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NATIONAL
SENIOR CERTIFICATE
GRADE 12
SEPTEMBER 2015
MATHEMATICAL LITERACY P1
MEMORANDUM
MARKS: 150
Symbol Explanation
M Method
A Accuracy
CA Consistent accuracy
RT/RG/RM Reading from a table/Reading from a graph/Read from map
RP Reading from the plan
SF Substitution in a formula
S Simplications
P Penalty (no units, incorrect rounding off etc.)
O Opinion
J Justification
RO Rounding Off
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MATHS LIT P1 MEMO GR12 SEPT 2015 ENG FINAL hlayiso.com
Mathematical Literacy · Grade 12 · Eastern Cape Mock Exam · 2015. Memorandum, 8 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2015
- Exam period
- Eastern Cape Mock Exam
- Paper
- 1
- Pages
- 8
- File size
- 419.3 KB
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2 MATHEMATICAL LITERACY P1 (EC/SEPTEMBER 2015)
QUESTION 1 [33]
Question Solution Explanation Marks
1.1 1.1.1 20 2RT (2)
1.1.2 R1 250 000 x 20% 1M
= R250 000 1S
= R1 250 000 – R250 000 1M
= R1 000 000 1A (4)
1.1.3
Monthly Repayment = 1 000 000 x 10,32 1CV 1 SF
1 000 1S
= R10 320 (3)
1.1.4 R10 320 x 12 x 20 1M
= R123 840 x 20 1S
= R2 476 800,00 1S (3)
1.1.5 R2 476 800 – R1000 000 1CV
= R1 476 800,00 1S (2)
1.2 1.2.1 6 brackets 2A (2)
1.2.2 1M
= R39 667,69 1S (2)
1.2.3 Annual tax = 93 135 + 36% of (476 012,28 – 1M
393 200) 1S
= 93 135 + 36% x (82 812,28)
= 93 135 + 29 812,42 1S
= 117 194,42 p.a. 1M
122 947,42 – 13 257 (Rebate)
Monthly tax = 109 690,42
12
= R9 140,87 1A (5)
1.2.4 1SF
= 7,5% 1A (2)
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(EC/SEPTEMBER 2015) MATHEMATICAL LITERACY P1 3
1.2.5 Tax threshold refers to the amount of earnings at 2 explanation
which people start paying tax, if you earn less
than this amount a year, you do not pay tax. (2)
1.3 1.3.1 R210,51 – R184,66 OR 184,66 x 14% 1M
=R25,85 = R25,85 1S (2)
1.3.2 6 x 9,941230 + 4 x 10,136180 + 6 x 14,077830 1M
= R59,65 + R40,54 + R84,47 3S
= R184,66 (4)
[33]
QUESTION 2 [28]
Question Solution Explanation Marks
2.1 2.1.1 24,5 2RD (2)
2.1.2 7,7 100
1M divide by
7,7 = 100 100
100 100 1S
0,077 (2)
2.1.3 0,077 x 13 570,84 1M
= 1 044,95 1S
= 1 045 1A (3)
2.1.4 61 x 1,05 1M
= 64,05 1S
= 64 050 1A (3)
2.1.5 1,05 hours x 60 = 63 minutes 1M
= 1 hour 3 minutes 1S
17:24
- 1:03
16:21 1S
OR
17:24 arrival time 24 = 0,4 hours
60
17hours + 0,4 hours = 17,4 hours
-1,05 hours
16,35 hours
16 hours + 0,35 hours
= 16 hours + 0,35 x 60 mins
= 16 hours 21mins
= 16:21 The time she left East London. (3)
2.1.6 Afternoon 2A (2)
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4 MATHEMATICAL LITERACY P1 (EC/SEPTEMBER 2015)
2.2 2.2.1 Available drink = 15 x 2 1C
= 30
1S
Required drink = 250 x 116
= 29 000
1 000 1A
= 29
It will be enough for all Grade 11 learners. (3)
2.2.2
x 250
= 166,67 1S
[Difference] 1 subtraction
250 – 166,67 1A
= 83,33 (3)
2.3 2.3.1 4 x 24 1M
= 96 hours 1S (2)
2.3.2 8 471 x 0,6214 miles 1M
5 263,88 miles 1S (2)
2.3.3 radius = diameter = 9 = 4,5 1M
2 2
= 3,142 (4,5 )2 1SF
2
= 63,63 1S (3)
[28]
QUESTION 3 [23]
Question Solution Explanation
3.1 3.1.1 GT 14 2A (2)
3.1.2 5 2A (2)
3.1.3 Glastonbury Road 2RM (2)
3.1.4 Albany Museum 2RM (2)
3.1.5 North West 2RM (2)
3.2 3.2.1 Draw Front Board 2RM (2)
3.2.2 7 and 19 2RM (2)
3.2.3 2 2RM (2)
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(EC/SEPTEMBER 2015) MATHEMATICAL LITERACY P1 5
3.2.4 47 : 1 755 = 1 : 40,8 1C
43 43 1CA
(Accept 42 – 45 mm) (2)
3.2.5 9 2A (2)
3.2.6 3A
= or 15% or 0,15 (3)
[23]
QUESTION 4 [38]
Question Solution Explanation Marks
4.1 4.1.1 9 Provinces 2RT (2)
4.1.2 Northern Cape 2RT (2)
4.1.3 1 575 990 – 766 593 2 Correct
= 809 397 values
1 CA (3)
4.1.4 A = 2 655 420 – (519 072 + 59 + 180 475 +
12 907 + 18 555 + 119 285) 1M
= 2 655 420 – 850 353 1S
= 1 805 067 1CA
OR
A = 11 302 312 – (883 802 + 766 593 + 279 724
+ 999 473 + 1 650 665 + 2 702 811 + 1 575 990 +
638 187)
= 11 302 312 – 9 497 245
= 1 805 067 (3)
B = 18 555 + 6 221 + 15 686 + 35 919 + 12 745 + 1Add
8 998 + 4 694 + 8 683 + 11 312
=122 813
1CA
OR
B = 16 156 984 – (2 991 791 + 407 + 1 122 334 +
86 970 + 530 357 + 11 302 312)
= 122 813 (2)
C = 16 156 984 - (2 655 420 + 943 923 + 2 219 1M
842 + 3 812 820 + 2 253 114 + 1 343 612 + 1 135
208 + 1 362 695)
= 430 350 1A
OR
C = 774 409 + 11 + 48 473 + 5 304 + 4 694 + 1M
14 735 + 2 79724)
= 430 350 1A (2)
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6 MATHEMATICAL LITERACY P1 (EC/SEPTEMBER 2015)
4.1.5 Graph
FS NC NW MP LP KZN EC GP WC
6 11 15 18 28 54 59 103 113
WAR VETERANS' GRANT PER
PROVINCE
120
100
80
Total beeficiaries
60
40
20
0 FS NC NW MP LP KZN EC GP WC
PROVINCES
1 Mark for 3 points correctly plotted = (3)
1 Mark for joining the points = (1) (4)
Answer only full marks
4.1.6 6 : 18 2A
1:3 (2)
4.1.7 KwaZulu Natal (35 919) 2RT (2)
4.1.8 1 362 695 = One Million, three hundred and sixty two 2A
thousand, six hundred and ninety five (2)
4.2 4.2.1 Coke (Summer) = 18 700 2RG
(Accept 18 600 – 18 800) (2)
4.2.2 Autumn and Winter 2RG (2)
4.2.3 Stacked bar graph or Stacked column graph or Stacked 2A
graph (2)
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(EC/SEPTEMBER 2015) MATHEMATICAL LITERACY P1 7
4.3 4.3.1 1M
Mean = 2 526,05 1 division
7 By 7
= 360,86 1S
= 361 1A (4)
4.3.2 Range = R1 200,00 – R250,00 2CV
= R950,00 1CA (3)
4.3.3 R500,00 2A (2)
[38]
QUESTION 5 [28]
Question Solution Explanation Marks
5.1 5.1.1 R17 500,00 2RG
OR
Venue A = R5 000 + R125(100)
= R5 000 + R12 500 AO
= R17 500,00 (2)
5.1.2 Venue C 2RG (2)
5.1.3 n = 6 2 RG
OR (Trial and error) Answer only
R4 000 : R2 500 + R250(2) = R3 000 Full marks
R2 500 + R250(4) = R3 500
R2 500 + R250(6) = R4 000 AO
n = 6 correct answer (2)
5.1.4 (i) (20,7500) 2RM
(ii) (90,25000) 2RM
(iii) (160, 25000) 2RM (6)
5.1.5 R5 000,00 2A (2)
5.2 5.2.1 = (78,8 – 32) 1SF
= 46,8 ÷ 1,8 1S
= 26 1A (3)
5.2.2 1numerator
=
1denominator
1S (3)
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8 MATHEMATICAL LITERACY P1 (EC/SEPTEMBER 2015)
5.2.3 Impossible OR 0 % 2A (2)
5.3.1 1SF
1S
= 6,14
= 7 minibus taxis 1S (3)
5.3.2 10,83 x 22,5 + 45 x 14 1M
= R243,68 + R630 1A
= R873,68 1S (3)
[28]
TOTAL: 150
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