Mathematical Literacy Grade 10 P1 National November 2019 Memo

NATIONAL SENIOR CERTIFICATE GRADE 10 NOVEMBER 2019 MATHEMATICAL LITERACY P1 MARKING GUIDELINE MARKS: 75 INSTRUCTIONS AND INFORMATION FOR MARKING Symbol Explanation M Method MA Method with accuracy A Accuracy CA Consistent accuracy RT/RG/RM Reading from a table/graph/map SF Correct substitution in a formula P Penalty, e.g. for no units, incorrect rounding off etc. S Simplification R Rounding off NPR No penalty rounding or omitting units AO Answers only, full marks C Conversion This marking guideline consists of 6 pages.

2 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2019) QUESTION 1 Quest Solution Explanation Level 1.1 R7 500,00 √√ 2A correctly identifying value (2) L1 1.2 Discrete √√ 2A correct answer (2) L1 1.3 Number of males = 120 × 45% √ 1MA multiplying = 120 × 0,45 correct values = 54 males √ 1A (2) L1 1.4.1 23:55 – 18:30 √ 1M subtracting = 5 hours 25 min √ time 1A correct time in hours and minutes (2) L1 1.4.2 Total Cost = R7 500 + R900 √√ CA FROM 1.4.1 = R8 400 √ 1A R900 1MA adding correct values 1CA answer (3) L1 1.4.3 𝑅8 400 CA FROM 1.4.2 Average cost = √ 120 1M = R70 √ 1CA (2) L1 1.5 Perimeter = 6 m × 4 √ 1SF correct values = 24 m √ in formula 1A answer in m (2) L1 [15] Copyright reserved Please turn over

(EC/NOVEMBER 2019) MATHEMATICAL LITERACY P1 3 QUESTION 2 Quest Solution Explanation Level 2.1.1 R65,00 √√ 2RT reading correct value from table (2) L1 2.1.2 R1 700 – R1 500 = R200 (over R1 500) √ 1M subtracting amounts ∴ Cost = R12,00 + (R1,20 × 2) √ 1SF = R14,40 √ 1CA OR R200 ÷ 100 = 2 √ 1M dividing (2 × R1,20) + R12,00 √ 1SF = R14,40 √ 1CA (3) L2 2.1.3 R0,00 √√ 2RT identifying OR correct value from No money √√ table (2) L1 2.2 VAT = 15% × R90,80 √ 1MA multiplying = 0,15 × R90,80 correct values = R13,62 √ 1A answer (2) L1 2.3 Interest per year = R2 000 × 0,095 1MA calculating = R190 √ interest per year Total Interest = R190 × 2 1M multiplying by 2 = R380 √ years Total value = R2 000 + R380 1CA final answer = R2 380 √ (3) L2 2.4.1 Variable: groceries, petrol, electricity, clothing, 2RT one variable and entertainment (CHOOSE ONE) √ one fixed Fixed: rent, car payment, insurance (Choose ONE) √ (2) L1 Copyright reserved Please turn over

4 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2019) 2.4.2 Total = 1 + 4 1MA adding parts for = 5 parts √ ratio 1 ∴ Electricity = × 𝑅3 700 √ 1M calculating ratio 5 1CA answer = R740 √ (3) L2 1MA multiplying 2 100 2.4.3 %= × 100 √ correct values 11 750 1S simplifying = 17,8723 … √ correctly = 18% √ 1R rounding to nearest % (3) L2 [20] QUESTION 3 Quest Solution Explanation Level 3.1 5 windows √√ 2RM (2) L1 3.2 West √√ 2A (2) L1 3.3.1 One unit on the floor plan is equal to fifty units 2 Explanation in reality. √√ (2) L1 3.3.2 Real width: 4,8 cm × 50 = 240 cm 1MA using scale to ≈ 2,4 m √ calculate length and width Real length: 9,3 cm × 50 = 465 cm ≈ 4,65 m √ 1MA converting to metres ∴ Area = 2,4 m × 4,65 m √ = 11,16 m2 √ 1SF substituting correct values 1CA answer (4) L3 [10] Copyright reserved Please turn over

(EC/NOVEMBER 2019) MATHEMATICAL LITERACY P1 5 QUESTION 4 Quest Solution Explanation Level 4.1 ¾ × 250 mℓ =187,5 mℓ √ 1MA multiplying correct values ∴ 187,5 mℓ × 3 √ = 562,5 mℓ √ 1S simplifying by multiplying by 3 OR 1CA answer in mℓ 9 ¾×3=4√ (3) 9 ∴ × 250 mℓ √ 4 = 562,5 mℓ √ L2 4.2 75mℓ ÷ 15 mℓ √ 1MA dividing correct = 5 tbsp √ values 1A answer (2) L1 4.3 0,23 kg × 1 000 √ 1MA multiplying = 230 g √ correct values 1A answer (2) L1 4.4.1 Radius = 32 cm ÷ 2 √ 2A correct radius = 16 cm √ AO acceptable OR Accept answer in mm Radius = 320 mm ÷ 2 √ or cm = 160 mm √ (2) L1 4.4.2 Volume = 3,142 × (160 mm)2 × 12 mm √√ CA FROM 4.4.1 = 965 222,4 mm3 √ (64 cm or 640 mm) OR 1C convert Volume = 3,142 × (16 cm)2 × 1,2 cm √ 1SF correct = 965, 2224 cm3 √ substitution ≈ 965 222,4 mm3 √ 1CA answer in mm3 (3) L2 [12] Copyright reserved Please turn over

6 MATHEMATICAL LITERACY P1 (EC/NOVEMBER 2019) QUESTION 5 Quest Solution Explanation Level 5.1.1 The median is the middle value of a data set, after 2A Correct definition arranging it in ascending/descending order. √√ (2) L1 5.1.2 R5 √ 2A correctly R29 √ identifying R5 and R29 (2) L1 5.1.3 383 1MA adding correctly Average = √√ 16 1M divide by 16 = 23,9375 √ 1CA (3) L2 5.1.4 √ 1MA using correct Range = 110 – 5 √ values = 105 1M subtracting (2) L1 5.1.5 5 1A correct numerator Probability (R29) = √√ 16 1A correct = 0,3125 denominator ≈ 0,313 √ 1 Rounding (3) L2 5.2.1 Pie chart √√ 2A identifying correct graph (2) L1 5.2.2 Adidas, Nike, Puma √√ 2RG correctly identifying top 3 OR A, C, D √√ (2) L1 5.2.3 32% × 300 √ 1MA multiplying = 96 learners √ correct values 1A (2) L2 [18] TOTAL: 75 Copyright reserved Please turn over