Education
KwaZulu-Natal Department of Education
Ath ARMA RRA E RIND, PERE EAEDPRRARAEAIAREEAASEA RELI AERA REL SRES RSD ABEL ELIMAREASEEAE |
LIFE SCIENCES
JUNE 2017
COMMON TEST
MARKS: 150
TIME: 2% hours
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Life Sciences Grade 11 KwaZulu Natal June 2017 Paper & Memo
Grade 11 Life Sciences question paper and memo from the KwaZulu Natal June 2017, 22 pages. Read online or get the free PDF download.
Life Sciences · Grade 11 · KwaZulu Natal June · 2017. Question paper and memorandum, 22 pages. Read online or download the PDF.
- Subject
- Life Sciences
- Grade
- Grade 11
- Document type
- Question paper and memo
- Year
- 2017
- Exam period
- KwaZulu Natal June
- Curriculum
- CAPS
- Pages
- 22
- File size
- 1.8 MB
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Life Sciences Grade 11 June 2017 Common Test
INSTRUCTIONS AND INFORMATION
Read the following instructions carefully before answering the questions.
1.
2.
10.
11.
Answer ALL the questions.
Write ALL the answers in your ANSWER BOOK.
Start the answers to EACH question at the top of a NEW page.
Number the answers correctly according to the numbering system used in this
question paper.
Present your answers according to the instructions of each question,
Make ALL drawings in pencil and label them in blue or black ink.
Draw diagrams, flow charts or tables only when asked to do so,
The diagrams in this question paper are NOT necessarily drawn to scale.
Do NOT use graph paper.
You may use a non-programmable calculator, protractor and a compass,
where necessary.
Write neatly and legibly.
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Life Sciences Grade 11 June 2017 Common Test
SECTION A
QUESTION 1
11 Various options are provided as possible answers to the following questions.
Choose the correct answer and write only the letter (A to D) next to the
question number (1.1.1 to 1.1.10) in your ANSWER BOOK, for example
1.1.11 D.
1.14 The dominant generation of the mosses and the angiosperms
respectively, is ..,
A gametophyte and sporophyte.
B sporophyte and gametophyte.
C sporophyte and sporophyte.
D — gametophyte and gametophyte.
1.1.2 The diagram below represents the reproductive structure of a plant
group that you have studied.
Which plant group has the above reproductive structure?
A Bryophytes
B Pteridophytes
Cc Gymnosperms
D Angiosperms
1.1.3 Bacteria that convert light energy to chemical potential energy stored
in organic compounds, are called ...
A heterotrophic bacteria.
B denitrifying bacteria.
C autotrophic bacteria.
D __nitrogen-fixing bacteria.
Life Sciences
1.1.4
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Grade 11 June 2017 Common Test
Study the list of characteristics below.
(i)
(ii)
Gil)
(iv)
(v)
Coelomate and triploblastic
Acoelomate and asymmetrical
Diploblastic
Bilateral symmetrical
Radially symmetrical
Which ONE of the following applies to the Cnidarians?
A (i), (ii) and (iv) only
B_ (iii) and (v) only
C (iv) and (v) only
D _{iv) only
The grade 11 learners conducted an investigation to compare the
effect of three antibiotics on the growth of the bacteria. They set up
agar plates containing nutrients and bacteria. Sterile discs (1, 2 and
3) containing three different antibiotics were then placed in each of
the plates. The dots represent the bacteria.
The results of the investigation are represented in the diagram
below.
Agar plates
Agar plates
Antibiotic + Antibiotic 2 Antibfotic 3
From the above it can be concluded that the bacteria are ...
A __ least resistant to antibiotic 1.
B least resistant to antibiotic 2.
C least resistant to antibiotic 3.
D not affected by the antibiotics.
Micro-organisms that have a cell wall, no chlorophyll and reproduce
by spores belong to the kingdom ...
A Fungi.
B Plantae.
C sProtista.
D ~~ Monera.
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Life Sciences Grade 11 June 2017 Common Test
1.1.7 Organisms that obtain their food from dead remains of plants or
animals are called ...
A producers.
B __heterotrophs.
C parasites
D _ saprophytes ;
1.1.8 Which group of micro-organisms fix nitrogen in the roots of some
plants and obtain nutrition in return?
A Fungi |
B Protists
Cc Bacteria |
D Viruses '
1.1.9 The elimination of undigested food and indigestible material from the
body is known as ...
A __ ingestion. :
B absorption. \
C egestion. |
D assimilation.
1.1.10 A condition of malnutrition resulting from eating too much of the
high-energy foods such carbohydrates and fats is ...
A _ bulimia.
B anorexia.
C obesity.
D __kwashiorkor.
