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Physical Sciences Grade 12 P2 National Mock 2021 QP
Grade 12 Physical Sciences Paper 2 question paper from the National Mock Exam 2021, 24 pages. Read online or download the free PDF.
Physical Sciences · Grade 12 · National Mock Exam · 2021. Question paper, 24 pages. Read online or download the PDF.
- Subject
- Physical Sciences
- Grade
- Grade 12
- Document type
- Question paper
- Year
- 2021
- Exam period
- National Mock Exam
- Paper
- 2
- Curriculum
- CAPS
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- 24
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- 885.8 KB
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National Mock Exam 2021
- Paper 2Question paperMemo
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Physical Sciences/P2
2.
SC/NSC
INSTRUCTIONS AND INFORMATION
1.
10.
11.
12.
Write your centre number and examination number in the appropriate spaces
on the ANSWER BOOK.
This question paper consists of TEN questions. Answer ALL the questions in
the ANSWER BOOK.
Start EACH question on a NEW page in the ANSWER BOOK.
Number the answers correctly according to the numbering system used in this
question paper.
Leave ONE line between two subquestions, e.g. between QUESTION 2.1 and
QUESTION 2.2.
You may use a non-programmable calculator.
You may use appropriate mathematical instruments.
Show ALL formulae and substitutions in ALL calculations.
Round off your FINAL numerical answers to a minimum of TWO decimal
places.
Give brief motivations, discussions, etc. where required.
You are advised to use the attached DATA SHEETS.
Write neatly and legibly.
Copyright reserved ANA | Fees rm oven
EASTERN CAPE
DBE/November 2020(2)
Physical Sciences/P2
3.
SC/NSC
QUESTION 1: MULTIPLE-CHOICE QUESTIONS
DBE/November 2020(2)
Four options are provided as possible answers to the following questions. Choose the
answer and write only the letter (A-D) next to the question numbers (1.1 to 1.10) in the
ANSWER BOOK, e.g. 1.11 E.
4.4 Which ONE of the following is an ALKANE?
A CeHs
Bo CeHio
C CeHi2
D CeHi4 (2)
1.2 Esters are formed by a reaction between two organic compounds, X and Y,
each with a different functional group.
The functional groups of these compounds are:
Compound X Compound Y
A Hydroxyl group Carboxyl group
B Hydroxyl group Carbonyl group
Cc Hydroxide ion Carboxyl group
D Hydroxide ion Carbonyl group (2)
1.3 When butane is subjected to high temperatures and pressures, the following
reaction takes place:
Butane — methane + Y
Which ONE of the following represents Y?
A CHCCH3
B CHzCHCH3
C CHsCH2CH3
D = CHsCHCHCH3 (2)
Certo MN 1 0 001000
Please turn over
Physical Sciences/P2 4. DBE/November 2020(2)
SC/NSC
1.4 A hydrochloric acid solution, HCf(aq), of concentration 1 mol-dm® is added to
EXCESS POWDERED magnesium at 25 °C.
Curve I below represents the volume of hydrogen gas produced during the
reaction.
Curve II was obtained at different conditions using the SAME VOLUME of
hydrochloric acid solution.
f
Il id
Volume of hydrogen gas
produced
sn
~
Time
Which ONE of the following represents the conditions used to obtain curve II?
STATE OF DIVISION | CONCENTRATION | TEMPERATURE
OF Mg (mol-dm*) (°C)
A | Ribbon 0,5 25
B | Ribbon 2 25
C | Powder 4 20
D | Powder 1 30 (2)
1.5 In which ONE of the following reactions at equilibrium will the YIELD of the
product increase when the VOLUME of the container is increased at constant
temperature?
A N20,(g) = 2NO2(g)
B Ha(g) + la(g) = 2HI(g)
C Nog) + 3H2(g) = 2NHs(g)
D —280,(g) + O2(g) = 2802(9) (2)
Please turn over
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Physical Sciences/P2 DBE/November 2020(2)
5.
SC/NSC
1.6 Which ONE of the following statements is TRUE for an EXOTHERMIC
reaction?
A More energy is absorbed than released.
B- More energy is released than absorbed.
C Heat of reaction (AH) is positive.
