Mathematical Literacy Grade 11 P1 2024 Memo

PROVINCIAL ASSESSMENT/ PROVINSIALE ASSESSERING GRADE/GRAAD 11 MATHEMATICAL LITERACY P1/ WISKUNDIGE GELETTERDHEID V1 NOVEMBER 2024 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 100 Symbol/Kode Explanation/Verduideliking M Method/Metode MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid C Conversion/Herleiding S Simplification/Vereenvoudiging RT Reading from table/a graph/document/diagram/Lees vanaf tabel/grafiek/document/diagram SF Correct substitution in a formula/Korrekte vervanging in formule O Opinion/Explanation/Reasonig/Opinie/Verduideliking/Redenasie P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede/verkeerde afronding, ens. R Rounding/Afronding NPR No penalty for correct rounding/Geen penalisasie vir korrekte afronding nie AO Answer only/Slegs antwoord MCA Method with constant accuracy/Metode met volgehoue akkuraatheid RCA Rounding consistent with accuracy/Afronding met volgehoue akkuraatheid These marking guidelines consist of 11 pages./ Hierdie nasienriglyne bestaan uit 11 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 2 NW/November 2024 Grade 11 – Marking Guidelines/Nasienriglyne NOTE:  If a candidate answers a question TWICE, only mark the FIRST attempt.  If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version.  Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error.  NOTE: consistent accuracy (CA) does not apply in cases of a breakdown.  If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra item presented.  As a general principle, if a candidate has incurred one mistake and there is evidence of sound mathematics thereafter, then that candidate should lose one mark only.  Rounding is an independent mark.  In order to award the verification/conclusion mark the candidate must have scored at least one mark in the calculation preceding the final conclusion. LET WEL:  As ‘n kandidaat ‘n vraag TWEE KEER beantwoord, sien slegs die EERSTE poging na.  As ‘n kandidaat ‘n antwoord van ‘n vraag doodtrek (kanselleer) en nie oordoen nie, sien die doodgetrekte (gekanselleerde) poging na.  Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, dit hou op by die tweede berekeningsfout.  LET WEL: volgehoue akkuraatheid (CA) geld nie in die geval van ‘n afbreuk nie.  Wanneer ‘n kandidaat aflesings vanaf ‘n grafiek, tabel, uitlegplan en kaart geneem en ekstra antwoorde gee, penaliseer vir elke ekstra item.  ‘n Algemene nasienbeginsel is dat indien ‘n kandidaat een fout maak en daarna voortgaan met korrekte wiskunde, dat die kandidaat slegs een punt verloor.  Afronding tel as ‘n afsonderlike punt.  Ten einde die verifikasie/gevolgtrekking punt toe te ken moes die kandidaat ten minste een punt gekry het in die berekeninge wat lei tot die finale gevolgtrekking. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 3 NW/November 2024 Grade 11 – Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 [20 MARKS/PUNTE] AO – Full marks Q/V Solution/Oplossing Explanation/Verduideliking T/L 1.1.1 5 items A 2A answer number of items/antwoord F aantal items L1 (2) 1.1.2 September month/maand A 2A answer month/antwoord maand F L1 OR/OF OR/OF 9th month/9de maand A 2A answer maand/Antwoord month (2) 1.1.3 VAT refers to a consumption tax on F goods and services levied at each stage L1 of the supply chain where value is added/BTW verwys na ‘n verbruikersbelasting op goedere en dienste gehef in elke stadium van die in die verskaffing van goedere en dienste 2A answer/antwoord A (2) 1.1.4 15 F VAT/BTW = R186,60 × MA 115 2MA multiply with 15 ÷115/ L1 VAT/BTW = R23,33913043 vermenigvuldig met 15 ÷115 VAT/BTW ≈ R23,24 OR/OF OR/OF TOTAL = R186,60 ÷ 1,15 MA = R162,2608696 1MA divide with 1,15/deel met 1,15 ≈ R162,26 VAT/BTW = R186,60 – R162,26 MA 1MA subtract/aftrek VAT/BTW = R24,34 OR/OF OR/OF 100 1MA multiply with 100/115 / TOTAL = R186,60 × MA 115 vermenigvuldig met 100/115 = R162,2608696 ≈ R162,26 VAT/BTW = R186,60 – R162,26 MA 1MA subtract/aftrek VAT/BTW = R24,34 (2) 1.1.5 Paid with cash/Met kontant betaal 2A answer/antwoord F A (2) L1 1.1.6 One hundred eighty-six rand and sixty F cents/Eenhonderd ses en tagtig rand en L1 sestig sent A 2A answer in words/antwoord in woorde (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 4 NW/November 2024 Grade 11 – Marking Guidelines/Nasienriglyne 1.2.1 Pie chart/ 2A answer type of graph/antwoord tipe D Sirkelgrafiekof sektorgrafiek A grafiek L1 (2) 1.2.2 Romance D = 100 – 28 – 20 – 14 – 12 – 8 MA 1MA subtract correct values/aftrek van L1 = 100 – 82 korrekte waardes = 18% A 1A answer % romance/antwoord % romanties (2) 1.2.3 Most watched = Comedy A 2A answer/antwoord D (2) L1 1.2.4 P (true-life story) P = 0% OR 0,0 OR Impossible L1 W (ware lewensverhaal) = 0% OF 0,0 OF Onmoontlik A 2A answer/antwoord (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 5 NW/November 2024 Grade 11 – Marking Guidelines/Nasienriglyne QUESTION 2/VRAAG 2 [31 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T/L 2.1.1 Litres petrol per month/Liter petrol per F maand 1MA divide with R23,25 per ℓ/deel met L1 = R4 500 ÷ R23,25/ℓ MA R23,25 per ℓ = 193,5483871 litres 1A answer litre petrol/Antwoord liter ≈ 193,55 litres A brandstof (2) 2.1.2 Total groceries per month/Totale 1MA multiply with 4 F kruideniersware per month weeks/vermenigvuldig met 4 weke L1 = R1 150 × 4 weeks MA 1A answer total groceries/antwoord = R4 600 A totale kruideniersware (2) 2.1.3 Total expenses/Totale uitgawes CA from QUESTION 2.1.2 F = R8 400 + R8 200 + R2 100 + L3 R4 600 + R4 500 + R2 000 + R4 850 + 1M adding all expenses/optel van alle R1 850 M uitgawes = R36 500 CA 1CA answer total expenses/antwoord totale uitgawes Amount left over to safe/ Bedrag oor om te spaar = Income – Expenses = R47 000 – R 36 500 M 1M subtract expenses/trek uitgawes af = R10 500 CA 1CA answer savings/Antwoord spaargeld (4) 2.1.4 % increase = 2024 − 2023 1SF correct values in fraction/korrekte F × 100 2023 waardes in breuk L2 𝑅5 000−𝑅4 465 1M multiply with 100/vermenigvuldig = SF × 100 M 𝑅4 465 met 100 = 11,98200828667% 1RA answer rounded to whole ≈ 12% RA number/antwoord afgerond tot heelgetel (3) 2.1.5 Other source of income: F Earning interest of investment/ Verdien L4 rente met belegging O 2O explanation/verduideliking OR/OF Mr. Smith can word overtime to earn more money/Mnr. Smith kan oortyd werk om eer geld te verdien O OR/OF Mrs. Smith can teach extra classes for extra income/Mev. Smith kan estra klasse aanbied vir ekstra inkomste O Any relevant answer (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 6 NW/November 2024 Grade 11 – Marking Guidelines/Nasienriglyne 2.2.1 R24 999 in words: F Twenty-four thousand, nine hundred L1 and ninety-nine rand/ Vier-en-twintig duisend, 2A correct value in words/korrekte negehonderderd nege-en-negintig rand waarde in woorde A (2) 2.2.2 Ratio nights at Sudwala to Sabie River 1MA correct ratio order/korrekte F 2 : 4 MA verhouding orde L2 1 : 2 CA 1CA simplified ratio/vereenvoudigde verhouding (2) 2.2.3 ONE other expanse/ander uitgawe: F  Lunch meals that are not included in L4 the package/Middagetes wat nie ingesluit in die packet nie O 2O ONE other expense/EEN ander  Other forms of travel in the park uitgawe then road/Ander vorme van Vervoer as padvervoer  Other activities/Ander aktiwiteite Name any ONE other expanse/Noem EEN ander uitgawe (2) 2.2.4 Deposits/Deponeer 1M multiply with 12 months/ F = R5 500 × 12 months/maande M vermenigvuldig met 12 maande L5 = R66 000 A 1A answer deposits/antwoord deponeer Interest earn/Rente verdien = R5 500 × 7% 1A answer interest earn per month/ = R385 A antwoord rente verdien per maand = R385 × 12 months/maande 1A answer total interest for the year/ = R4 620 A antwoord totale