Physical Sciences Grade 12 Paper 1 Mpumalanga June 2025 Memo

education MPUMALANGA PROVINCE REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 PHYSICAL SCIENCES: PHYSICS P41 FISIESE WETENSKAPPE: FISIKA V1 JUNIE/JUNE 2025 MARKING GUIDELINES/NAS/ENRIGLYNE MARKS/PUNTE: 150 These marking guidelines consists of 17 pages Hierdie nasienriglyne bestaan uit 17 bladsye Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

QUESTION 1 / VRAAG 1 4.4 4:2 1.3 1.4 1.5 1.6 flak 1.8 1.9 1.10 Copyright reserved/Kopiereg voorbehou D vv G vv DvyY B vv B vv Avy Dvv Bvv ByY Dvv MDENune Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn Please turn over/Blaai om asseblief (2) (2) (2) (2) (2) (2) (2) (2) (2) (2) [20]

MDE/Nune Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn QUESTION 2/ VRAAG 2 2.1. Marking criteria/Nasienkriteria \f any one of the underlined key words/phrases in the correct context is omitted, deduct 1 mark. /Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. When a net force acts on an object, the object will accelerate in the direction of the force and the acceleration is directly proportional to the resultant/net force and inversely proportional to the mass of the object. vv Wanneer ‘n resulterende/netto krag op ‘n voorwerp inwerk, versnel die voorwerp in die rigting van die krag ieen 'n versnelling direk eweredig aan die resultante/netto_krag en omgekeerd eweredig aan die massa van die voorwerp. OR/OF The resultant/net force acting on an object is equal to the rate of change of momentum of the object. (2 or 0) Die resulterende/netto krag wat op ‘n voorwerp inwerk is gelyk aan die tempo van verandering van momentum. (2 of 0) (2) 2:2 Nw Tv fv wv (4) Accepted labels / Aanvaarde benoemings Ww Fy / Fw/ force of earth on block / weight / mg / gravitational force / 11760N T Tension / Fr f Frriction / Fr / frictional force /wrywing N Normal force / Fn Notes/Aantekeninge: e Mark awarded for label and arrow. e Any additional forces: deduct 1 mark: max 3/4 e No labels: deduct 1 mark: max 3/4 e If everything correct, but no arrows: deduct 1 mark: 3/4 e Force(s) not touching object: deduct 1 mark: max 3/4 e Ignore relative sizes of the vectors Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

2.3 2.4 2.5 2.6 27 MDENune Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn f=uNv = (0.2)(1200)(9,8)cos20° v =2210,16N¥ (3) YESHA ¥ (1) For trailer: Fret = ma P T + (4) + ((Fot) =ma > Any one/Enige een ¥ T—2210,16 Y —(1200)(9,8)sin20° v= (1 200)(2,5) v T — 6232,317 = 3000 T =9 232,22NY (5) Marking criteria/Nasienkriteria If any one of the underlined key words/phrases in the correct context is omitted, deduct 1 mark. Andien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. A body will remain in its state of rest or motion at constant velocity unless a non-zero resultant/net force acts on it.vv ‘n Liggaam sal in sy toestand van rus of beweging teen konstante snelheid volhard, tensy 'n nie-nul resulterende/netto krag daarop inwerk. (2) For trailer: Fret = ma T + (-f) + ((-Fgi) = ma T= 2210,16 - (1200)(9,8)sin20° v= 0 v T —6232,317 =0 T =6232,32N For bakkie: Fret = ma F + (-f) + ((-Fol) + (-T) = ma £ — (0,3)2700)(9,8) cos20° v —(2700)(9,8)sin20° v - 6232,32 = 0 F — 7459,28 — 9049,85 - 6232,32 =0 F = 22 741,45 NV (5) [22] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