D__ Energy of the products is greater than the energy of the reactants. (2)
1.7 Consider the equation below.
HsPO,(aq) + H2O(t) = H3O*(aq) + HPO; (aq)
Which ONE of the following is a conjugate acid-base pair?
A H30*(aq) and H2O(2)
B —_-H3PO,4(aq) and H20(8)
C — HsPOs(aq) and H20*(aq)
D —_H30*(aq) and H2PO; (aq) (2)
1.8 Consider the balanced equation for the reaction below:
2Cr*(aq) + Sn**(aq) > 2Cr°*(aq) + Sn?*(aq)
The OXIDISING AGENT is:
A Cr**(aq)
B Cr*(aq)
Cc Sn**(aq)
D Sn**(aq) (2)
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1.9
1.10
An electrochemical cell is set up at standard conditions. The cell notation for
the cell is given below.
Mg(s) | Mg**(aq) || Pb**(aq) | Pb(s)
The cell is now connected in a circuit. Which ONE of the graphs below BEST
represents the concentrations of the electrolytes after a long time?
The electrolytic cell illustrated below is used to electroplate a nickel rod with
copper.
A 4
i=
i
oO
=
5 ,|___Pb*"(aa)
24
g Mg™*(aq)
c
g
Cc
fo}
oO >
Time (s)
Cc
£
3 Mg*"(aq)
°
—
§
i 41
3
2+,
5 Pb**(a
oO >
Time (s)
B
5 Pb**(aq)
3
—E
&
21
£
c
8 Mg?*(aq)
fo}
o >
Time (s)
Mg*"(aq)
=
Pb**(aq)
Concentration (mol-dm’)
Time (s)
Which ONE of the following is the correct representation of a suitable
electrolyte and the nickel rod that should be used in the above cell to obtain
the expected results?
| ELECTROLYTE NICKEL ROD
A | _NiSOdag) __ X.
Bo CuSO4(aq) x |
ic | NiSO«4(aq) _ : Y
D | CuSOs«(aq) Y
(2)
(2)
Physical Sciences/P2 7. DBE/November 2020(2)
SC/NSC
QUESTION 2 (Start on a new page.)
The letters A to E in the table below represent five organic compounds.
H Br CHs CH2CH3
a B | oat
4 i ba CH2CH3
H H H OH
c nd id te D | CH3(CH2)2CH(OH)CH2CH3
HAH OA |
E | CHsCH2CH2CH2CH2CH2CHCH2
2.1 Write down the LETTER that represents EACH of the following:
2.1.1 A ketone (1)
2.1.2 A hydrocarbon (1)
2.1.3 An alkene (1)
2.2 Write down the:
2.2.1 IUPAC name of compound A (3)
2.2.2 STRUCTURAL FORMULA of compound D (2)
2.2.3 IUPAC name of the STRAIGHT CHAIN FUNCTIONAL ISOMER of
compound C (2)
2.3 Compound B is a straight chain compound that undergoes the following
exothermic reaction:
2C,Hy + 2502(g) > 16CO2(g) + 18H20(g)
2.3.1 Besides being exothermic, what type of reaction is represented
above? (1)
2.3.2 Determine the MOLECULAR FORMULA of compound B. (2)
The reaction above takes place in a closed container at a constant
temperature higher than 100 °C and at constant pressure.
2.3.3 Calculate the TOTAL VOLUME of gas formed in the container
when 50 cm® of C,Hy reacts completely with oxygen. (3)
[16]
comttecres AINA NAGI)
Physical Sciences/P2
QUESTION 3 (Start on a new page.)
Compounds A, B and C are used to investigate a factor which influences the boiling
points of organic compounds. The results of the investigation are given in the table
SCINSC
DBE/November 2020(2)
below.
COMPOUND BOILING POINT (°C)
A_ | Butan-1-ol 117
B | Butan-2-ol : 100
c 2-methylpropan-2-ol 82 :
3.1 ls this a fair investigation? Choose from YES or NO.
3.2 Give a reason for the answer to QUESTION 3.1.
3.3 Fully explain the difference in the boiling points of compounds B and C.
3.4 Define the term positional isomer.
3.5 From compounds A, B and C, choose the letter(s) that represent(s) EACH of
the following:
3.5.1
3.5.2
3.6 The graph below represents the relationship between vapour pressure and
Positional isomers
A tertiary alcohol
Give a reason for the answer.
temperature for compound A (butan-1-ol).
