NATIONAL
SENIOR CERTIFICATE
GRADE 10
NOVEMBER 2018
MATHEMATICAL LITERACY P1
MARKING GUIDELINE
MARKS: 75
INSTRUCTIONS AND INFORMATION FOR MARKING
Symbol Explanation
M Method
MA Method with accuracy
A Accuracy
CA Consistent accuracy
RT/RG/RM Reading from a table/graph/map
SF Correct substitution in a formula
P Penalty, e.g. for no units, incorrect rounding off etc.
S Simplification
R Rounding off
NPR No penalty rounding or omitting units
AO Answers only full marks
C Conversion
This marking guideline consists of 7 pages.
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Mathematical Literacy Grade 10 P1 National November 2018 Memo
Grade 10 Mathematical Literacy Paper 1 memorandum from the National November Exam 2018 (English), 7 pages. Read online or get the free PDF download, question paper linked when available.
Mathematical Literacy · Grade 10 · National November Exam · 2018 · English. Memorandum, 7 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 10
- Language
- English
- Document type
- Memorandum
- Year
- 2018
- Exam period
- National November Exam
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 7
- File size
- 304.3 KB
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2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2018)
QUESTION 1
Quest Solution Explanation L/T
1.1
1.1.1 R499,00 2RT Reading value
from table
Answer L1
(2) F
1.1.2 Total cost price = 90% × R499,00 1M
= R449,10 1 CA
OR
10 1M
Total cost price = × R499 = R49,90
100
1CA
L1
R499,00 – R49,90 = R449,10
Answer (2) F
1.1.3 Original price of item = R499,00 ÷ 1,15 1M Answer
= R433,91 1Divide by 1,15
= R434,00 1CA L1
Answer (3) F
1.1.4 1M Method L1
15 F
Deposit amount = × 499,00
100
= R74,85
1CA
Answer
OR
85% × 𝑅499,00 = R424,15
1M Method
1CA Answer
R499,00 – R424,15 = R74,85
(2)
Copyright reserved Please turn over
(EC/NOVEMBER 2018) MATHEMATICAL LITERACY P1 3
Quest Solution Explanation L/T
1.1.5 Length = 120 cm ÷ 100 1M division by 100
L1
= 1,2 metres 1C
M
2MA Answer
(2)
1.2 Discrete data is usually whole values / collected by 2A explanation
counting people or objects.
L1
Accept any relevant explanation. (2) D
1.3 This means that every 1 unit on the plan is equivalent to 2A explanation
100 units in real life. L1
Accept any relevant explanation. (2) MP
[15]
QUESTION 2
Quest Solution Explanation L/T
2.1
2.1.1 R13,27 2RT Reading from L1
the table (2) F
𝑅13,89 −𝑅13,27
2.1.2 % 𝑐ℎ𝑎𝑛𝑔𝑒 = × 100% 1SF L2
𝑅13,27
𝑅0,62 F
= × 100% 1S
𝑅13,27
= 4,67% 1CA (3)
2.2
2.2.1 Cost = 𝑅0,80 × 30 = 𝑅24,00 1M Multiply by 30 L2
1CA amount F
(2)
2.2.2 Time (hrs.+ min) = 2 × 60 + 30 1M L2
F
= 150 minutes 1C
= 150 × 0,90 1M multiply by
90 cents
= R135,00 1CA answer
(4)
Copyright reserved Please turn over
4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2018)
Quest Solution Explanation L/T
2.2.3 𝑅135,00 1M
Cost in rands =
30
1CA amount
= R4,50 per day
Answer from 2.2.2 L1
(2) F
2.3 Add parts: 2 + 3 = 5 1M
2 1CA amount L2
Mandy will receive: × R500 = R200
5
(2) F
2.4
2.4.1 R200 or two hundred rands 2RG
L2
(2) F
2.4.2 2 people 2RG L2
(2) F
2.4.3 Costs = R800 ÷ 9 1M
= R88,888
= R88,89 1CA simplification
L2
NPR (2) F
[21]
QUESTION 3
Quest Solution Explanation L/T
3.1
3.1.1 10 : 15 1MA Correct ratio
2: 3 OR 1:1,5 1CA simplification
answer is given as a
unit ratio L1
(2) M
3.1.2 Water: 1,5 x 500 mℓ = 750 mℓ
1MA
Salt: 1,5 x 5 mℓ = 7,5 mℓ
1MA
L2
(2) M
3.1.3 Flour (grams) = 0,25 x 1 000 = 250 grams 1M
1CA
L1
(2) M
Copyright reserved Please turn over
(EC/NOVEMBER 2018) MATHEMATICAL LITERACY P1 5
Quest Solution Explanation L/T
3.2 Perimeter fence = 2(6,5 m+ 0,8 m) +2(4,5 m+0,8 m) 1A adding correct
lengths
= 2(7,3 m) + 2(5,3 m) 1C conversion to m
= 14,6 m +10,6 m 1CA simplification
= 25,2 m 1CA answer
OR
Perimeter fence = 2(650 + 80) +2(450 + 80) 1A adding correct
lengths
= 1 460 cm +1 060 cm 1CA simplification
= 2 520 cm ÷100 cm 1C conversion to m
1CA answer
= 25,2 m L3
(4) M
3.3
3.3.1 90 ℉ 2RT
Accept 89 to 91 ℉ L1
(2) M
9
3.3.2 ℉= × 32° + 32° 1SF
5
= 57,6 + 32°
1Simplification
= 89,6°
= 90 ℉
1CA answer L2
(3) M
[15]
Copyright reserved Please turn over
6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2018)
QUESTION 4
Quest Solution Explanation L/T
4.1 Distance (in km) = 15 cm × 3 750 000 1M
= 56 250 000 ÷ 100 000 1C
1CA answer
= 562,5 km L1
(3) MP
4.2 Length
500 mm ÷ 100 mm = 5 tins 1M dividing
Width
300 mm ÷ 100 mm = 3 tins 1M dividing
Height
240 mm ÷ 120 mm = 2 tins 1M dividing
Total number of tins
5 × 3 × 2 = 30 tins
1M multiplying
1CA simplification L2
(5) MP
[8]
QUESTION 5
Quest Solution Explanation L/T
5.1
5.1.1 Mode 55 2RT L1
(2) D
5.1.2 Mean is a type of average obtained when all the scores 2A explanation
are added together and then divided by the number of
scores.
L1
Accept any relevant explanation. (2) D
5.1.3 44; 46; 47; 49; 50; 51; 1M arranging values in
52; 53; 55; 55; 55; 58; 60; 62; 64 ascending order
53 + 55
Median =
2
108 1M simplifying
=
2
1A correct value L1
= 54 (3) D
Copyright reserved Please turn over
(EC/NOVEMBER 2018) MATHEMATICAL LITERACY P1 7
Quest Solution Explanation L/T
5.1.4 Range = 64 – 44 1M
= 20 1A L1
(2) D
5.2
5.2.1 A = 327 − 212 B = 212 + 101 2 MA for A value
= 115 = 313 2MA for B value
OR
A = 487 − 372 B = 800 − 487 2MA for A value
= 115 = 313 2MA for B value L1
(4) D
5.3 473 1RT numerator
P(Girl) =
800
1M multiply by 100
= 0,59125 x 100
CA answer
= 59,125%
= 59,13% NPR L1
(3) P
[16]
TOTAL: 75
Copyright reserved Please turn over
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