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DEPARTMENT OF EDUCATION
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DEPARTEMENT VAN ONDERWYS
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LEFAPHA LA THUTO
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ISEBE LEZEMFUNDO
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PROVINSIALE VOORBEREIDENDE EKSAMEN/
PROVINCIAL PREPARATORY EXAMINATION
GRAAD/GRADE 12
FISIESE WETENSKAPPE/PHYSICAL SCIENCES
VRAESTEL/PAPER 2
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SEPTEMBER 2024
PUNTE/MARKS: 150
TYD/TIME: 3 uur/hours
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Physical Sciences Grade 12 P2 Northern Cape Prelim 2024 Memo
Grade 12 Physical Sciences Paper 2 memorandum from the Northern Cape Prelim Exam 2024, 33 pages. Read online or download the free PDF.
Physical Sciences · Grade 12 · Northern Cape Prelim Exam · 2024. Memorandum, 33 pages. Read online or download the PDF.
- Subject
- Physical Sciences
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2024
- Exam period
- Northern Cape Prelim Exam
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 33
- File size
- 586.3 KB
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INSTRUCTIONS AND INFORMATION
1. Write your name on the ANSWER BOOK.
2. This question paper consists of NINE questions. Answer ALL the questions in
the ANSWER BOOK.
3. Start EACH question on a NEW page in the ANSWER BOOK.
4. Number the answers correctly according to the numbering system used in this
question paper.
5. Leave ONE line between two subquestions, e.g. between QUESTION 2.1 and
QUESTION 2.2.
6. You may use a non-programmable calculator.
7. You may use appropriate mathematical instruments.
8. Show ALL formulae and substitutions in ALL calculations.
9. Round off your FINAL numerical answers to a minimum of TWO decimal
places.
10. Give brief motivations, discussions, etc. where required.
11. You are advised to use the attached DATA SHEETS.
12. Write neatly and legibly.
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QUESTION 1: MULTIPLE-CHOICE QUESTIONS
Various options are provided as possible answers to the following questions. Each
question has only ONE correct answer. Choose the answer and write only the letter
(A–D) next to the question numbers (1.1 to 1.10) in the ANSWER BOOK, e.g. 1.11 E.
1.1 Which ONE of the following compounds is a ketone?
A CH3COCH2CH3
B CH3COOCH2CH3
C CH3CH2CH2CHO
D CH3CH(OH)CH2CH3 (2)
1.2 Consider the flow diagram below that represents an organic reaction:
Compound X HBr 2-bromo-3-methylbutane
The IUPAC name of compound X is:
A 2-methylbutane
B 3-methylbutane
C 2-methylbut-3-ene
D 3-methylbut-2-ene (2)
1.3 Which ONE of the following pairs of reactants can be used to prepare ethyl
propanoate in the laboratory?
A Ethane and propanoic acid
B Propanol and ethanoic acid
C Ethanol and propanoic acid
D Ethene and propanol (2)
1.4 Which ONE of the following compounds will enable butan-2-ol to undergo an
elimination reaction?
A Concentrated HCℓ
B Concentrated H2SO4
C Diluted HNO3
D Diluted NaOH (2)
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1.5 When zinc (II) carbonate reacts with excess hydrochloric acid, carbon dioxide
is produced.
The graphs below were obtained under two different reaction conditions.
Volume of CO2 (cm3)
R
S
Time (s)
The change in the graph from S to R could be brought about by …
A decreasing the concentration of the acid.
B increasing the mass of the zinc (II) carbonate.
C decreasing the particle size of the zinc (II) carbonate.
D adding a catalyst. (2)
1.6 The reaction represented by the balanced equation below reaches equilibrium
in a closed container.
H2(g) + I2(g) ⇌ 2HI(g) ∆H < 0
How will the equilibrium be affected if the volume of the container is increased
at constant temperature and then the temperature is increased at constant
volume?
EFFECT OF INCREASE EFFECT OF INCREASE IN
IN VOLUME TEMPERATURE
Reverse reaction
A No effect
is favoured
Reverse reaction Reverse reaction
B
is favoured is favoured
Forward reaction
C No effect
is favoured
Reverse reaction Forward reaction
D
is favoured is favoured (2)
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1.7 Nitric acid is titrated with an ammonium hydroxide solution.
The EQUIVALENCE POINT is the point in the titration where …
A the concentration of the indicator changes.
B nacid = nbase.
C [H3O+] = [OH−].
D the pH = 7. (2)
1.8 Consider the equation:
H2O + A → OH- + H2SO4
The reactant A represents a/an:
A base having the formula HSO4-
B acid having the formula HSO4-
C base having the formula SO42-
D acid having the formula SO42- (2)
1.9 Consider the following chemical reactions:
REACTION X: Pb(s) → Pb2+(aq) + 2e-
REACTION Y: 4H+(aq) + O2(g) + 4e- → 2H2O(ℓ)
Which ONE of the following combinations is CORRECT for reaction X and Y?
REACTION X REACTION Y
A Pb is reduced O2 is oxidised
B Pb is oxidised H+ is reduced
C Pb is oxidised O2 is reduced
D Pb is reduced H+ is oxidised (2)
1.10 Which ONE of the following CORRECTLY shows the gases produced at the
different electrodes during the electrolysis of a concentrated solution of
sodium chloride?
CATHODE ANODE
A Hydrogen gas Chlorine gas
B Chlorine gas Water vapour
C Oxygen gas Chlorine gas
D Chlorine gas Hydrogen gas (2)
[20]
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QUESTION 2 (Start on a new page.)
The letters A to F in the table below represent six organic compounds.
