Physical Sciences Grade 12 Paper 2 Mpumalanga June 2025 Memo

education MPUMALANGA PROVINCE REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE NASIONALE SENIORSERTIFIKAAT GRADE/GRAAD 12 PHYSICAL SCIENCES: CHEMISTRY P2 FISIESE WETENSKAPPE: CHEMIE (V2) JUNE/JUNIE 2025 MARKING GUIDELINES/NAS/ENRIGLYNE MARKS/PUNTE: 150 This marking guidelines consists of 15 pages. Hierdie nasienryglyne bestaan uit 15 bladsye. Copyright Reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines QUESTION 1 / VRAAG 1 110 BYY 12 Cvv 13° Dv 14. Avv 15 Cvv 16 Cvv 17 BYY 18 Dvv 19 Dvv 110 Dv¥v [20] QUESTION 2 / VRAAG 2 2.1.1 Cv (1) 2.1.2 Av (1) 213 Dx (1) 2.2.1 5-ethyl-2-methylhept-3-yne /5-etiel-2-metielhept-3-yn Marking criteria: Nasienkriteria: e Correct stem i.e. heptyne. ¥ e Korrekte stam d.i. heptyn. ¥ e All substituents (ethyl and methyl) ¢ Alle substituente (etiel en metiel) correctly identified. v korrek geidentifiseer. ~ e IUPAC name completely correct « /UPAC-naam _ heeltemal korrek including numbering, sequence, insluitende volgorde, koppeltekens hyphens and commas. ¥ en kommas. ¥ (3) Copyright Reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines 2.2.2 HK , H-G-H H H H Cl H | HH I ft f tot | | v “TTP rt tT H Cl | H H HH H H—C—H H—C—H H v Marking criteria/Nasienkriteria e Eight C atoms in longest chain/ Agt C-atome in langste kettingY ¢ One Cl atom on C2 and one on C4./Een Ci-atom op C2 en een op C4 Vv e Ethyl! substituent on C3 and methy! substituent on C6./Etielsubstituent op C3 en metielsubstituent op C6V IF/INDIEN H-atom or bond omitted/H-atoom of binding uitgelaat. Max/Maks: 2/5 (3) 2.2.3. Aldehyde/Aldehied v (1) 2.2.4 O | tl 4 on (1) 2.3.1 | Marking criteria/Nasienkriteria If any one of the underlined key phrases in the correct context is omitted, deduct 1 mark./indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is, trek 1 punt af. The underlined phrases must be in the correct context. / Die onderstreepte frases moet in die korrekte konteks wees. Organic compound with the same molecular formula, but_different positions of the side chain, substituents or functional groups on the parent chain. Vv Organiese verbindings met dieselfde_molekulére formule, maar verskillende posisies van die syketting. substituente of funksionele groepe op die stamketting (2) 2.3.2 H H H H Vv Marking criteria/Nasienkriteria ee tog Ep ds e OH-group on C1 ¥ | | | |-—__— e OH-groep op C1 H H H H v e Whole structure correct. ¥ e Hele struktuur korrek (2) Copyright Reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

23.3 2.4.1 2.4.2 2.4.3 2.4.4 25 June/Junie 2025 NSC/NSS- Marking Guidelines Secondary alcohol/Sekondére alkohol ¥ The —OH group is (covalently) bonded to a carbon that is bonded to two other C-atoms “ Die —OH groep (kovalent) gebind is aan ‘n koolstof wat gebind is aan twee ander C-atome Esterification /Condensation/Esterifikasie/Kondensasie ¥ Marking criteria/Nasienkriteria Functional group correct ¥ Funksionelegroep korrek Whole structure correct. ¥ Hele struktuur korrek H2SO4/ Sulphuric acid/Swae/suur ~ (a) Piping a I} H e H—C—C—C—C—O—C-+C—H | | | “F-~ | vy H H H H H i. Butyl Yethanoate~/ Butieletancaat Marking criteria / Nasienkriteria: Substitute / Vervang 72 g:mol n = a v Use mole ration/ gebruik molverhoudingv Substitute number of moles and 22,4 dm?