Mathematical Literacy Grade 10 P2 2026 Memo (Eng)

Mock hlayiso mock exams Practice Series: Grade 10 Exam Preparation WWW.HLAYISO.COM NATIONAL SENIOR CERTIFICATE GRADE 10 MATHEMATICAL LITERACY P2 NOVEMBER EXAMINATION 2026 (MOCK) MARKING GUIDELINES MARKS: 75 These marking guidelines consist of 6 pages. Copyright reserved Please turn over

Mathematical Literacy/P2 2 Hlayiso/Mock 2026 NSC – Marking Guidelines SYMBOL AND EXPLANATION Symbol Explanation Symbol Explanation M Method A Accuracy MA Method with accuracy CA Consistent accuracy C Conversion D Definition F Choosing the correct formula SF Substitution in a formula J Justification O Opinion/Reason/Example P Penalty (e.g. no units, incorrect rounding) R Rounding RT/RM Reading from a table/map S Simplification NPR No penalty for rounding AO Answer only, full marks KEY TO TOPIC AND LEVEL: M = Measurement; MP = Maps, plans and other representations; P = Probability; L1–L4 = cognitive levels 1 to 4 NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error. • Answers only, without working, are awarded full marks unless stated otherwise. • In opinion or verification questions, marks are only awarded if the relevant calculations are shown. QUESTION 1 1.1 1.1.1 D ✓A 1.1.2 C ✓A 1.1.3 A ✓A 1.1.4 B ✓A M L1 (4) 1.2.1 13:45 ✓✓A correct 24-hour time (13:45 p.m.: 1 mark) M L1 (2) 1.2.2 08:15 + 37 min 50 s ✓M adding the race time = 08:52:50 (accept 8:52:50 a.m.) ✓A answer M L2 (2) Copyright reserved Please turn over

Mathematical Literacy/P2 3 Hlayiso/Mock 2026 NSC – Marking Guidelines 1.3.1 3 × 15 mℓ ✓M multiplying by 15 = 45 mℓ ✓A answer M L1 (2) 1.3.2 30 ℓ = 30 000 mℓ ✓C converting to mℓ (or 750 Number of mixes = 30 000 ÷ 750 = 40 mℓ = 0,75 ℓ) Powder = 40 × 3 × 10 g = 1 200 g ✓M dividing by 750 Tubs = 1 200 ÷ 500 = 2,4 ✓M mass of powder (30 g They must buy 3 tubs. per mix) OR ✓R rounding UP to 3 tubs 30 000 ÷ 750 × 30 g = 1 200 g; 1 200 ÷ 500 = 2,4 ≈ 3 (2 tubs: max 3 marks) tubs M L3 (4) 1.4 ◦ C = (77 − 32) ÷ 1,8 ✓SF substitution = 45 ÷ 1,8 ✓S simplification = 25 ◦ C ✓A answer M L2 (3) [17] QUESTION 2 2.1.1 A scaled drawing that shows the layout (rooms, walls, ✓✓D correct explanation doors and windows) of a building as seen from above. (Partial explanation: 1 mark) MP L1 (2) 2.1.2 South-east (SE) ✓✓A (South only or East only: 0 marks) MP L2 (2) 2.1.3 Walk north through the lounge and through the arch ✓A lounge and arch into the into the passage. passage Turn right (go east) along the passage. ✓A turn right/east Bedroom 2 is the last door on the left-hand side (north) ✓A door on the left/north of the passage. (Accept any correct, logical route.) MP L3 (3) Copyright reserved Please turn over