A CH3CH2COOCH3 D CH3CHCHCH2CH3
H
H C H
H H O H O
H C C C C C H
B E H C CH2 CH3
H H H
H C H
H C H
H
C 2-fluoro-3,4-dimethylhexane F Butanoic acid
Write down the:
2.1 LETTER of the compound that belongs to the halo-alkanes (1)
2.2 STRUCTURAL FORMULA of the functional group of compound F (1)
2.3 LETTER of the compound that represents an unsaturated hydrocarbon (1)
2.4 NAME of the functional group of compound E (1)
2.5 NAME of the inorganic acid needed to prepare compound A (1)
2.6 LETTER of the compound that represents an aldehyde (1)
2.7 Empirical formula of compound A (1)
2.8 STRUCTURAL FORMULA of compound C (3)
2.9 IUPAC NAME of compound B (2)
2.10 LETTERS of the compounds that are FUNCTIONAL isomers of each other (1)
[13]
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QUESTION 3 (Start on a new page.)
An investigation was carried out to determine the relationship between the boiling point of
different alkanes and one of their structural isomers.
The results obtained are shown in the table below:
BOILING BOILING
NAME ISOMER
POINT (°C) POINT (°C)
A ethane -88,5
B butane -1 E methyl propane -12
C pentane 34 F 2-methylbutane 28
D hexane 68,7 G 2,3-dimethylbutane 58
3.1 Define the term structural isomer. (2)
3.2 What TYPE of isomerism is used during this investigation? (1)
3.3 Explain the difference in boiling points between butane and its isomer methyl
propane. (3)
3.4 Consider compounds A to D.
For this part of the investigation, write down the:
3.4.1 Control variable (1)
3.4.2 Independent variable (1)
3.4.3 Which ONE of compounds A to D has the highest vapour pressure?
Explain the answer by referring to the intermolecular forces and the
energy. (3)
3.5 Write down a conclusion for this investigation. (2)
3.6 Use molecular formulae to write down a balanced chemical equation for the
combustion of pentane. (3)
[16]
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QUESTION 4 (Start on a new page.)
Study the flow diagram of various organic reactions and answer the questions that follow.
Reaction I
Compound A Butene Propane
+
Reaction II H2(g)
Compound B
Reaction III
2-chlorobutane
Reaction V
Reaction IV
Compound C 2-butanol
4.1 For reaction I, write down the:
4.1.1 TYPE of the reaction (1)
4.1.2 IUPAC NAME of compound A (2)
4.2 Consider reaction II and write down the:
4.2.1 TYPE of the reaction (1)
4.2.2 IUPAC NAME of organic compound B (1)
4.2.3 NAME of a suitable catalyst (1)
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4.3 Write down the TYPE of reaction represented by reaction III. (1)
4.4 Reaction IV is an elimination reaction. Write down the:
4.4.1 TYPE of elimination reaction (1)
4.4.2 Reaction conditions (2)
4.4.3 Balanced chemical equation for the formation of compound C, using
STRUCTURAL FORMULAE (5)
4.5 Consider reaction V. Write down the:
4.5.1 NAME or FORMULA of the inorganic reactant needed (1)
4.5.2 Type of alcohol represented by 2-butanol
Choose from PRIMARY, SECONDARY or TERTIARY.
Give a reason for the answer. (2)
[18]
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QUESTION 5 (Start on a new page.)
The reaction of magnesium (Mg) and EXCESS diluted hydrochloric acid (HCℓ) is used to
investigate some factors affecting the reaction rate. The balanced equation for the reaction
is:
Mg(s) + 2HCℓ(ℓ) → MgCℓ2(aq) + H2(g)
The table below summarises the reaction conditions.
EXPERIMENT STATE of Mg MASS of Mg TEMPERATURE (°C)
1 ribbon x 25
2 powder x 25
3 powder ½x 20
5.1 Define the term reaction rate. (2)
5.2 Which experiment will have the highest reaction rate?
Choose from EXPERIMENT 1, EXPERIMENT 2 or EXPERIMENT 3. (1)
5.3 Use the collision theory to explain the answer to QUESTION 5.2. (2)
5.4 Besides temperature, write down ONE other way to increase the reaction rate
in EXPERIMENT 2. (1)
The mass of gas produced in EXPERIMENT 2 is obtained by measuring the loss in mass
of the flask and its contents at one-second intervals.
Z
Hydrochloric acid
solution Gas bubbles
Magnesium powder
Balance
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The results of this experiment is displayed in the graph below.
Mass of H2 (g)
3,5
2,8
1 2 3 4 5 6 Time (s)
5.5 Write down the name of apparatus Z. (1)
5.6 Give a reason why this experimental setup cannot be classified as a closed
system. (1)
5.7 Calculate the AVERAGE RATE (in g·s-1) of this reaction during the first four
seconds. (2)
5.8 Write down the loss in mass of the flask and its contents. (1)
5.9 Use the graph to calculate the mass of magnesium powder (x) used in
EXPERIMENT 2. (5)
5.10 Why is the magnesium in EXPERIMENT 2 the limiting reagent? (1)
5.11 Redraw the graph given in your ANSWER BOOK and name it Graph 2.
On the same set of axes, draw the graph for EXPERIMENT 3 and label this
Graph 3. (2)
[19]
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QUESTION 6 (Start on a new page.)
The table below shows the effect of temperature changes on the value of the equilibrium
constant (Kc) when the following reaction takes place in a closed container of volume
500 cm3.
2NO2(g) ⇌ N2O4(g)
(brown gas) (colourless gas)
TEMPERATURE (K) Equilibrium constant (Kc)
300 1 x101
400 3 x 10-2
500 1 x 10-3
600 1 x 10-4
700 8,33 x 10-5
6.1 Define the term chemical equilibrium. (2)
6.2 Which colour will be seen at 300 K?
Choose from BROWN, COLOURLESS or LIGHT BROWN. (1)
6.3 Is the forward reaction exothermic or endothermic?
Explain the answer. (3)
6.4 X g of NO2 is sealed in the container at 300 K.
At equilibrium, the concentration of N2O4 was 3 mol∙dm3.
Calculate X. (8)
6.5 How will an increase in the reactant (NO2) at 700 K effect the rate of the reverse
reaction?