-mol™ in n = = v m a ‘, . actual Substitute / Vervang 76% in %yield = acon Final answer / Finale antwoord: 53,2 dm? v v _m "=u _ 45 ~ 72v = 0,625 mol nCO, = 5nCsH12 = 5(0,625) “en me NN V=fVa ] ~~ ” = 3,125 x 22,4V OR/OF ate Sonn = 70 dm? Nactuatwerkiik = 2.375 mol _x 'V=nVm on tamenil = 2,375 x 22,4v Vactualiwerkik = 53,2 dmv = 53,2 dmsv Copyright Reserved/Kopiereg voorbehou (2) (1) (1) (2) (2) (5) [28] Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines QUESTION 3 / VRAAG 3 3.1 3.2 3.3 3.4.1 3.4.2 3.4.3 3.5 3.6 Copyright Reserved/Kopiereg voorbehou Marking criteria/Nasienriglyne lf any one of the underlined key phrases in the correct context is omitted, deduct 1 mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is, trek 1 punt af. The temperature at which the vapour pressure of a substance equals atmospheric pressure. /Die temperatuur waarby die dampdruk van die stof gelyk is aan atmosferiese druk. VV IF Temperature is omitted 0/2. Flamable/ViambaarY Use straight chain v primary alcohols v Gebruik requitketting primére alkohole Chain length/number of C-atoms/molecular mass/surface area ¥ Kettinglengte/aantal C-atome/molekulére massa/opperviak Hydroxyl (group)/Hidroksiel(groep) ¥ Ethanol/Etanol “ C/propan-1-ol/propan-1-ol ¥ ACCEPT/ANVAAR: Formula/formule Marking criteria: e Compare the structures of the compounds e Compare the strength of intermolecular forces e Compare the energy required to overcome intermolecular forces e Vergelyk die struktuur van die verbindings e Vergelyk die sterkte van intermolekulére kragte e Vergelyk die energie benodig om intermolekulére kragte te oorkom C/CH3CH2CH2OH/Propan-t1-ol e Structure/Struktuur LONGEST chain length/largest surface area (over which intermolecular forces act ¥ e Intermolecular forces STRONGEST/MOST intermolecular forces/ Van der Waals forces/London forces/ dipole-dipole forces V e Energy Most/more_ energy is needed to overcome or break intermolecular forces/Van der Waals forces/dipole-dipole forces VW OR (2) (1) (2) (1) (1) (1) (1) Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines A/CH3;0H/methanol « Structure Shortest_chain length/smallest surface area (over which intermolecular forces act ¥ « Intermolecular forces Weakest/less intermolecular forces/ Van der Waals forces/London forces/ dipole-dipole forces ¥ e Energy Least energy is needed to overcome or break intermolecular forces/Van der Waals forces/dipole-dipole forces ¥ OR From A to C e Structure Chain length/ surface area inreases. ¥ e Intermolecular forces The intermolecular forces/ Van der Waals forces/London forces/ dipole- dipole forces increase. ¥ e Energy The energy require to overcome the intermolecular forces /Van der Waals forces/London forces/ dipole-dipole forces increases ¥ OR From C to A e Structure Chain length/ surface area decreases. ¥ e Intermolecular forces The intermolecular forces/ Van der Waals forces/London forces/ dipole- dipole forces decrease. ¥ e Energy The energy require to overcome the intermolecular forces /Van der Waals forces/London forces/ dipole-dipole forces decreases V C/CH3CH2CH20H/Propan-1-ol e = Struktuur Langste_kettinglente/grootste opperviak (waaroor intermolekulére kragte werk) ¥ e Intermolekulére kragte Sterkste/meeste _intermolekulére__kragte/ Van der Waalskragte/ Londonkragte/ dipool-dipoolkragte ¥ e Energie Meeste energie benodig om _ die __intermolekulére__kragte/Van der Waalskragte/ dipool-dipoolkragte te oorkom/breek. ¥ Copyright Reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines OF C/CH30H/Metanol «© = Struktuur Kortste_kettinglente/kleinste opperviak (waaroor intermolekulére kragte werk) ¥ e Intermolekulére kragte Swakste/minste__intermolekulére__kragte/ Van der Waalskragte/ Londonkragte/ dipool-dipoolkragte ¥ « Energie Minste energie benodig om die intermolekulére kragte/Van der Waalskragte/ dipool-dipooikragte te oorkom/breek. ¥ OF Van A tot C e Struktuur Kettinglengte/ opperviakte(waaroor intermolekulére kragte werk) verhoog.” e Intermolekulére kragte Die intermolekulére kragte/ Van der Waalskragte/ Londonkragte/ dipool- dipoolkragte verhoog.