Mathematical Literacy/P2 4 Hlayiso/Mock 2026 NSC – Marking Guidelines 2.1.4 Bedroom 2 and Bedroom 3 ✓A Bedroom 2 (they have windows in the EAST wall; the sun rises in ✓A Bedroom 3 the east) MP L3 (2) 2.1.5 1 unit (e.g. 1 cm) on the plan represents 100 of the ✓✓A correct explanation same units (e.g. 100 cm = 1 m) in reality. (No mention of the same units: 1 mark) MP L1 (2) 2.1.6 6,5 cm ×100 = 650 cm ✓M multiplying by 100 650 ÷ 100 = 6,5 m ✓C converting to m ✓CA answer in m MP L2 (3) 2.1.7 Length = 4,5 × 100 = 450 cm = 4,5 m ✓M using the scale Width = 3,5 × 100 = 350 cm = 3,5 m ✓C converting to metres Area = 4,5 m × 3,5 m = 15,75 m2 ✓CA area 15,75 m2 is LESS than 16 m2 ✓J conclusion Her claim is NOT valid. MP L4 (4) 2.1.8 North-facing windows = 4; total windows = 12 ✓RM 4 and 12 P(north) = 4 × 100% ✓CA percentage 12 P L2 (2) = 33,3% (accept 33% or 33,33%) [20] QUESTION 3 3.1.1 Area = 9 m × 2,8 m ✓SF substitution = 25,2 m2 ✓A answer M L1 (2) 3.1.2 Windows = 2 × (1,5 × 1,2) = 3,6 m2 ✓M area of TWO windows Door = 0,9 × 2,1 = 1,89 m2 ✓A area of the door Area to paint = 25,2 − 3,6 − 1,89 ✓M subtracting from 25,2 = 19,71 m2 m2 M L2 (3) Copyright reserved Please turn over

Mathematical Literacy/P2 5 Hlayiso/Mock 2026 NSC – Marking Guidelines 3.1.3 Area for two coats = 19,71 × 2 = 39,42 m2 ✓M multiplying by 2 Paint = 39,42 ÷ 8 ✓M dividing by 8 = 4,93 ℓ (4,9275 ℓ) ✓CA answer M L2 (3) 3.1.4 Tins = 4,93 ÷ 2 = 2,46 . . . ✓M dividing by 2 ≈ 3 tins ✓R rounding UP Cost = 3× R219,99 = R659,97 ✓CA total cost (CA from 3.1.3) M L3 (3) 3.2.1 3,142 × 2,4 m ✓SF substitution = 7,54 m ✓A answer M L2 (2) 3.2.2 Radius = 2,4 ÷ 2 = 1,2 m; height = 45 cm = 0,45 m ✓A radius Volume = 3,142 × (1,2)2 × 0,45 ✓C 45 cm to m = 2,036016 m3 = 2 036 ℓ ✓SF substitution OR 3,142 × 1202 × 45 = 2 036 016 cm3 = 2 036 ℓ ✓CA volume in litres M L3 (4) 3.2.3 Time = 2 036 ℓ ÷ 18 ℓ/min = 113,1 min = 1 h 53 min ✓M dividing by 18 1 h 53 min is less than 2 hours, so his claim is VALID. ✓C converting to hours OR In 2 h: 120 × 18 = 2 160 ℓ > 2 036 ℓ, so VALID ✓J valid (CA from 3.2.2) (Alternative: ✓C 2 h = 120 min ✓M 120 × 18 = 2 160 M L4 (3) ℓ ✓J valid, since 2 160 ℓ > 2 036 ℓ) [20] Copyright reserved Please turn over

Mathematical Literacy/P2 6 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 4 4.1.1 2+3+1 ✓RT reading 2, 3 and 1 = 6 parts ✓A answer MP L1 (2) 4.1.2 Allen key (F) ✓✓A MP L1 (2) 4.1.3 Fix the THREE shelves (B), with the dowels in place, ✓A shelves to one side panel to ONE side panel (A), ✓A 6 screws using 6 screws (D) ✓A Allen key and tightening them with the Allen key (F). MP L2 (3) 4.1.4 The rack is more stable on the floor / the parts do not ✓✓O valid reason fall over while being joined / one person can assemble MP L3 (2) it without someone holding it up. (Accept any other valid reason.) 216 km 4.2 Driving time = = 2,4 h ✓SF 2,4 h 90 km/h 0,4 × 60 = 24 min ⇒ 2 h 24 min ✓C converting to h and min Total time = 2 h 24 min + 25 min = 2 h 49 min ✓M adding the 25-minute Arrival = 07:40 + 2 h 49 min = 10:29 stop 10:29 is before 10:30, so the claim is VALID. ✓CA arrival time ✓J conclusion M L4 (5) 7 4.3.1 P(blue) = × 100% ✓A 20 7 20 = 35% ✓CA percentage P L2 (2) 4.3.2 Impossible (there are no green tokens) ✓✓A P L1 (2) [18] TOTAL: 75 Copyright reserved