Choose from INCREASES, DECREASES or STAYS THE SAME. (1)
6.6 The pressure on the system is increased by decreasing the volume of the
container at 300 K.
How will this change affect the:
6.6.1 Value of KC?
Choose from INCREASES, DECREASES or REMAINS THE SAME.
Give a reason for the answer. (2)
6.6.2 Concentration of the products?
Choose from INCREASES, DECREASES or REMAINS THE SAME.
Explain the answer using Le Chatelier's principle. (3)
[20]
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QUESTION 7 (Start on a new page.)
7.1 Hydrofluoric acid (HF) is a weak acid..
7.1.1 Define the term weak acid. (2)
7.1.2 A sample of hydrofluoric acid has a pH of 4,5 at 25 °C.
Calculate the concentration of the hydronium ions (H3O+(aq)) in the
sample. (3)
When hydrofluoric acid reacts with sodium hydroxide, sodium fluoride is formed.
7.1.3 Will the pH of the sodium fluoride solution be GREATER THAN 7,
SMALLER THAN 7 or EQUAL TO 7?
Give a reason for the answer. (2)
7.2 In REACTION A, 3,5 g of pure MgCO3(s) reacted completely in 50 cm3 of HCℓ.
The balanced equation for the reaction is given below:
REACTION A: MgCO3 + 2HCℓ → MgCℓ2 + CO2 + H2O
The EXCESS HCℓ neutralises exactly 20 cm3 of a NaOH solution with a
concentration of 1,2 mol∙dm-3 in REACTION B.
REACTION B: HCℓ + NaOH → NaCℓ + H2O
7.2.1 Calculate the number of moles of HCℓ reacted in REACTION A. (3)
7.2.2 Calculate the concentration of the original solution of HCℓ. (6)
[16]
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QUESTION 8 (Start on a new page.)
The diagram below represents a galvanic cell functioning under standard conditions with
magnesium and iron as electrodes. The nett cell equation for this cell is:
2Fe3+(aq) + 3Mg(s) → 2Fe(s) + 3Mg2+(aq)
V
Mg Fe
Mg2+(aq) Fe3+(aq)
KCℓ
8.1 For this cell, write down:
8.1.1 The energy conversion that takes place (1)
8.1.2 TWO standard conditions (2)
8.1.3 The electrode which acts as the CATHODE
Give a reason for the answer. (2)
8.1.4 The oxidation half-reaction (2)
8.1.5 The cell notation (3)
8.1.6 The NAME of the component responsible for electrical neutrality of the
half cells (1)
8.2 Calculate the initial EMF of the cell. (4)
[15]
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QUESTION 9 (Start on a new page.)
In the electrolytic cell represented below, two CARBON RODS, P and Q, are used as
electrodes and concentrated copper (II) chloride solution is used as electrolyte.
P Q
CuCℓ2(aq)
9.1 Define the term electrolysis. (2)
9.2 What observation can be made at electrode P while the cell is operating? (1)
9.3 Write down the half-reaction that takes place at electrode Q. (2)
9.4 Write down the NAME or FORMULA of the reducing agent in this reaction. (1)
9.5 What is the function of CuCℓ2(aq) as electrolyte in this cell? (1)
This cell is now used for the refining of copper.
9.6 Which electrode (P or Q) will have to be replaced with pure copper during the
refining process?
Give a reason for the answer. (2)
9.7 Explain why the concentration of the ions in the solution remains constant. (1)
9.8 Silver and platinum are formed at the bottom of the container during the refining
process of impure copper.
Refer to the relative strength of the reducing agents to explain why these two
metals do not form ions. (3)
[13]
TOTAL: 150
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DATA FOR PHYSICAL SCIENCES GRADE 12
PAPER 2 (CHEMISTRY)
GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12
VRAESTEL 2 (CHEMIE)
TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES
NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE
Standard pressure
Standaarddruk
p 1,013 x 105 Pa
Molar gas volume at STP
Vm 22,4 dm3∙mol-1
Molêre gasvolume by STD
Standard temperature
T 273 K
Standaardtemperatuur
Charge on electron
e -1,6 x 10-19 C
Lading op elektron
Avogadro's constant
NA 6,02 x 1023 mol-1