3.6.1
3.6.2
Copyright reserved
Vapour pressure (kPa)
Temperature (°C)
Write down the value of X.
Redraw the graph above in the ANSWER BOOK. On the same set
of axes, sketch the curve that will be obtained for compound C.
Clearly label the curves A and C. Indicate the relevant boiling point
for compound C on the graph.
EASTERN CAPE
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(3)
(2)
(1)
(2)
(1)
(2)
[13]
Physical Sciences/P2 9. DBE/November 2020(2)
SC/NSC
QUESTION 4 (Start on a new page.)
4.1
The flow diagram below shows various organic reactions using propane as
starting reactant. R, T and U represent different organic compounds.
Compound T is a CARBOXYLIC ACID and compound U is a FUNCTIONAL
ISOMER of pentanoic acid.
Reaction 1 Reaction 2
Propane | Br, > R Dilute NaQH Propan-1-ol
T || Reaction 3
y
U
Write down the NAME of the type of reaction represented by:
4.1.1 Reaction 1
4.1.2 Reaction 2
Consider reaction 1 and reaction 2.
4.1.3 Write down the IUPAC name of compound R.
Reaction 3 takes place in the presence of a catalyst and heat.
Write down the:
4.1.4 NAME or FORMULA of the catalyst
4.1.5 IUPAC name of compound T
4.1.6 STRUCTURAL FORMULA of compound U
sepamanceseree TANITA EAA
Please turn over
(1)
(1)
(2)
(1)
(2)
(2)
Physical Sciences/P2 10. DBE/November 2020(2)
4.2
SC/NSC
A laboratory technician wants to prepare but-2-ene using but-1-ene as
starting reagent, as shown below.
i
H— C=C 6 EH —————> _ But-2-ene
H H H H
The following chemicals are available in the laboratory:
[concentrated H2SO4__| H20 | concentrated NaOH _|
Select the chemicals required to design this preparation from the list above.
For EACH step of the preparation, write down the balanced equation, using
STRUCTURAL FORMULAE for all organic compounds. Indicate the
chemicals needed in each step. (6)
[15]
QUESTION 5 (Start on a new page.)
5.1
5.2
5.3
Study the Maxwell-Boltzmann distribution curve for a certain reaction below.
P
P and Q are the labels of the axes. What quantity is represented by:
5.1.1 P (1)
5.1.2 Q (1)
Line R represents the minimum eneray required for the reaction to take place.
5.2.1 Write down the term for the underlined phrase. (1)
5.2.2 How will the shaded area on the graph be affected when a catalyst
is added? Choose from INCREASE, DECREASE or REMAINS
THE SAME. (1)
Use the collision theory to explain how a catalyst influences the rate of
reaction. (4)
Copys esenes HUNAN Amor
Physical Sciences/P2 11. DBE/November 2020(2)
SC/NSC
5.4 The reaction between POWDERED calcium carbonate, CaCO3(s), and
EXCESS hydrochloric acid, HCf&aq), is used to investigate reaction rate at
25 °C. The balanced equation for the reaction is:
CaCO,(s) + 2HCt(aq) + CaCt,(aq) + H20() + CO2(g)
Several experiments are conducted using the same mass of IMPURE calcium
carbonate and different initial concentrations of dilute hydrochloric acid. The
graph below represents the results obtained. Assume that the impurities do
not react.
4
60Rt r Eas seees +H
2
i
a
oS
r
t
ES
(S)
1
t
t
t
w
oO
"
(cm*-min")
NO
o
ne Geena
=
oO
r
i"
Average rate of production of CO.
ine Li =
0 0,005 0,01 0,015 0,02 0,025 0,03 0,035
Initial concentration of HC£ (mol-dm*)
For this investigation, write down a:
5.4.1 Controlled variable
5.4.2 Conclusion
The CaCo,(s) in 6g of the impure sample reacts completely with
0,03 mol-dm™~ HC£(aq) in 26 minutes.
