Mathematics Grade 3 Gauteng Provincial November 2022 Memo

UHLOLO EPHONDWENI EYENKANGA 2023 IBANGA 3 ISIKHOKELO SOKUMAKA IMATHEMATIKA: ISIXHOSA 6 amaphepha

ISIKHOKELO SOKUMAKA Ibanga 3 IMathematika 1 C 1 inqaku 2 B 1 inqaku 3 D 1 inqaku 4 A 1 inqaku 5 B 1 inqaku 6 C 1 inqaku 7 C 1 inqaku 8 D 1 inqaku 9 B 1 inqaku 10 D 1 inqaku 11 7:40 ekuseni Okanye imizuzu engamashumi amabini phambi 1 inqaku kwentsimbi yesibhozo  12 iikota ezimbini  1 inqaku 13 ama 30 emizuzu  1 inqaku 14 IPentagoni  1 inqaku 15 IiKilomitha  1 inqaku 16 A 500  1 inqaku ngempendulo B 1 500  nganye echanekileyo (2 amanqaku) 17 1 inqaku  2

ISIKHOKELO SOKUMAKA Ibanga 3 IMathematika Ulandelelwano olululo 18 706; 705; 701; 659; 607  1 inqaku ngolandelelwano olululo (1 inqaku) 19 A B – Ityhubhu  1 inqaku B C – Ikhowuni  ngempendulo nganye (2 amanqaku) 20 Isithathu sekota ukugcwala  1 inqaku 21 A C3 okanye 3C  4 amanqaku B D4 okanye 4D  1 ngempendulo nganye C C2 okanye 2C  echanekileyo D IPhiramidi  (4 amanqaku) 22 1 Bala zonke izikwere = 16  1 inqaku Okanye ngempendulo 2 Umqolo x ikholam = 16  nganye echanekileyo Okanye (2 amanqaku) 3 4 x 4 = 16 (Nokuba yeyiphi imethodi echanekileyo yamkelekile) 3

ISIKHOKELO SOKUMAKA Ibanga 3 IMathematika 23 6 x 4 = 24  1 inqaku Okanye ngempendulo 12 + 12 = 24 nganye Okanye echanekileyo 24 amaqanda  (2 amanqaku) (Nokuba yeyiphi imethodi echanekileyo yamkelekile) 24 360 ÷ 12 = 30 grams  1 inqaku 2 x 30 grams = 60 grams  ngempendulo nganye (Nokuba yeyiphi imethodi echanekileyo yokwahlula yamkelekile) echanekileyo (2 amanqaku) 25 USara mde kuno Jay nge 13 lwee cm  1 inqaku 151 cm – 138 cm = 13 cm  ngempendulo nganye echanekileyo (2 amanqaku) 26 12 ÷ 4 = 3  1 inqaku Okanye ngempendulo 12 ÷ 3 = 4 nganye Yamkela noba yeyiphi imethodi echanekileyo echanekileyo (1 inqaku) 27 5 x 6 = 30  1 inqaku Zingama 30 izincamathelisi  ngemethodi echanekileyo, 1 Yamkela noba yeyiphi imethodi echanekileyo inqaku ngempendulo nganye echanekileyo (2 amanqaku) 4

ISIKHOKELO SOKUMAKA Ibanga 3 IMathematika 28 36 ÷ 3 = 12  1 inqaku ngempendulo echanekileyo, 1 inqaku ngokuqakatha okuchanekileyo (2 amanqaku)  0 3 6 9 12 15 18 21 24 27 30 33 36 39 Yamkela nokuba yeyiphi imethodi echanekileyo 29 8 x 4 = 32  1 inqaku ngempendulo Usebenzise iilamuni ezingama 32 ukwenza ilemonadi  echanekileyo, 1 inqaku ngokuqakatha okuchanekileyo (2 amanqaku) 30 15 + 6 = 21  1 inqaku ngemethodi Zingama 21 iiapile zizonke  echanekileyo, 1 inqaku ngempendulo nganye echanekileyo (2 amanqaku) 31 242 + 353 1 inqaku ngemethodi = (200 + 40 + 2) + (300 + 50 + 3)  echanekileyo, 1 (200 + 300) (40 + 50) (2 + 3) inqaku 500 + 90 + 5 ngempendulo 595  nganye echanekileyo (2 amanqaku) 5

ISIKHOKELO SOKUMAKA Ibanga 3 IMathematika 32 598 – 75 =  1 inqaku ngemethodi = (500 and 90 and 8) – (70 and 5) echanekileyo, 1 (500 – 0) (90 – 70) (8 – 5) inqaku = 500 – 20 – 3 ngempendulo = 523  nganye echanekileyo (2 amanqaku) Yamkela nokuba yeyiphi imethodi echanekileyo 33 A Incwadi ngezilwanyana  1 inqaku B 23  ngempendulo nganye C 2 abafundi echanekileyo (3 amanqaku) ITOTALI: 50 amanqaku 6