Mathematical Literacy Grade 10 P2 National November 2017 Memo

NATIONAL SENIOR CERTIFICATE GRADE 10 NOVEMBER 2017 MATHEMATICAL LITERACY P2 MARKING GUIDELINE Codes Explanation M Method MA Method with Accuracy CA Consistent Accuracy A Accuracy C Conversion D Define J Justification/Reason/Explain S Simplification RD Reading from a table OR a graph OR a diagram OR a map OR a plan F Choosing the correct formula SF Substitution in a formula O Opinion P Penalty, e.g. for no units, incorrect rounding off, etc. R Rounding Off AO Answer only NPR No penalty for rounding off OR omitting units This marking guideline consists of 5 pages.

2 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2017) KEY TO TOPIC SYMBOL: F = Finance; M = Measurement; MP = Maps, Plans and other Representations DH = Data Handling; P = Probability QUESTION 1 [21 marks] Ques Solution Explanation Topic & Level 1.1.1 Purchases for the month M 1M Adding purchases F = 476,00 + 135,50 + 99,50 + 77,50 + 129,50 + 57,00 1A Total purchases L2 = R975,00 A (2) 1.1.2 0,31 1M Divide by 12 F Interest per month = M 12 L3 = 0,025833333  A 1A Monthly interest Interest on outstanding amount = 0,025833333  1215,80  M 1M Multiply by = R31,40816667 1215,80 ≈ R31,41  CA 1CA Interest amount OR 1M Multiply by 31 1215,80 Interest payable =  1215,80  M 100 1A Annual interest 376  M 1M Divide by 12 = 12  M 1CA Interest amount ≈ R31,41  M (4) 1.1.3 327,34MA 1MA Numerator and F Percentage =  100%  M 1 636,71 denominator L2 = 19,9998778 % 1M Multiply by 100 = 20 %  CA 1CA Percentage (3) 1.1.4 Dress did not fit.  A 2A Reason DH OR L4 Dress was too small.  A OR Dress was too big.  A OR Dress had a factory fault. A Accept any other relevant reason (2) 1.1.5 It is unhygienic.  A 1A Reason DH OR L4 It could have been fitted on.  A OR It is stated on the cash slip that underwear may not be returned.  A (2) Accept any other logical reason 1.2.1 The data is discrete,  A 1A Correct type DH because the Bunny Chows are counted / whole L4 numbers  O 2O Opinion (3) 1.2.2 It cannot be said with certainty, because the days of the P week are not given in the graph.  A 2O Opinion (2) L4 1.2.3 Day 27 to Day 28 decreased,  A 1O Decrease 27-28 DH Day 28 to Day 30 increased  A and 1O Increase 28-30 L4 Day 30 to Day 31 decreased  A 1O Decrease 30-31 (3) Copyright reserved Please turn over

(EC/NOVEMBER 2017) MATHEMATICAL LITERACY P2 3 QUESTION 2 [22 marks] Ques Solution Explanation Topic & Level 2.1.1 Fee for 2016 (A) = R3,00 + R1,30 / R100 F = 3,00 + 0,013 × 500  SF  M 1SF Substitution L3 = 3,00 + 6,5 1M Multiply 500 = R9,50  CA 1CA Fee Fee for 2017 = R10,70 Difference in price = R10,70 – R9,50 = R1,20  CA 1CA Difference OR Fee for 2016 (A) = 1,3 × 5 M 1M Multiply by 5 = 6,5 + 3CA M 1M Adding 3 = R9,50  CA CA 1CA Fee Fee for 2017 = R10,70 CA Difference in price = R10,70 – R9,50 = R1,20  CA 1CA Difference (4) 2.1.2 Percentage change – Withdrawal (Own Bank) F 10,70−10,45 = 10,45 × 100%  F 1F Correct formula L4 = 2,4 %  CA 1CA Percentage Percentage change – Withdrawal (Other Bank) 16,70−16,45 = 16,45 × 100% = 1,5 %  CA 1CA Percentage 50% more = 1,5 × 1,5 = 2,25 %  CA 1MA Calculate 50% 2,25 % ≠ 2,4% increase Statement is invalid  CA 1O Invalid (5) 2.2.1 1 1M Multiply by 28 M Grams of yeast = × 28  M 4 1A Number in grams L2 = 7 gram  A (2) 2.2.2 °C = (°F – 32) ÷ 1,8 1SF Substitute correct M = (115 °F – 32) ÷ 1,8  SF value L3 = 83 ÷ 1,8 S 1S Simplification = 46,11111111 = 46 °C  CA 1R Nearest °C (3) 2.2.3 Measurement of loaf pans in inches = 9 inch × 5 inch M Measurement of loaf pans in centimetres L4 = 22,86 cm × 12,7 cm 1MA Multiply by 2,54 9 inch × 2,54 = 22,86 cm  MA 1CA Convert 5 inch to 5 inch × 2,54 = 12,7 cm  CA cm She is using the correct loaf pans  O 1O Correct pans (3) 2.2.4 Total time M = Mixing + Rising + Panning + Baking  M 1M Adding all the L3&4 = 8 minutes + 90 minutes + 30 minutes + 30 minutes times (minimum) 158  CA 1CA Total time = 60 1CA Answer in hours = 2,63... hours  CA 1CA Convert to hours = 2 hours 38 minutes  CA and minutes Statement is not valid  O 1O Invalid (5) Copyright reserved Please turn over

