NATIONAL
SENIOR CERTIFICATE/
NASIONALE
SENIOR SERTIFIKAAT
GRADE/GRAAD 11
NOVEMBER 2020
MATHEMATICS P1/WISKUNDE V1
MARKING GUIDELINE/NASIENRIGLYN
EXEMPLAR/EKSEMPLAAR
MARKS/PUNTE: 150
This marking guideline consists of 15 pages./
Hierdie nasienriglyn bestaan uit 15 bladsye.
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Mathematics Grade 11 P1 National Exemplar November 2020 Memo
Grade 11 Mathematics Paper 1 memorandum from the National Exemplar November Exam 2020, 15 pages. Read online or download the free PDF.
Mathematics · Grade 11 · National Exemplar November Exam · 2020. Memorandum, 15 pages. Read online or download the PDF.
- Subject
- Mathematics
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- Grade 11
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- Year
- 2020
- Exam period
- National Exemplar November Exam
- Paper
- 1
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- 15
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National Exemplar November Exam 2020
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2 MATHEMATICS P1/WISKUNDE V1 (EC/NOVEMBER 2020)
NOTE/LET WEL:
x If a candidate answers a question TWICE, mark the FIRST attempt ONLY.
Indien ʼn kandidaat ʼn vraag TWEE keer beantwoord, merk SLEGS die EERSTE poging.
x Consistent accuracy applies in ALL aspects of the marking guideline.
Volgehoue akkuraatheid geld deurgaans in ALLE aspekte van die nasienriglyn.
x If a candidate crossed out an attempt of a question and did not redo the question, mark
the crossed-out attempt.
Indien ʼn kandidaat ʼn poging vir ʼn vraag deurgetrek het en nie die vraag weer
beantwoord het nie, merk die poging wat deurgetrek is.
x The mark for substitution is awarded for substitution into the correct formula.
Die punt vir substitusie word toegeken vir substitusie in die korrekte formule.
QUESTION 1/VRAAG 1
1.1.1 (3x 2)( x 5) 0
2 3 3 answers / antwoorde
? x or / of x 5 (2)
3
1.1.2 3x 5 x 1 0
2
b r b 2 4ac
?x
2a
(5) r (5) 2 4(3)(1) 3 substitution / vervanging
2(3)
5 r 37
6 3 3 answers / antwoorde
(3)
0,18 or / of 1,85
1.1.3 x 4 x2
x2 4 x 3 squaring both sides/
( x 2) (4 x) 2 kwadreer beide kante
x 2 16 8 x x 2
3 standard form / standaardvorm
x 2 9 x 18 0 3 factors / faktore
( x 6)( x 3) 0 3 both x-values / beide x-waardes
3 selection / keuse
? x 3 or / of xz6 (5)
1.1.4 2x2 5x d 3
3 standard form / standaardvorm
2x2 5x 3 d 0 3 factors / faktore
(2 x 1)( x 3) d 0 -3
1 1
?3 d x d 3 3 3 d x d
2 2
(4)
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(EC/NOVEMBER 2020) MATHEMATICS P1/WISKUNDE V1 3