MDENune Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn QUESTION 3/ VRAAG 3 3.1 3.2 3.3.1 3.3.2 3.4 9,8 ms? V downwards/afwaarts Vv Free fall is the motion during which the only force acting on an object is the gravitational force.. v Y (2 or 0) Vryval is die beweging waartydens die enigste krag wat op 'n voorwerp inwerk, die gravitasiekrag is. (2 or 0) OPTION 1/OPSIE 1 Upwards positive/Opwaarts positief ve = vi2+ Zady ¥ vi? = (0)? + 2(-9,8)(-92,4) ¥ w=42.56m:s' v Downwards positive/Afwaarts positief ve = vit+ 2aAy ve? = (0)? + 2(9,8)(92,4) vi = 42.56 m:s* POSITIVE MARKING FROM Q3.2 POSITIEWE MERK VANAF Q3.2 OPTION 1/OPSIE 1 Upwards positive/Opwaarts positief vf =vi+ at v -42,56 = 0 + (-9,8)At v At=4,34s v Downwards positive/Afwaarts positief vf = vi + aAt 42,56 = 0 + (9,8)At At= 4,345 OPTION 2/OPSIE 2 Upwards positive/Opwaarts positief Ax=viAt + %aAt? ¥ -92,4 = OAt + % (-9,8)Ar v At=4,34s v Downwards positive/Afwaarts positief Ax = viAt + % aAt? 92,4 = OAt + % (9,8)At? At =4,34s POSITIVE MARKING FROM Q3.2 & 3.3 POSITIEWE MERK VANAF Q3.2 & 3.3 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief (2) (2) (3) (3)

MDE/June Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn Downwards positive/Afwaarts positief ; 42,56 vim-s") 0 —> 4,34 t(s) ¥ Marking criteria for graph Mark Nasienriglyne vir grafiek Punt Correct shape of graph v | Korrekte vorm van grafiek Final velocity v Eindsnelheid Time at which it reaches the ground v Tyd wat dit neem om die grond te tref Upwards positive/Opwaarts positief 4 v(m-s"t) 4,34 -42,56 t(s) (3) 3.5 Same/Dieselfde v Mass has no influence/Gravitational acceleration is the same/it is in a free fall v Massa het geen invloed nie/Gravitasie versnelling is dieselfde/dit is in vryval (2) [15] QUESTION 4/ VRAAG 4 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

MDE/Nune Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn 41 Impulse is the product of the resultant/net force acting on an object and the time the net force acts on the object. vv (2 or 0) Impuls is die produk van die resulterende/netto krag wat op 'n voorwerp inwerk en die tyd wat die netto krag op die voorwerp inwerk.. (2 of 0) (2) 4.2 Frer At = Ap Fret-At = mvr — mvi } v Any one/enige een Impulse = mvs — mvi = (0,15)(3,65) — (0,15)(-6,5) ~ = 1,52 kg: m-s/N:s VW (3) 4.3. | Ewtop = Emsotrom Extop + Eptor = Exsottom + Epgotrom } v Any one/enige een Yamv? + mgh = Y%mv? + mgh 0 + (0,15)(9,8)h » = 4(0,15)(6.5)? “+ 0 h=2,16m Initial height dropped from is 2,16 m. YBh=%x 2,16 ¥ = 0,72m The ball does not meet minimum requirementsY because it only reached 0,65 m. (5) [10] QUESTION 5/ VRAAG 5 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

5.1 5.2 5.3 5.4 MDE/June Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn Marking criteria/Nasienkriteria \f any one of the underlined key words/phrases in the correct context is omitted, deduct 1 mark. /Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. The total mechanical energy (sum of gravitational potential energy and kinetic energy) in an isolated system remains constant.v v Die totale meganiese energie (som van gravitasie- potensiéle energie en kinetiese energie) in 'n geslote sisteem bly konstant. Nv FY wv Accepted labels / Aanvaarde benoemings w Fg / Fw/ force of earth on block / weight / mg / gravitational force /2450 N F Applied force / Force of trolley A on trolley B N Normal force / Fn Notes/Aantekeninge: e Mark awarded for label and arrow. e Any additional forces: deduct 1 mark: max 2/5 e No labels: deduct 1 mark: max 2/5 e If everything correct, but no arrows: deduct 1 mark: 2/5 e Force(s) not touching object: deduct 1 mark: max 2 fe e Ignore relative sizes of the vectors Emtop = Emsottom Extop + Eprop = Exsotrom + Epsottom } v Any one/enige een Yamv? + mgh = Yamv2 + mgh 0 + (300)(9,8)(30) v= %4(300)v? V+ 0 v= 24,25 ms! Vv POSITIVE MARKING FROM Q5.3 POSITIEWE MERK VANAF Q5.3 TAKE TO THE RIGHT AS POSITIVE/NEEM REGS AS POSITIEF Copyright reserved/Kopiereg voorbehou } Please turn over/Blaai om asseblief (2) (3) (4) (5)

