Physical Sciences Grade 12 Paper 1 EC June 2016 Memo

Downloaded from hlayiso.com GRADE 12/GRAAD 12 PHYSICAL SCIENCES/FISIESE WETENSKAPPE PAPER 1 (PHYSICS)/ VRAESTEL 1 (FISIKA) JUNE 2016/JUNIE 2016 MEMORANDUM MARKS: 150/PUNTE: 150 This memorandum consists of 11 pages. Hierdie memorandum bestaan uit 11 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com 2 PHYSICAL SCIENCES P1 (EC/JUNE 2016) QUESTION 1/VRAAG 1 1.1 A 1.2 B 1.3 C 1.4 D 1.5 A 1.6 C 1.7 A 1.8 C 1.9 A 1.10 D [20] QUESTION 2/VRAAG 2 2.1 The force that opposes the motion Die krag wat die beweging van of an object 9 and which 'n voorwerp teenwerk 9 en wat acts parallel to the surface. 9 parallel met die oppervlak inwerk. 9 (2) 2.2 When a resultant/net force acts on an Wanneer 'n resulterende/netto krag op 'n object, the object accelerates in the voorwerp inwerk, versnel die voorwerp in die direction of the (net) force 9 at rigting van die (netto) krag 9 teen an acceleration directly proportional 'n versnelling direk eweredig aan die krag 9 to the force 9and en inversely proportional to the mass omgekeerd eweredig aan die massa of the object. 9 van die voorwerp. 9 (3) 2.3 Marking criteria Nasienkriteria N Correct arrow and label for Korrekte pyl en byskrif vir F each force: 3 elke krag: 3 Comparative lengths of Vergelykende lengtes van f arrows are not required. pyle word nie vereis nie. Components of forces are Komponente van kragte T not accepted. word nie aanvaar nie. w Accepted labels/Aanvaarbare byskrifte Fw/Fg/mg/Fweight/Weight/Gravitational force/Force of gravity w Fw/Fg/mg/Fgewig/Gewig/Gravitasiekrag Fapplied F Ftoegepas FT/Tension/Force of rope on block T FT/Spanning/Spankrag/Spanningskrag/Krag van tou op blok Ffriction/Ff/Friction/Frictional force/Force of friction f Fwrywing/Ff/Wrywing/Wrywingskrag FN/Fnormal/Normal force N FN/Fnormaal/Normaalkrag (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/JUNIE 2016) FISIESE WETENSKAPPE V1 3 2.4 OPTION 1 / OPSIE 1 Accept / Aanvaar OPTION 3 / OPSIE 3 fk = ȝkN 9 f = ȝN If proportion is used: First proof that = ȝkmgcosș ȝ2 = ȝ4. If not; max 2/4. = (0,589) x (2)(9,8)cos30° 9 9 As eweredigheid gebruik word: Bewys eers dat ȝ2 = ȝ4. Indien nie; maks 2/4. = 10 N 9 Accept / Aanvaar OPTION 2 / OPSIE 2 fk = ȝkN 9 f = ȝN = ȝ4mgcosș N = mgcosș 20 = ȝ4(4)(9,8)cos30° 9 = (2)(9,8)(cos30°) 9 ȝ4 = 0,589 = 16,974 N Accept / Aanvaar m2 : m4 = 1 : 2 9 fk = ȝkN 9 f = ȝN f2 : f4 = 1 : 2 = (0,589)(16,974) 9 f2 = ½ x 20 = 10 N 9 = 10 N 9 (4) 2.5 From 2.4 / Vanaf 2.4 OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2 + + Fnet = ma 9 Fnet = ma 9 9 9 4 kg: 73,8 - T - 20 - (4)(9,8)(sin 30°) = 4a 4 kg: -73,8 + T + 20 + (4)(9,8)(sin 30°) = -4a 9 9 9 9 2 kg: T - 10 - (2)(9,8)(sin 30°) = 2a 2 kg: -T + 10 + (2)(9,8)(sin 30°) = -2a 9 9 T = 24,6 N 9 T = 24,6 N 9 OPTION 3 / OPSIE 3 System method: Max: 4/6 + Sisteemmetode: Maks: 4/6 Fnet = ma 9 73,8 - 20 - 10 - (4)(9,8)(sin 