1.2.1 2 2
§ 8 ·
2
§ 8 ·3 § 8 ·
¨ ¸ ¨¨ 3 ¸¸ 3 ¨¨ 3 ¸¸
© 27 ¹ © 27 ¹ © 27 ¹
2
§2·
¨ ¸
©3¹ 3 answer / antwoord
4 (2)
9 OR/OF
2
OR/OF ª§ 2 ·3 º 3
2
3 «¨ ¸ »
ª§ 2 ·3 º 3 «¬© 3 ¹ »¼
«¨ ¸ »
«¬© 3 ¹ »¼
2
§2·
¨ ¸
©3¹ 3 answer / antwoord
4
9 (2)
1.2.2 12 2 3 1 2 32 3 1 3 2 3
3 4.3 2 3 2 3 2
2.3 2 3 2 3 2
62 3 answer / antwoord
4 (3)
OR/OF
OR/OF 3 36
12 2 3 1 36 12 2 3 2 3 62 3 2 3 2
3 answer / antwoord
62 3 2 3 2
(3)
4
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4 MATHEMATICS P1/WISKUNDE V1 (EC/NOVEMBER 2020)
1.3 5y x 2 (1)
x 2 3 xy 4 y 4 (2)
3 x 5x 2
x 5y 2 (3)
Subst. / Vervang (3) into/in (2) : 3 substitution / vervanging
? (5 y 2) 3 y (5 y 2) 4 y 4
2
0
3 standard form / standaardvorm
25 y 20 y 4 15 y 6 y 4 y 4
2 2
0 3 method;factors / metode;faktore
10 y 2 10 y 0 3 both x-values / beide x-waardes
10 y ( y 1) 0
?y 0 or / of y 1
x 5y 2 3 both y-values / beide y-waardes
x 5 0 2 or / of x 5 1 2 (6)
?x 2 or / of x 3
OR / OF 3 y 1
5 x2
5y x 2 1
x 2 3 xy 4 y 4 (2) 3 substitution / vervanging
x2 1
y x2 3
5 5
Subst./Vervang 3 into/in 2 ,
3 standard form / standaardvorm
x 3x
2 1
5 ( x 2) 4 1
5 ( x 2) 4
3 factors / faktore
x 53 x( x 2) 54 ( x 2)
2
4
3 both y-values / beide y-waardes
5 x 2 3 x 2 6 x 4 x 8 20 0
2 x 2 x 12
2
0 3 both x-values / beide x-waardes
(6)
x2 x 6 0
( x 3)( x 2) 0
? x 2 or / of x 3
y 1
5 2 2 or / of y 1
5 (3 2)
?y 0 or / of y 1
1.4.1 Perimeter/Omtrek 2l 2b
280 2(2 x) 2 y 3 substitution / vervanging
2 y 280 4 x
3 simplification / vereenvoudiging
? y 140 2 x
Area/Oppervlakte lb
3 A 2x(140 2x)
2x u y
2 x(140 2 x)
280 x 4 x 2 (3)
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(EC/NOVEMBER 2020) MATHEMATICS P1/WISKUNDE V1 5
1.4.2 A 280 x 4 x 2
4( x 2 70 x)
4( x 2 70 x 1225 1225) 3 completing the square /
vierkantsvoltooiing
4[( x 35) 2 1225]
4( x 35) 2 4900 3 4900
? The maximum area is 4900 m 2
3 correct conclusion /
korrekte gevolgtrekking
Die maksimum oppervlakte is 4900 m 2
(3)
OR/OF OR/OF
b
x
2a 3 method/metode
280
2(4) 3 35 m
35 m 3 answer / antwoord
? A 280 (35) 4(35) (3)
4 900 m 2 [31]
QUESTION 2/VRAAG 2
2.1 3.2 x 1 2.4 x 3.2 x.2 2.22 x 3 3.2x.2 2.22 x
3.2 x 22 x 3.2 x 22 x
3 factorisation of numerator /
2.2 x (3 2 x ) faktorisering van teller
2 x (3 2 x ) 3 factorisation of denominator /
2 faktorisering van noemer
3 answer / antwoord
(4)
2
2.2.1 5x 5
20
2
2
x 5
4 3 x5 4
5
2 2 5
x 5
4 3 x5
2 2 5
42
5
?x 22 2
25
32 3 answer / antwoord
(3)
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6 MATHEMATICS P1/WISKUNDE V1 (EC/NOVEMBER 2020)
2.2.2 12 x.3x 1 648
x x