Avogadro-konstante
TABLE 2: FORMULAE/TABEL 2: FORMULES
m N
n n
M NA
n m V
c or/of c n
V MV Vm
c a v a na
pH = -log[H3O+]
cbvb nb
Kw = [H3O+][OH-] = 1 x 10-14 at/by 298 K
Eθcell Eθcathode Eθanode / Eθsel Ekatode
θ
Eθanode
or/of
Eθcell Ereduction
θ
Eθoxidation / Eθsel Ereduksie
θ
Eθoksidasie
or/of
Eθcell Eθoxidisingagent Ereducing
θ θ θ θ
agent / Esel Eoksideermiddel Ereduseermiddel
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TABLE 3: THE PERIODIC TABLE OF ELEMENTS
TABEL 3: DIE PERIODIEKE TABEL VAN ELEMENTE
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
(I) (II) (III) (IV) (V) (VI) (VII) (VIII)
Atomic number
1 KEY/SLEUTEL Atoomgetal 2
2,1 H He
1 29 4
3 4 Electronegativity Symbol 5 6 7 8 9 10
1,0 1,5 1,9 Cu 2,0 2,5 3,0 3,5 4,0
Li Be Elektronegatiwiteit
63,5
Simbool B C N O F Ne
7 9 11 12 14 16 19 20
11 12 13 14 15 16 17 18
0,9 Na 1,2 Mg Approximate relative atomic mass 1,5 Aℓ 1,8 Si 2,1 P 2,5 S 3,0 Cℓ Ar
23 24 Benaderde relatiewe atoommassa 27 28 31 32 35,5 40
19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36
0,8 K 1,0 Ca 1,3 Sc 1,5 Ti 1,6 V 1,6 Cr 1,5 Mn 1,8 Fe 1,8 Co 1,8 Ni 1,9 Cu 1,6 Zn 1,6 Ga 1,8 Ge 2,0 As 2,4 Se 2,8 Br Kr
39 40 45 48 51 52 55 56 59 59 63,5 65 70 73 75 79 80 84
37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54
0,8 Rb 1,0 Sr 1,2 Y 1,4 Zr Nb 1,8 Mo 1,9 Tc 2,2 Ru 2,2 Rh 2,2 Pd 1,9 Ag 1,7 Cd 1,7 In 1,8 Sn 1,9 Sb 2,1 Te 2,5 I Xe
86 88 89 91 92 96 101 103 106 108 112 115 119 122 128 127 131
55 56 57 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86
0,7 Cs 0,9 Ba La 1,6 Hf Ta W Re Os Ir Pt Au Hg 1,8 Tℓ 1,8 Pb 1,9 Bi 2,0 Po 2,5 At Rn
133 137 139 179 181 184 186 190 192 195 197 201 204 207 209
87 88 89
0,7 Fr 0,9 Ra Ac 58 59 60 61 62 63 64 65 66 67 68 69 70 71
226
Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu
140 141 144 150 152 157 159 163 165 167 169 173 175
90 91 92 93 94 95 96 97 98 99 100 101 102 103
Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr
232 238
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TABLE 4A: STANDARD REDUCTION POTENTIALS
TABEL 4A: STANDAARD-REDUKSIEPOTENSIALE
Half-reactions/Halfreaksies E (V)
F2(g) + 2e ⇌ 2F + 2,87
Co3+ + e ⇌ Co2+ + 1,81
H2O2 + 2H+ +2e ⇌ 2H2O +1,77
MnO 4 + 8H+ + 5e ⇌ Mn2+ + 4H2O + 1,51
Cℓ2(g) + 2e ⇌ 2Cℓ
+ 1,36
2
Cr2O 7 +
+ 14H + 6e ⇌ 2Cr3+ + 7H2O + 1,33
Increasing strength of oxidising agents/Toenemende sterkte van oksideermiddels Increasing strength of reducing agents/Toenemende sterkte van reduseermiddels
O2(g) + 4H+ + 4e ⇌ 2H2O + 1,23
MnO2 + 4H+ + 2e ⇌ Mn2+ + 2H2O + 1,23
Pt2+ + 2e ⇌ Pt + 1,20
Br2(ℓ) + 2e ⇌ 2Br + 1,07
NO 3 + 4H+ + 3e
⇌ NO(g) + 2H2O + 0,96
Hg2+ + 2e ⇌ Hg(ℓ) + 0,85
Ag+ + e ⇌ Ag + 0,80
NO 3 + 2H+ + e
⇌ NO2(g) + H2O + 0,80
Fe3+ + e ⇌ Fe2+ + 0,77
O2(g) + 2H+ + 2e ⇌ H2O2 + 0,68
I2 + 2e ⇌ 2I + 0,54
Cu+ + e ⇌ Cu + 0,52
SO2 + 4H+ + 4e ⇌ S + 2H2O + 0,45
2H2O + O2 + 4e ⇌ 4OH + 0,40
Cu2+ + 2e ⇌ Cu + 0,34
2
SO 4 + 4H+ + 2e ⇌ SO2(g) + 2H2O + 0,17
Cu2+ + e ⇌ Cu+ + 0,16
Sn4+ + 2e ⇌ Sn2+ + 0,15
S + 2H+ + 2e ⇌ H2S(g) + 0,14
2H+ + 2e ⇌ H2(g) 0,00
Fe3+ + 3e ⇌ Fe 0,06
Pb2+ + 2e ⇌ Pb 0,13
Sn2+ + 2e ⇌ Sn 0,14
Ni2+ + 2e ⇌ Ni 0,27
Co2+ + 2e ⇌ Co 0,28
Cd2+ + 2e ⇌ Cd 0,40
Cr3+ + e ⇌ Cr2+ 0,41
Fe2+ + 2e ⇌ Fe 0,44
Cr3+ + 3e ⇌ Cr 0,74
Zn2+ + 2e ⇌ Zn 0,76
2H2O + 2e ⇌ H2(g) + 2OH 0,83
Cr2+ + 2e ⇌ Cr 0,91
Mn2+ + 2e ⇌ Mn 1,18
Aℓ3+ + 3e ⇌ Aℓ 1,66
Mg2+ + 2e ⇌ Mg 2,36
Na+ + e ⇌ Na 2,71
Ca2+ + 2e ⇌ Ca 2,87
Sr2+ + 2e ⇌ Sr 2,89
Ba2+ + 2e ⇌ Ba 2,90
Cs+ + e- ⇌ Cs 2,92
K+ + e ⇌ K 2,93
Li+ + e ⇌ Li 3,05
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TABLE 4B: STANDARD REDUCTION POTENTIALS
TABEL 4B: STANDAARD-REDUKSIEPOTENSIALE
Half-reactions/Halfreaksies E (V)
Li+ + e ⇌ Li 3,05
K+ + e ⇌ K 2,93
Cs+ + e- ⇌ Cs 2,92
Ba2+ + 2e ⇌ Ba 2,90
Sr2+ + 2e ⇌ Sr 2,89
Ca2+ + 2e ⇌ Ca 2,87
Na+ + e ⇌ Na 2,71