(10 x 2) (20)
Life Sciences
1.2
1.3
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Grade 11
+
June 2017 Common Test
Give the correct biological term for each of the following descriptions. Write
only the term next to the question number (1.2.1 to 1.2.9) in your ANSWER
BOOK.
1.2.1
1.2.2
1.2.3
1.2.4
1.2.5
1.2.6
1.2.7
1.2.8
1.2.9
The type of respiration that occurs in the presence of oxygen
The rhythmical contractions of the muscles of the alimentary canal
causing food to move along the gut
The digestive juice which has no enzymes
Organisms consisting of a cell or cells in which the genetic material
is contained within a distinct nucleus
A disease-causing organism
A method of asexua! reproduction where unicellular organisms
simply splits into two
The micro-organism that causes malaria
A part of the alimentary canal that serves as a passage for both air
and food
A plant with no true roots, stems and leaves
(9x 1)
Indicate whether each of the statements in COLUMN | applies to A ONLY, B
ONLY, BOTH A AND B or NONE of the items in COLUMN II. Write A only, B
only, both A and B, or none next to the question number (1.3.1 to 1.3.4) in
the ANSWER BOOK.
COLUMN | COLUMN Il
1.3.1 The products of final digestion in the gut | A. Proteins
B. Lipids
1.3.2 Animals without back bones A. Invertebrates
: B_ Vertebrates
1.3.3. A biological agent that can only A. Protist
reproduce inside the cell of a living B. Virus
organism
1.3.4 Micro-organisms used in medical A. Fungi
biotechnology B. Bacteria
(4x 2)
(9)
(8)
Life Sciences
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Grade 11 June 2017 Common Test
1.4 The diagrams below represent the reproductive structures of a plant studied.
1.4.1
1.4.2
1.4.3
1.4.4
Provide labels for parts 1 and 2.
What is the most likely pollinating agent for the above flower.
Give ONE observable reason for your answer in QUESTION 1.4.2
After fertilisation the ovule becomes the seed.
Explain ONE advantage of seeds over spores.
(2)
(1)
(2)
(6)
Life Sciences
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Grade 11 . June 2017 Common Test
1.5 The diagram below shows the gut in an animal from one of the phyla you have
studied.
1.5.1
1.5.2
1.6.3
1.5.4
State whether the animal has a blind gut or a through gut.
Explain ONE advantage of the gut mentioned in 1.5.1.
Name TWO phyla that have animals with a gut like the one in the
diagram.
State what is meant by cephalisation.
TOTAL SECTION A:
(1)
(2)
(2)
(2)
(7)
50
Life Sciences
SECTION B
QUESTION 2
2.1
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Grade 11 June 2017 Common Test
The diagram below represents the human digestive system,
Give the LETTER/S and the NAME/S of the part/s which:
(a) Contain or secrete enzymes which act upon carbohydrates
(b) Secrete hydrochloric acid
(c) is made up of the caecum, colon and rectum
State TWO functions of the liquid stored in part B.
Explain TWO structural adaptations of a villus found in part F.
State why gland E is regarded as both endocrine and exocrine.
Describe how the hormone secreted by the pancreas regulates the
blood glucose level when it drops below normal.
(2)
(2)
(2)
(4)
(2)
(4)
(20)
Life Sciences
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Grade 11 June 2017 Common Test
2.2 The diagram below represents an organism in one of the phyla of the kingdom
Animalia.
Locust
2.2.1 Identify the phylum to which the locust belongs.
2.2.2 State whether the locust is dip/oblastic or triploblastic animal.
2.2.3 Name the type of skeleton found in a locust.
2.2.4 State TWO disadvantages of the type of skeleton mentioned in 2.2.3
and explain how the locust overcomes each of these disadvantages.
2.2.5 Explain why a blood system is necessary in coelomate organisms
such as the locust.
(1)
(1)
(4)
(2)
(9)
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Life Sciences Grade 11 June 2017 Common Test
2.3 Read the extract below and then answer the questions that follow.
Most important of the tropical diseases
Malaria has been called the ‘most important’ of the tropical diseases by World
Health Organisation (WHO, 1990). It leaves a heavy toll of illness and is lethal,
especially to the children. It poses a risk to business travels, tourists and
immigrants. Imported cases of malaria are increasingly seen in non-endemic
area such as Europe and North America.
In many parts of Africa people are infected so frequently that they develop a
degree of acquired immunity, and may become ‘asymptomatic’ carriers of the
infection. Epidemics are most frequent in rural areas. The global distribution is
mostly concentrated near the equator.
2.3.1 | Name the vector of malaria.
2.3.2 List TWO symptoms of malaria.
2.3.3 Suggest TWO reasons for the high incidence of malaria infections in
Central Africa.