12 .3 .3 648 3 12x.3x 216
x x
12 .3 216
x
12.3 216
36 x 216 3 62 x 63
62 x 63 3 equating exponents /
2x 3 gelykstel van eksponente
3 3 answer / antwoord
x
2 (4)
2.3 3x 2
f ( x)
x 10 x 25
2
3 x2 10x 25 0 for undefined /
f is undefined when : f is ongedefinieerd wanneer vir ongedefinieerd
x 10 x 25 0
2
( x 5) 2 0
x 5 3 x 5
? f is defined for : x , but x z 5 3 x ℝ 3 x z 5
f is gedefinieerd vir : x , maar x z 5 (4)
[15]
QUESTION 3/VRAAG 3
3.1.1 9 ; 5 ; 1; …;−143
Tn 13 4n 3 13 3 −4n
(2)
3.1.2 Tn 13 4n
T7 13 4(7) 3 substitution / vervanging
15 3 −15
(2)
3.1.3 Tn 13 4n
143 13 4n 3 substitution / vervanging
156 4n
? n 39 3 answer / antwoord
(2)
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(EC/NOVEMBER 2020) MATHEMATICS P1/WISKUNDE V1 7
3.2 Tn an b
16a b 38 1
3 16a b 38 and/en 41a b 113
41a b 113 2
25a 75 3 method / metode
?a 3
16 3 b 38 3 Tn 3n 10
48 b 38
? b 10
Tn 3n 10 3n=3
1 3n 10
9 3n
?n 3 (4)
[10]
QUESTION 4/VRAAG 4
4.1 −12 ; −8 ; 0 ; 12
4 8 12
4 4 3 28 3 48
28 ; 48 (2)
4.2 2a 4 3a b 4 a b c 12
?a 2 3(2) b 4 2 2 c 12 3 a 2
3 b 2
b 2 c 12
3 c 12
3 Tn 2n 2 2n 12
?Tn 2n 2 2n 12 (4)
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8 MATHEMATICS P1/WISKUNDE V1 (EC/NOVEMBER 2020)
4.3 For first differences: / Vir eerste verskille
4;8;12; ... 3 Tn 4n
Tn 4n
3 n 48
192 4n 3 answer / antwoord
? n 48 (3)
?192 lies between T48 and T49
192 lê tussen T48 en T49
OR/OF
OR/OF
Tn 1 Tn 192 3 2(n 1) 2 2(n 1) 12 (2n 2 2n 12) 192
2(n 1) 2 2(n 1) 12 (2n 2 2n 12) 192
3 4n = 192
2(n 2 2n 1) 2n 2 12 2n 2 2n 12 192
2n 2 4n 2 2n 2 12 2n 2 2n 12 192
? 4n 192 3 answer / antwoord
(3)
n 48
?192 lies between T48 and T49
192 lê tussen T48 en T49
4.4 Pn 0 Tn 168 0
Tn 168 3 2n2 2n 12 168
3 standard form / standaardvorm
2n 2 2n 12 168
2n 2 2n 180 0 3 factorisation / faktorisering
3 9 n 10
n 2 n 90 0
-9 10
(n 10)(n 9) 0 3 answer / antwoord
9 n 10 (5)
but / maar : n ! 0
? Number of terms 9
Aantal terme 9
4.5 Tn 2n 2 2n 12
3 Tn 2(n 2 n 6)
2(n 2 n 6)
3 explanation / verduideliking
? 2 u any n ! 0 is always even, so Tn will always be even
2 u enige n ! 0 is altyd ewe, so Tn sal altyd ewe wees. (2)
[16]
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(EC/NOVEMBER 2020) MATHEMATICS P1/WISKUNDE V1 9
QUESTION 5/VRAAG 5
5.1 b
At TP/By Draaipunt: x 3 method / metode
2a
6
2(1)
3 3 x-coordinate / x-koördinaat
?y (3) 2 6(3) 7
3 y-coordinate / y-koördinaat
16
(3)
OR/OF
f ( x) x2 6 x 7
( x 2 6 x 7)
3 completing the square /
[( x 2 6 x 9) 9 7] vierkantsvoltooiing
[( x 3) 2 16]
( x 3) 2 16 3 x-coordinate / x-koördinaat
3 y-coordinate / y-koördinaat