Increasing strength of oxidising agents/Toenemende sterkte van oksideermiddels Increasing strength of reducing agents/Toenemende sterkte van reduseermiddels
Mg2+ + 2e ⇌ Mg 2,36
Aℓ3+ + 3e ⇌ Aℓ 1,66
Mn2+ + 2e ⇌ Mn 1,18
Cr2+ + 2e ⇌ Cr 0,91
2H2O + 2e ⇌ H2(g) + 2OH 0,83
Zn2+ + 2e ⇌ Zn 0,76
Cr3+ + 3e ⇌ Cr 0,74
Fe2+ + 2e ⇌ Fe 0,44
Cr3+ + e ⇌ Cr2+ 0,41
Cd2+ + 2e ⇌ Cd 0,40
Co2+ + 2e ⇌ Co 0,28
Ni2+ + 2e ⇌ Ni 0,27
Sn2+ + 2e ⇌ Sn 0,14
Pb2+ + 2e ⇌ Pb 0,13
Fe3+ + 3e ⇌ Fe 0,06
2H+ + 2e ⇌ H2(g) 0,00
S + 2H+ + 2e ⇌ H2S(g) + 0,14
Sn4+ + 2e ⇌ Sn2+ + 0,15
Cu2+ + e ⇌ Cu+ + 0,16
2
SO 4 + 4H+ + 2e ⇌ SO2(g) + 2H2O + 0,17
Cu2+ + 2e ⇌ Cu + 0,34
2H2O + O2 + 4e ⇌ 4OH + 0,40
SO2 + 4H+ + 4e ⇌ S + 2H2O + 0,45
Cu+ + e ⇌ Cu + 0,52
I2 + 2e ⇌ 2I + 0,54
O2(g) + 2H+ + 2e ⇌ H2O2 + 0,68
Fe3+ + e ⇌ Fe2+ + 0,77
NO 3 + 2H+ + e
⇌ NO2(g) + H2O + 0,80
Ag+ + e ⇌ Ag + 0,80
Hg2+ + 2e ⇌ Hg(ℓ) + 0,85
NO 3 + 4H+ + 3e
⇌ NO(g) + 2H2O + 0,96
Br2(ℓ) + 2e ⇌ 2Br + 1,07
Pt2+ + 2e ⇌ Pt + 1,20
MnO2 + 4H+ + 2e ⇌ Mn2+ + 2H2O + 1,23
O2(g) + 4H+ + 4e ⇌ 2H2O + 1,23
2
Cr2O 7 + 14H+ + 6e ⇌ 2Cr3+ + 7H2O + 1,33
Cℓ2(g) + 2e ⇌ 2Cℓ
+ 1,36
MnO 4 + 8H+ + 5e ⇌ Mn2+ + 4H2O + 1,51
H2O2 + 2H+ +2e ⇌ 2H2O +1,77
Co3+ + e ⇌ Co2+ + 1,81
F2(g) + 2e ⇌ 2F + 2,87
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—————————————————————
DEPARTMENT OF EDUCATION
—————————————————————
DEPARTEMENT VAN ONDERWYS
—————————————————————
LEFAPHA LA THUTO
—————————————————————
ISEBE LEZEMFUNDO
—————————————————————
PROVINCIAL PREPARATORY EXAMINATION/
PROVINSIALE VOORBEREIDENDE EKSAMEN
GRADE/GRAAD 12
PHYSICAL SCIENCES: CHEMISTRY
FISIESE WETENSKAPPE: CHEMIE
PAPER/VRAESTEL 2
SEPTEMBER 2024
MARKING GUIDELINES/NASIENRIGLYNE
MARKS/PUNTE: 150
These marking guidelines consist of 14 pages./
Hierdie nasienriglyne bestaan uit 14 bladsye.
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QUESTION 1/VRAAG 1
1.1 A (2)
1.2 D (2)
1.3 C (2)
1.4 B (2)
1.5 B (2)
1.6 A (2)
1.7 B (2)
1.8 A (2)
1.9 C (2)
1.10 A (2)
[20]
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QUESTION 2/VRAAG 2
2.1 C✓ (1)
2.2 O
‖ ✓
C O-H (1)
2.3 D✓ (1)
2.4 Formyl (group) ✓/Formiel (groep) (1)
2.5 (Concentrated) sulphuric acid ✓/(Gekonsentreerde) swawelsuur (1)
2.6 E✓ (1)
2.7 C2 H4 O ✓ (1)
2.8
Marking criteria/Nasienkriteria
H • Fluoro substituent ✓
Fluorosubstituent
H C H • 2 methyl substituents✓
2 metiel substituente
H H H H H
• Whole structure correct✓
Hele struktuur korrek
H C C C C C C H
IF/INDIEN: H-atom/bond omitted/
H F H H H H-atoom/binding uitgelaat. -1
H C H
H
(3)
2.9 4,4 – dimethyl hexan-2-one/4,4 – dimetielheksan-2-oon
4,4 – dimetiel-2-hexanone/4.4 – dimetiel-2-heksanoon
Marking criteria/Nasienkriteria
• Correct chain length, ie. hex ✓
Korrekte kettinglengte, bv. heks
• Everything else correct:
IUPAC name completely correct including numbering, sequence,
hyphens and comma. ✓
Alles verder korrek:
IUPAC name volledig korrek insluitend nomering, volgorde, koppeltekens
en kommas.
(2)
2.10 A and/en F✓ (1)
[13]
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QUESTION 3/VRAAG 3
3.1 Marking criteria/Nasienriglyn
If any of the underlined key words/phrases in the correct context is omitted
deduct 1 mark./Indien enige van die onderstreepte sleutelwoorde/frases in die
korrekte konteks uitgelaat is, trek 1 punt af.
Compounds with the same molecular formula, but different structural
formula.✓✓
Verbindings met dieselfde molekulȇre formule, maar verskillende struktuur
formules. (2)
3.2 Chain( isomerism) ✓/Ketting (isomerie) (1)
3.3 Marking Guidelines/Nasienriglyne
• Compare the structures/Vergelyk die strukture
• Compare strengths of IMF/Vergelyk die sterkte van IMK
• Compare energy needed to overcome/break IMF/Vergelyk die energie
nodig om kragte te oorkom/breek
• Butane (B) (is a straight chain molecule and thus) has a greater surface
area ✓ than methyl propane (E) / Betaan(B) is `n reguitketting molekule
met n groter kontakoppervlakte as metielpropaan(E).
