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Mathematical Literacy Grade 10 P2 National November 2018 Memo

Grade 10 Mathematical Literacy Paper 2 memorandum from the National November Exam 2018 (English), 5 pages. Read online or get the free PDF download, question paper linked when available.

Subject: Mathematical LiteracyGrade 1020185 pages
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NATIONAL SENIOR CERTIFICATE GRADE 10 NOVEMBER 2018 MATHEMATICAL LITERACY P2 MARKING GUIDELINE MARKS: 75 Codes Explanation M Method MA Method with Accuracy CA Consistent Accuracy A Accuracy C Conversion D Define J Justification/Reason/Explain S Simplification RD Reading from a table OR a graph OR a diagram OR a map OR a plan F Choosing the correct formula SF Substitution in a formula O Opinion P Penalty, e.g. for no units, incorrect rounding off, etc. R Rounding Off AO Answer only NPR No penalty for rounding OR omitting units This marking guideline consists of 5 pages.
2 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2018) KEY TO TOPIC SYMBOL: F = Finance; M = Measurement; MP = Maps, Plans and other Representations DH = Data Handling; P = Probability. QUESTION 1 [25 marks]  Ques. Solution Explanation Topic and Level 1.1.1 A = R2 923,25 + R224,00 + R1 182,00 + R1 875,00 M 1M Adding all F = R6 204,25 A deductions L2 1A Total deductions (2) CA from (A) B = R6 204,25 + R18 795,75 MCA 1MCA Addition = R25 000 CA 1CA Gross Pay/ Basic Salary (2) 1.1.2 % Pension deduction CA from 1.1.1 (B) F 1 875 1MCA Correct values L2 = MCA × 100% M 1M Multiply by 100 25 000 = 7,5% (2) 1.1.3 Payslip no.: 75 F 75 1MA Divided by 12 L3 Years = MA 12 = 6,25 years A 1M Number of years Months = 0,25 × 12 = 3 months MCA 1MCA Convert decimal 6 years and 3 months CA part to months 1CA Years and months (4) 1.1.4  Privacy 2A Reason F OR L4  Confidentiality A OR  Fraud A (2) 1.1.5 New salary = R25 000 × 1,064 CA from 1.1.1 (B) F = R26 600 MCA 1MCA New Salary L4 New Tax Amount = R2 923,25 + R175,00 = R3 098,25 MA 1MA New Tax New Pension = R1 875,00 + R120,00 = R 1 995 MA 1MA New Pension Net pay = R26 600 – (R3 098,25 + R 1 995 + R224,00 + R1 182,00) = R26 600 – R6 499,25 MCA 1MCA Subtraction = R20 100,75 CA 1CA New Net Pay Difference in Net Pay = R20 100,75 – R18 795,75 = R1 305,00 CA 1CA Difference Statement valid O 1O Valid (7) No mark for opinion without calculations Copyright reserved Please turn over
(EC/NOVEMBER 2018) MATHEMATICAL LITERACY P2 3 1.2.1 Area of base = Length × Breadth M = 100 cm × 35 cm SF 1SF Correct length L3 = 1 m × 0,35 m C and breadth = 0,35 m2 CA 1C Conversion to m 1CA Area in m2 (3) Penalise for incorrect unit in final answer 1.2.2 Height of sand = 0,75 × 70 cm MA 1MA 75% of 70 M = 52,5 cm S 1S Simplification L2 ≈ 53 cm R 1R Nearest cm (3) [25] QUESTION 2 [20 marks] Ques. Solution Explanation Topic and Level 2.1.1 383 203 1MA Correct values DH % Storage = × 100% MA multiplied by 100 L2 898 221 = 42,7% A 1A Percentage (2) NPR A A 2.1.2 From 2014 to 2017 the water storage decreased and then 1A 2014 – 2017 DH increased in 2018 A 1A Decrease L4 1A Increase 2018 (3) 2.1.3 Below average rainfall A 2O Reason DH OR L4 Low rainfall (2) Copyright reserved Please turn over
4 MATHEMATICAL LITERACY P2 (EC/NOVEMBER 2018) 2.1.4 Mean % DH 38,7 + 37,1 + 65,8 + 33,9 + 27,4 + 50,1 M 1M Adding all values L3 = 6 M 250 1M Dividing by 6 = 1CA Average (3) 6 = 41,7% CA NPR 4 2.1.5 Probability = 6 A 2A Numerator P A 1A Denominator L2 = 0,667 CA 1CA 3 dec. places (4) 2.2 Volume of water tank M = 𝜋 × radius × radius × height 1SF Substitution L4 1A Radius A = 3,142 × 750 mm × 750 mm × 1 820 mm SF 1C Conversion to cm = 3,142 × 75 cm × 75 cm × 182 cm C 1CA Volume = 3 216 622.5 cm3 CA 1C Conversion to = 3 216, 6225 litres C litres O The advertised capacity refers to the maximum amount 1O Opinion of water the water tank can hold, while the calculated capacity refers to the actual content of the water tank. Accept any other relevant explanation. (6) [20] QUESTION 3 [18 marks] Ques. Solution Explanation Topic and Level 3.1.1 Perimeter of base = 2 × length + 2 × breadth M = (2 x 190 cm) + (2 × 160 cm) SF 1SF Substitution L3 = (2 × 1,9 m) + (2 × 1,6 m) C 1C Conversion to m = 3,8 m + 3,2 m = 7 m CA 1CA Perimeter (3) 3.1.2 Height of the sand = 0,805 x 31 cm MA 1MA Calculating % M = 24,955 cm L2 ≈ 25 cm SF 1R Nearest cm (2) 3.2.1 Playschool only caters for children from 3 months to 5 2A Reason MP years old. A (2) L4 3.2.2 Yes A 1A Yes MP There are toilets for the disabled. A 1O Reason (2) L2 Copyright reserved Please turn over
(EC/NOVEMBER 2018) MATHEMATICAL LITERACY P2 5 3.2.3 Safety reasons 2O Reason MP OR L4 Noise levels of crying babies A OR Close to the changing room A Accept any other relevant explanation (2) 3.3.1 2O Reason F The infants from 3 months – 1 year 6 months need more L4 attention. A They need to be changed regularly. A Accept any other relevant explanation (2) 3.3.2 Income = (9 × 1 050) + (10 × 820) + (16 × 550) 1M Multiplying and F = R9 450 + R8 200 + R8 800 S adding L3 = R26 450 × 12 M 1A Number of = R317 400 CA 3y7mnths – 5 yrs. 1S Simplification 1M Multiply by 12 1CA Annual income (5) [18] QUESTION 4 [12 marks] Ques. Solution Explanation Topic and Level A A 1A South MP 4.1.1 Travel south on the N1, pass the offramp on the east, 1A N1 L4 A 1A Turn west turn west at the intersection of the N1 and N12 and 1A N12 (4) continue the N12. A M 4.1.2 Bar scale: 1,8 cm = 1 000 m 1M Measure bar scale MP 1,8 cm = 100 000 cm C 1C Metres to cm L3 1 cm = 55 555, 55556 cm 1CA Unit scale ⸫ 1: 55 555,55556 CA Accept 1,7 – 1,9 No mark in the final answer if units indicated NPR (3) 4.2.1 1 500 000 A 1A 1 500 000 DH Number of tourists = 1,0625 M 1M Dividing by L2 = 1 411 764,706 1,0625 = 1 411 765 R 1CA Number of tourists (3) 4.2.2 Holiday in December A 2A Reason DH OR L4 People have money to travel A Accept any other relevant reason (2) [12] TOTAL: 75 Copyright reserved Please turn over

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