2.3.4 Give ONE reason why malaria poses a risk to the business travellers.
2.3.5 Describe how acquired immunity is achieved.
2.3.6 Define the term asymptomatic as used in the passage.
(1)
(2)
(2)
(3)
(2)
(11)
[40]
Life Sciences
QUESTION 3
3.1
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Grade 11 June 2017 Common Test
The diagram below represents a phylogenetic tree of different groups of plants.
> Origin of land plants
: Early vascular plants
According the phylogenetic tree, which group gave rise to all the other
groups.
In which era did the angiosperms first appear?
Which characteristic separates the bryophytes from charophyceans?
How long ago did the progymnosperms become extinct?
Tabulate any TWO differences between the gymnosperms and the
angiosperms with regards to reproduction.
Are the mosses or angiosperms more closely related to the
gymnosperms?
Explain your answer in QUESTION 3.1.6.
Angiosperm plants undergo sexual and asexual reproduction.
Explain TWO advantages of sexual reproduction for the survival of
plants.
(1)
(1)
(2)
(5)
(1)
(2)
(4)
(17)
|
|
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Life Sciences Grade 11 dune 2017 Common Test
3.2
A grade 11 learner conducted an investigation to determine whether
chlorophyll is necessary for photosynthesis using a variegated leaf. Part A is
white and part B is green.
Variegated leaf
3.2.1 Why should the plant be destarched before a leaf can be tested for
starch. (2)
3.2.2 State the colour of Part A after the starch test. (1)
3.2.3 Explain the various steps the learner will follow when testing for starch
in the leaf of the plant. (6)
3.2.4 Drawa labelled diagram ofa chloroplast. (4)
(13)
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Life Sciences Grade 11 June Examination 2017
3.3. The graph below shows the results of an investigation to determine the effect of
light. intensity on the rate of photosynthesis.
The effect of light intensity on the rate of photosynthesis
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Number of bubbles given off in 1 minute
1 0,5 0,25 0,125
Distance. between a water plant and light source (m)
3.3.1. Formulate a hypothesis for this investigation. (2)
3.3.2 How was the rate of photosynthesis measured in this investigation? (1)
3.3.3 Identify the gas released in this investigation. (1)
3.3.4 How many bubbles were released per minute when the light source
was 0,5 m from the water plant? (1)
3.3.5 The number of bubbles given off remained the same even though the
light intensity increased when the light was moved from 0,25m to
0,125m..
Provide an explanation for the above observation. (2)
3.3.6 State THREE factors that should be kept constant in this investigation. (3)
0
TOTAL SECTIONB: 980
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Life Sciences Grade 11 June 2017 Common Test
SECTION C
QUESTION 4
Carbon dioxide is required in the dark phase of photosynthesis but is released during
the Kreb’s cycle of cellular respiration.
Describe the dark phase of photosynthesis and Kreb’s cycle of respiration and then
explain the structural adaptations of the mitochondria for respiration.
CONTENT: (17)
SYNTHESIS: (3)
(20)
NOTE: NO marks will be awarded for answers in the form of flow charts,
tables or diagrams.
TOTAL SECTION C: 20
GRAND TOTAL: 150
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Life Sciences Grade 11 ~ Marking Guideline June 2017 Common Test Life Sciences Grade 11 — Marking Guideline June 2017 Common Test |
14. — If only letter is asked for and oniy name is given (and vice versa) SECTION A
No credit 7
QUESTION 1
15. If units are not given in measurements. .
Candidates will lose marks. Memorandum will allocate marks for units separately 14 144A AVY
4.1.2 BYY
16. Be sensitive to the sense of an answer, which may be stated in a different way. 4.1.3 Cy
1.1.4 BYY
17. Caption . 4.15 Cy
All illustrations (diagrams, graphs, tables, etc.) must have a caption 4.1.6 AMY
147 DYv
18. Code-switching of official languages (terms and concepts) 1.1.8 oy
A single word or two that appears in any official language other than the learners’ 1.1.9 Cy
assessment language used fo the greatest extent in his/her answers should be credited, 1.110 Cvv (10x2} (20)
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consulted. This is applicable to all official languages. 1.2 1.2.1 Aerobic respiration
1.2.2 Peristalsis”
1.23 Bilev”
124 Eukaryotes“/eukaryotic
1.25 Pathogen”
1.2.6 Binary fission”
1.27 Plasmodium”
128 Pharynx”
129 — Thallus¥ . @) |
13° 134 Nonevv
1.3.2 Aonlyv¥”
1.3.3 Bonly~” noe
43.4 BothAand BYY (4x2) (8)
V4 1.41 A-AntherY
B- Stigmay @)
142 Wind ¥ (1)
14.3 - Nopetals” i
- Large anther”
- Feathery stigma”
- Long filaments”
Mark first ONE only Any (1)
14.4 - Seeds have more food than spores¥ !