• Butane thus has stronger intermolecular forces ✓ than methyl propane./
Butaan het dus sterker intermolekulëre kragte as metielpropaan.
• More energy is needed to overcome the IMF in butane/ Meer energie is
dus nodig om die IMK in butaan te oorkom
OR
• Methyl propane(E) has (a side chain and therefore) a smaller surface area
than butane (B) / Metielpropaan(E) het `n syketting en dus `n kleiner
kontakoppervlakte as butaan(B).
• Methyl propane has weaker intermolecular forces than butane /
Metielpropaan het swakker intermolekulëre kragte as butaan.
• Less energy is needed to overcome the intermolecular forces in methyl
propane/ Minder energie is nodig om die intermolekulëre kragte in
metielpropaan te oorkom.
(3)
3.4
3.4.1 Homologous series/homoloë reeks ✓
Functional group / funksionele groep (1)
3.4.2 Number of carbons / chain length✓/ surface area / molecular mass
Aantal koolstofatome / kettinglengte / kontak oppervlakte / molekulȇre massa (1)
3.4.3 A / ethane✓/etaan
It has (the lowest boiling point and thus) the weakest intermolecular force/
London forces✓ therefore the least energy is needed to overcome the forces.✓/
Dit het (die laagste kookpunt en het dus) die swakste intermolekulëre krag/
Londonkragte, wat die minste energie vereis om dit te oorkom. (3)
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3.5
Marking criteria/Nasienriglyne
• Dependent and independent variable identified
Afhanklike en onafhanklike veranderlikes korrek geïdentifiseer
• Correct relationship between dependant and independent variables
stated
Korrekte verwantskap tussen die afhanklike en onafhanklike gestel
1
IF/INDIEN: Directly proportional/Direk eweredig (Max/Maks 2 )
The longer the chain length the higher the boiling point. ✓✓/The greater the
surface area the higher the boiling point.
Hoe langer die koolstofketting hoe groter die kookpunt./Hoe groter die
oppervlakte area hoe groter die kookpunt.
Or / of
The shorter the chain length / more branched, the lower the boiling point / Less
surface area equals a lower boiling point.
Hoe korter die koolstofketting, meer vertak hoe laer die kookpunt / Kleiner
reaksie oppervlak lei tot laer kookpunt. (2)
3.6 C5H12 + 8O2 ✓→ 5CO2 + 6H2O ✓ (Bal)✓
Marking criteria/Nasienriglyne
Reactants✓
Products✓
Balancing✓ (3)
[16]
QUESTION 4/VRAAG 4
4.1
4.1.1 Cracking ✓/Kraking / Elimination/ Eliminasie (1)
4.1.2 Heptane ✓/Heptaan (2)
4.2
4.2.1 Addition/Hydrogenation✓
Addisie/Hidrogenasie (1)
4.2.2 Butane✓/Butaan (1)
4.2.3 Platinum /Pt ✓ or Palladium /Pd or Nickel /Ni (1)
4.3 Substitution✓/halogenation/chlorination
Substitusie/halogenering/chlorinering (1)
4.4
4.4.1 Dehydrohalogenation✓or dehydrochlorination/
Dehidrohalogenering of diehidrochlorinering (1)
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4.4.2 Concentrated strong base(NaOH etc), ✓heat ✓/ (2)
Gekonsentreerde sterk basis(NaOH, etc), hitte
4.4.3
H Cℓ H H
H C C C C H
✓ + NaOH ✓ → H2O + NaCℓ ✓ +
H H H H
H H H
H C C C C H
H H H
Note: Functional group carries a mark regardless the position/
Funksionelegroep kry `n punt ongeag die posisie (5)
4.5
4.5.1 H2O / water✓or dilute sodium hydroxide (NaOH / KOH / LiOH) / verdunde
(1)
4.5.2 Secondary ✓/Sekondȇr
The C-atom to which the hydroxyl group /OH-group is attached, is attached to
two other C-atoms. ✓
Die C-atoom waaraan die hidroksielgroep verbind is, is aan twee ander
C-atome verbind. (2)
[18]
QUESTION 5/VRAAG 5
5.1 NOTE/LET WEL
Give the mark for per unit time only if in context of reaction rate.
Gee die punt vir per eenheidtyd slegs indien in konteks met reaksietempo.
ANY ONE/ENIGE EEN
• Change in concentration of products/reactants per (unit) time.
Verandering in konsentrasie van produkte/reaktanse per (eenheid) tyd.
• Change in amount/number of moles/volume/mass of products or reactants
per (unit) time.
Verandering in hoeveelheid/getal mol/volume/massa van produkte of
reaktanse per (eenheid) tyd.
• Amount/number of moles/volume/mass of products formed/reactants used
per (unit) time.
Hoeveelheid/getal mol/volume/massa van produkte gevorm / reaktanse
gebruik per eenheids tyd.
• Rate of change in concentration/amount/number of moles/volume/mass.
Tempo van verandering in konsentrasie/hoeveelheid/getal mol/
volume/massa. (2 or/of 0) (2)
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5.2 Experiment 2✓ (1)
5.3 Larger surface area (state of division). ✓ More effective collisions per unit
time/ per second. ✓
Groter reaksie oppervlakte (toestand van verdeeldheid). Meer effektiewe
botsings per eenheidstyd en die reaksie tempo verhoog. (2)
5.4 Increase the concentration of HCℓ / verhoog die gekonsetrasie van HCℓ✓ or (1)
Catalyst / Katalisator
5.5 Conical flask / Erlenmeyer flask✓
Koniese fles / Erlenmeyerfles (1)
5.6 (Hydrogen) gas is escaping✓/ (Waterstofgas) ontsnap or
The flask is open / die fles is oop (1)
5.7 ∆m
rate/tempo =
Δt
3,5 - 0 ✓
=
4-0
= 0,875 (0,88) (g.s-1) (2)
5.8 3,5 g ✓ (1)
5.9 m
n(H2) =
M
3,5
=
2
= 1,75 mol
n(Mg) = n(H2) = 1,75 mol
m(Mg) = nM
= (1,75)(24)
= 42 g (5)