rente vir die jaar Total after a year/Totaal na ‘n jaar = R66 000 + R4 620 = R70 620 CA 1CA total after a year/totale na ‘n jaar OR/OF OR/OF Interest earn/Rente verdien = R5 500 × 7% 1A answer interest earn per month/ = R385 A antwoord rente verdien per maand Total per month/Totaal per maand 1M adding deposit plus interest/bytel van = R5 500 + R385 M deposito by rente = R5 885 A 1A answer total per month/antwoord totaal per maand Total after a year/Totaal na ‘n jaar 1M multiply with 12 months/ = R5 885 × 12 months/maande M vermenigvuldig met 12 maande = R70 620 CA 1CA total after a year/totaal na ‘n jaar (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 7 NW/November 2024 Grade 11 – Marking Guidelines/Nasienriglyne 2.2.5 Investment 6 months/maande CA from QUESTION 2.2.4/CA vanaf F 0,092 VRAAG 2.2.4 L3 = R30 000 × MA 2 1MA multiply with correct interest rate = R1 380 A per half year/vermenigvuldig met = R30 000 + R1 380 korrekte rentekoers halfjaarliks = R31 380 A 1A answer interest 6 months/antwoord rente 6 maande Investment 12 months/maande 1A answer balance after 6 months/ 0,092 antwoord saldo na 6 maande = R31 380 × 2 = R1 443,48 = R31 380 + R1 443,48 1A answer balance after 12 months/ = R32 823,48 A antwoord saldo na 12 maande Total of both investments/Totaal vir beide beleggings = R70 620 + R32 823,48 1CA answer total of both investments/ = R103 443,48 CA antwoord total beleggings Travel cost for 4 people/Reiskoste vir 4 mense = R24 999 × 4 OR/ R103 443,48 ÷ 4 1A answer cost for 4 people/antwoord = R99 996 OF = R25 860,87 A koste vir 4 mense ⸫ Her claim is correct, because the travel cost will be R99 996 and the investments will be R103 443,48, thus they will have enough money for the vacation by R3 447,48./ Haar bewering is korrek, want die reiskoste beloop R99 996 en die beleggings sal R103 443,48 wees, dus sal hulle genoeg geld het vir die vakansie met R3 447,48. O 1O conclusion/gevolgtrekking (7) [31] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 8 NW/November 2024 Grade 11 – Marking Guidelines/Nasienriglyne QUESTION 3/VRAAG 3 [28 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T/L 3.1.1 4th fastest/4de vinnigste D = Henricho Bruintjies RT 2RT read from table/aflees van tabel L1 (2) 3.1.2 Arrange/Rangskik D 1) 14 May 1986 L2 2) 03 April 1992 3) 15 July 1992 4) 16 July 1993 5) 21 September 1993 RT 1RT correct dates/korrekte datums 6) 26 September 1995 A 1A correct descending order/korrekte 7) 12 May 1998 dalende orde 8) 27 February 2000 9) 01 February 2001 10) 19 December 2003 (2) 3.1.3 Modal place of birth/Modale plek van D geboorte 2A answer modal place of birth/antwoord L1 = Pretoria A modale geboorte plek (2) 3.1.4 Average (mean) / Gemiddeld D = Sumtotal ÷ amount of numbers L3 09,919 = 09,82+09,86+09,87+09,89+09,93 +09,94+09,94+ 𝑨 +09,98+10,01 1SF substitute formula/vervang formule SF 10 89,24 + 𝑨 09,919 = S 1S simplification/vereenvoudiging 10 09,919 × 10 = 89,24 + A 1MA changing the subject of the 99,19 = 89,24 + A formula/verander die onderwerp 99,19 – 89,24 = A MA van die formule 09,95 seconds = A A 1A answer A/Antwoord A (4) 3.1.5 Range = biggest – smallest/ D Omvang =grootste – kleinste L2 MA 1RT correct values/korrekte waardes Range = 10,01 sec – 09,82 sec RT 1MA subtract values/trek waardes af Range = 0,19 seconds CA 1CA answer range/antwoord omvang (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 9 NW/November 2024 Grade 11 – Marking Guidelines/Nasienriglyne 3.2.1 Gauteng medals in total/medalje in 1M adding three values/tel drie waardes D totaal bymeakaar L1 = 17 + 23 + 29 M 1CA answer total medals USA/Antwoord = 69 CA totale medaljes (2) 3.2.2 Difference/Verskil NW – Free State 1RT correct values/korrekte waardes D = 18 – 9 RT M 1M subtract values/waardes aftrek L2 = 9 CA 1CA answer difference/antwoord verskil (3) 3.2.3 Western Cape % bronze medals/ D Wes-Kaap % brons medaljes 1MA correct fraction values/korrekte L2 25 waardes in breuk = MA × 100 M 25+18+20 1M multiply with 100/vermenigvuldig 25 met 100 = 63 = 39,68253968% = 39,68% CA 1CA answer %/antwoord % (3) 3.2.4 P (provinces more than 20 gold)/ P W (provinsies meer as 20 goud) 1A numerator/noemer L2 2 A 1A denominator/teller = 1RCA answer decimal number – rounded 9 A = 0,222222222 to two decimal places/antwoord = 0,22 RCA desimale getal – afgerond tot twee desimale plekke (3) 3.2.5 Limpopo total 2024 = 6 + 6 + 4 D Limpopo total 2024 = 16 L4 % growth/% groei 𝑛𝑒𝑤−𝑜𝑙𝑑 𝑛𝑢𝑤𝑒−𝑜𝑢 = × 100 / × 100 1MA correct values/korrekte waardes 𝑜𝑙𝑑 𝑜𝑢 16−8 1M multiply with 100/vermenigvuldig = MA × 100 M met 100 8 = 100% A 1A answer % increase/antwoord % gestyg ⸫ The claim is valid/Die bewering is geldig O 1O conclusion/gevolgtrekking OR/OF OR/OF Total medals 2024 = 6 + 6 + 4 = 16 A 1A total medals 2024/totale medaljes 8 × 50% = 4 M 2024 8 + 4 = 12 A 1M multiplied with 50%/vermenigvuldig 16 is more than 12 (50% growth) met 50% 1A answer added value/answer ⸫ The claim is valid/Die bewering is vermeerderde waarde geldig O 1O conclusion/gevolgtrekking (4) [28] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

QUESTION 4/VRAAG 4 [21 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T/L 4.1.1 Opening balance – 1st day amounts/ F Openingsaldo – 1ste dag bedrae 1M subtract debit amounts/aftrek debiet L2 = R42 952,19 – R2 100 – R8 800 M bedrae – R6,00 – R6,00 M 1M subtract transactions costs/aftrek = R42 952,19 – R10 912 transaksiekoste = R32 040,19 A 1A answer balance/antwoord saldo (3) 4.1.2 Transaction cost/Transaksiekoste CA from QUESTION 4.1.1/CA vanaf F = 1,15% × R1 150 MA VRAAG 4.1.1 L3 = R13,225 1MA multiplying correct values (1,15% ≈ R13,23 A and R1 150)/vermenigvuldig korrekte waardes (1,15% en Balance – 2nd day amounts/ R1 150) Saldo – 2de dag bedrae 1A answer transaction cost/Antwoord = R32 040,19 – R1 150 – R13,23 M transaksiekoste = R32 040,19 – R1 163,23 1M subtracting 2nd day amounts/trek 2de = R30 876,96 CA dag bedrae af 1CA answer balance/Antwoord saldo [Accept: R30 876,97 if rounded only at the end] (4) 4.2.1 P (loan factor more than 19,00)/ P W (leningsfaktor meer as 19,00) L2 3 A 1A numerator/noemer = 1M denominator/teller 7 A 1R answer % - rounded to whole number/ = 42,85714285% antwoord % - afgerond tot heelgetal ≈ 43% R (3) 4.2.2 Loan amount = selling price – deposit/ F Leningsbedrag = Verkoopprys – L2 deposito 1M subtracting deposit/trek deposito af = R198 000 – R29 700 M 1A answer loan amount/antwoord = R168 300 A leningsbedrag (2) 4.2.3 Monthly payment CA from QUESTION 4.2.2/CA vanaf F = loan amount ÷ 1 000 × loan factor VRAAG 4.2.2 L3 = R168 300 ÷ 1 000 × 25,60  = R4 308,48  1SF substitute formula/vervang formule 1A answer monthly payment/antwoord Total monthly payment maandelikse paaiement = R4 308,48 + R65,00 admin = R4 373,48 CA 1CA answer total monthly payment/ antwoord totale maandelikse paaiement (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 11 NW/November 2024 Grade 11 – Marking Guidelines/Nasienriglyne 4.2.4 Total repayment/Totale terugbetaling CA from QUESTION 4.2.3/CA vanaf F = Deposit + monthly payments VRAAG 4.2.3 L4 = R29 700 + (R4 373,48 × 48 MA) 1MA multiply months with repayment/ = R29 700 + R209 927,04 M vermenigvuldig maande met = R239 627,04 CA terugbetaling 1M adding deposit/bytel van deposito Interest/Rente 1CA answer total repayment/antwoord = total repayment – selling price totale terugbetelaing = R239 627,04 – R198 000 M 1M subtract selling price/aftrek = R41 627,04 CA verkoopsprys 1CA answer interest amount/antwoord ⸫ His statement is correct, his interest per maand will be more than R40 000/Sy stelling is korrek, sy rente sal meer as R40 00 wees O 1O conclusion/gevolgtrekking (6) [21] TOTAL/TOTAAL: 100 Copyright reserved/Kopiereg voorbehou