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SENIOR CERTIFICATE EXAMINATIONS
LIFE SCIENCES P2
2016
MEMORANDUM
MARKS: 150
This memorandum consists of 11 pages.
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Life Sciences Grade 12 Paper 2 NSC June 2016 Memo (English)
Grade 12 Life Sciences Paper 2 memorandum from the NSC June Exam 2016 (English), 11 pages. Read online or download the free PDF.
Life Sciences · Grade 12 · NSC June Exam · 2016. Memorandum, 11 pages. Read online or download the PDF.
- Subject
- Life Sciences
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2016
- Exam period
- NSC June Exam
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 11
- File size
- 350.7 KB
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This exam
NSC June Exam 2016
Questions in this paper
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Life Sciences/P2 2 DBE/2016
SCE
PRINCIPLES RELATED TO MARKING LIFE SCIENCES
1. If more information than marks allocated is given
Stop marking when maximum marks is reached and put a wavy line and 'max' in the
right-hand margin.
2. If, for example, three reasons are required and five are given
Mark the first three irrespective of whether all or some are correct/incorrect.
3. If whole process is given when only a part of it is required
Read all and credit the relevant part.
4. If comparisons are asked for but descriptions are given
Accept if the differences/similarities are clear.
5. If tabulation is required but paragraphs are given
Candidates will lose marks for not tabulating.
6. If diagrams are given with annotations when descriptions are required
Candidates will lose marks.
7. If flow charts are given instead of descriptions
Candidates will lose marks.
8. If sequence is muddled and links do not make sense
Where sequence and links are correct, credit. Where sequence and links are
incorrect, do not credit. If sequence and links become correct again, resume credit.
9. Non-recognised abbreviations
Accept if first defined in answer. If not defined, do not credit the unrecognised
abbreviation but credit the rest of the answer if correct.
10. Wrong numbering
If answer fits into the correct sequence of questions but the wrong number is given,
it is acceptable.
11. If language used changes the intended meaning
Do not accept.
12. Spelling errors
If recognisable, accept the answer, provided it does not mean something else in Life
Sciences or if it is out of context.
13. If common names are given in terminology
Accept, provided it was accepted at the national memo discussion meeting.
14. If only the letter is asked for but only the name is given (and vice versa)
Do not credit.
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Life Sciences/P2 3 DBE/2016
SCE
15. If units are not given in measurements
Candidates will lose marks. Memorandum will allocate marks for units separately.
16. Be sensitive to the sense of an answer, which may be stated in a different way.
17. Caption
All illustrations (diagrams, graphs, tables, etc.) must have a caption.
18. Code-switching of official languages (terms and concepts)
A single word or two that appear(s) in any official language other than the learners'
assessment language used to the greatest extent in his/her answers should be
credited if it is correct. A marker that is proficient in the relevant official language
should be consulted. This is applicable to all official languages.
19. Changes to the memorandum
No changes must be made to the memoranda without consulting the provincial
internal moderator who in turn will consult with the national internal moderator (and
the Umalusi moderators where necessary).
20. Official memoranda
Only memoranda bearing the signatures of the national internal moderator and the
Umalusi moderators and distributed by the National Department of Basic Education
via the provinces must be used.
