Physical Sciences Grade 12 Paper 1 KZN March 2015 Memo

__DNownloaded from _ hlayiso com Basic Education KwaZulu-Natal Department of Education REPUBLIC OF SOUTH AFRICA : : . % o _ PHYSICAL SCIENCES: PHYSICS (P1) 4 7 COMMON TEST ; He MARCH 2015 | x O) ( } MARKS: 50 TIME : 1 hour This question paper consists of 8 pages and a 1-page data sheet. Copyright Reserved Please Turn Over

Physical Sciences P1 Downloaded from hlayiso.CQMso15 common Test NSC INSTRUCTIONS AND INFORMATION TO CANDIDATES 10. 11. 12. Write your name on the ANSWER BOOK. This question paper consists of FIVE questions. Answer ALL the questions in the ANSWER BOOK. Start EACH question on a NEW page in the ANSWER BOOK. Number the answers correctly according to the numbering system used in this question paper. Leave ONE line between two subsections, for example between QUESTION 2.1 and QUESTION 2.2. You may use a non-programmable calculator. You may use appropriate mathematical instruments. You are advised to use the attached DATA SHEETS. Show ALL formulae and substitutions in ALL calculations. Round off your final numerical answers to a minimum of TWO decimal places. Give brief motivations, discussions, et cetera where required. Write neatly and legibly. Copyright Reserved Please Turn Over

Physical Sciences P1 NSC QUESTION 1: MULTIPLE- CHOICE QUESTIONS Downloaded from hlayiso.co m March 2015 Common Test Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Write only the letter (A - D) next to the question number (1.1 — 1.4) in the ANSWER BOOK, for example 1.11 D. 1.1. Asphere of mass 1 kg is held vertically above another sphere of mass 10 kg at a point near the Earth’s surface. The spheres are released simultaneously. If the effects of air friction are ignored, the distance between the spheres as they fall vertically will. . . increase decrease remain the same first decrease then increase when (2) 1.2 The momentum of an object falling vertically from rest is, p, after a time, t. If the effects of friction are ignored, what will the momentum be after time 2t ? A Pp B 2p Cc 3p D 6p Copyright Reserved (2) Please Turn Over

Downloaded from hlayiso.co Physical Sciences P14 arch 2015 Common Test NSC 1.3. Aboy pushes a motor car with a constant force of 400 N. The car experiences a constant frictional force of 100 N while it is moving. The magnitude of the force exerted by the car on the boy is... A 100N B 200N C 300N D 400N (2) 1.4 Arocket of mass, M, has a weight, W, on the surface of the earth. The rocket is blasted off to a height equal to the earth’s radius. At this point the mass of the rocket has decreased to “2 M because some of the fuel has been used up. The gravitational force of attraction between the rocket and the earth at this height is... A 4W B 8Ww Cc YW D ww (2) [8] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com 5 Physical Sciences P1 March 2015 Common Test NSC QUESTION 2 (Start on a new page) During a rescue mission, a stationary helicopter lifts a soldier of mass 75 kg, vertically upwards at a constant acceleration of 0,4 m:s*, by means of a rope. Ignore the effects of air friction when answering the following questions. 2.1. State Newton’s Second Law of Motion, in words. (2) 2.2 Drawa labelled free-body diagram showing all the forces acting on the soldier while he is being lifted vertically upwards. (3) 2.3 Calculate the magnitude of the force which the rope exerts on the soldier while the soldier is accelerating upwards at 0,4 m-s™. (4) The helicopter now accelerates vertically downwards. 2.4 How will the tension in the rope be affected? (Choose from INCREASES, DECREASES, NO EFFECT) (2) [11] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences P1 March 2015 Common Test NSC QUESTION 3 (Start on a new page) The position-time graph (not drawn to scale), represents the motion of a projectile that is fired vertically upwards from a point, P, above the ground. 4jeanese------- y(m) to |____-_------------------- 8 t(s) Ignore the effects of air friction when answering the following questions. 3.1. How does the magnitude of the initial velocity of the projectile compare with the magnitude of the velocity at time t? (Write down GREATER THAN, EQUAL TO OR LESS THAN) (1) 3.2 What is the value of t? (1) 3.3. How does the acceleration of the projectile at 3 s compare to its acceleration at t? (Write down GREATER THAN, EQUAL TO OR LESS THAN) (1) 3.4 Calculate the magnitude of the velocity with which the projectile was fired vertically upwards. (3) 3.5 Calculate the height of point P. (4) 3.6 Sketch a labelled acceleration-time graph in your answer book for the entire motion of the projectile. (3) [13] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com NSC Physical Sciences P1 QUESTION 4 (Start on a new page) The diagram below represents a minibus of mass 3 200 kg travelling at 12 m-s” on a straight horizontal road to the right. A car of mass 1 400 kg is travelling towards the minibus on the same road. The minibus collides with the car. Both vehicles come to an immediate stop after the collision. The above system must be taken as a closed system. 4.1 What is meant by a CLOSED SYSTEM? (2) 4.2 How does the magnitude of the initial momentum of the minibus compare to the magnitude of the initial momentum of the car? (Choose from GREATER THAN, EQUAL TO OR LESS THAN) (1) 4.3. State, without performing a calculation, whether the collision between the minibus is elastic or inelastic. (2) 4.4 The speed limit on this road is 20 m-s™. Determine, by doing the necessary calculations, whether the car was travelling within the speed limit. (5) [10] Copyright Reserved Please Turn Over March 2015 Common Test