30°) - (2)(9,8)(sin 30°) = 6a 9 9 T = 24,6 N 9 OPTION 4 / OPSIE 4 System method: Max: 4/6 + Sisteemmetode: Maks: 4/6 Fnet = ma 9 -73,8 + 20 + 10 + (4)(9,8)(sin 30°) + (2)(9,8)(sin 30°) = -6a 9 9 T = 24,6 N 9 (6) 2.6.1 Remains the same. (99) Bly dieselfde. (99) (2) 2.6.2 Remains the same. (99) Bly dieselfde. (99) (2) 2.6.3 Increases (99) Vermeerder (99) (2) [26] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com 4 PHYSICAL SCIENCES P1 (EC/JUNE 2016) QUESTION 3/VRAAG 3 3.1 FGas on rocket Marking criteria Nasienkriteria FGas op vuurpyl Up arrow and correct label: 3 Op-pyl en korrekte byskrif: 3 Down arrow and correct label: 9 Af-pyl en korrekte byskrif: 3 FEarth on rocket Up arrow > down arrow: 9 Op-pyl > af-pyl: 9 FAarde op vuurpyl If dot not shown: max 2/3 As kol nie gewys is nie: maks 2/3 Accepted labels / Aanvaarbare byskrifte w / Fw / Fg / mg / Fweight / Weight / Gravitational FEarth on rocket force / Force of gravity FAarde op vuurpyl w / Fw / Fg / mg / Fgewig / Gewig / Gravitasiekrag Fpropulsion / Fapplied / Propulsion / Propulsive force FGas on rocket FGas op vuurpyl Fstukrag / Ftoegepas / Stukrag / Aandrywingskrag (3) 3.2.1 Upwards9 Opwaarts9 (1) 3.2.2 Downwards9 Afwaarts9 (1) Weight is the only force acting on the rocket. 9 3.3 Q9 – (2) Gewig is die enigste krag wat op die vuurpyl inwerk. 3.4.1 OPTION 1 / OPSIE 1 + If downwards is chosen as positive: max 2/3. Indien afwaarts as positief gekies is: maks 2/3. vf = vi + aǻt 9 112,8 = 0 + a(4) 9 Example for option 1 / Voorbeeld vir opsie 1 a = 28,2 m·s-2 9 vf = vi + aǻt + -112,8 = 0 + a(4) OPTION 2 / OPSIE 2 + a = -28,2 m·s-2 ǻx = viǻt + ½aǻt2 9 Similar for options two and three. 225,6 = 0 + ½(a)(42) 9 a = 28,2 m·s-2 9 Soortgelyk vir opsie twee en drie. OPTION 3 / OPSIE 3 + vf2 = vi2 + 2aǻx 9 112,82 = 02 + 2(a)(225,6) 9 a = 28,2 m·s-2 9 (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/JUNIE 2016) FISIESE WETENSKAPPE V1 5 3.4.2 OPTION 1 / OPSIE 1 + If downwards is chosen as positive: max 4/6. Indien afwaarts as positief gekies is: maks 4/6. ǻt(RG) ǻy = viǻt + ½aǻt2 9 Example: Option 1 / Voorbeeld: Opsie 1 -225,6 = 112,8ǻt + ½(-9,8)ǻt2 9 9 9 + ǻt(RG) ǻy = viǻt + ½aǻt2 ǻt = 24,872 s 225,6 = -112,8ǻt + ½(9,8)ǻt2 ǻt = 24,872 s ǻt (total / totaal) = 24,872 + 4 9 ǻt (total / totaal) = 24,872 + 4 = 28,87 s 9 = 28,87 s Similar for options two and three. Soortgelyk vir opsie twee en drie. OPTION 2 / OPSIE 2 + ǻt(RS) vf = vi + aǻt 9 0 = 112,8 + (-9,8)ǻt 9 ǻt = 11,510 s ǻy(RS) ǻy = viǻt + ½aǻt2 § vf  vi · = (112,8)(11,510) + ½(-9,8)(11,510)2 9 OR / OF 'y ¨ ¸'t = 649,176 m © 2 ¹ § 0  112,8 · ¨ ¸(11,510) 9 vf2 = vi2 + 2aǻx © 2 ¹ OR / OF 02 = (112,82) + 2(-9,8)ǻx 9 649,164 m ǻx = 649,176 m ǻy = viǻt + ½aǻt2 ǻt(SG) (-649,176 - 225,6) = 0 + ½(-9,8)ǻt2 9 ǻt = 13,361 s ǻt (total / totaal) = 4 + 11,510 + 13,361 9 = 28,87 s 9 OPTION 3 / OPSIE 3 + v at ground / v by grond vf2 = vi2 + 2aǻx 9 = (112,82) + 