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Life Sciences/P2 4 DBE/2016
SCE
SECTION A
QUESTION 1
1.1 1.1.1 A
1.1.2 D
1.1.3 C
1.1.4 B
1.1.5 A
1.1.6 C
1.1.7 D
1.1.8 C
1.1.9 C
1.1.10 C ( 10 x 2) (20)
1.2 1.2.1 Dihybrid
1.2.2 Biodiversity
1.2.3 Foramen magnum
1.2.4 Population
1.2.5 Hypothesis
1.2.6 Haemophilia
1.2.7 Extinction
1.2.8 Gene
1.2.9 Bipedalism (9 x 1) (9)
1.3 1.3.1 Yand Z (2)
(Mark first TWO only)
1.3.2 Y – Tau
Z – Chaka (2)
1.3.3 IAIA
IAi
(Any order) (2)
(6)
1.4 1.4.1 (a) 46 (1)
(b) 44 (1)
(c) 2 (1)
1.4.2 23 (1)
1.4.3 Male (1)
(5)
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Life Sciences/P2 5 DBE/2016
SCE
1.5 1.5.1 (a) Prophase I (1)
(b) Metaphase II (1)
1.5.2 (a) Centriole (1)
(b) Nuclear membrane/(nucleus) (1)
(c) Homologous pair/Bivalent (1)
1.5.3 (a) - Forms spindlefibres (2)
(b) Carries genetic/hereditary material (1)
1.5.4 Haploid (1)
1.5.5 Crossing over (1)
(10)
TOTAL SECTION A: 50
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Life Sciences/P2 6 DBE/2016
SCE
SECTION B
QUESTION 2
2.1 2.1.1 (a) Whitefur (1)
(b) Blackfur (1)
2.1.2 (a) 1 and 3 (2)
(Mark first TWO only)
(b) 1 (1)
(Mark first ONE only)
2.1.3
P1 Phenotype Black X White
Genotype BB X bb
Meiosis
G/gametes B, B X b, b
Fertilisation
F1 Genotype Bb; Bb, Bb; Bb
Phenotype All black
*0%white
P 1 and F 1
Meiosis and fertilisation
(*compulsory mark + 5)
OR
P1 Phenotype Black X White
Genotype BB X bb
Meiosis
Gametes B B
Fertilisation b Bb Bb
b Bb Bb
1 mark for correct gametes
1 mark for correct genotypes
F1 Phenotype All black
*0% white
P 1 and
F1
Meiosis and fertilisation (* compulsory (6)
mark + 5) (11)
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Life Sciences/P2 7 DBE/2016
SCE
2.2 2.2.1 The two types of shrimp/ type A and B did not belong to the same
species/ were different species
(Mark first ONE only) (1)
2.2.2 - Individuals that belong to the same species are able to
interbreed
- the two types of shrimps did not mate with each other and
therefore were unable to interbreed Any (1 x 2) (2)
(Mark first ONE only)
2.2.3 To ensure that the results would be reliable (1)
(4)
2.3 - The original population is separated into two populations
- by a geographical barrier
- There is no gene flow/no interbreeding between the populations
- Each population is exposed to different environmental conditions
- Natural selection occurred independently in each population
- and the individuals of each population became different from each other
over time
- genotypically and phenotypically
- Even if the two populations were to mix again
- they would not be able to reproduce with each other
Any (5)
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Life Sciences/P2 8 DBE/2016
SCE
2.4 2.4.1 - Ponds 1 and 2 should have identicalenvironmental/
biological/physical conditions/examples
- Equal numbers of predatory fish in both ponds
(Any 1 x 2) (2)
2.4.2 (a) The type of predators (1)
(b) The number of spots (1)
2.4.3 - As a control/to compare the results between the ponds.
- To ensure that any changes that occurred were due to the
- presence of the predator/independent variable (3)
2.4.4 - There is variation amongst the male guppies
- Some have more spots
- while others have fewer spots
- The ones that have more spots attract predators
- and are eaten/killed by predators
- The ones with fewer spots survived and reproduced
- to pass the gene for fewer spots on to the next generation
Over a period of time, pond 1 with predators had guppies with
fewer spots Any (5)
(12)
2.5 2.5.1 Phylogenetic tree (1)
2.5.2 4 (1)
2.5.3 (a) Paranthropus (1)
(b) Ardipithecus (1)
(c) Paranthropus robustus (1)
2.5.4 Mrs Ples
Taung Child
Little Foot
(Mark first ONE only) (Any 1) (1)
2.5.5 H. habilis
H. erectus
H. naledi
(Mark first TWO only) (Any 2) (2)
(8)
[40]
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Life Sciences/P2 9 DBE/2016
SCE
QUESTION 3
3.1 3.1.1 High yield
Short stem (2)
3.1.2 hT (1)
(Mark first ONE only)
3.1.3 HHtt, Hhtt (2)
(Mark first TWO only)
3.1.4 Does not break easily in windy conditions/to carry a bigger yield/
easier to harvest Any (1)
3.1.5 The plant breeder must cross plants of variety A (HHtt) with