? Turning point / Draaipunt : 3;16 (3)
5.2 x2 6 x 7 0 3 f ( x) 0
x2 6 x 7 0
( x 7)( x 1) 0
? x 7 or / of x 1 3 answers / antwoorde
(2)
5.3
3 y-intercept / y-afsnit
3 x-intercepts / x-afsnitte
3 turning point / draaipunt
3 shape / vorm
(4)
5.4 x 3 3answer / antwoord
(1)
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10 MATHEMATICS P1/WISKUNDE V1 (EC/NOVEMBER 2020)
5.5 f ( x) x2 6x 7
f (3) (3) 2 6(3) 7 3 f (3) 20
20
(1) 2 6(1) 7
f (1) 3 f (1) 12
12
12 ( 20) 3 substituting into gradient formula /
Average/Gemiddelde m vervanging in gradiënt-formule
1 (3)
32
4
8 3 answer / antwoord
(4)
5.6 f ( x) x 6 x 7
2
( x 3) 2 16
2 3 a 1 and/en q 16
? h( x ) ( x 3) 4 16
3 p 1
( x 1) 2 16
(2)
[16]
QUESTION 6/VRAAG 6
6.1 a
f ( x) q
x p
a
1 3 p 33q 1
x3
(2)
6.2 a
f ( x) 1
x3
a
6 1 3 substitution / vervanging
2 3
?a 5 3 answer / antwoord
(2)
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(EC/NOVEMBER 2020) MATHEMATICS P1/WISKUNDE V1 11
6.3 5
f ( x) 1
x3
5 3 y 0
0 1
x3
5
1
x3 3 x 8
x3 5
x 8
? A(8;0) (2)
6.4 A(8;0) and/en D(3;1)
y2 y1
mAD
x2 x1
1 0 3 substitution / vervanging
3 (8)
1 3 mAD
?b
5
g ( x) bx c
1 3 substitution / vervanging
xc
5
1 1
0 8 c or / of 1 3 c
5 5
8 3 equation / vergelyking
?c
5
1 8
g ( x) x
5 5 (4)
6.5 x (f ; f) but / maar x z 3 3 x (f ; f) 3 x z 3
OR / OF (2)
x ℝ, x z 3 3 x ℝ 3 x z 3
(2)
6.6 f ( x)
g ( x)
5 1 8 5 1 8
1 x 3 1 x
x3 5 5 x3 5 5
25 5( x 3) x( x 3) 8( x 3)
25 5 x 15 x 2 3 x 8 x 24 3 standard form / standaardvorm
x 6 x 16 0
2
3 x-values / x-waardes
( x 8)( x 2) 0
x 8 or x 2
5
y 1 3 coordinates / koördinate
23
2
? B (2; 2) (4)
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12 MATHEMATICS P1/WISKUNDE V1 (EC/NOVEMBER 2020)
6.7 8 d x 3 or x t 0 33 8 d x 3 3 x t 0
OR / OF OR / OF
x >[8; 3) [0; f)@ ∈ [[−8; −3) 33 [0; ∞)] 3 (3)
[19]
QUESTION 7/VRAAG 7
7.1.1 y 4 3 answer / antwoord
(1)
7.1.2 y (4; f) 3 answer / antwoord (1)
OR / OF OR / OF
3 answer / antwoord (1)
y ! 4
7.1.3 §1·
x
g ( x) ¨ ¸ 4
©2¹
0
§1· 3 y-value / y-waarde
y ¨ ¸ 4
©2¹
3 substitution / vervanging
3
x
§1·
0 ¨ ¸ 4
©2¹
x
4 21
3 answer / antwoord
22 2 x
(3)
?2 x
x 2
Intercepts / Afsnitte :(0; 3) and / en ( 2;0)
7.1.4 x ! 2 3 answer / antwoord
(1)
7.2
y
3 asymptote above x-axis
q asimptoot bo x-as
3 y-intercept positive
y-afsnit positief
3 shape / vorm
x
h
(3)
[9]
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(EC/NOVEMBER 2020) MATHEMATICS P1/WISKUNDE V1 13
QUESTION 8/VRAAG 8
8.1 § inom ·
m
ieff ¨1 ¸ 1 3 formula / formule
© m ¹
12
§ 0.095 · 3 substitution / vervanging
¨1 ¸ 1
© 12 ¹
0,099247 ...