5.4.3 Use the information in the graph to calculate the percentage purity
of the calcium carbonate. Assume that the molar gas volume at
25 °C is 24 000 cm.
cere EAA AAA
EASTERN CAPE
(1)
(2)
(6)
[17]
Physical Sciences/P2 12. DBE/November 2020(2)
SC/NSC
QUESTION 6 (Start on a new page.)
Steam, H20(g), reacts with hot carbon, C(s), at 1 000 °C according to the following
balanced equation:
2H,0(g) + C(s) = 2Ha(g) + CO2(g)
Initially, 36 g of steam and a certain amount of carbon were placed in a 2 dm® sealed
container and allowed to react. At equilibrium it was found that the amount of carbon
changed by 0,225 mol.
6.1 Define the term dynamic equilibrium. (2)
6.2 Calculate the equilibrium constant, Ke, for the reaction at 1 000 °C. (8)
6.3 The graph shows how the rates of the forward and reverse reactions change
with time.
Forward reaction
--- Reverse reaction
Rate
to ty te ts Time
6.3.1 Give a reason why the rate of the forward reaction decreases
between tp and ti. (1)
6.3.2 What change was made to the equilibrium mixture at ts? (1)
At time te, the temperature of the system is increased.
6.3.3 Is the forward reaction EXOTHERMIC or ENDOTHERMIC? (1)
6.3.4 Refer to Le Chatelier’s principle to explain the answer to
QUESTION 6.3.3. (2)
[15]
comotoes NNN =o
Physical Sciences/P2 13. DBE/November 2020(2)
SC/NSC
QUESTION 7 (Start on a new page.)
Two beakers, A and B, contain strong bases.
Beaker A: 500 cm* of barium hydroxide, Ba(OH)2(aq) of unknown concentration X
Beaker B: 400 cm? of potassium hydroxide, KOH(aq) of concentration 0,1° mol-dm?
7.1 Define a base according to the Arrhenius theory. (2)
7.2 Calculate the number of moles of hydroxide ions (OH ) in beaker B. (2)
7.3 The contents of beakers A and B are added together in beaker C. The
solution in beaker C has a pH of 13.
Assume that the volumes are additive and that the temperature of the
solutions is 25 °C.
/ —»*
c
A B
3 0,1. mol-dm*
Ba(OH)(aq) | 500 cm pH = 13 400 cm? | KOH(aq)
7.3.1 Calculate the concentration, X, of the Ba(OH)2 in beaker A. (8)
The solution in beaker C is titrated with ethanoic acid. It was found that
15 cm? of the solution neutralises 30 cm’ of the acid.
The balanced equation for the reaction is:
CH3COOH(aq) + OH (aq) — CH,COO (aq) + H2O(f)
7.3.2 Is ethanoic acid, CH3COOH(aq), a WEAK acid or a STRONG acid?
Give a reason for the answer. (2)
7.3.3 Calculate the concentration of the ethanoic acid. (4)
[18]
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Physical Sciences/P2 14. DBE/November 2020(2)
SC/NSC
QUESTION 8 (Start on a new page.)
A galvanic cell at standard conditions is represented by the cell notation below. X and
Y are unknown electrodes.
X | Zn**(aq) || Fe**(aq) , Fe**(aq) | Y
8.1 Write down the NAME or FORMULA of:
8.1.1 Electrode X (1)
8.1.2 Electrode Y (1)
8.1.3 The oxidising agent (1)
8.2 Write down:
8.2.1 ONE function of electrode Y (1)
8.2.2 The half-reaction that takes place at electrode Y (2)
8.2.3 The net (overall) equation for the cell reaction that takes place in
this cell (3)
8.3 Calculate the initial emf of this cell. (4)
8.4 How will the initial emf of the cell be affected when the concentration of the
iron(IIl) ions is changed to 0,6 mol-dm*? Choose from INCREASES,
DECREASES or REMAINS THE SAME. (1)
[14]
Coovmontreserved TANITA AU CUMUTAT MY Pease ten oven
EASTERN CAPE
Physical Sciences/P2
15. DBE/November 2020(2)
SCINSC
QUESTION 9 (Start on a new page.)
The simplified diagram below represents an electrochemical cell used for the
purification of copper. The impure copper contains small amounts of silver (Ag) and
zinc (Zn) as the only impurities.
