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SENIOR CERTIFICATE EXAMINATIONS/
SENIORSERTIFIKAAT-EKSAMEN
NATIONAL SENIOR CERTIFICATE EXAMINATIONS/
NASIONALE SENIORSERTIFIKAAT-EKSAMEN
MATHEMATICS P1/
WISKUNDE V1
MARKING GUIDELINES/NASIENRIGLYNE
2021
MARKS: 150
PUNTE: 150
These marking guidelines consist of 13 pages.
Hierdie nasienriglyne bestaan uit 13 bladsye.
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Mathematics Grade 12 Paper 1 NSC June 2021 Memo
Grade 12 Mathematics Paper 1 memorandum from the NSC June Exam 2021, 13 pages. Read online or get the free PDF download, question paper linked when available.
Mathematics · Grade 12 · NSC June Exam · 2021. Memorandum. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2021
- Exam period
- NSC June Exam
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 13
- File size
- 589.6 KB
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This exam
NSC June Exam 2021
Questions in this paper
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Mathematics P1/Wiskunde V1 2 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
NOTE:
If a candidate answers a question TWICE, only mark the FIRST attempt.
Consistent Accuracy applies in all aspects of the marking memorandum.
LET WEL:
Indien 'n kandidaat 'n vraag TWEE keer beantwoord, merk slegs die EERSTE poging.
Volgehoue akkuraatheid is DEURGAANS op ALLE aspekte van die memorandum van
toepassing.
QUESTION/VRAAG 1
1.1.1 x 2 x 20 0
x 5x 4 0 factors
x=5
x=5 or x = –4
x = –4 (3)
1.1.2 3x 2 x 6 0
2
2 22 43 6 substitution
x
23
1 19
x simplification
3
x = –1,12
x = –1,12 or x = 1,79
x = 1,79 (4)
1.1.3 ( x 1) 2 9
standard form
x 2 2x 8 0
( x 4)( x 2) 0
Critical values: x = 4 or x=–2 critical values
–2 4
x 2 or x 4 x 2 or x 4
(4)
OR/OF OR/OF
( ; 2) or (4; ) ( ; 2) or (4; )
OR/OF OR/OF
x 1 3 or x 1 3 x 1 3
x4 or x 2 x 1 3
x 4 or x 2
(4)
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Mathematics P1/Wiskunde V1 3 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
1.1.4 2 x6 2 x
2 x6 x2 isolating the surd
4( x 6) ( x 2) 2
4 x 24 x 2 4 x 4
4 x 24 x 2 4 x 4
x 2 8x 20 0
( x 10)( x 2) 0
x 10
x 10 or x 2 x 2
(4)
1.2 4 x 2 y . . . (1) 4x 2 y
4 x y 2 8 . . . (2)
substitution
2 y y2 8
standard form
y2 y 6 0
( y 3)( y 2) 0
y = 3 or y = –2 y-values
1 x-values
x or x = 1
4 (5)
OR/OF OR/OF
y 4 x 2 . . . (1) y 4x 2
4 x y 2 8 . . . (2)
4 x 4 x 2 8
2
substitution
4 x 16 x 2 16 x 4 8 0
16 x 2 12 x 4 0
4 x 2 3x 1 0
4x 1x 1 0 standard form
1
x or x = 1 x-values
4
y = 3 or y = –2 y-values
(5)
1.3
2 x 3 y 23 3 6
2 3
3
2 x 3 y 218 36
218 or 3 6
2 2
x 18
and 3 3 y 6
x = 18 or y = 6
x = 18 and y=6
x y 18 6
x y 12 answer (A)
(4)
[24]
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Mathematics P1/Wiskunde V1 4 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 2
2.1.1 72 ; 100 ; 120 ; 132 ; …
28 20 12
–8 –8 second differences = – 8
2a = – 8
a=–4
a=–4
3a + b = 28
b = 40
b = 40
a + b + c = 72
c = 36
c = 36
Tn 4n2 40n 36 (4)
2.1.2 T12 36 8n 36 8(12) 60 36 – 8n
4n 2 40n 36 60 – 60
standard form
n 2 10n 24 0
(n 12)(n 2) 0 factors
n 12 n 12
(5)
2.1.3 Tn 8n 40 0
/ 8n 40
n 5
n5
Tn 4(5) 2 40(5) 36 136 136 (3)