? r 9,92 % 3 answer / antwoord
(3)
8.2 A P (1 i ) n
R 764 050 ,60 P 1 0,08
5
3 A R764050,60
764050 .60 3 substitution / vervanging
P 5
1 0.08
R 520 000 3 answer / antwoord
(3)
8.3.1 ª § 0,075 ·
48
º§ 0,11 ·12
A «28 000 ¨1 ¸ R 7 300 » ¨1 ¸ 48
«¬ © 12 ¹ »¼© 4 ¹ § 0,075 ·
3 28 000¨1 ¸
12 © 12 ¹
§ 0,11 ·
R 37 760 ,78 R 7 300 ¨1 ¸ 3 −R7 300
© 4 ¹
12
12 § 0,11 ·
§ 0,11 · 3 u ¨1 ¸
R 30 460 ,78¨1 ¸ © 4 ¹
© 4 ¹
3 simplification / vereenvoudiging
R 42 181,59
3 answer / antwoord
(5)
8.3.2 A P(1 i ) n
60
§ 0, 08 ·
A R42181,59 ¨1 ¸ 3 substitution into correct formula
© 12 ¹
vervanging in korrekte formule
R62844, 06
R80 000 R62844, 06 3 R62 844,06
R17155,94
?A P(1 i ) n 3 R17 155,964
60
§ 0, 08 ·
R17155,94 P ¨1 ¸
© 12 ¹ 3 method / metode
17155,94
P 60
§ 0, 08 ·
¨1 ¸
© 12 ¹
R11515, 25
? He needs to deposit R11 515 /
Hy moet R11 515 deponeer 3 answer / antwoord (5)
[16]
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14 MATHEMATICS P1/WISKUNDE V1 (EC/NOVEMBER 2020)
QUESTION 9/VRAAG 9
9.1 If A and B are independent, then:
As A en B onafhanklik is, dan:
P(A and/en B) = P(A) u P(B)
P(A) = 1 P(not/nie A)
= 1 0,45 3 0,55
= 0,55
11
=
20
P(A or/of B) = P(A) + P(B) – P(A and/en B)
0,685 = 0,55 + 0,3 – P(A and/en B) 3 substitution / vervanging
∴P(A and/en B) = 0,165
33
= 3 answer / antwoord
200
P(A) u P(B) = 0,55 u 0,3 3 P(A) u P(B)
= 0,165
33
=
200
∴ A and B are independent events. /
3 conclusion / gevolgtrekking
A en B is onafhanklike gebeurtenisse.
(5)
9.2.1
S
N R
9 5
c (8)
3 a = 10
12
a (10) b (13) 3 b =13
3c=8
4 3 d =14
d (14)
A
a = 10 ; b = 13 ; c = 8 ; d = 14 (4)
9.2.2 39 5 39 5
P A or/of (N and/en R) 3 3
75 75 75 75
44 3 answer / antwoord
75 (3)
| 0,59 [12]
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(EC/NOVEMBER 2020) MATHEMATICS P1/WISKUNDE V1 15
QUESTION 10/VRAAG 10
10 Let the total number of balls be t.
Laat die totale aantal balle t wees. 5 4
3 3and/en
t t 1
Green/Groen: 5 G
4
Blue/Blou: t – 5 t 1
5 G
t
B
G
B
B
P(GG) = P(G) u P(G) 3 equation / vergelyking
5 4 5
u
t t 1 18
20 5 3 standard form / standaardvorm
t (t 1) 18
5t 2 5t 360
5t 5t 360 0
2
3 factorisation / faktorisering
t 2 t 72 0
3t=9
(t 9)(t 8) 0
? t 9 or t z 8
? There are 9 balls.
Daar is 9 balle.
(6)
TOTAL / TOTAAL: 150
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