Electrolyte
DC source
+——Impure copper
9.1 Define the term electrolysis.
9.2 Write down the NAME or FORMULA of TWO positive ions present in the
electrolyte. :
9.3 Write down the half-reaction that takes place at the cathode.
9.4 Refer to the Table of Standard Reduction Potentials and explain why the
purified copper will NOT contain any zinc.
9.5 Calculate the maximum mass of Cu formed if 0,6 moles of electrons are
transferred.
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(2)
(2)
(3)
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[12]
Physical Sciences/P2 16. DBE/November 2020(2)
SC/NSC
QUESTION 10 (Start on a new page.)
Consider the Table of Standard Reduction Potentials below.
Half-reactions E® (v)
Cr++2e = Or - 0,91
2H2O +2e = Helg)+20H- | -0,83
Zn*+2e = Zn -0,76
Cr+3e = Cr -0,74
Fe*+2e = Fe - 0,44
Cette = Crt -0,41
Sn*+2e = Sn +0,15
Cute = Cut + 0,16
Cu%+2e = Cu + 0,34
2H20+0O2+4e = 40H” +0,40
Cuv+e = Cu + 0,52
Agtt+e = Ag +0,80
Oo(g) + 4H*+4e° = 2H20 +423
Chkig)+2e7 = 2Ct + 1,36
10.1 Define the term reducing agent in terms of electron transfer.
10.2 From the above Table of Standard Reduction Potentials, write down the:
10.2.1 NAME or FORMULA of the strongest reducing agent
10.2.2 Oxidation half-reaction with the lowest oxidation potential
10.2.3 Reduction potential of the half-reaction in which Cr’*(aq) acts as
reducing agent
10.3 A learner pours a copper(I!) sulphate solution into a zinc container.
10.3.1 Is a zinc container suitable to store a copper(II) sulphate solution?
Choose from YES or NO.
10.3.2 Explain the answer to QUESTION 10.3.1 by referring to the above
table.
TOTAL:
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EASTERN CAPE
(2)
(1)
(2)
(1)
(1)
(3)
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150
Physical Sciences/P2 1.
SC/NSC
DATA FOR PHYSICAL SCIENCES GRADE 12
PAPER 2 (CHEMISTRY)
GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12
VRAESTEL 2 (CHEMIE)
TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES
DBE/November 2020(2)
NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE
TABLE 2: FORMULAE/TABEL 2: FORMULES
| om N
n=— n=—
M Ny
n m Vv
=f lof = n=—
c V eee c MV V,
CaNV0 Da H = -log[H.0*
cv. on, pH = -log[H30*]
Kw = [H30"][OH] = 1 x 10° atiby 298 K
aay = Feathode ~ Erode / =a = Preise - EF enode
orlof
| ¢e () C) 8 t) 8
Een = Epduction ~ Eosdation! Eset = Ereduisie — Eotsidasie
or/of
6 _pe 8 8 _ fe a)
Eee ~ Eoadisingagent ~ E reducingagent 1B ee ~ E osideermiddel E reduseemiddel
Copyright reserved I A
EASTERN CAPE
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Physical Sciences/P2
Increasing oxidising ability/ Toenemende oksiderende vermoé
Copyright reserved
3,
SC/NSC
TABLE 4A: STANDARD REDUCTION POTENTIALS