5.10 The hydrochloric acid was in excess /all the magnesium reacted.
Die soutsuur was in oormaat /al die magnesium het gereageer. (1)
5.11
Marking criteria/ Nasienkriteria
Graph 3 has a smaller gradient✓
Mass of H2 (g)
Graph 2 Grafiek 3 het 'n kleiner gradiënt
Graph 3 forms half of the H2 compared to exp 2✓
Grafiek 3 vorm helfte van H2 in vergelyking met
Graph 3 eksp. 2
Time (s) (2)
[19]
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QUESTION 6/VRAAG 6
6.1 The stage in a chemical reaction when the rate of forward reaction equals the
rate of reverse reaction. (2 or 0)
Die stadium in 'n chemiese reaksie wanneer die tempo van die voorwaartse
reaksie is gelyk aan die tempo van die terugwaarste reaksie. (2 of 0)
OR/OF
The stage in a chemical reaction when the concentrations /quantities of
reactants and products remain constant.
Die stadium in 'n chemiese reaksie wanneer die konsentrasies/hoeveelhede
van reaktanse en produkte konstant bly. (2)
6.2 Light brown✓/Ligbruin (1)
ACCEPT: colourless/AANVAAR: kleurloos
6.3 Exothermic ✓
• Kc decreases with an increase in temperature✓
• The reverse reaction is favoured✓
Eksotermies
• Kc neem af met 'n toename in temperatuur
• Die terugwaartse reaksie word bevoordeel (3)
6.4 OPTION 1/OPSIE 1
CALCULATIONS USING MOLES
Marking guidelines/Nasienriglyne:
(a) n(N2O4) at equilibrium = cV = (3)(0,5) = 1,5 mol
(b) Using ratio ✓/Gebruik van verhouding
(c) n(NO2) at equilibrium = initial n(NO2) – used n(NO2) ✓
(d) Division of equilibrium moles of NO2 with 0,5 to get equilibrium concentration
(e) Correct Kc expression)✓/Korrekte Kc uitdrukking
(f) Substitution of Kc as 10 ✓/Substitusie van Kc as 10
(g) Substitution of concentrations into Kc expression
(h) Final answer/finale antwoord: 150,6 g
2NO2(g) N2O4(g)
Molar ratio 2 1
Molêre verhouding
Initial mol X -
Aanvanklike mol(mol) 46
Change in mol. 3 1,5 (b) ✓
Verandering in mol(mol)
Equilibrium amount (mol) X
- 3 ✓(c) 1,5✓(a)
Ewewig hoeveelheid(mol) 46
Equilibrium concentration X
-3 3
Konsentrasie by ewewig 46
✓(d) (given)
(mol·dm-3) 0,5
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[N2O4 ]
KC = ✓ (e)
[NO2 ]2
3
10✓ (f) = X ✓ (g)
-3 2
[46 ]
0,5
X = 150,6 g ✓ (h)
OR
2NO2(g) N2O4(g)
Molar ratio 2 1
Molêre verhouding
Initial mol n -
Aanvanklike mol(mol)
Change in mol. 3 1,5 (b) ✓
Verandering in mol(mol)
Equilibrium amount (mol) n - 3 ✓(c)
1,5✓(a)
Ewewig hoeveelheid(mol)
Equilibrium concentration 𝑛-3
✓(d) 3
Konsentrasie by ewewig 0,5
(given)
(mol·dm-3)
[N2 O4 ]
Kc = (e) ✓
[NO2 ]2
3
10✓ (f) = 𝑛-3 2 ✓ (g)
[ 0,5 ]
n = 3,274 mol
mX = nM
= (3,274)(46)
= 150,6 g ✓ (h)
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OPTION 2/OPSIE 2
CALCULATIONS USING CONCENTRATION
Marking guidelines/Nasienriglyne:
(a) n(N2O4) at equilibrium = change in c
(b) Using ratio/Gebruik van verhouding
(c) n(NO2) at equilibrium = initial n(NO2) – used n(NO2)
(d) Correct Kc expression/Korrekte Kc uitdrukking
(e) Substitution of Kc as 10/Substitusie van Kc as 10
(f) Substitution of concentrations into Kc expression
(g) The concentration of x(NO2) solving Kc = 6,548 mol∙dm-3
(h) Final answer/finale antwoord: 150,6 g
2NO2(g) N2O4(g)
Molar ratio 2 1
Molêre verhouding
Initial concentration c -
Aanvanklike konsentrasie (mol∙dm-3)
Change in concentration. 6 (b) ✓ 3 (a) ✓
Verandering in konsentrasie (mol∙dm-3)
Equilibrium concentration c-6 (c)✓ 3
Konsentrasie by ewewig (mol·dm-3) (given)
[N2 O4 ]
Kc = (d) ✓
[NO2 ]2
3
10✓ (e) = ✓ (f)
[x-6]2
[NO2] = 6,548 mol∙dm-3✓ (g)
mX = cMV
= (6,548)(46)(0,5)
= 150,6 g (h) ✓
OPTION 3/OPSIE 3
CALCULATIONS USING CONCENTRATION
Marking guidelines/Nasienriglyne:
(a) n(N2O4) and n(NO2) at equilibrium = cV ✓
(b) Using ratio ✓/Gebruik van verhouding
(c) initial n(NO2) = used n(NO2) + n(NO2) at
equilibrium ✓
(d equilibrium concentration of NO2 from Kc calculation
(e) Correct Kc expression)✓/Korrekte Kc uitdrukking
(f) Substitution of Kc as 10 ✓/Substitusie van Kc as 10
(g) Substitution of concentrations into Kc expression
(h) Final answer/finale antwoord: 150,6 g
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2NO2(g) N2O4(g)
Molar ratio 2 1
Molêre verhouding
Initial moles 3 + 0,27 0
