Mathematical Literacy Grade 10 P1 National November 2017 Memo

NATIONAL SENIOR CERTIFICATE GRADE 10 NOVEMBER 2017 MATHEMATICAL LITERACY P1 MARKING GUIDELINES MARKS: 75 Symbol Explanation M Method A Accuracy CA Consistent accuracy RT/RG/RM Reading from a table/graph/map SF Correct substitution in a formula P Penalty, e.g. for no units, incorrect rounding off etc. S Simplification R Rounding off AO Answer only This marking guideline consists of 6 pages.

2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2017) QUESTION 1 Quest Solution Explanation Level 1.1 1.1.1 Inverse/Indirect proportion  2M Correct Answer (2) L1 1.1.2 40 10 1M Divide by 10 : 10  10 1 CA =4:1 AO (2) L1 1.1.3 Direct proportion  1M Correct Answer (2) L1 1.2 1.2.1 1M Method 𝑅42,00 Cost price =  12 = R3,50  1CA Correct Answer L1 (2) 1.2.2 Selling price−Cost price % profit = × 100% 𝐶𝑜𝑠𝑡 𝑝𝑟𝑖𝑐𝑒 R5,00−R3,50 1SF Substitution = × 100%  𝑅3,50 1M Mark for L2 R1,50 = 𝑅3,50 × 100%  R1,50 = 42,8571% 1CA Answer (3) = 42,86%  1.3 1.3.1 Four thousand nine hundred and ninety nine rand  2M Correct Answer (2) L1 1.3.2 Deposit = 10% of R4 999 1M Multiply by 10 the correct %(10 = 100 × 𝑅4 999  ÷ 100) = R499,90  1CA Correct Answer (2) L1 Copyright reserved Please turn over

(EC/NOVEMBER 2017) MATHEMATICAL LITERACY P1 3 1.3.3 Total amount = R499,90  + R369,89 × 24  1M Addition = R9 377,26  1M Multiply by 24 1A Answer (3) L2 [18] QUESTION 2 2.1 Buffalo City Metropolitan Municipality  2RT Reading from the table (2) L1 2.2 19/05/2017  2RT Reading from the table (2) L1 2.3 Payment/Credit/Amount paid  2Explanation (2) Accept any relevant explanation L1 2.4 14% of R184,21 1M Method 14 = 100 × 𝑅184,21  = R25,7894 1R Rounding Answer Only ≈ R25,79  Full marks (2) L1 2.5 Cost = (6 𝐾𝑙 × 11,917550) + (4 𝐾𝑙 × 12,151250) + 1M Method (3𝐾𝑙 ×16,876510)  1M Addition = 71,5053 + 48,605 + 50,62953  = R170,73983 1CA Answer L3 = R170,74  (3) Copyright reserved Please turn over

4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2017) 2.6 Value A = R1 285,98 + R62,81  2M Addition = R1 348,79  1CA Answer OR Value A = (R1 433,18 – R800 – R12,15) + (R45 + R216,40 + R210 + R136,93 + R119,43)  1M Addition 1M Simplification = R621,03 + 727,76 L1 = R1 348,79  1CA Answer (3) [14] QUESTION 3 3.1 3.1.1 Spoon  (i.e. 4 spoons = 4 × 10 𝑚𝑙) 2A Answer (2) Accept teaspoons (i.e. 8 teaspoons = 8 × 5 𝑚𝑙) L1 3.1.2 24 ÷ 8 = 3  2M Method = 7 𝑚𝑙 × 3  = 21 𝑚𝑙  1A Answer (3) OR 7 𝑚𝑙 ∶ 8 𝑐𝑢𝑝𝑐𝑎𝑘𝑒𝑠 𝑥 ∶ 24 𝑐𝑢𝑝𝑐𝑎𝑘𝑒𝑠 8 𝑥 = 24 × 7  24 ×7 𝑥 =  8 𝑥 = 21 𝑚𝑙  L2 3.1.3 (℉− 32°) ℃= 1,8 (356°−32°) 1SF Substituting ℃=  Formula 1,8 ℃= 324°  1S Simplifying 1,8 1A Answer ℃ = 180°  (3) L2 Copyright reserved Please turn over

(EC/NOVEMBER 2017) MATHEMATICAL LITERACY P1 5 3.2 3.2.1 Perimeter is the distance around a 2-Dimensional 2A Answer shape  (2) Accept any relevant answer L1 3.2.2 V=𝑙 ×𝑤 ×ℎ 1SF Substituting Formula V = 40 𝑐𝑚 × 20 𝑐𝑚 × 6 𝑐𝑚  1CA Correct Answer V = 4 800 𝑐𝑚3  (2) L2 [12] QUESTION 4 4.1 South-East (SE)  2CA Correct Answer (2) L1 4.2 Eight windows/ 8 windows  2CA Correct Answer (2) L1 4.3 Seven interior doors/ 7 interior doors  2CA Correct Answer (2) L1 4.4 𝑙 = 4,5 𝑐𝑚 /45 𝑚𝑚  2CA Correct Answer Accept 4,3 – 4,7cm 𝑤 = 2,5 𝑐𝑚 /25𝑚𝑚  2,3 – 2,7cm (2) L1 4.5 Actual length = 4,5 𝑐𝑚 × 120  2M Method Calculating actual Actual width = 2,5 𝑐𝑚 × 120 length and width Actual area = 5,4 𝑚 × 3,0 𝑚  1CA Correct Answer Actual area = 16,2 𝑚2  OR Actual area = 540 𝑐𝑚 × 300 𝑐𝑚  1M Method = 162 000 𝑐𝑚2 ÷ 10 000  1M Dividing by = 16,2 𝑚2  10 000 1CA Correct Answer L2 (3) [11] Copyright reserved Please turn over

6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2017) QUESTION 5 5.1 5.1.1 17; 22; 25; 32; 34; 34; 39; 39; 42; 45; 47; 47; 47; 48; 2 Arrange values 50; 54; 62; 64; 67  Ascending (2) L1 5.1.2 Median = 45  2 Correct value Median (2) L1 5.1.3 Mode = 47  2 Correct value Mode (2) L1 5.1.4 Range = 67 – 17  1M Subtraction = 50%  1M Answer (2) L3 5.1.5 17+22+25+32+34+34+⋯+47+48 1M Adding value Mean =  19 815 = 19  1M Dividing by 19 = 42,894768 ≈ 43  1R Rounding (3) L2 5.1.6 3 1M Fraction P (less than 30%) = 19  × 100%  1M Multiply by 100% = 15,789  1M Answer 1M Rounding ≈ 16%  (4) L2 5.2 Interval Tally Frequency 2 answers correct 1 0–29 /// 3 mark 30–39 //// 5 3 answers correct 2 40–49 //// / 6 marks 50–59 // 2 4 answers correct 3 60–69 /// 3 marks Total 19 5 answers correct 4 marks Total correct 1 mark (5) L2 [20] TOTAL: 75 Copyright reserved Please turn over