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Memorandum

Mathematical Literacy Grade 10 P1 National November 2018 Memo

Grade 10 Mathematical Literacy Paper 1 memorandum from the National November Exam 2018 (English), 7 pages. Read online or get the free PDF download, question paper linked when available.

Subject: Mathematical LiteracyGrade 1020187 pages
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NATIONAL SENIOR CERTIFICATE GRADE 10 NOVEMBER 2018 MATHEMATICAL LITERACY P1 MARKING GUIDELINE MARKS: 75 INSTRUCTIONS AND INFORMATION FOR MARKING Symbol Explanation M Method MA Method with accuracy A Accuracy CA Consistent accuracy RT/RG/RM Reading from a table/graph/map SF Correct substitution in a formula P Penalty, e.g. for no units, incorrect rounding off etc. S Simplification R Rounding off NPR No penalty rounding or omitting units AO Answers only full marks C Conversion This marking guideline consists of 7 pages.
2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2018) QUESTION 1 Quest Solution Explanation L/T 1.1 1.1.1 R499,00  2RT Reading value from table Answer L1 (2) F 1.1.2 Total cost price = 90% × R499,00  1M = R449,10  1 CA OR 10 1M Total cost price = × R499 = R49,90  100 1CA L1 R499,00 – R49,90 = R449,10  Answer (2) F 1.1.3 Original price of item = R499,00 ÷ 1,15  1M Answer = R433,91  1Divide by 1,15 = R434,00  1CA L1 Answer (3) F 1.1.4 1M Method L1 15 F Deposit amount = × 499,00  100 = R74,85  1CA Answer OR 85% × 𝑅499,00 = R424,15  1M Method 1CA Answer R499,00 – R424,15 = R74,85  (2) Copyright reserved Please turn over
(EC/NOVEMBER 2018) MATHEMATICAL LITERACY P1 3 Quest Solution Explanation L/T 1.1.5 Length = 120 cm ÷ 100  1M division by 100 L1 = 1,2 metres  1C M 2MA Answer (2) 1.2 Discrete data is usually whole values / collected by 2A explanation counting people or objects.   L1 Accept any relevant explanation. (2) D 1.3 This means that every 1 unit on the plan is equivalent to 2A explanation 100 units in real life.  L1 Accept any relevant explanation. (2) MP [15] QUESTION 2 Quest Solution Explanation L/T 2.1 2.1.1 R13,27  2RT Reading from L1 the table (2) F 𝑅13,89 −𝑅13,27 2.1.2 % 𝑐ℎ𝑎𝑛𝑔𝑒 = × 100%  1SF L2 𝑅13,27 𝑅0,62 F = × 100%  1S 𝑅13,27 = 4,67%  1CA (3) 2.2 2.2.1 Cost = 𝑅0,80 × 30  = 𝑅24,00  1M Multiply by 30 L2 1CA amount F (2) 2.2.2 Time (hrs.+ min) = 2 × 60 + 30  1M L2 F = 150 minutes  1C = 150 × 0,90  1M multiply by 90 cents = R135,00  1CA answer (4) Copyright reserved Please turn over
4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2018) Quest Solution Explanation L/T 2.2.3 𝑅135,00 1M Cost in rands =  30 1CA amount = R4,50 per day  Answer from 2.2.2 L1 (2) F 2.3 Add parts: 2 + 3 = 5 1M 2 1CA amount L2 Mandy will receive: × R500 = R200  5 (2) F 2.4 2.4.1 R200 or two hundred rands  2RG L2 (2) F 2.4.2 2 people  2RG L2 (2) F 2.4.3 Costs = R800 ÷ 9  1M = R88,888 = R88,89  1CA simplification L2 NPR (2) F [21] QUESTION 3 Quest Solution Explanation L/T 3.1 3.1.1 10 : 15  1MA Correct ratio 2: 3  OR 1:1,5  1CA simplification answer is given as a unit ratio L1 (2) M 3.1.2 Water: 1,5 x 500 mℓ = 750 mℓ  1MA Salt: 1,5 x 5 mℓ = 7,5 mℓ  1MA L2 (2) M 3.1.3 Flour (grams) = 0,25 x 1 000 = 250 grams  1M 1CA L1 (2) M Copyright reserved Please turn over
(EC/NOVEMBER 2018) MATHEMATICAL LITERACY P1 5 Quest Solution Explanation L/T 3.2 Perimeter fence = 2(6,5 m+ 0,8 m) +2(4,5 m+0,8 m)  1A adding correct lengths = 2(7,3 m) + 2(5,3 m)  1C conversion to m = 14,6 m +10,6 m  1CA simplification = 25,2 m  1CA answer OR Perimeter fence = 2(650 + 80) +2(450 + 80)  1A adding correct lengths = 1 460 cm +1 060 cm  1CA simplification = 2 520 cm ÷100 cm  1C conversion to m 1CA answer = 25,2 m  L3 (4) M 3.3 3.3.1 90 ℉  2RT Accept 89 to 91 ℉ L1 (2) M 9 3.3.2 ℉= × 32° + 32°  1SF 5 = 57,6 + 32°  1Simplification = 89,6° = 90 ℉  1CA answer L2 (3) M [15] Copyright reserved Please turn over
6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2018) QUESTION 4 Quest Solution Explanation L/T 4.1 Distance (in km) = 15 cm × 3 750 000  1M = 56 250 000 ÷ 100 000 1C 1CA answer = 562,5 km  L1 (3) MP 4.2 Length 500 mm ÷ 100 mm = 5 tins  1M dividing Width 300 mm ÷ 100 mm = 3 tins  1M dividing Height 240 mm ÷ 120 mm = 2 tins  1M dividing Total number of tins 5 × 3 × 2  = 30 tins  1M multiplying 1CA simplification L2 (5) MP [8] QUESTION 5 Quest Solution Explanation L/T 5.1 5.1.1 Mode 55  2RT L1 (2) D 5.1.2 Mean is a type of average obtained when all the scores 2A explanation are added together and then divided by the number of scores.  L1 Accept any relevant explanation. (2) D 5.1.3 44; 46; 47; 49; 50; 51; 1M arranging values in 52; 53; 55; 55; 55; 58; 60; 62; 64  ascending order 53 + 55 Median = 2 108 1M simplifying =  2 1A correct value L1 = 54  (3) D Copyright reserved Please turn over
(EC/NOVEMBER 2018) MATHEMATICAL LITERACY P1 7 Quest Solution Explanation L/T 5.1.4 Range = 64 – 44  1M = 20  1A L1 (2) D 5.2 5.2.1 A = 327 − 212  B = 212 + 101  2 MA for A value = 115  = 313  2MA for B value OR A = 487 − 372  B = 800 − 487  2MA for A value = 115  = 313  2MA for B value L1 (4) D 5.3 473 1RT numerator P(Girl) =  800 1M multiply by 100 = 0,59125 x 100  CA answer = 59,125% = 59,13%  NPR L1 (3) P [16] TOTAL: 75 Copyright reserved Please turn over

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