Aanvanklike konsentrasie (mol) (c ) ✓
Change in mole. 3 (b) ✓ 1,5
Verandering in mol (mol)
Equilibrium amount ( mole)
0.27 (a) 1,5(a) ✓
Ewewigs hoeveelheid (mol)
Equilibrium concentration 0,548 (d) 3
Konsentrasie by ewewig (mol·dm-3) (given)
[N2 O4 ]
Kc = (e) ✓
[NO2 ]2
3
10✓ (f) = ✓ (g)
[[NO2 ]2
[NO2] = 0,548 mol∙dm-3 ✓ (d)
mX = nM
= (3,27)(46)
= 150,6 g ✓ (h) (8)
6.5 Decrease ✓/Neem af (1)
6.6
6.6.1 Stays the same, ✓ only temperature affects the Kc value ✓/
Bly dieselfde, slegs temperatuur affekteer die Kc waarde (2)
6.6.2 Increase✓
• Higher pressure favours the reaction that forms less moles✓
• The forward reaction is favoured ✓
Verhoog
• Hoër druk bevoordeel die reaksie wat minder mol vorm
• Die voorwaartse reaksie word bevoordeel (3)
[20]
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QUESTION 7/VRAAG 7
7.1.1 An acid ionises incompletely in water✓ to form a low concentration of H3O+ . ✓
'n Suur ioniseer onvolledig in water om 'n lae konsentrase H3O+ te vorm. (2)
7.1.2 OPTION 1 OPTION 2
pH = -log[H3O+]✓ [H3O+] = 10-pH ✓
4,5✓ = -log[H3O+] = 10-4.5 ✓
= 3,16 x 10-5 mol.dm-3 ✓ = 3,16 x 10-5 mol.dm-3 ✓ (3)
7.1.3 Greater than 7 ✓
A strong base (NaOH) reacts with a weak acid (HF) ✓/'n Sterk basis (NaOH)
reageer met 'n swak suur (HF) (2)
m
7.2.1 n(MgCO3) =
M
3,5
=
84
= 0,042 mol
n(HCℓ) = 2n(MgCO3) = (2)(0,042) ✓
= 0,084 mol ✓ (3)
7.2.2 POSITIVE MARKING FROM QUESTION 7.2.1
n(NaOH) = cV ✓
= (1,2)(0,02) ✓
= 0,024 mol
n(HCℓ)excess = n(NaOH) = 0,024 mol ✓
n(HCℓ)initial = n(reacted) + n(excess)
= 0,084 + 0,024 ✓
= 0,108 mol
n
c(HCℓ) =
V
0,108
= ✓
0,05
= 2,16 mol·dm-3 ✓
Range (2,08 – 2,16) (6)
[16]
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QUESTION 8/VRAAG 8
8.1
8.1.1 Chemical to electrical✓/Chemies na elektries (1)
8.1.2 Concentration/Konsentrasie – 1 mol∙dm-3 ✓
Temperature/Temperatuur - 25°C / 298 K✓ (2)
8.1.3 Fe ✓
Reduction takes place at this electrode ✓/Reduksie vind plaas by hierdie
elektrode.
OR
Fe3+ is a stronger oxidizing agent than Mg2+ / Fe3+ is ‘n sterker oksideermiddel
as Mg2+.
OR
Decrease in oxidation number of Fe3+ / Afname in oksidasiegetal van Fe3+ (2)
8.1.4 Mg → Mg2+ + 2e- ✓✓ (2)
8.1.5 Mg(s) l Mg2+(aq) ✓ll ✓ Fe3+(aq) l Fe(s)✓
NOTE: Ignore phases/NOTA: Ignoreer fases (3)
8.1.6 Salt bridge ✓/Soutbrug (1)
8.2 E θcell = E θcathode − E θanode ✓
= - 0,06 ✓ - (-2,36)✓
= 2,3 V✓ (4)
[15]
QUESTION 9/VRAAG 9
9.1 ANY ONE/ENIGE EEN:
• The chemical process in which electrical energy is converted to
chemical energy. (2 or 0)
Die chemiese proses waarin elektriese energie omgeskakel word na
chemiese energie.
• The use of electrical energy to produce a chemical change.
Die gebruik van elektriese energie om 'n chemiese verandering te weeg
te bring.
• Decomposition of an ionic compound by means of electrical energy.
Ontbinding van 'n ioniese verbinding met behulp van elektriese energie.
• The process during which and electric current passes through a
solution/ionic liquid/molten ionic compound.
Die proses waardeur 'n elektriese stroom deur 'n oplossing/ioniese
vloeistof/gesmelte ioniese verbinding beweeg. (2)
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Fisiese Wetenskappe/Graad 12 Marking Guidelines/Nasienriglyne
9.2 Red brown deposit/ copper deposit / mass increase / change in colour✓
Rooibruin neerslag/ koper neerslag / toename in massa / kleur verander (1)
9.3 2Cℓ- → Cℓ2 + 2e- ✓✓ (2)
9.4 Chloride ion ✓/Chloorioon (Cℓ-(ag)) (1)
9.5 It conducts electricity through the movement of ions ✓
Dit gelei elektrisiteit deur middel van bewegende ione. (1)
9.6 P✓
Pure copper forms through reduction of Cu2+ at the cathode✓
Suiwer koper vorm deur reduksie van Cu2+ by die katode (2)
9.7 The rate of reduction is equal to the rate of oxidation✓
Die tempo van reduksie is gelyk aan die tempo van oksidasie. (1)
9.8 Ag and Pt is weaker reducing agents ✓than Cu ✓and will not be oxidised✓
OR
Cu is a stronger reducing agent than Ag and gets oxidised
Ag en Pt is swakker reduseermiddels as Cu en word dus nie geoksideer nie.
OF
Cu is 'n sterker reduseermiddel as Ag en word dus geoksideer (3)
[13]
GRAND TOTAL/GROOTTOTAAL: 150
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