Mathematical Literacy Grade 11 NSC Prelim 2016 Paper & Memo

gt a SREB R ARS eS eS SES es ee eee ay i" MATHEMATICS " ly a a COMMON TEST : ' SEPTEMBER 2016 i MARKS: 75 TIME: 1% hours Education KwaZulu-Natal Department of Education REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 11 N.B: This question paper consists of 7 pages.

Mathematics 2 September 2016 Common Test NSC INSTRUCTIONS AND INFORMATION Read the following instructions carefully before answering the questions. lL. This question paper consists of FIVE questions. 2. Answer ALL the questions. 3. Clearly show ALL calculations and diagrams that you have used in determining your answer. 4. You may use an approved scientific calculator (non-programmable and non-graphical). 5. Ifnecessary round off answers to TWO decimal places, unless stated otherwise. ( ; 6. Answers only will not be awarded full marks. 7. Diagrams are not necessarily drawn to scale. 8. Number the answers correctly according to the numbering system used in this question paper. 9. Write neatly and legibly. Copyright Reserved Please Turn Over

Mathematics 3 September 2016 Common Test NSC QUESTION 1 1.1 A travel agent did a survey amongst his clients as to which type of holiday they prefer. The table below shows the results of this survey. Game Sea Drakensberg Total reserve Male 250 70 a 500 Female 150 b 160 c Total d 170 e 910 1.1.1 Write down the values ofa, b, ¢, d and e. (2) 1.1.2 Ifa client is selected at random, what is the probability that this client } (a) Will prefer visiting a game reserve? (1) (b) Will be a female? qd) (c) Will be a female and prefer visiting a game reserve? dd) (d) Will be a female or prefer visiting a game reserve? (2) 1.1.3. Consider the following two events: Event A: a client is a female Event B: a client prefers visiting a game reserve when going on holiday. Are events A and B independent? Motivate your answer with the necessary calculations. (3) 1.2 Figures obtained from a city’s police department indicate that of all the vehicles stolen, 70% were stolen by syndicates (gangs) to be sold off, and 30% were stolen by individual Co} persons for their own use. Of the vehicles stolen by syndicates: e 10% were recovered (found back) within 24 hours; *® 30% were recovered after 24 hours; and © 60% were never recovered. Of the vehicles stolen by individual persons: « 30% were recovered within 24 hours; e 40% were recovered after 24 hours; and * 30% were never recovered. 1.2.1 Draw a tree diagram to represent the above information. @) 1.2.2 Calculate the probability that if a vehicle was stolen in this city, it would be stolen by a syndicate and recovered within 24 hours. (2) 1.2.3 Calculate the probability that a vehicle stolen in this city will not be recovered. (3) [18] Copyright Reserved Please Turn Over

Mathematics 4 September 2016 Common Test NSC QUESTION 2 A frustum is the portion of a cone which remains after a smaller cone has been cut off its upper part. FRUSTUM 13,5 em arem Gaba Smaller cone that has been cut off. The height of the small cone is 13,5 cm and the height of the large cone is 27om. C i The diameter of the base of the large cone is 24cm and the diameter of the base of the small cone is 12cm. 2.1 Find the volume of the frustum, giving your answer in terms of 7. (4) 2.2 The frustum has the same volume as a certain sphere. Calculate the radius of this sphere. List of formulas to choose from when answering Question 2: Vata? ( Vearh : Vetmn (3) [7] Copyright Reserved Please Turn Over

NSC : Mathematics 5 September 2016 Common Test | QUESTION 3 3.1 Inthe diagram A(-15; p) is a point such that OA=17 and DOA =6, where @ isa reflex angle. y °C eL) Se BO; y) } A(-15; p) 3.1.1 Calculate the value of p. (2) 3.1.2 Determine the value of each of the following without the use of a calculator: (a) cos 0 qd) (b) tan (180° — 8) (2) (c) — sin (@ — 360°) . cos (90° — 0) (3) 3.1.3 B isapointon OA, such that OB = 10, Calculate the values of x and y without calculating the size of angle @. (4) (5 3.2 Simplify the following and express your answer as a single trigonometric term. _ o cos ( x). tan 225 + fan 6 60° — x) (1) sin 90° ~ sinx 3.3. Prove the following identity: 2 sin’ x cosx =< (4) 2tanx — 2 sinx cosx sinx 3.4 Determine the general solution for x if: sin (2x + 15°) = cos (x ~ 15°) (5) [28] Copyright Reserved Please Turn Over