“ e Energie e Die energie benodig om die intermolekulére kragte/Van der Waalskragte/ dipool-dipoolkragte te oorkom/breek verhoog. ¥ (3) OF Van C totA e Struktuur Kettinglengte/ opperviakte(waaroor intermolekulére kragte werk) verlaag.~” e Intermolekulére kragte Die intermolekulére kragte/ Van der Waalskragte/ Londonkragte/ dipool- dipoolkragte verlaag.¥ e Energie Die energie benodig om die intermolekulére kragte/Van der Waalskragte/ dipool-dipoolkragte te oorkom/breek verlaag. V 3.7.1. The two compounds have the same molecular mass/Die twee verbindings het dieselfde molekulére massa (1) Copyright Reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines Boke Marking criteria: State that carboxylic acids have two sites for hydrogen bonding State that alcohols have one site for hydrogen bonding Compare the strength of intermolecular forces Compare the energy required to overcome intermolecular forces Nasienkriteria: Benoem die intermolekulére kragte Ste! dat karboksielsure twee plekke het vir waterstofbindings Stel dat aikohole een plek het vir waterstofbinding Vergelyk die sterkte van die IMK's / energie benodig om IMK's te oorkom Vergelyk die energie benodig om intermolekulére kragte te oorkom Copyright Reserved/Kopiereg voorbehou Compound C/ CH3CH2CH:OH/ propan-t-ol/ alcohol has one site for hydrogen bonding Compound X/CHsCOOH/ ethanoic acid/carboxylic acid has two/more sites for hydrogen bonding. “ Intermolecular forces in Compound X/CH3COOH/ ethanoic acid / carboxylic acid are stronger than the intermolecular forces in compound _ C/ CH3CH2CH2OH/ propan-1-ol/ alcohol. ~ More energy is needed to overcome/break intermolecular forces in compound Compound X/CHsCOOH/ ethanoic acid / carboxylic acid than Compound C/ CH3CH2CH20H/ propan-1-ol/ alcohol “ Verbinding C/ CH3sCH2CH2O0H/propan-t-ol/alkohol het een punt_vir waterstofbindings en verbinding X/CH3COOH/etanoésuur / karboksielsuur het twee/meer punte vir waterstofbindings. “ Intermolekulére__kragte in _verbinding — X/CH3COOH/__ etanoésuur/ karboksielsuur_is_ sterker_ as die intermofekulére kragte in verbinding C/ CH3CH2CH20H/propan-1-ol/alkohol. “ Meer energie word benodig om _intermolekulére_kragte in _verbinding X/CHsCOOH/etanoésuur/__karboksielsuur__as__in__verbinding _C/ CH3sCH2CH20H/propan-1-ol/alkohol “ (4) [17] Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines QUESTION 4/ VRAAG 4 4.1.1 4.1.2 4.1.3 4.2.1 4.2.2 4.2.3 4.3.1 4.3.2 4.4 Copyright Reserved/Kopiereg voorbehou Addition/hydrogenationY Addisie/hidrogenasie/hidrogenering Substitution” Substitusie Elimination/dehydrationY Eliminasie/dehidrasie Butan-2-ol/2-Butanolv Marking criteria: ¢ Correct stem i.e.butanol ¥ e |UPAC name completely correct including numbering and hyphens.” Nasienkriteria e Korrekte stam d.i. butanol e /UPAC-naam heeltemal korrek insiuitende nommering en koppeltekens. Water/H20 ¥ Hydration/Hidrasie. ¥ Saturated/Versadig ¥ Compounds in which there are no multiple bonds between C atoms in their hydrocarbon chains. “ Verbindings waarin daar geen meervoudige bindings tussen C-atome in hul koolwaterstofkettings is nie Heat/UV light/hf/ Hitte/UV lig/hf ~ H /Cl\ H_ H H oH V H lit} 1 | % vo strongly | jets 1 ¥ H—C—-C+-C—C—H + NaOH(c) ——* H—-C-*C==C-+-C—H + NaCl + H20 1 Yvyod heated J. oe H H HH H H H Marking Criteria/Nasienriglyne e Chlorine on the second C for 2-chlorobutaneY Chloor atoom op die tweede C-atoom vir 2-chiorobutaan e Whole structural formula correct ¥ Hele struktuurformule vir 2-bromobutaan korrek e NaOH as reactant ¥ NaOH as ‘n reaktant e Water(H20) as part of the productsY¥ Water (H2O) as deel van die produkte e The functional group on the second carbon for but-2-eneY Die funksionele groep op die tweede koolstof atoom vir but-2-een e Whole structural formula correct “ Hele struktuur korrek (1) (1) (1) (2) (1) (1) (2) (1) (6) Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines NOTE/LET WEL molecular formulae e Penaliseer slegs « Penalise only once for the use of condensed structural formulae or een keer vir die gebruik van gekondenseerde Struktuurformules of molekulére formule 4.5 No water (H2O)” and a non-reactive solvent/dissolve in ethanolY Geen water (H20) en onreaktiewe oplosmiddel/ los op in etanol QUESTION 5/ VRAAG 5 5.14 _m, n(Q2) = _ 36,8 ~ 32v = 1,15 mol” Marking criteria/Nasienriglyne ® Formula /Formule ¢ Substitute 32 in formula / Vervang 32 in formule « Answer / Antwoord 5.1.2 POSITIVE MARKING FROM QUESTION 5.1.1 n(PbS) = = n(02) n(PbS) =F (1,15) = 0,7666 mol m n= m 0,7666 = 2307 m = 183,23 g Vv Marking criteria/Nasienriglyne e Mol ratio/ mol verhouding e Substitute 239 in formula / Vervang 239 in formule e Answer / Antwoord 5.1.3 POSITIVE MARKING FROM QUESTION 5.1.2 83,23 %Purity = a x 100% 00 =22,9%V 5.2.1 H20 v 5.2.2 2(min) ¥ 5.2.3 The reaction stopped/The reaction reached completion/The limiting reactant has been used up.” Die reaksie het gestop/Die reaksie het voltooing bereik/ Die beperkende reaktant is opgebruik Copyright Reserved/Kopiereg voorbehou (2) [17] (3) (3) (2) (1) (1) (1) Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines 5.2.4 The change in concentration v of reactants or products per unit time” /Die verandering in konsentrasie V van reaktante of produkte per eenheid tydv . (2) 5.2.5 Am Rate = — Wt 25 — 50v =—€ 2(60)” ) = 0,2083 (g:s*)v (3) 5.2.6 Marking criteria/Nasienriglyne « Both curves start at the same point and have the same endpoint/ Beide kurwes begin by dieselfde punt en het dieselfde eindpunt ¥ e Steeper gradient / steiler hellingY Mass /Massa SO3 Time /Tyd (min) (2) 5.2.7 e Increase in temperature increases the average kinetic energy/molecules move faster. Vv Toename in temperatuur verhoog die gemiddelde kinetiese energie/molekule beweeg vinniger. e More molecules have enough/sufficient kinetic energy/More molecules have E.2E.v Meer molekule het genoeg/voldoende kinetiese energie/Meer molekule het E,2E.. e More effective collisions per unit time/second. /Frequency of effective collisions increases. v Meer _effektiewe _botsings per __eenheidtyd/sekonde./Frekwensie van effektiewe botsings neem toe. (3) [21] Copyright Reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

June/Junie 2025 QUESTION 6 / VRAAG 6 6.1.1 Close system is isolated from its surroundings./ ‘n Geslote sisteem is geisoleer van die omgewingY (1) 6.1.2 e From green to yellow./ Van groen na geelv e When concentration is increased the reaction that decreases the concentration is favoured / Wanneer konsentrasie verhoog sal die reaksie wat die konsentrasie verlaag bevoordeel word. ¥ e [NO] increases/the reverse reaction is favoured/ [NO] verhoog/die terugwaartse reaksie word bevoordeel. ¥ e [NOC{] will increase / [NOCE] sal toeneemv (4) 6.1.3 | Marking criteria/Nasienriglyne If any one of the underlined key phrases in the correct context is omitted, deduct 1 mark./indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is, trek 1 punt af. When the equilibrium in a closed system is disturbed, the system will re-instate a new equilibrium by favouring the reaction that will oppose the disturbance. / Wanneer die ewewig in 'n geslote sisteem versteur word, stel die sisteem 'n nuwe ewewig in deur die reaksie wat die versteuring teenwerk, te bevoordeel. vv (2) DECREASED / VERLAAG. Vv The concentration of Cfz inceases. / Die konsentrasie van Cf2 verhoog. ¥ The forward reaction is favoured.Die voorwaartse reaksie is bevoordeel” The reaction that forms the most/greatest number of moles was favoured, thus the pressure was decreased. /Die reaksie wat die meeste/grootste aantal mol vorm was bevoordeel.v (4) 6.2.1 Exothermic / Eksotermies V (1) 6.2.2 e From the graph, we can see that an increase in temperature decreases the yield of ammonia/ Vanaf die grafiek kan afgelei word dat ‘n toename in temperatuur die hoeveelheid ammoniak laat toeneem. V e Anincrease in temperature favours the endothermixc reaction/ ‘n toename in temperatuur sal die endotermiese reaksie bevoordeel. e Increase in temperature favours the reverse reaction/Verhoging in temperatuur bevoordeel die terugwaarste reaksie. ¥ e Thus, the forward reaction is exothermic / die voorwaartse reaksie is eksotermies. ¥ (4) 6.2.3 50% (1) Copyright Reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines 6.3. Marking criteria / Nasienkriteria: a. b oa Substitute 4 in nCuC4* initial and 2,2 in NCu(H2O)e6"* final in table Vervang 4 in nCuC#é aanvankik @N 2,2 in NCu(H2O)6*finaal in tabel Use mol ratio / Gebruik mol verhouding : 1:4:1 ¥ n Equilibrium/ n Ewewig = nReactants / nReaktanteinitiaybegin + NReactants / nReaktante reacted! reageer a . n Equilibrium/ n Ewewig = n Reactants initiabegin - N Reactants reacted/ reageer dq ‘e. Divide by the volume (2)/ Deel deur die volume (2) V f. Correct Ke expression / Korrekte Ke uitdrukking v g he . Correct substitute into Kc expression / Korrekte invervanging in Ke — uitdrukking ¥ . Final answer / Finale antwoord (0,00218) v Cu(H20)2"(aq) 40 (aq) CuCl? (aq) Initial mol 0 0 4 Aanvanklike mol Change in mol +2,2 - + -2,2 : Verandering in mol ae Ba Ratio v (b) Equilibrium mol C227 8.8 1.8 Ewewigs mol . Equilibrium concentration 11 ve 44 0.9 vig)! . Ewewigskonstante ( ( ) Y Divide by 2 (e) _ [cue] ee = [Cu(H,0)2"}/cr}* (f) NB: If the chemical equation has (0.9) been reversed in the table, award = ———; 7/8 marks, no mark for the answer. (1,1)(4,4) =0,00218Y (h) (8) [25] Copyright Reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines QUESTION 7 / VRAAG 7 7.1. An Acid is a proton donor (H* -ion donor) /'n Suur is 'n protonskenker (H* -ioon- skenker). vv (2) 7.2.1 Asubstance that can act as either acid or base. vv ‘n Stof wat as of 'n suur Of 'n basis kan reageer (2) 7.2.2 HSO3 ¥ (1) 7.2.3 H2SOs, HSO3 Yand/en | ACCEPT: if arrows on the equation were used. H20, H30* ¥ | AANVAAR: Indien pyle op die vergelyking gebruik is (2) 7.3. Bromothymol blue / Broomtimoibiou “ e ls most suitable for a solution with a pH = 7/ Mees geskik vir oplossing wat ’n pH =7 het. ¥ e Reaction of a strong acid and a strong base/The equivalence pont is equal to pH 7/ Reaksie van 'n sterk suur en 'n sterk basis/Die ekwivalente punt is gelyk aan ’n pH van 7” (3) 7.4.1. n(NaOH) = cV = (1,2)(0,2)” = 0,24 mol ¥ (2) POSITIVE MARKING FROM QUESTION 7.4.1 POSITIEWE NASIEN VAN VRAAG 7.4.1 74.2 Marking criteria / Nasienkriteria: a) Formula c=o v b) Substitute 0,85 and 0,02367 in correct formula / Vervang 0,85 en 0,02367 in regte formule” c) Mol ration (NazCOsz) :n (HNO) 1:2 ¥ d) V(HNOs) in 0,05 dm? to 0,2 dm3v e) 1 initial (HNOs) ~ N excess (HNOs) vv f) | Substitude 56 in correct formula 4,426464 g) purity = —="— x 100% % h) Final answer (34,0 — 34,5) v n (NazCOs) = cVY (a) CaVa_ Ne = (0,85) (0,02367) v(b) | GV, ny ; = 0,0201195 mol c,x50 2 fa 1 n(HNOs) = 2n(Na2COs) aes ¥(c) =0,0201195 x 2 (c) =| aa = 0,040239 mol in 50cm? —| =2:80478 mot-dmn n(HNOzs)=cV =0,80478x0,05 =0,040239 mol Copyright Reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

June/Junie 2025 NSC/NSS- Marking Guidelines Therefore (4 x 0,040239 mol) = 0,160956 mol in 200 cm? v (d) used (HNO3) = Ninita| (HNO3) — Nexcess(HNO3) Nuseg(HNO3) = 0,24 — 0,160956 vv (e) Nusedf HNO) = 0,079 mol m n(KOH) = uM 0,079044 = sav 8 m = 4,426464 g 4,426464 %purity/suiwerheid = —3,— 100¥ (g) = 34,05% v (h) (9) [21] GRAND TOTAL/GROOTTOTAAL [150] Copyright Reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief