1CA value of 127,575 litres (3) 4.2 4.2.1 Actual length = 50,4 mm × 150 ✓ M 1M × 150 M = 7 560 mm ÷ 1 000 ✓ M 1M ÷ 1 000 L2 = 7,56 m ✓ CA 1CA correct value Actual width = 25,6 mm × 150 ✓ M 1M × 150 = 3 840 mm ÷ 1 000 ✓ M 1M ÷ 1 000 = 3,84 m ✓ CA 1CA correct value (6) 4.2.2 Area of rectangle = length × breadth 1SF correct values M = 7,56 m × 3,84 m ✓✓SF 1M multiply values L3 M 1CA answer = 29,03 m2 ✓ CA (3) Copyright reserved Please turn over

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2022) 4.3 10 000 1000 Probability not winning: − 10 000 10 000 1A numerator P ✓A 1A denominator L2 9 000 = × 100 10 000 ✓A 1A for 90% = 90% ✓ A (3) 4.3.1 Unlikely ✓✓ A 2A Explanation P L1 (2) 4.3.2 10% : 90 % ✓ A 1A ratio concept P L1 1:9 ✓A 1A simplified values (2) [27] TOTAL: 100 Copyright reserved Please turn over