- and can therefore survive longer”
- Seeds are dispersed in many ways”
- whereas spores are dispersed by wind only
. Any1x2 = (2)
Mark the first ONE only (®)
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2.2 221
2.2.2
2.23
224
2.25
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2.3.2
2.3.3
2.3.4
Copyright reserved
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Grade 11 — Marking Guideline
June 2017 Common Test
ArthropodaY (4)
Triploblastic’ (1)
Exoskeleton” (4)
itis impermeable, gas exchange cafi no longer occur throughout
the body surface.”
It has specialised gas exchange openings.“
lt cannot stretch to accommodate growth of the body.”
This is avoided by moulting at regular intervals.” (4)
The body wail of the animals are separated from the gut
wail /there is increased distance between: the gut and other parts
of the body
making diffusion inadequate for transport of food, gases and
excretory wastes. V Q
9)
Mosquitoes¥ /Anopheles mosquitoes (1)
pene ee tune
Headachev’
Fever”
Sweating’
Chills~
Muscular Pains
Abdominal Pains”
DiarrhoeaY”
Nausea and Vomiting”
Loss of Appetite”
Cough”
Mark first TWO only Any (2)
High rainfall”
Inadequate medical facilities”
No money to buy insecticides”
Lack of awareness”
Mark first TWO only Any (2)
Business people may not have acquired immunity/antibodies“””
to fight the infection.
Increased chances of exposure to diseases” Any (1)
Life Sciences
2.3.5
2.3.6
QUESTION 3
34 3.1.1
3.4.2
3.13
3.44
3.15
316
3.1.8
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8
Grade 11 — Marking Guideline June 2017 Common Test
Person gets a mild form of a disease through natural infection”
The body produces antibodies to fight the diseasev’, get better
The antibodies remain” in the body
To fight off any further infection of the same diseasev
Any (3)
- Isa person who is a carrier for a disease”
- but experience-no symptoms.” (2)
(11)
140]
Green algaew” . a)
Mesozoic” (1)
Bryophytes are land piants“/Charophyceans are aquatic (1)
Accept in the range 250-260”: myav/million years ago {2)
v
Gymnosperms Angiosperms
- Bear naked seeds¥ - Bear seeds that are
enclosed in a fruit”
-__Bear cones¥” =__Bear flowers”
- Seeds dispersed by - Seeds are dispersed by
wind only” various agents”
- Pollination occurs by - Pollination by various
wind only” agents”
Any2x2+1Table (5)
Angiosperms” (1)
- They share a more recent” common ancestor”
OR
- Both” bear seeds” @)
- Offspring produced are genetically different from each other and
their parents”
- If conditions in the habitat change drastically, some of the
individuals will survive.
- The zygote/seeds covered with thick protective coat”
- which allow it to survive unfavourable conditions.
- Large store of food in seeds”
- allows seeds to remain dormant until conditions are suitable”
2x2 (4)
(17)
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Life Sciences
SECTION C
QUESTION 4
Dark phase
using energy from ATP”
Kreb’s cycle
In the presence of oxygen”
Adaptations of the mitochondria for cellular respiration
1
Grade 11 — Marking Guideline
It occurs in the stroma of the chloroplast¥ -
Carbon dioxide from the atmosphereY
combines with energised hydrogen atoms” from the light phase
to form carbohydrates” such as glucose and starch.
The reactions are controlled by enzymes”
It occurs in the mitochondrion”
Pyruvic acidY produced during glycolysis
is used in a cyclic series of reactions”
Energised- hydrogen atoms are released”
Which combine with co-enzymes”
and COz is releasedvinto the atmosphere
June 2017 Common Test
Any 5
Any6
- Outer membrane is smooth~/mitochondria are rod-shaped
~ allowing for easy movement” of the mitochondria .
- Outer membrane is permeableY
- to allow for diffusion of oxygen» /pyruvic acid
- Inner membrane is highly folded to form cristae”
- to increase the surface area for attachment of enzymesY”
- Mitochondria contain DNAY /ribosomes
~ for the manufacture of enzymes”
ASSESSING THE PRESENTATION OF ESSAY
Any3x2=6
Content: (17)
Synthesis: (3)
[20]
All information provided is relevant to
the question
Ideas arranged in a logical
sequence
“Answered all aspects required by thé essay
All information provided is relevant to
the:
- Dark phase
= Kreb's cycle
- Adaptations of mitochondria
There is no irrelevant information
All the information regarding
- Dark phase
- Kreb’s cycle
- Adaptations of
mitochondria
Are arranged in a logical
sequence.
Atleast the following marks should be
obtained for each of the following:
- Dark phase (3/5)
~Kreb’s cycle (4/6)
- Adaptations of mitochondria (4/6)
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TOTAL SECTION C: 20
GRAND TOTAL: 150
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