Mathemutios 6 September 2016 Common Test NSC QUESTION 4 The following sketch represents the graphs of: SR) = aeos (x+ 6) and. a) = esinx for x @[-180° ; 180°] . : ~ Bd 4; a — If pa a To a a re OT ED C me. i i 41 From the sketch‘above write down the-values of @, b and ¢. (3) 42. A(-14,64°; p) and B(q;-0,51) are the coordinates of the points of intersection of f and g. Write down, rounded off to:2:deeimal places, the values of: 4.2.1 p O% 422 ¢ (dy 43 Fort which values of x will f(x) . g(x) 2 0? (2) 44 Ifthe.graph of f is shifted 45° to the left, write down the equation of the new graph, a (8) Copyright Reserved Please Tarn Over

Mathematics 7 September 2016 Common Test QUESTION 5 5.1 In the figure below, AB = 107 mm, BC =68mm and ABC = 79°. AC L DC. DAC=22°. ’ 5.1.1 Calculate the length of AC. (3) 5.1.2 Calculate the length of DC. QQ) 52 5.2.1 Complete: Areaof A ABC = sab ees () 5.2.2 In the figure below AB=AD with DC=%BD and DC=r. It is also given that ABD =o, and sin 20 = 2 sina cosa. A } a Cc B D ; (a) Showthat AD = —" (4) cos @ (b) Now determine the area of A ADC, in terms of a and r. A [14] TOTAL MARKS: 75 Copyright Reserved

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Mathematics 3 Common’ ~~ ptember 2016 . NSC . ww 12.1 y ‘within 24h) 10% 2 7a 24 LA for Birst branching: into S and IP 1A for branching from S into R(within 24h), R(after 24h) and on R(within 24h) NR 1A for branching from IP into wT Rests 24h) R(within 24h), R(after 24h) and. NR S: syndicates; IP: individual persons; ; R: recovered; NR: not recovered (3) 1.2.2 ag x 10% = 0,07 1A for 70% x 10% OR 0,7x0,1 0,7x0,1=0,07 1A foi angwer 2 10% x 60% + 30% x 30% LA for 70% x 60% OR 0,7x0,6 123 |= 051 * OR 1A for 30% x 30% OR 0;3x0,3 0,7x0,640,3x0,3 1A for correct answer =051 (3) [18]. QUESTION 2 2.1 | Volume of large cone = 477k =ix(2Peny 1A for substitution = 12960 ¥ 1CA for answer Volume of small cone = 17h = 426)'03,5) =162 2v 1A for answer Volume of frustum = 1296 7-162 7 =11340 ¥ 1CA for answer (4) 2.2 | Volume of sphere= $777 $m? = 11340 ¥ 1 CA for equating r=850,5 ¥ 1CA for simplification r=94AT om ¥ 1CA for answer (3) ia} Copyright Reserved Please Tum Over Mathematics t : nec ‘Common Test September 2016 QUESTION 3 | 3.1 | 3.1.1 =1P -Cisev 1A for using Pythagoras | = 8 1A for correct answer Q) 3.12 —15 : a) cos “TT v 1A for answer ay 3.12 | tan (180° - 6) = tm ¥ 1A for correct reduction ) _8 = iofv 1€A for answer 15 2) 3.12 sin © — 360°) . cos (90°— 6) © ; | 1A for sin(@—360°) =sin@ = sind sind 77 1A for cos(90" -6)=sin8 = six? = (<8) 17 4 oa ~ 339 1CA for answer _ @) 313 |g w 82 ICA for equating the rato 17-10 ly = -80 i 80 i yay 8 470 ¥ 1CA. for answer -15_ x - . cos@ = ———-=— ¥ 1CA for equating the ratio 1710 17x = -150 ' 150 =p oF -89L 1CA for answer (4) Copyright Reserved yy ie Turn Over

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‘Mathematics 7 Common?” ‘ptember 2016 ssc od 352 521 |*%absincv 1M for correct formula @ 322 @ |sp=2 BAD = 180° - 20v 1A for finding BAD AD _ _BD_y 1A for applying sine rule sinB- ‘sinBAD AD = —_* __. v 1A for correct substitution sina sin(L80°- 2a) AD = 2r sing sin 2@ oy si = ome 1CA for simplification/substitution 2sing cos a@ aot va ADC= 180° -a ¥ 1A for finding ADC s.Area of AADC = ¥% AD.x. sin(180°—a@) | 1A for applying area rule = %——rsinav r cos @ 1A for substituting AD= and cos & =“2 sina , sin(L80" —a)=sing cos & =’*r way LA for answer a (14) TOTAL MARKS: 75 Copyright Reserved