2(-9,8)(-225,6) 9 vf = -130,941 m·s-1 § v f  vi · ǻt(RG) vf = vi + aǻt 'y ¨ ¸'t -130,941 = 112,8 + (-9,8)ǻt OR / OF © 2 ¹ 9 9 §  130,941 ( 112,8) · ǻt = 24,872 s  225,6 9 ¨ ¸'t 9 © 2 ¹ 't 24,872 s ǻt (total / totaal) = 4 + 24,872 9 = 28,87 s 9 (6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com 6 PHYSICAL SCIENCES P1 (EC/JUNE 2016) 3.5 v 112,8 Accept / Aanvaar 28,9 (*) 28,87 0 t 4 Marking criteria / Nasienkriteria (0;0) indicated. 1 (4;112,8) indicated. 1 t = 28,87(*) indicated; positive marking from Q3.4.2. 1 Graph starts at (0;0); straight line from (0;0) to (4;112,8) with positive 1 gradient. From (4;112,8): Straight line with negative gradient and ends at 1 t = 28,87(*). Last value = positive marking from Q3.4.2. From (4;112,8): Straight line intersects the time axis between t = 4 1 and t = 28,87(*). Last value = positive marking from Q3.4.2. If downwards is chosen as positive: max 4/6. Indien afwaarts as positief gekies is: maks 4/6. Graph should be as indicated below, with similar marking criteria. Grafiek moet wees soos hieronder aangedui met soortgelyke nasienkriteria. v 4 0 t 28,87 Accept / Aanvaar -112,8 28,9 (*) Marking criteria / Nasienkriteria (0;0) indicated. 1 (4;-112,8) indicated. 1 t = 28,87(*) indicated; positive marking from Q3.4.2. 1 Graph starts at (0;0); straight line from (0;0) to (4;-112,8) with negative gradient. 1 From (4;-112,8): Straight line with positive gradient and ends at t = 28,87(*). Last value = positive marking from Q3.4.2. 1 From (4;-112,8): Straight line intersects the time axis between t = 4 and t = 28,87(*). Last value = positive marking from Q3.4.2. 1 (6) [22] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/JUNIE 2016) FISIESE WETENSKAPPE V1 7 QUESTION 4/VRAAG 4 4.1 Momentum is the product of an Momentum is die produk van 'n object's mass and its velocity. (99) voorwerp se massa en sy snelheid. (99) (2) 4.2 OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2 Dir opposite to motion: Dir of motion: + Rig van beweging: Rig teenoorgesteld + ǻp = mvf - mvi 9 ǻp = mvf - mvi 9 aan beweging: = (175)(0 - (+20)) 9 = (175)(0 - (-20)) 9 = -3 500 kg·m·s-1 9 = 3 500 kg·m·s-1 9 k ǻp = 3 500 kg·m·s-1; k ǻp = 3 500 kg·m·s-1; opposite to direction of motion` 9 opposite to direction of motion` 9 teenoorgesteld aan bewegingsrigting teenoorgesteld aan bewegingsrigting (4) 4.3 OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2 Dir opposite to motion: Dir of motion: + Rig van beweging: Rig teenoorgesteld + Fnetǻt = ǻp 9 Fnetǻt = ǻp 9 aan beweging: f(8) = -3 500 9 f(8) = 3 500 9 f = -437,5 N 9 f = 437,5 N 9 k f = 437,5 N; k f = 437,5 N; opposite to direction of motion 9 opposite to direction of motion 9 teenoorgesteld aan bewegingsrigting teenoorgesteld aan bewegingsrigting (4) 4.4 The net/total work done on an object 9 Die netto/totale arbeid verrig op 'n voorwerp 9 is equal to the change in the is gelyk aan die verandering in die object's kinetic energy. 