plants of variety A(HHtt) (2)
(8)
3.2 T
Lamarckism Darwinism
1 Variation of the offspring 1 Variation in the offspring is
occurs when individuals in the inherited
population change
2 Change occurs because of 2 Natural selection – individuals best
adaptation to the suited to the environment survive
environment/Law of use and
disuse/ deterministic theory
3 Individuals in the population 3 The population as a whole
change changes
4 Acquired characteristics are 4 Characteristic are passed on from
inherited by offspring generation to generation to enable
individuals to survive in the
environment
(Mark first THREE only) (Any (3 x 2) + 1 for table) (7)
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Life Sciences/P2 10 DBE/2016
SCE
3.3 3.3.1 - Olfactory brain centres reduced/ reduced sense of smell
- Eyes in front/ Binocular vision / stereoscopic vision
- Eyes with cones/ colour vision
- Freely rotating arms
- Elbow joints allowing rotation of forearm
- Flat nails instead of claws/ bare, sensitive finger tips
- Opposable thumbs/precision grip
- Bipedal/ upright posture / foramen magnum in a more
forward position
- Sexual dimorphism/ distinct differences between males and
females
- Two teats
- Parts of the brain that process information from the hands
and eyes are enlarged
- Long upper arms
- Large brains / skulls compared to their body mass
- Five digits per limb Any (5)
(Mark first FIVE only)
3.3.2 (a) More curved spine/S-shape in humans
less curved/ C-shaped in apes (2)
(b) Short and wide pelvis in humans
long and narrow pelvis in apes (2)
3.3.3 - Canines/teeth have changed from large to small
- This is due to a change from eating raw food
- to eating cookedfood (4)
(13)
3.4 3.4.1 2 (1)
3.4.2 (a) Albino female (1)
(b) Aa (2)
3.4.3 (a) 50% (1)
(b) 25% (1)
(6)
3.5 - A gene mutation affects the sequence of nitrogen bases/
change in the individual nitrogen bases
- in DNA
- This changes transcription
- Resulting in a changed mRNA/codon
- which changes the order of the code on the DNA and the RNA/the order
of the nitrogen bases
- A different amino acid may be coded for
- by tRNA leading to the formation of a different protein (Any 6) (6)
[40]
TOTAL SECTION B: 80
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Life Sciences/P2 11 DBE/2016
SCE
SECTION C
QUESTION 4
Location, structure and function
- The DNA is located in the nucleus/chromosome/genes/mitochondria
- DNA is a nucleic acid
- It has a doublestranded
- helix configuration
- consisting of building blocks called nucleotides
The three components of a nucleotide are as follows:
- Nitrogenous bases
- Phosphate portion
- Deoxyribose sugar portion(in DNA)
- 4 nitrogenous bases are A,T,C,G of DNA:
- adenine (A) bonds with thymine (T)
- cytosine (C) bonds with guanine (G)
- by hydrogen bonds
- Sections of DNA carry hereditary information
- DNA contains coded information for protein synthesis Max (10)
Replication
- The double helix unwinds
- Double stranded DNA unzips
- as the weak hydrogen bonds break
- Each original DNA strand serves as a template
- Free nucleotidesbuild
- a new DNA strandonto each of the original DNA strands
- by attaching to their complementarynitrogenous bases/(A to T, and C to G)
- this results in two identicalDNA molecule Max (7)
Content: (17)
Synthesis: (3)
(20)
ASSESSING THE PRESENTATION OF THE ESSAY
Criterion Relevance (R) Logical sequence (L) Comprehensive (C)
Generally All information provided is Ideas are arranged in a Answered all aspects required
relevant to the question. logical/cause-effect sequence. by the essay in sufficiently
detail.
In this All the information provided The information given regarding At least the following marks
essay in is relevant to the location, the location, structure, functions should be obtained for:
Q4 structure, functions of DNA of the DNA and the replication - location, structure and
and the replication process. process is arranged in a logical functions of the DNA (7/10)
and sequential manner. - DNA replication (4/7)
There is no irrelevant
information
Mark 1 1 1
TOTAL SECTION C: 20
GRAND TOTAL: 150
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