Downloaded from hlayiso. co NSC : Physical Sciences P1 Mis Common Test ; QUESTION 5 (Start on a new page) _ The diagram below represents a diver, of mass 75 kg, jumping into the air from the end of a diving board. | i ! \ i | ' i | i \ The diver lands on the diving board with a speed of 6.m-s™. Her feet is in - contact with the board for.0,8 s before she bounces off the board. The diving board exerts a net force of 1 500 N on the diver while she is in contact with the board. | 5.1 Define impulse in words. . (2) O . 5.2 Calculate the speed with which the diver rebounds after landing on the diving board. (5) [8] | | 5.3. Give the name of the theorem that you used to answer question 5.2 above. (1) | TOTAL: 50 | | Copyright Reserved Please Turn Over

Physical Sciences P1 Downloaded from hlayiso.com NSC DATA FOR PHYSICAL SCIENCES (PHYSICS) GRADE 12 GEGEWENS VIR FISIESE WETENSKAPPE (FISIKA) GRAAD 12 TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE March 2015 Common Test KONSTANTES NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE Acceleration due to gravity et Swaartekragversnelling 9 9,8 ms Universal gravitational constant G 6,67 x 107° N.m2.kg? TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING Vp = Vj + at Ax =viAt+taat? or/of Ay =v,At+taat? VE EV; Vv, +V v4> = V2 + 2aAx orfof v,? =v, +2aby | AX -( a orlofAy =(“ a Ke E, om 1 mv2 2 FORCE/KRAG Fret =ma p=mv Fig =Ap=mv, =m, Fy=m Esc Gmim2 2 r Copyright Reserved

Downloaded from hlayiso.com

- Downloaded from hlayiso.com JEAQ WNL BSeeIq parsssay wSuxdod () Au yes = qusiey, ui y'g2- = ALE EI + »(B)(¥'62) = AVE + IVA = ay se (©) 7 Swyez= AS8'6-) + A= 0 Aye + Wain ve () porenbes ee a) AS ZE () vorjenba 1 €NOILSAND Cel @ S/PSBSERINND TZ (») ANGSL = 1 AW xX Gt = s('exgy-+ 4 ew = (64) + 1 yeu = 4 et () encore (smoue so yi6uei) Alubiem ueu} s9y2e18 uoisus 1 AvOISUSL, ce (2) / algo ay} jo ssew ay} 0} feuoniodosd Afesseaul pue A201} BUY 0} [EUORIOdOsd ApOSUIp S| UONEJE|SOOB SIU | "GO10} OLY JO UOHOELIP ‘BUF UL a}e8 [2098 IIIM Palgo Sy} ‘algo ue uo spe sau; (Jeu)jUEYNsa:e Ue EZ ZNOLLSAND [a] atx ara wk sea eb srg Th aro bk + NOLLSSND z wnpuzowew BupeW SL0z YOseW id SsqUaNS IOIskud 40A0 WIN @8kId penesey 1Bukdo9 ‘saBed ¢ jo s}sjsuoo wnpueiowoU siyL anou b = SIWIL os ‘SWUVIN ALVOIsILYaD YOINAS TWNOLLWN : s}0z HOU A i WNONVEOWON ONDRVIN : i LSAL NOWNCO : i (td) SOISAHd ?SAONFIOS TWOISAHd i SPPPPTTTTTTTT Terr reer eer eee eee ee err wesceeese ? Vvoludv HLNOS 40 OManday uojeonpg 40 Juaunsedag jeyen-ninzemy uoneonpy oiseg

Downloaded from hlayiso.com - penlesoy yYyBAdo [os] = -1WLOL Ig] (L) WsIOBY] WINJUSWOW-ssindul = ¢'¢ (a) ASO = IA (9 - A) sg2= (8'0) » (00SL-) AYU = +V youd anisod se UOOW pseMUMOP O¥eL YO A ,SWOL = 1A ((9-) = 8a) pg = A (8'0) 4 (0091) pau = VW yeud aageBou se UOHOU PIEMUMOP AVL ag (2) / p8y0R 80J0} OU} USIYM JO} BUI] OU] PUB BdJOJ JOU 94} JO JONpod = °G ( ) ¢ NOILSANOD lov (g) / ‘Pull pesds oy pepesoxe sey Jeo ey)’ SW OZ UB} Jayeei6 si eo ay} Jo paeds ay} SOUS AySWey'le- = weo(!a ) 0 = APUAXOOKL) + A (ZL X 002 €) A 49(¢A UW) + snqquu(s\UU) = 489(1ALU) + SNQUUIL(!A UL) Jaye. dejo, = aojeq d jejo) vy (2) APOWSEIAUL =P (t) poyienbe = _Z'p (Z) 019Z S| BOJOJ [ELUDIXO JON / 4 AWSISAS QU} UO JOE SOOO) [BUAJXO ON LV ( ‘ vy NOILSAND lev] “seu Z LUNWIXeu sIXe-x BADGE MeJP Se}ep|pued J] (e) 8'6- (s) SIxe-X OU} 0} Jel[eJed oul] jyBIENS » saxe , (,s-w)e oe wnpuesowsew BupyeyWy $L0z Ye, Ld seouelng jeoiskud