9 voorwerp se kinetiese energie. 9 OR/OF The work done on an object by Die arbeid verrig op 'n voorwerp deur a resultant/net force 9 'n resulterende/netto krag 9 is equal to the change in the is gelyk aan die verandering in object's kinetic energy. 9 die voorwerp se kinetiese energie. 9 (2) 4.5 f = 437,5 N from / van 4.3 OPTION 1 / OPSIE 1 Dir of motion: + OPTION 2 / OPSIE 2 Dir of motion: + Rig van beweging: Rig van beweging: Wf = ǻK 9 § v  vi · 'x ¨ f ¸'t = ½(175)(02) - ½(175)(+202) 9 © 2 ¹ = -35 000 J 9 § 0  20 · ¨ ¸(8) 9 OPTION 3 / OPSIE 3 Dir of motion: + © 2 ¹ Rig van beweging: 80 m Wf = ǻK + ǻU 9 = ½(175)(02) - ½(175)(+202) + 0 9 Wf = fǻxcosș 9 = -35 000 J 9 = (437,5)(80)(cos 180°) = -35 000 J 9 (3) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com 8 PHYSICAL SCIENCES P1 (EC/JUNE 2016) QUESTION 5/VRAAG 5 5.1 In an isolated system 3 In 'n geslote sisteem 9 the total mechanical energy (sum of bly die totale meganiese energie (som gravitational potential energy and van gravitasie-potensiële energie en kinetic energy) remains constant. 3 kinetiese energie) konstant. 9 (2) 5.2 EM (Top/Bo) = EM (Bottom/Onder) 3 (Ep + Ek) = (Ep + Ek) Anyone mgh + ½ mv2 = mgh + ½ mv2 Enigeen 2 2 (1,6)(9,8)(1,5) + ½(1,6)v = 0 + ½(1,6)(5,6 ) 3 3 3 v = 1,40 m·s-1 3 (5) 5.3 Total linear momentum of a closed system3Totale lineêre momentum in 'n geslote remains constant/is conserved. 9 sisteem 9 bly konstant/behoue. 9 (2) 5.4 OPTION 1 / OPSIE 1 + Ȉpi = Ȉpf Anyone 3 Enigeen m1v1 + m2v2 = m1+2v 0,005v1 + 1,595(0) 3 = 1,6(1,40) 3 v1 = 448 m·s-1 Magnitude of vel/speed = 448 m·s-1 3 Grootte van snelheid/spoed OPTION 2 / OPSIE 2 + ǻp1 = -ǻp2 Anyone m1ǻv1 = -m2ǻv2 3 Enigeen 0,005(1,4 - v1) 3 = -1,595(1,4 - 0) 3 v1 = 448 m·s-1 Magnitude of vel/speed = 448 m·s-1 3 Grootte van snelheid/spoed (4) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/JUNIE 2016) FISIESE WETENSKAPPE V1 9 QUESTION 6/VRAAG 6 6.1 Speed 9 Spoed 9 (1) 6.2 3 9 (m·s-1) (1) 6.3.1 It is the change in frequency (or pitch) Dit is die verandering in frekwensie (of of the sound detected by a listener 9 toonhoogte) van die klank waargeneem because deur 'n luisteraar 9 the sound source and the omdat listener have different velocities die klankbron en die luisteraar verskillende relative to the medium of sound snelhede relatief tot die medium het waarin propagation. 9 die klank voortgeplant word. 9 (2) 6.3.2 345 9 (m·s-1) (1) 6.3.3 § v r vL · fL ¨¨ ¸¸fS 9 © v r vS ¹ § 345  0 ·§ 1000 · 9 ¨¨ ¸¸¨ ¸ 9 © 345  57,5 ¹© 1 ¹ 1200 Hz 9 (4) 6.3.4 295 9 (K) Accept: The same temperature Aanvaar: Dieselfde temperatuur (1) 6.4.1 (Diagram) 3 9 (1) The source is stationary. 