TABEL 4A: STANDAARD-REDUKSIEPOTENSIALE
Half-reactions/Halfreaksies E° (Vv)
Fo(g)+2e = 2F + 2,87
Co*+e = Co™ + 1,81
H2Q2+ 2H" +2e7 = 2H2O 41,77
MnO] +8H*+5e> = Mn“ +4H,O | +1,51
Ch(g)+2e = 2Cr +1,36
CrO} +44H"+6e = 2Cr*+7HO | +1,33
O.(g)+4H* +4e" = 2H20 + 1,23
MnO2+ 4H* +2e° = Mn” + 2H0 + 1,23
Pt+2e . Pt + 1,20
Bro(t)+2e° = 2Br + 1,07
NO, +4H'+3e = NO(g)+2H,0 | +0,96
Hg**+2e = Hag(t) + 0,85
Agite = Ag +0,80
NO} +2H*+e = NO2(g)+H20 +0,80
Fe*+e = Fe™* +077
O2(g) + 2H*+2e = HO2 + 0,68
k+2e = 2b + 0,54
Cu’+e = Cu + 0,52
SO2+4H*+4e = S+2H20 +0,45
2H20+O2+4e7 = 40H” +0,40
Cu*+2e = Cu + 0,34
S04 +4H'+2e = S02(g)+2H20| +0,17
Cu*+e = Cu +0,16
Sn“*+2e = Sn* +0,15
S+2H*+2e = HeS(g) +0,14
2H*+2e = Helg) 0,00
Fe*+3e = Fe — 0,06
Pb**+2e = Pb -0,13
Sn**+2e = Sn ~0,14
Ni*+2e = Ni —0,27
Co” + 26° Co - 0,28
Cd**+2e = Cd - 0,40
Crt+e = Cr -0,41
Fe +2e = Fe ~ 0,44
cr+3e = Cr -0,74
Zn*+2e = Zn -0,76
2HO+2e" = Hg)+2O0H | -0,83
Crt+2e = Cr -0,91
Mn**+2e° = Mn -1,18
Abt +3e = At -1,66
Mg**+2e" = Mg - 2,36
Na’+e. = Na -2,71
Ca*+2e = Ca - 2,87
SPt+2e = Sr — 2,89
Ba**+2e = Ba — 2,90
Cs*+e = Cs - 2,92
Kite = K - 2,93
Lite - 3,05
= Li
ASTERN CAPE
DBE/November 2020(2)
Increasing reducing ability/ Toenemende reduserende vermoé
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Physical Sciences/P2
Increasing oxidising ability/Toenemende oksiderende vermoé
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4.
SC/NSC
TABLE 4B: STANDARD REDUCTION POTENTIALS
TABEL 4B: STANDAARD-REDUKSIEPOTENSIALE
Half-reactions/Halfreaksies E® (v)
lite a Li — 3,05
K'te =o K — 2,93
Cs*+e = Cs — 2,92
Ba*+2e = Ba - 2,90
Sr+2e = Sr — 2,89
Ca +2e° = Ca ~ 2,87
Na*+e7 = Na -2,71
Mg" +2e° = Mg — 2,36
Abt+3e° = AL — 1,66
Mn** + 26° Mn = 1,18
Ce +2e° = Cr -0,91
2H.0+2e = Hy(g)+20H” | -0,83
Zn*+2e = Zn — 0,76
Crt+3e° = Cr — 0,74
Fe*+2e = Fe ~ 0,44
crt+e = Cr -0,41
Cd**+2e° = Cd — 0,40
Co*+2e = Co - 0,28
Ni +2e- = Ni — 0,27
Sn*+2e = Sn 0,14
Pb” +2e° = Pb - 0,13
Fe*+3e = Fe — 0,06
2H*+2e° = Hag) 0,00
S+2H"+2e = HS(g) +0,14
Sn +2e = Sn* + 0,15
Cu%+e = Cur +0,16
S03 +4H*+2e° = SO2(g)+2H,0| +0,17
Cu*+2e = Cu + 0,34
2H20 +02+4e° = 40H +0,40
SQ.+4H’+4e° = S+2H0 + 0,45
Cu’+e™ = Cu + 0,52
b+2e = 2 + 0,54
O2(g) + 2H +2e7 = HzOQ2 + 0,68
Fe"+e = Fe™* +0,77
NO} +2H* +e NO2(g)+H20 | +0,80
Ag’+e = Ag + 0,80
Hg” +2e" = Hg() + 0,85
NO; +4H'+3e = NO(g)+2H20 | +0,96
Bro(f)+2e = 2Br +1,07
Pit+2e7 = Pt + 1,20
MnQ2+ 4H*+2e == Mn**+2H20 + 1,23
O.(g)+4H*+4e° = = 2H20 + 1,23
CrO? +44H'+6e = 2Cr*+7H20 | +14,33
Ci(g)+2e7 = 208 + 1,36
MnO, +8H*+5e7 = Mn +4HoO | +4,51
H202+2H*+2e° = 2H,O +1,77
Co* +e = Co* + 1,81
Fo(g)+2e = + 2,87
2F-
EASTERN CAPE
DBE/November 2020(2)
Increasing reducing ability/Toenemende reduserende vermoé
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