Mathematical Literacy Grade 10 P1 2026 Memo (Eng)

Mock hlayiso mock exams Practice Series: Grade 10 Exam Preparation WWW.HLAYISO.COM NATIONAL SENIOR CERTIFICATE GRADE 10 MATHEMATICAL LITERACY P1 NOVEMBER EXAMINATION 2026 (MOCK) MARKING GUIDELINES MARKS: 75 These marking guidelines consist of 7 pages. Copyright reserved Please turn over

Mathematical Literacy/P1 2 Hlayiso/Mock 2026 NSC – Marking Guidelines SYMBOL AND EXPLANATION Symbol Explanation Symbol Explanation M Method A Accuracy MA Method with accuracy CA Consistent accuracy C Conversion D Definition F Choosing the correct formula SF Substitution in a formula J Justification O Opinion/Reason/Example P Penalty (e.g. no units, incorrect rounding) R Rounding RT/RG Reading from a table/graph S Simplification NPR No penalty for rounding AO Answer only, full marks KEY TO TOPIC AND LEVEL: F = Finance; M = Measurement; DH = Data handling; P = Probability; L1–L4 = cognitive levels 1 to 4 NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error. • Answers only, without working, are awarded full marks unless stated otherwise. • In opinion or verification questions, marks are only awarded if the relevant calculations are shown. QUESTION 1 1.1.1 Fixed: rent / funeral policy / school fees / cellphone ✓A ONE fixed expense contract / savings ✓A ONE variable expense Variable: groceries / prepaid electricity / transport (taxi (Accept clothing account as fares) / clothing account / entertainment either fixed or variable) F L1 (2) 1.1.2 Twenty-one thousand six hundred rand ✓✓A correct words (1 mark if “rand” is omitted) F L1 (2) 1.1.3 A = R4 200 ÷ 12 ✓M dividing by 12 = R350 ✓A answer F L1 (2) Copyright reserved Please turn over

Mathematical Literacy/P1 3 Hlayiso/Mock 2026 NSC – Marking Guidelines 1.1.4 B = R4 950 + R4 380 + R1 246 + R1 640 + R385 + ✓M adding ALL ten R350 + R399 + R600 + R1 000 + R650 expenses = R15 600 ✓CA answer from 1.1.3 F L1 (2) 1.1.5 Surplus = R21 600 − R15 600 ✓M income − expenditure = R6 000 ✓CA answer from 1.1.4 F L2 (2) 1.1.6 Rent + groceries = R4 950 + R4 380 = R9 330 ✓M adding rent and R9 330 groceries %= × 100% R21 600 ✓M % of total income = 43,19% ✓A/O 43,19% and 43,19% < 50%, so her statement is VALID. conclusion OR (Alternative: ✓M adding Half of R21 600 = R10 800 ✓M half of R21 600 ✓A/O R9 330 < R10 800, so her statement is VALID. R10 800 and conclusion) (Conclusion mark only if calculations are shown) F L3 (3) 2 1.2 Emergency fund = × R6 000 ✓M total parts = 5 5 = R2 400 ✓M 52 × surplus (Holiday fund = 35 × R6 000 = R3 600) ✓CA answer from 1.1.5 F L2 (3) [16] Copyright reserved Please turn over

Mathematical Literacy/P1 4 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 2 2.1.1 15 September 2026 (15/09/2026) ✓✓RT correct date F L1 (2) 2.1.2 It is the payment of R1 862,40 that Ms Mokoena made ✓✓O explanation (payment (on 30/07/2026) to pay off the previous balance. It is made / amount paid in / subtracted, so the balance brought forward is R0,00. credit) F L2 (2) 2.1.3 Water used = 4 541 kℓ − 4 518 kℓ ✓RT both readings = 23 kℓ ✓M subtracting F L1 (2) 2.1.4 First 6 kℓ: R0,00 ✓RT correct tariffs from the Next 9 kℓ: 9× R18,60 = R167,40 table Remaining 23 − 15 = 8 kℓ: 8× R26,40 = R211,20 ✓M 9 kℓ × R18,60 A = R0 + R167,40 + R211,20 = R378,60 ✓M 8 kℓ × R26,40 ✓CA total (Max 2 marks if 23 kℓ is multiplied by one tariff only) F L3 (4) 2.1.5 VAT = 15%× R185,00 ✓M 15% of R185,00 = 0,15× R185,00 = R27,75 ✓A simplification F L2 (2) 2.1.6 B = 15%× R378,60 = R56,79 ✓CA value of B from 2.1.4 C = R0,00 + R412,50 + R378,60 + R56,79 + ✓M adding ALL the current R185,00 + R27,75 + R238,00 + R35,70 charges = R1 334,34 ✓CA value of C F L3 (3) 2.1.7 New tariff = R26,40 ×1,075 ✓M increasing by 7,5% OR R26,40 + (7,5% × R26,40) = R26,40 + R1,98 ✓A new tariff = R28,38 per kℓ ✓O conclusion R28,38 > R28,00, so her claim is VALID. F L3 (3) Copyright reserved Please turn over