OR/OF OR/OF
b 40 substitution
5
2a 8 n 5
Tn 4(5)2 40(5) 36
136
136
(3)
2.1.4 Maximum value = 41 value
(1)
2.2 2 sin 3x 11 15 2 sin 3x equating
4 sin 3x 4 4 sin 3x 4
sin 3x 1 sin 3x 1
3x 90
answer
x 30
(4)
[17]
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Mathematics P1/Wiskunde V1 5 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 3
3.1.1 n 1 n 1
1 1
Tn ar n 1 2000 2000 (1)
5 5
3.1.2 7 1 16
1 16 (1)
T7 2000 125
5 125
3.1.3 n 1
16 1
2000 equating
15625 5
n 1
1 1
1953125 5
9 n 1
1 1 1 same base / use of log
OR n 1 log 1
5 5 5
1953125
n–1=9
n = 10 answer (3)
3.2 a a
S 27 S 27
1 r 1 r
a(1 r 3 ) a(1 r 3 )
S3 26 S3 26
1 r 1 r
27(1 r 3 ) 26 substitution
26
1 r3
27
1
r3
27
1 1
r r
3 3
(4)
OR/OF OR/OF
a
S 27
1 r
a 27(1 r ) a 27(1 r )
But a ar ar 2 26 a ar ar 2 26
a(1 r r 2 ) 26
substitution
27(1 r )(1 r r 2 ) 26
26
(1 r )(1 r r 2 )
27
26
r 2 r 1 r3 r 2 r
27
26
r3 1
27
1
r3
27
1
r
1 r (4)
3 3
[9]
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Mathematics P1/Wiskunde V1 6 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 4
4.1 x 1 x 7 x 1 x 7
2 x 8 2 x 8
x 4 x 4
y 3 y 3
2
f ( x) 3
x4
p 4 and q 3 (4)
OR/OF OR/OF
p + q = 1 ……(1) p+q=1
–p + q = –7
q = p – 7 …….(2) q=p–7
subs. (2) into (1)
p+p–7=1 substitution
2p = 8 simplification
p=4
q = –3 (4)
4.2 2
y 3
x4
2
0 3 y=0
x4
2 3( x 4) 0
3x 14 0
14 14
x x (2)
3 3
4.3
horizontal asymptote
vertical asymptote
–4,67 y intercept
–4 O shape
–3
–3,5
(4)
[10]
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Mathematics P1/Wiskunde V1 7 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 5
5.1 2 x 2 4 x 16 0
x 2 2x 8 0
factors
( x 4)( x 2) 0
x = 4 or x = – 2 x=–2 x=4
A(2 ; 0) and B(4 ; 0) (3)
5.2 f ( x) 2 x 2 4 x 16
b 4
1 1
2a 2(2)
f (1) 2(1) 2 4(1) 16 18
C(1;18) 18 (2)
OR/OF OR/OF
f ( x) 2 x 2 4 x 16
f / ( x) 4 x 4
4x 4 0
x 1 1
f (1) 2(1) 2 4(1) 16 18 18
C(1;18) (2)
5.3 y 18 y 18
(1)
OR/OF OR/OF
y( ;18] y( ;18]
(1)
5.4 TP (1 ; 18) for f
TP (2 ; 15) for h TP for h at (2 ; 15)
p 1 q 3 p 1
q 3
(3)
5.5 y 2x 4
x 2y 4 swop x and y
1
1
y x2 y x2
2 2
(2)
1
5.6 g ( x) 0 or g ( x) 0
x = 4 or x = –2 (product 0 at x-intercepts) x=4
x = –2
(2)
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Mathematics P1/Wiskunde V1 8 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
5.7 2 x 2 4 x 16 k 2 x 4 equating
2 x 2 2 x 12 k 0 standard form
b 2 4ac 0 b 2 4ac 0
substitution
(2) 2 4(2)(12 k ) 0
4 8(12 k ) 0
100 8k 0
k 12,5 answer
(5)
OR/OF
OR/OF
g ( x) 2
/
g / ( x) 2
f / ( x) 4 x 4 2 f / ( x) 4 x 4
1
x
2
1 1
f 17,5 f 17,5
2 2
1 1
g 5 g 5
2 2
k 12,5 answer (5)
[18]
QUESTION/VRAAG 6
6.1.1 y 3x
swop x and y
x 3y
y log 3 x
equation
(2)
x 4
6.1.2 h( x) 3 2
Transformation: 4 units left, 2 units down
x = 2 (A)
P / (2 ; 9)
y = 9 (A)
(2)
x p
6.2 f ( x) 2 q
q 16 q 16
16 2 p 3 16
substitute (3 ; 16)
2 p 3 32
2 p 3 2 5 2 p3 25 or p 3 log2 32
p35
p2 p2
(4)
[8]
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Mathematics P1/Wiskunde V1 9 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 7
7.1 i
16
13 080 10 0001 substitution into correct
4
16
formula
i 13080 n = 16
1
4 10000
i 16 13080 simplification
1
4 10000
i
0,0169227...
