Gr10 Math P1 (Afrikaans and English) June 2019 Possible Answers_hlayiso.com_.pdf

Downloaded from hlayiso.com GAUTENG DEPARTMENT OF EDUCATION / GAUTENGSE DEPARTEMENT VAN ONDERWYS PROVINCIAL EXAMINATION / PROVINSIALE EKSAMEN JUNE 2019 / JUNIE 2019 GRADE 10 / GRAAD 10 MARKING GUIDELINE NASIENRIGLYNE MATHEMATICS WISKUNDE (PAPER 1) / (VRAESTEL 1) TIME / TYD: 60 minutes / minute TOTAL / TOTAAL: 50 1

Downloaded from hlayiso.com MATHEMATICS / WISKUNDE MEMORANDUM (PAPER / VRAESTEL 1) GRADE / GRAAD 10 GAUTENG DEPARTMENT OF EDUCATION / GAUTENGSE DEPARTEMENT VAN ONDERWYS PROVINCIAL EXAMINATION / PROVINSIALE EKSAMEN QUESTION 1 / VRAAG 1 1.1.1 ( )( )  simplify / vereenvoudig first two terms / eerste twee terme last two terms / laaste twee terme (3) 1.1.2 9 x 1.5 x  2 45 x 1 32 x  2 .5 x  2  2 x  2 x 1  32 x  2 3 .5  32 x  2 .5x 1 5 5 OR / OF OR / OF x 1 x2 9 .5 45x 1   32 x  2  2 x  2 .5x  2  x 1  5  (3) 1.2.1 ( ) ( )( ) ( ) (2) 1.2.2 3(3x 4 y ) 2  (3 x 2 y 2 )3  12 x 2  12 y 4  27x8 y 2   27 x8 y 2  27 x 6 y 6  12 x 2  12 y 4  27x6 y 6   3[9 x 6 y 2  x 2  y 4   4  x 2  y 4 ] grouping and common factor / groepering en gemeenskaplike   3  x  y 2  x  y 2  3x3 y  2  3x3 y  2  faktor  3   x  y 2  x  y 2    3x3 y  2  3x3 y  2  (6) [14] 2

Downloaded from hlayiso.com MATHEMATICS / WISKUNDE MEMORANDUM (PAPER / VRAESTEL 1) GRADE / GRAAD 10 QUESTION 2 / VRAAG 2 2.1.1 ( ) standard form / standaardvorm factors / faktore ( )( ) both answers / albei antwoorde or (3) 2.1.2 x  3 2 x  4 2 x   1 x2 x 1 x 1  ( x  3) ( x  3) 2 x  4 2 x    ( x 1)( x 1) ( x 1)( x  1) x 1 x 1 ( x  3)  (2 x  4)( x 1)   2 x( x  1)  x  3  2x2  2x  4   2x2  2x   2 x2  2 x  4 x   7  2 x 2  2 x x7  x7 (5) x 1 2.1.3 2 2 x 4  2 x 1  21  2 1  2 x 1 4 1 2x    4 2 2x  8  2x  8 2 x  23  x 3 x 3 (3) 2.2.1 2   2 x  1 3 1  2 x  4  1  2 x  4 1 1  x 2  x  2 2  2  x (3) 2.2.2  1 correct answer / korrekte x  2;  antwoord  2 (1) 2.2.3 correct number line / korrekte getallelyn -2 (1) 3

Downloaded from hlayiso.com MATHEMATICS / WISKUNDE MEMORANDUM (PAPER / VRAESTEL 1) GRADE / GRAAD 10 2.3 x 2  ( x  1) 2  85  x2  ( x 1)2  85 x 2  x 2  2 x  1  85  0 simplify / vereenvoudig 2 x 2  2 x  84  0 2( x  7) ( x  6)  0 x   7 or / of x  6  show that -7 is N / A / aandui N/A/ n.v.t. N/A dat -7 nvt is nvt Numbers / Getalle: 6; 7  Numbers / Getalle: 6; 7 (4) [20] QUESTION 3 / VRAAG 3 3.1 1 Tn  3n  1 1 1 1 T1    3(1)  1 4 4 1 T2  1  1  3(2)  1 7 7 1 1 The first two terms are: / Die eerste twee terme is: , 4 7 (2) 3.2 1 1  325 3n  1  1  1 3n  1  325 325 3n  1 3n  324  n 108 n 108 (2) [4] 4

Downloaded from hlayiso.com MATHEMATICS / WISKUNDE MEMORANDUM (PAPER / VRAESTEL 1) GRADE / GRAAD 10 QUESTION 4 / VRAAG 4 4.1 B (2;0) coordinate B and C / C (0;  4) koördinate B en C y  ax 2  q y  ax 2  4 0  a (2) 2  4 correct substitute / korrekte 4  4a vervanging a 1 y  x2  4 answer / antwoord (3) 4.2 D (0;1) coordinate of D / A (2;0) Koördinaat van D y  mx  c 0  m(2)  1 correct substitute / korrekte 1   2 m vervanging 1 m 1 2 m 2 1 y  x 1 2 (3) 4.3 1 y  x 1 2 y  2x  4 1 2 x  4  x 1 2 1  2 x  4  x 1 3 2 x 5 2 10 x 10 3  x 3  10  y  2   4  3 8 y 8 3  y 3  10 8  (3) E ;   3 3 5

Downloaded from hlayiso.com MATHEMATICS / WISKUNDE MEMORANDUM (PAPER / VRAESTEL 1) GRADE / GRAAD 10 4.4 y4 answer / antwoord (1) 4.5 0 x 2 correct values / korrekte waardes correct inequality signs / korrekte ongelykheidstekens OR / OF x   0; 2 (2) [12] TOTAL / TOTAAL: 50 6