Mathematical Literacy/P1 5 Hlayiso/Mock 2026 NSC – Marking Guidelines 2.2 n = 18 ÷ 12 = 1,5 years ✓C converting 18 months to A = R7 800 (1 + 0,068 × 1,5) 1,5 years = R7 800 × 1,102 = R8 595,60 ✓SF substitution Interest = R8 595,60 − R7 800 = R795,60 ✓CA final amount OR ✓CA interest Interest = R7 800 ×0,068 × 1,5 = R795,60 (Alternative I = P × i × n: ✓C 1,5 years ✓SF ✓M P × i × n ✓CA R795,60 – full marks) (If n = 18 is used: max 2 marks) F L2 (4) [22] QUESTION 3 3.1.1 Discrete ✓✓A DH L1 (2) 3.1.2 9; 12; 14; 16; 18; 20; 22; 25; 25; 25; 28; 31; 35; 42 ✓✓A all 14 values in correct order (1 mark if one value is missing or out of order) DH L1 (2) 22 + 25 3.1.3 Median = ✓M average of the 7th and 2 = 23,5 bottles 8th values ✓CA answer from 3.1.2 DH L2 (2) 3.1.4 Mode = 25 bottles ✓✓A DH L1 (2) 3.1.5 Sum = 9 + 12 + 14 + 16 + 18 + 20 + 22 + 25 + 25 + ✓M adding the values 25 + 28 + 31 + 35 + 42 = 322 ✓M dividing by 14 322 Mean = ✓CA answer 14 = 23 bottles DH L2 (3) Copyright reserved Please turn over

Mathematical Literacy/P1 6 Hlayiso/Mock 2026 NSC – Marking Guidelines 3.1.6 More than 30 bottles: 31; 35; 42 ⇒ 3 members ✓A 3 members 3 ✓M dividing by 14 P(more than 30) = 14 ✓R decimal rounded to 2 = 0,214 . . . ≈ 0,21 decimal places P L2 (3) 3.2.1 Paper = 100% − (35% + 20% + 15% + 8%) ✓M subtracting from 100% = 22% ✓A answer DH L2 (2) 3.2.2 Glass and cans = 20% + 15% = 35% ✓RG 20% and 15% Mass = 35% × 160 kg ✓M percentage of 160 kg = 56 kg ✓A answer with unit OR DH L2 (3) Glass = 0,2 × 160 = 32 kg; Cans = 0,15 × 160 = 24 kg Total = 32 + 24 = 56 kg [19] Copyright reserved Please turn over

Mathematical Literacy/P1 7 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 4 4.1.1 Distance (in km) ✓✓A F L1 (2) 4.1.2 B = R650 + R8,50 ×150 ✓M R650 + R8,50 × 150 = R650 + R1 275 = R1 925 ✓A value of B A: R2 350 − R650 = R1 700 ✓M subtracting R650 and A = R1 700 ÷ R8,50 = 200 km dividing by R8,50 (Pattern: distance increases by 50 km, cost by R425) ✓A value of A (AO: full marks) F L2 (4) 4.1.3 Cost = R650 + R8,50 ×136 ✓M substituting 136 km = R650 + R1 156 = R1 806,00 ✓A total cost Per learner = R1 806 ÷22 ✓M dividing by 22 = R82,09 ✓O conclusion based on R82,09 < R85,00, so his statement is CORRECT. R82,09 (accept R82,10 / R82; NPR) F L4 (4) R1 199 − R899 4.2.1 % discount = × 100% ✓SF substitution R1 199 R300 ✓S R300 discount = × 100% ✓CA percentage R1 199 = 25,02% (accept 25%) F L2 (3) 4.2.2 Profit = R899 − R620 ✓M selling price − cost = R279,00 price ✓A answer F L1 (2) 4.2.3 Total profit = 46× R279 ✓M multiplying by 46 = R12 834,00 ✓CA total profit from 4.2.2 R12 834 > R12 500, so the manager’s claim is VALID. ✓O conclusion F L3 (3) [18] TOTAL: 75 Copyright reserved