4
i 0,06769...
i 6,77% answer (A)
(4)
7.2.1
F
x 1 i 1
n
i
0,075 60 0,075
9 0001 1
12 12
F
0,075
substitution into correct
12 Formula
F R 652 743,95
answer
(3)
7.2.2 60 9 000 R540 000 60 9 000 R540 000
A P(1 i) n
n
0,075
652743,95 1 190 214,14 540000
12 equation
n
0, 075
730 214,14 652 743,95 1
12
1,1186.... 1, 00625
n simplification
n log1,00625 1,1186 use of logs
n 18 months 18 months (6)
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Mathematics P1/Wiskunde V1 10 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
OR/OF OR/OF
Interest over 5 years = 652 743,95 – 9 000 × 60 60 × 9 000
= 112 743,95
interest on n years
= 190 214,14 – 112 743, 95 = 77 470,19 answer
n
0,075 equating
652 743,95 + 77 470,19 = 652743,95 1
12
1,1186.... 1, 00625 simplification
n
n log1,00625 1,1186 use of logs
n 18 months 18 months
(6)
[13]
QUESTION/VRAAG 8
8.1 f ( x) 3 x 2
f ( x h) f ( x )
f / ( x) lim
h 0 h
3( x h)2 3x 2 substitution
f / ( x) lim
h 0 h
3x 2 6 xh 3h 2 3x 2
f / ( x) lim expansion
h 0 h
6 xh 3h 2
= lim
h 0 h simplification
h(6 x 3h) h(6 x 3h)
= lim lim
h 0 h 0 h
h
= 6x 6x
(5)
2 2
8.2.1 f ( x) x 3 9 x
2
9x
f / ( x) 2 x 18x 3 2x
18 x 3
(3)
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Mathematics P1/Wiskunde V1 11 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
8.2.2 g ( x) ( x 3)( x 1)
1
1
x 2x 2
g ( x) x 2 x 3
2
1
1
g / ( x) 1 x 2 1 x 2
(4)
[12]
QUESTION/VRAAG 9
9.1 f / ( x) 6 x 2 6 x 12 6 x 2 6 x 12
6 x 2 6 x 12 0 =0
x2 x 2 0
factors
( x 2)( x 1) 0
x 2 or x 1
x -values
y = 20 or y=–7
y -values
A(–2 ; 20) and B(1 ; –7)
(5)
9.2 f ( x) 12 x 6
// 12 x 6
12 x 6 0 f / / ( x) 0
12 x 6
1
x x
1
2 2
(3)
OR/OF
2 1 1 OR/OF
x 1
2 2 x
1 2
x
2 1
x
2
(3)
9.3 f (2) 24
/
f (2)/
Equation of the tangent: y 4 24( x 2) 24
y 24 x 44 equation
(3)
[11]
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Mathematics P1/Wiskunde V1 12 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 10
y
10.1
x = –1 and x = 2
TP at x = –1
x
1 TP at x = 1
shape
(4)
10.2.1
A B
O
1
Area of segment = Area of big circle
4
1
= (x x 2 )2
1
(x x2 )2
4 4
A B
O
Area triangle ABO counted
1
= Area x x 2 2
Area
1
2
x x2
2
2
Area of shaded region subtract areas
1 1
= (x x 2 )2 – x x 2
4 2
2
2
=
4
x x2
2
common factor
(5)
2 2
x 2x x
3 4
4
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Mathematics P1/Wiskunde V1 13 DBE/2021
SC/SS/NSC/NSS – Marking Guidelines/Nasienriglyne
10.2.2 Area of shaded region
2 x 4 2 x 3 x 2
4
dA 2
4x 6x 2x 2
3 2
4x 6x 2x
3 2
dx 4
4
4x 3 6x 2 2x 0
x(2 x 2 3x 1) 0
x(2 x 1)( x 1) 0 factors
1 1
x 0 or x or x 1 x 0; x 1; x
2 2
1
x (4)
2
[13]
QUESTION/VRAAG 11
11.1 P(A) = 1 – P(not A) = 0,6 0,6
P(A and B) = P(A) × P(B) P(A and B) = P(A) × P(B)
= 0,6 × 0,3
9
=
50 answer (A)
0,18
(3)
11.2.1 15 15
a 0,1 (A)
150 150
(1)
11.2.2 m 1 0,7 0,3 0,3 (A)
(1)
11.2.3 0,24 0,14 0,02 0,12 0,1 2b 0,7 addition
2b 0,08 simplification
b 0,04 b 0,04
0,04 150 6 6
(4)
11.3.1 9 × 9 × 8 = 648 9 9 × 8
(2)
11.3.2 2 × 8 × 4 = 64 2 × 8 × 4
2 × 8 × 5 = 80 2 × 8 × 5
Total number = 64 + 80 = 144 144 (A)
(4)
[15]
TOTAL/TOTAAL: 150
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