MDE/June Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn Zpi = Xpr . (mya + (mvia= (mvi1 + (mvij2_ Y Any one/enige een (300)(24,25) v +0 = (300 + 250)vi v vr = 13,23 m-s"' ¥ to the right/na regs ¥ 5.5 | POSITIVE MARKING FROM Q5.3 & Q5.4 POSITIEWE MERK VANAF Q5.3 & Q5.4 Whet = AEk t Any one fAx cos@ + fgiAx cos© = Yamver? — Yamvi2 (10) Axcos180°v + (550)(9,8)sin 30° Axcos180° v= 0 = [4(550)(13,23)?] v Ax=17,79mv (5) [19] QUESTION 6/ VRAAG 6 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

MDE/une Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn 6.1.1 Doppler effect as the change in frequency (or pitch) of the sound detected by a listener, because the sound source and the listener have different velocities relative to the medium of sound propagation.v v (2 or 0) Doppler-effek neer as die verandering in frekwensie (of toonhoogte) van die klank waargeneem deur 'n luisteraar omdat die klankbron en die luisteraar verskillende snelhede relatief tot die medium waarin die klank voortgeplant word, het. (2 of 0) (2) 6.1.2. Higher than v Hoér as (1) 6.1.3 — ‘t els Y OR feels 335 +0 v ae -) Sap f, = 903,97 Hz v (5) 614) yasy Accept : ve% t At d 20=-v 3 d=60m¥ (3) 6.2.1 Yvv (2) 6.2.2 Away from the Earth/Weg van die Aarde v Vv (2) [15] QUESTION 7 / VRAAG 7 7.1 | Marking criteria/Nasienkriteria Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

MDE/June Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn Note: If masses used ( %, ) If any one of the underlined key words/phrases in the correct context is omitted, deduct 1 mark. /Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. The magnitude of the electrostatic force exerted by one point charge (Q1) on another point charge (Qz2) is directly proportional to the product of the magnitudes of the charges Y and inversely proportional to the square of the distance (r) between them ¥ Die grootte van die elektrostatiese krag wat een puntlading (Q:) op 'n ander puntlading (Q2) uitoefen, is direk eweredig aan die produk van die groottes van die ladings en omgekeerd eweredig aan die kwadraat van die afstand (r) tussen hulle. G2 Fev Fg v Accepted labels / Aanvaarde benoemings Fe Electrostatic force between charges X and Y Elektrostatiese krag tussen ladings X en Y Fy Gravitational force on X Gravitasiekrag op X Notes/Aantekeninge: e Any additional forces: deduct 1 mark: max i, e No labels: deduct 1 mark: max "Yo e No arrows: 0/2 e Force(s) not touching object: deduct 1 mark: max 1, e Ignore relative sizes of the vectors 7.3 kQ1Q F)=mg p= ee Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief (2) (2) (6)

MDE/June Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn = (40x 103) (9,8) ¥ = 0,392 N Fy =Fe (9x10°)q? (0,3) 0,392 = q =2x10°C v Charge on Y original = 4 x 10° C v (9x10°) q? v (0,3)° QUESTION 8 / VRAAG 8 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief [10]