4 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2017) QUESTION 3 [19 marks] Ques Solution Explanation Topic & Level  RD 3.1.1 Guests to invite = 112 – 2 M 1RD Number of seats MP = 110 guests  CA 1M Subtract 2 L2 1CA Number of guests (3) 3.1.2 For easy movement.  A 2O Reason MP OR L4 Uncomfortable to sit on the short side.  A Accept any other logical reason. (2) 3.1.3 A 1A Pass dance floor MP Walk pass the dance floor, pass the podium and turn 1A Direction L4 left.  A OR Accept any other logical explanation. (2) 3.1.4 Probability of guest sitting at table with even number 1A Numerator P =7 A 1 1A Denominator L2 A 1CA Answer to 3 = 0,142857142 decimal places (3) = 0,143  CA Answer must not be greater than 1 3.1.5 Floor Area of hall = length × width M = 15,5 m × 9 m  SF 1SF Substitution L3 = 139,5 m2  CA 1CA Floor Area 1 Area of Dance floor = × 139,5 m2 3 1CA Area of dance = 46,5 m2  CA floor (3) 3.2 Hiring of the venue: R3 500,00 CA from 3.1.1 F Draping and décor: R4 750,00 L3&4 Cost for DJ = R250 × 6 hours = R1 500  CA 1CA Cost for DJ Catering = (R200 × 100 guests) + (R100 × 13)  MA 1MA 200 × 100 and = R20 000 + R1 300 100 × 13 = R21 300  CA 1CA Total cost = R3 500,00 + R4 750,00 + R1 500 + R21 300  M 1M Adding all values = R31 050  CA 1CA Total cost Statement invalid  MA 1O Invalid (6) Copyright reserved Please turn over

(EC/NOVEMBER 2017) MATHEMATICAL LITERACY P2 5 QUESTION 4 [13 marks] Ques Solution Explanation Topic & Level 4.1 Statement invalid  A 1A Invalid MP  A The distance between the two towns is not the same 2O Explanation (3) L4 4.2.1 Mean temperature DH 16+17+17+17+ 16 + 15 + 13 + 14 + 13+14  M 1M Adding all values L3 = 10  M 152 1M Dividing by 10 = 10 1CA Mean = 15,2 °C  CA temperature (3) 4.2.2 Order 1M Ascending or DH -4; -2; -1; -1; 0; 1; 1; 1; 1; 1  M descending L2 0+1 1M Concept of Median = M 2 1 median = 2 = 0,5 °C  CA 1CA Median value (3) 4.2.3 Modal value = 1 °C  A 2A Modal value (2) DH L2 4.3 Probability of rain = Impossible  A 2A Impossible P OR L2 0 A 1A Numerator Probability of rain = 10 A 1A Denominator OR 2A 0% Probability of rain = 0 %  A OR 2A None (2) Probability of rain = None  A TOTAL: 75 Copyright reserved Please turn over