Mathematical Literacy Grade 10 P2 National November 2019 Memo

NATIONAL SENIOR CERTIFICATE GRADE 10 NOVEMBER 2019 MATHEMATICAL LITERACY P2 MARKING GUIDELINE MARKS: 75 Codes Explanation M Method MA Method with Accuracy CA Consistent Accuracy A Accuracy C Conversion D Define J Justification/Reason/Explain S Simplification RD Reading from a table OR a graph OR a diagram OR a map OR a plan F Choosing the correct formula SF Substitution in a formula O Opinion P Penalty, e.g. for no units, incorrect rounding off, etc. R Rounding Off AO Answer only NPR No penalty for rounding OR omitting units This marking guideline consists of 6 pages.

2 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2019) QUESTION 1 [26 marks] Question Solution Explanation Topic and Level 1.1.1 A= R10 887,11 – R125,60 – R1,00 M 1M subtracting R1 F = R10 760,51  CA 1CA for answer L2 (2) 1.1.2  Deposit = R2,00 + R1,00 x (number of R100’s) 1 Number of R100 F 1M Method M L4 Fees for 03/1/2019 = R2 + R1 x (R1 000 ÷ R100) = R2 + R10 1A Answer = R12 A The statement is valid  O 1CA Opinion (4) OOOO 1.1.3 Balance 28/1/19 = R19 718,01 OOCO+ (R15 – R12)  M 1M Method F = R19 721, CACA01  CA 1 CA correct value L3 (2) 1.1.4 M 1M adding values F Bank fees =R12 + R2,50 + R 2,50 + R1,00 + R2,50 L3 = R20,50  A 1A correct value His statement is not correct C 1 Conclusion (3) 1.1.5 So that they can be able to do their daily 2O Opinion F operations.  O L4 OR To be able to pay their employees  O OR That is their way of getting the income  O OR Accept other relevant reasoning. (2) 1.2.1 1M multiply by M 0,27 x 1 000 M 1 000 L4 = 270 ℓ CA 1CA Answer (2) 1.2.2 1M addition M Ratio: = 1 + 3+ 5 = 9 L3 1 Cement = × 270 ℓ 9 = 30 ℓ  A 1A correct value 3 Sand = × 270 l 9 = 90 ℓ  A 5 1A correct value Gravel = × 270 l 9 = 150 ℓ  A 1A correct value (4) Copyright reserved Please turn over

(EC/NOVEMBER 2018) MATHEMATICAL LITERACY P2 3 1.2.3 A 1A Correct hours F Amount to be paid = R45,75 x (5 + 1) x 2 M 1M multiply by 2 L2 = R549 CA 1CA Answer (3) 1.2.4 F Total Costs = R1 524, 99 + R549 M 1M adding material L4 and cost = R2 073, 99 CA 1CA Total Cost Total Savings = (3,5% x R11 560) x 6 months = R2 427,60 A 1A Total Savings Kim will have enough money for the project. C 1 Conclusion (4) [26] Copyright reserved Please turn over

4 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2019) QUESTION 2 [13 marks] Question Solution Explanation Topic and Level 2.1.1 Area = π r2 1M Using correct radius M = 3,142 x 2,15 x 2,15  M in the formula (M) L2 = 14,52 m2 CA 1CA for Answer (2) 2.1.2 Volume of the cylinder = 14,52 x 0,9 SF 1 SF M = 13,07 m 1CA from 2.1.1 L3 2 2 = × 13,07 M 1M Method using 3 3 = 8,71 m3 There is enough sand to collect it free  C 1 for Conclusion (4) 2 2.2.1 Space prepared = 3% x 929 m M 1M using 3% M = 27, 87 m2 CA 1CA for Answer L4 Area of trampoline = 14,52 m2 He will have enough space  O 1O for Opinion (3) 2.2.2 M M 1M Method using 2,5% F New premium = (2,5% x R2 534) + (R2 534) 1M Adding L4 = R2 597,35  CA 1CA Answer His estimation is not correct.  C 1 Conclusion (4) [13] Copyright reserved Please turn over

(EC/NOVEMBER 2018) MATHEMATICAL LITERACY P2 5 QUESTION 3 [15 marks] Question Solution Explanation Topic and Level 3.1.1  MP From Graaff-Reinet you go straight with the R75 route 1 R75 L2 pass Jansenville, Wolwefontein, Kariega, pass Uitenhage 2A Mention at until you reach Port Elizabeth A least 2 towns (3) 3.1.2 South East  A 2A Correct MP direction L2 (2) 3.1.3 The boxes will be sent overseas. O 2O Opinion MP OR L4 Any other logical reason. (2) 3.2.1 Distance from Addo to Uitenhage = 2 cm or 20 mm M 1M measure from MP [Accept 1,9 – 2,4 cm] map L4 Scale: 1 : 2 500 000 Actual distance = 2 x 2 500 000 M 1M using scale 5 000 000 1SF using correct =  SF 100 000 values = 50 km  A 1A Answer in km (4) 3.2.2 𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒 1M changing MP Time = M 𝑠𝑝𝑒𝑒𝑑 subject of formula L4 50 𝑘𝑚 =  SF 1 SF 100 𝑘𝑚/ℎ = 30 min.  A 1A Answer His prediction is not valid, he will reach PE at 10:30. O 1O Opinion (4) [15] Copyright reserved Please turn over

6 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2019) QUESTION 4 [21 marks] Question Solution Explanation Topic and Level 4.1.1 𝑇𝑜𝑡𝑎𝑙 𝑜𝑓 𝑚𝑎𝑟𝑘𝑠 1A Adding total Data Average = 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑙𝑒𝑎𝑟𝑛𝑒𝑟𝑠 1M Method divide by L3 = 1 960 AM 30 30 = 65,33  CA 1CA Answer (3) 4.1.2 Mode is the number that appears the most on the 1 Explanation Data data.  E 1 Correct mode L4 A Mode = 57% therefore her statement is 1 Conclusion invalid. C (3) 4.2.1 A=8A 1A for 8 Data B=6A 1A for 6 L2 (2) 4.2.2 (6+4+2+0) 1M finding probability Data P (less than 60%) = × 100 M 30 L3 1CA Answer CA = 40% CA (2) 4.3.1 A = 100% – (6+5+12+71) % M 1M Subtracting from Data = 6% A 100% L3 1A Answer Semi-detached houses= 6% × 324 292 M 1M finding 6% =19 457,52 =19 458 CA 1CA Answer (4) 4.3.2 Flush toilets = 90% x 324 292 M 1M using 90% F = 291 862,8  CA 1CA Answer L2 = 291 863  R 1R Rounding up (3) 4.3.3 Ratio = 12%: 6% M 1M using correct Data percentages L2 = 2 : 1 S 1 Simplification (2) 4.3.4 Granny flats O 2O Opinion Data OR L4 RDP houses O Accept any other relevant answer. (2) [21] TOTAL: 75 Copyright reserved Please turn over