6.4.2 19 – 9 (2) Die bron staan stil. [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com 10 PHYSICAL SCIENCES P1 (EC/JUNE 2016) QUESTION 7/VRAAG 7 7.1.1 A region of space in which an electric 'n Gebied in die ruimte waarin charge experiences a force. (99) 'n elektriese lading 'n krag ondervind. (99) (2) 7.1.2 Marking criteria Nasienkriteria + Correct shape 3 Korrekte patroon 3 Direction of field lines 3 Rigting van veldlyne 3 (2) 7.1.3 kQ E 9 r2 (9 x 10 9 )(2 x 10 9 ) 12 9 18 N ˜ C 1 9 (3) 7.2.1 Y to/na X 9 (1) 7.2.2 OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2 QX  QY QX  QY Q 9 Q 9 2 2 ( 2)  ( 7) ( 2 x 10 9 )  ( 7 x 10 9 ) 9 9 2 2  2,5 nC 9  2,5 x 10 9 C 9 (3) 7.2.3 The magnitude of the electrostatic force Die grootte van die elektrostatiese krag exerted by one point charge on another wat een puntlading op ’n ander punt- point charge 9 lading uitoefen, 9 is directly proportional to the product of is direk eweredig aan die produk van die the magnitudes of the charges 9 grootte van die ladings 9 and inversely proportional to the square en omgekeerd eweredig aan die of the distance between them. 9 kwadraat van die afstand tussen hulle. 9 (3) 7.2.4 OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2 kQQ kQQ F 9 F 9 r2 r2 (9 x 10 9 )(2,5 x 10 9 )(2,5 x 10 9 ) (9 x 10 9 )( 2,5 x 10 9 )( 2,5 x 10 9 ) 99 99 22 22 1,41x 10 8 N 9 1,41x 10 8 N 9 F = 1,41 x 10-8 N; F = 1,41 x 10-8 N; 9 9 repulsive / to the left repulsive / to the left afstotend / na links afstotend / na links (5) [19] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com (EC/JUNIE 2016) FISIESE WETENSKAPPE V1 11 QUESTION/VRAAG 8 8.1 Each body in the universe attracts every other body with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres. Elke liggaam in die heelal trek elke ander liggaam aan met ‘n krag direk eweredig aan die produk van hul massas en omgekeerd eweredig aan die kwadraat van die afstand tussen hulle middelpunte. (2) 8.2 GMe g at h = (re + h) 2 6,67 ×10 -11 × 5,98 ×10 24 = (6,38 ×10 6 + 0,05 × 6,38 ×10 6 ) 2 = 8,89 m.s-2 (5) 8.3 Increases/Neem toe (1) 8.4 Factor of 4 9 /Faktor van 4. The force is inversely proportional to the distance r between their centres. 99 Die krag is omgekeerd eweredig aan die afstand r tussen hulle middelpunte. 99 (3) [11] QUESTION/VRAAG 9 9.1 Impulse is defined as the product of the resultant/net force acting on an object and the time the resultant/net force acts on the object. 99 Impuls word definieer as die produk van die resultant/netto krag wat op ‘n voorwerp inwerk en die tyd wat die resultant/netto lrag op die voorwerp inwerk. 99 (2) 9.2 Impulse = Fnet.ǻt = ǻp = mǻv ( Towards the barrier is taken as positive) (Na die voorwerp word geneem as positief) Impulse = mǻv = 1 500(0 – 13,89) (50 km.h-1 = 50 × 10 003 600 = 13,89 m.s-1) = í20 833,33 N.s = 20 833,33 away from the barrier/weg vanaf die voorwerp (5) 9.3 Impulse = Fnet.ǻt í20 833,33 = Fnet×0,15 Fnet = í138888,87 N Fnet = 138 888,87 N away from the barrier/weg vanaf die voorwerp (4) [11] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

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