MDENune Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn 8.1 The electric field at a point is the electrostatic force experienced per unit positive charge placed at that point.“ v (2 or 0) Die efektriese veld by 'n punt is die elektrostatiese krag wat per eenheidspositiewe-lading wat by daardie punt gepiaas is, ondervind word. (20r0) (2) Criteria for sketch/Kriteria vir skets Marks/Punte Correct shape as shown. v Korrekte vorm soos getoon. Direction away from positive to negative. v4 Rigting weg van positief na negatief. Field lines start on spheres and do not cross for correct v diagram. Veldlyne begin op elke sfeer en kruis nie vir korrekte diagram. (3) 8.2 8.3 Added / Bygevoeg V (1) 84.1[ 7 @y e —4 x 107° n= —16 x10-% = 2,5 x 10" electrons/elektrone V (3) 8.4.2 | Marking criteria/Merk kriteria e Mark for correct formula to calculate E e Mark for substituting into formula for charge A e Mark for substituting into formula for charge C Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

| _® Mark for correct direction MDE/June Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn « Mark for correct use of positive and negative signs e Mark for the final answer kQ 72 r. B= Enet=Ea tEgtEc _ x 10°)(1 x 1078) e (9 x 10°)(2,5 x 107°) - (9 x 10°)(4 x 107°) ~ (0,016)? v (0,014)? ~ (0,01)2 Enet = 2, 098 x 10° N.C* ¥ left ¥ QUESTION 9/ VRAAG 9 9.1 Copyright reserved/Kopiereg voorbehou The maximum energy provided by a battery per unit charge passing through it. vv (2 or 0) Please turn over/Blaai om asseblief (6) [15] (2)

MDE/une Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn Die maksimum energie wat ‘n battery lewer per eenheidslading wat daardeur vloei. (2 of 0) 92 fi a,i1,1 R= 2,860 v (3) 9.3 | OPTION 1/OPSIE 1 Diagram B e The total resistance of the circuit increasesY e Total current decreasesY e The Vint decreasesY e therefore Vext increases OPTION 2/OPSIE 2 Diagram A The total resistance of the circuit decreasesY Total current increasesY The Vint increasesY therefore Vext decreases (3) 9.4.1 | POSITIVE MARKING FROM Q9.2 POSITIEWE MERK VANAF Q9.2 1=3,50A v (3) 9.4.2 | POSITIVE MARKING FROM Q9.2 & 9.4.1 POSITIEWE MERK VANAF Q9.2 & 9.4.1 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

MDE/une Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn Diagram A E=1(R+r) v © =3,5 (2,86 +r) Vv....... 1 Diagram B 12 #55 72,18 A €=1(R+n © =2,18 (5,5 4r) W......2 Equation 1 = Equation2 ¥ 3,5 (2,86 +r) = 2,18(5,5 + r) r=15Q Vv 9.4.3 | POSITIVE MARKING FROM Q9.2 & 9.4.1 & 9.4.2 | POSITIEWE MERK VANAF Q9.2 & 9.4.1 & 9.4.2 €=l(R+09 = 3,5 (2,86 +1,5) V = 15,26 V v OR E=1(R+5) = 2,18 (5,5 +1,5) ¥ =15,26Vv Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief (5) (2)

9.4.4 9.5 MDE/une Junie2025 NSC/NSS-Marking Guideline/Nasienriglyn POSITIVE MARKING FROM Q9.2 & 9.4.1 & 9.4.2 & 9.4.3 POSITIEWE MERK VANAF Q9.2 & 9.4.1 & 9.4.2 & 9.4.3 OPTION 1/OPSIE 1 P=PRV = (2,18)? (5,5)¥ = 26,14 WY OPTION 2/OPSIE 2 P P= a2"? 5,5 P = 26,18WvY ll | x OPTION 3/OPSIE 3 P=Viv = (12) (2,18)” = 26,16 Wv The voltmeter reading INCREASES. v Total resistance increases and total current decreases, Vv Vint decreases “ * Die voltmeterlesing NEEM TOE * Totale weerstand neem toe en totale stroom neem af + Vint neem af TOTAL/TOTAAL Copyright reserved/Kopiereg voorbehou (3) (3) [24] 150